AP Calculus BC Quiz
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LIMITS AND CONTINUITY
Question 1
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A function is
g
(
x
)
=
x
2
−
4
x
+
2
g(x)=\frac{x^2-4}{x+2}
g
(
x
)
=
x
+
2
x
2
−
4
for
x
≠
−
2
x\ne-2
x
=
−
2
and
g
(
−
2
)
=
3
g(-2)=3
g
(
−
2
)
=
3
; what value makes
g
g
g
continuous at
x
=
−
2
x=-2
x
=
−
2
?
A
−
4
-4
−
4
B
−
2
-2
−
2
C
0
0
0
D
3
3
3
E
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