AP Calculus BC Quiz
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LIMITS AND CONTINUITY
Question 1
of 20
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For
m
(
x
)
=
x
2
+
2
x
−
8
x
−
2
m(x)=\frac{x^2+2x-8}{x-2}
m
(
x
)
=
x
−
2
x
2
+
2
x
−
8
when
x
≠
2
x\ne2
x
=
2
and
m
(
2
)
=
0
m(2)=0
m
(
2
)
=
0
, which limit expression represents
m
(
x
)
m(x)
m
(
x
)
as
x
→
2
x\to2
x
→
2
?
A
lim
x
→
2
m
(
x
)
=
0
\lim_{x\to2} m(x)=0
lim
x
→
2
m
(
x
)
=
0
B
lim
x
→
2
m
(
x
)
=
6
\lim_{x\to2} m(x)=6
lim
x
→
2
m
(
x
)
=
6
C
m
(
2
)
=
6
m(2)=6
m
(
2
)
=
6
D
lim
x
→
6
m
(
x
)
=
2
\lim_{x\to6} m(x)=2
lim
x
→
6
m
(
x
)
=
2
E
lim
x
→
2
m
(
x
)
=
2
\lim_{x\to2} m(x)=2
lim
x
→
2
m
(
x
)
=
2
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