AP Calculus BC Quiz
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APPLICATIONS OF INTEGRATION
Question 1
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What integral gives the volume when the region between
y
=
x
2
y=x^2
y
=
x
2
and
y
=
2
x
y=2x
y
=
2
x
on
[
0
,
2
]
[0,2]
[
0
,
2
]
is revolved about
y
=
−
1
y=-1
y
=
−
1
?
A
π
∫
0
2
[
(
2
x
+
1
)
2
−
(
x
2
+
1
)
2
]
d
x
\pi\displaystyle\int_{0}^{2}\big[(2x+1)^2-(x^2+1)^2\big]\,dx
π
∫
0
2
[
(
2
x
+
1
)
2
−
(
x
2
+
1
)
2
]
d
x
B
π
∫
0
2
[
(
2
x
)
2
−
(
x
2
)
2
]
d
x
\pi\displaystyle\int_{0}^{2}\big[(2x)^2-(x^2)^2\big]\,dx
π
∫
0
2
[
(
2
x
)
2
−
(
x
2
)
2
]
d
x
C
π
∫
0
2
[
(
x
2
+
1
)
2
−
(
2
x
+
1
)
2
]
d
x
\pi\displaystyle\int_{0}^{2}\big[(x^2+1)^2-(2x+1)^2\big]\,dx
π
∫
0
2
[
(
x
2
+
1
)
2
−
(
2
x
+
1
)
2
]
d
x
D
π
∫
0
2
[
(
2
x
−
1
)
2
−
(
x
2
−
1
)
2
]
d
x
\pi\displaystyle\int_{0}^{2}\big[(2x-1)^2-(x^2-1)^2\big]\,dx
π
∫
0
2
[
(
2
x
−
1
)
2
−
(
x
2
−
1
)
2
]
d
x
E
π
∫
0
2
[
(
2
x
+
1
)
−
(
x
2
+
1
)
]
2
d
x
\pi\displaystyle\int_{0}^{2}\big[(2x+1)-(x^2+1)\big]^2\,dx
π
∫
0
2
[
(
2
x
+
1
)
−
(
x
2
+
1
)
]
2
d
x
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