pH and pK - AP Chemistry

  1. Calculate KbK_b if Ka=1.0×10−5K_a = 1.0 \times 10^{-5} for a conjugate acid-base pair.
    Kb=1.0×10−9K_b = 1.0 \times 10^{-9}. Using Ka×Kb=1.0×10−14K_a \times K_b = 1.0 \times 10^{-14}.
  2. Calculate the pH of a 0.05 M H2_2SO4_4 solution.
    pH ≈ 1. H2_2SO4_4 is diprotic; [H+^+] = 0.10 M.
  3. Identify the pH range of a basic solution.
    pH > 7. Higher OH−^- concentration than neutral solution.
  4. What is the pKb_b of a strong base?
    Low pKb_b. Strong bases have very negative pKb_b values.
  5. Identify the pH range of an acidic solution.
    pH < 7. Higher H+^+ concentration than neutral solution.
  6. What is the formula for the base dissociation constant (KbK_b)?
    KbK_b is the equilibrium constant for the dissociation of a base. Measures the extent of base ionization in solution.
  7. Calculate the pH of a 0.1 M HCl solution.
    pH = 1. HCl completely ionizes; [H+^+] = 0.1 M.
  8. Find the pOH of a solution with pH = 2.
    pOH = 12. Using the relationship pH + pOH = 14.
  9. What does a high pKa_a indicate about the strength of an acid?
    Weak acid. High pKa_a means low ionization tendency.
  10. Calculate the [H+^+] for a solution with pH = 6.
    [H+^+] = 1.0×10−61.0 \times 10^{-6} M. Using [H+^+] = 10−pH10^{-\text{pH}} relationship.
  11. What is the relationship between KaK_a and pKapK_a?
    pKa=−log10(Ka)\text{pK}_a = -\text{log}_{10}(K_a). Takes the negative logarithm of the acid constant.
  12. What is the relationship between KaK_a and KbK_b for a conjugate acid-base pair?
    Ka×Kb=KwK_a \times K_b = K_w. Fundamental relationship for conjugate pairs.
  13. Calculate the [OH−^-] for a solution with pOH = 8.
    [OH−^-] = 1.0×10−81.0 \times 10^{-8} M. Using [OH−^-] = 10−pOH10^{-\text{pOH}} relationship.
  14. What is the pH of a 0.1 M acetic acid solution with Ka=1.8×10−5K_a = 1.8 \times 10^{-5}?
    pH ≈ 2.88. Using the weak acid approximation formula.
  15. State the relationship between pH and pOH in water at 25°C.
    pH+pOH=14\text{pH} + \text{pOH} = 14. Based on the ion product of water at 25°C.
  16. Identify the term for the negative logarithm of the base dissociation constant.
    pKb_b. Standard notation for base dissociation constant.
  17. What is the pH of pure water at 25°C?
    pH = 7. Autoionization gives equal H+^+ and OH−^-.
  18. Define the term 'acid dissociation constant' (KaK_a).
    KaK_a is the equilibrium constant for the dissociation of an acid. Measures the extent of acid ionization in solution.
  19. What is the formula for calculating pH?
    pH=−log10[H+]\text{pH} = -\text{log}_{10}[\text{H}^+]. Negative log base 10 of hydrogen ion concentration.
  20. Which has a higher pH: 0.1 M HCl or 0.1 M CH3_3COOH?
    0.1 M CH3_3COOH. Acetic acid is weak, HCl is strong acid.
  21. Calculate the pH of a 0.001 M HNO3_3 solution.
    pH = 3. HNO3_3 completely ionizes; [H+^+] = 0.001 M.
  22. Determine the pH of a 0.01 M NaOH solution.
    pH = 12. NaOH gives [OH−^-] = 0.01 M, so pOH = 2.
  23. Calculate the pKa_a for an acid with Ka=3.2×10−4K_a = 3.2 \times 10^{-4}.
    pKa_a ≈ 3.5. Using pKa=−log⁡(3.2×10−4)\text{pK}_a = -\log(3.2 \times 10^{-4}).
  24. What is the pH of a 1.0 M solution of a strong base?
    pH = 14. Strong base gives [OH−^-] = 1.0 M, pOH = 0.
  25. Find the pH of a 0.1 M solution of a strong acid.
    pH = 1. Strong acids completely ionize in solution.
  26. If KaK_a is small, is the acid strong or weak?
    Weak acid. Small KaK_a means limited ionization.
  27. If KaK_a is large, is the acid strong or weak?
    Strong acid. Large KaK_a means extensive ionization.
  28. What is the formula for calculating pOH?
    pOH=−log10[OH−]\text{pOH} = -\text{log}_{10}[\text{OH}^-]. Negative log base 10 of hydroxide ion concentration.
  29. Calculate the pKb_b for a base with Kb=4.5×10−8K_b = 4.5 \times 10^{-8}.
    pKb_b ≈ 7.35. Using pKb=−log⁡(4.5×10−8)\text{pK}_b = -\log(4.5 \times 10^{-8}).
  30. What is the pH of a 0.01 M NH3_3 solution (Kb=1.8×10−5K_b = 1.8 \times 10^{-5})?
    pH ≈ 11.13. Using weak base approximation with given KbK_b.
  31. State the relationship between KbK_b and pKbpK_b.
    pKb=−log⁡10(Kb)pK_b = -\log_{10}(K_b). Takes the negative logarithm of the base constant.
  32. What is the pH of a neutral solution at 25°C?
    pH = 7. Equal concentrations of H+^+ and OH−^- ions.
  33. What is the formula for the ion product of water (KwK_w) at 25°C?
    Kw=1.0×10−14K_w = 1.0 \times 10^{-14}. Ion product constant for water at standard temperature.
  34. Calculate the pH of a solution with [H+^+] = 1.0×10−31.0 \times 10^{-3} M.
    pH = 3. Using pH=−log⁡(1.0×10−3)=3\text{pH} = -\log(1.0 \times 10^{-3}) = 3.
  35. What does a low pKb_b indicate about the strength of a base?
    Strong base. Low pKb_b means high ionization tendency.
  36. Determine the pOH of a solution with [OH−^-] = 1.0×10−41.0 \times 10^{-4} M.
    pOH = 4. Using pOH=−log⁡(1.0×10−4)=4\text{pOH} = -\log(1.0 \times 10^{-4}) = 4.
  37. Find the pH of a solution with pOH = 5.
    pH = 9. Using the relationship pH + pOH = 14.
  38. If pKa_a is 4, what is the strength of the acid?
    Weak acid. pKa_a = 4 indicates moderate acid strength.

Study these flashcards