AP Calculus BC Quiz
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CONTEXTUAL APPLICATIONS OF DIFFERENTIATION
Question 1
of 20
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A motorcycle's acceleration is
a
(
t
)
=
2
cos
t
a(t)=2\cos t
a
(
t
)
=
2
cos
t
with
v
(
0
)
=
−
1
v(0)=-1
v
(
0
)
=
−
1
; what is
v
(
π
2
)
v\left(\frac{\pi}{2}\right)
v
(
2
π
)
?
A
v
(
π
2
)
=
−
1
+
∫
0
π
/
2
2
cos
t
d
t
v\left(\frac{\pi}{2}\right)=-1+\int_0^{\pi/2}2\cos t\,dt
v
(
2
π
)
=
−
1
+
∫
0
π
/2
2
cos
t
d
t
B
v
(
π
2
)
=
∫
0
π
/
2
2
cos
t
d
t
v\left(\frac{\pi}{2}\right)=\int_0^{\pi/2}2\cos t\,dt
v
(
2
π
)
=
∫
0
π
/2
2
cos
t
d
t
C
v
(
π
2
)
=
−
1
+
2
cos
(
π
2
)
v\left(\frac{\pi}{2}\right)=-1+2\cos\left(\frac{\pi}{2}\right)
v
(
2
π
)
=
−
1
+
2
cos
(
2
π
)
D
v
(
π
2
)
=
−
1
+
∫
0
π
/
2
(
−
2
sin
t
)
d
t
v\left(\frac{\pi}{2}\right)=-1+\int_0^{\pi/2}(-2\sin t)\,dt
v
(
2
π
)
=
−
1
+
∫
0
π
/2
(
−
2
sin
t
)
d
t
E
v
(
π
2
)
=
−
1
+
∫
0
π
/
2
cos
t
d
t
v\left(\frac{\pi}{2}\right)=-1+\int_0^{\pi/2}\cos t\,dt
v
(
2
π
)
=
−
1
+
∫
0
π
/2
cos
t
d
t
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