AP Calculus BC Quiz
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DIFFERENTIAL EQUATIONS
Question 1
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A function satisfies
d
y
d
x
=
y
(
x
+
2
)
\dfrac{dy}{dx}=\dfrac{y}{(x+2)}
d
x
d
y
=
(
x
+
2
)
y
with
y
(
0
)
=
6
y(0)=6
y
(
0
)
=
6
; which is the particular solution?
A
y
=
3
(
x
+
2
)
y=3(x+2)
y
=
3
(
x
+
2
)
B
y
=
6
(
x
+
2
)
y=6(x+2)
y
=
6
(
x
+
2
)
C
y
=
C
(
x
+
2
)
y=C(x+2)
y
=
C
(
x
+
2
)
D
y
=
12
x
+
2
y=\dfrac{12}{x+2}
y
=
x
+
2
12
E
y
=
3
ln
(
x
+
2
)
y=3\ln(x+2)
y
=
3
ln
(
x
+
2
)
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