Estimating Limit Values from Tables - AP Calculus BC
- The function is continuous. A table of values for is given: for values of -10, -100, -1000, and -10000, the corresponding values are -0.4, -0.49, -0.499, and -0.4999. What is the best estimate for ? Answer: -0.5 The correct answer is -0.5. The limit as describes the end behavior of the function as decreases without bound. The table shows that as becomes more negative, the values of get closer to -0.5. Choice C is the first value in the table. Choice B is a common limit value but not supported by the data. Choice D is incorrect as the values are approaching a single number.
- Values of a function are given for selected values of near -1. For values of -1.1, -1.01, and -1.001, the corresponding values are 8.8, 8.98, and 8.998. For values of -0.999, -0.99, and -0.9, the corresponding values are 7.002, 7.02, and 7.2. The value of is 3. What is the best estimate for ? Answer: 9 The correct answer is 9. The notation indicates the limit as approaches -1 from the left side (values less than -1). The table shows that for values of -1.1, -1.01, and -1.001, the values of are approaching 9. Choice A is the value of the function at . Choice B is the right-hand limit, not the left-hand limit. Choice D is incorrect because the one-sided limit exists.
- The functions and are continuous. For values of 1.9, 1.99, and 1.999, the values are 2.8, 2.98, and 2.998. For values of 2.001, 2.01, and 2.1, the values are 3.002, 3.02, and 3.2. For values of 2.9, 2.99, and 2.999, the values are 8.7, 8.97, and 8.997. For values of 3.001, 3.01, and 3.1, the values are 9.003, 9.03, and 9.3. What is the best estimate for ? Answer: 9 The correct answer is 9. To evaluate the limit of a composite function, first evaluate the inner limit: . From the table for , as , . Now, evaluate the outer limit using this result: . From the table for , as , . Therefore, . Choice B is the limit of the inner function. Choice A is the value x is approaching.
- The functions and are continuous. For values of 0.9, 0.99, and 0.999, the values are 3.8, 3.98, and 3.998. For values of 1.001, 1.01, and 1.1, the values are 4.002, 4.02, and 4.2. For values of 3.9, 3.99, and 3.999, the values are -5.2, -5.02, and -5.002. For values of 4.001, 4.01, and 4.1, the values are -4.998, -4.98, and -4.8. What is the best estimate for ? Answer: -5 The correct answer is -5. First, we find the limit of the inner function, . The table for shows that as approaches 1, approaches 4. Next, we use this value as the input for the outer function's limit: . The table for shows that as approaches 4, approaches -5. Thus, . Choice B is the limit of the inner function.
- The functions and are continuous. A table of values near is given. For values of 3.9, 3.99, and 3.999, the values are 6.8, 6.98, and 6.998, and the values are -2.2, -2.02, and -2.002. For values of 4.001, 4.01, and 4.1, the values are 7.002, 7.02, and 7.2, and the values are -1.998, -1.98, and -1.8. What is the best estimate for ? Answer: -14 The correct answer is -14. From the table, as , and . Using the product property of limits, . Choice B is the sum of the limits. Choice C is the product of the first values in the table. Choice D is incorrect because both individual limits exist.
- A differentiable function satisfies . A table of values for the difference quotient is given. For values of -0.1, -0.01, and -0.001, the quotient's values are 3.9, 3.99, and 3.999. For values of 0.001, 0.01, and 0.1, the quotient's values are 4.001, 4.01, and 4.1. What is the best estimate for ? Answer: 4 The correct answer is 4. The expression in the limit is the definition of the derivative of at , i.e., . The table directly provides values of this difference quotient as approaches 0 from the left and the right. As , the quotient approaches 4. As , the quotient approaches 4. Since both one-sided limits are equal, the limit is 4. Choice C is the value of .
- The functions and are continuous. A table of values near is given. For values of -3.1, -3.01, and -3.001, the values are 11.7, 11.97, and 11.997, and the values are 1.9, 1.99, and 1.999. For values of -2.999, -2.99, and -2.9, the values are 12.003, 12.03, and 12.3, and the values are 2.001, 2.01, and 2.1. What is the best estimate for ? Answer: 6 The correct answer is 6. From the table, as , and . Using the quotient property of limits, . Choice B is the sum of the limits. Choice C is the sum of the function values at x=-3 (if they were given). Choice D is incorrect because the individual limits exist and the denominator's limit is not zero.
- Values of a function are given for selected values of near -4. For values of -4.1, -4.01, and -4.001, the values are 500, 5000, and 50000. For values of -3.999, -3.99, and -3.9, the values are 49999, 4999, and 499. The function is undefined at . What is the best estimate for ? Answer: The correct answer is . As approaches -4 from the left, the values of are increasing without bound. As approaches -4 from the right, the values of are also increasing without bound. Since both sides approach positive infinity, the limit is considered to be . Choice A is one of the data points. Choice D is incorrect because the behavior from both sides is the same (approaching ).
- The function is continuous. A table of values for near is given. For values of -0.1, -0.01, and -0.001, the values are 4.8, 4.98, and 4.998. For values of 0.001, 0.01, and 0.1, the values are 5.002, 5.02, and 5.2. What is the best estimate for ? Answer: 5 The correct answer is 5. From the table, we estimate that . For the known function , we know that . By the product property of limits, . Choice C is the limit of . Choice A would be true if one of the limits were 0. Choice D is incorrect because both individual limits exist.
- The function is continuous. A table of values for is given: for values of 10, 100, 1000, and 10000, the corresponding values are 3.1, 3.01, 3.001, and 3.0001. What is the best estimate for ? Answer: 3 The correct answer is 3. The limit as describes the end behavior of the function as increases without bound. The table shows that as gets larger, the values of get closer and closer to 3. Choice A is a common limit value but not supported by the data. Choice C is the first value in the table. Choice D is incorrect as the values are approaching a single number.
- A function is continuous. For values of 2.9, 2.99, and 2.999, the values for are -0.1, -0.01, and -0.001. For values of 3.001, 3.01, and 3.1, the values for are 0.001, 0.01, and 0.1. We know . What is the best estimate for ? Answer: 1 The correct answer is 1. We can use a change of variable. Let . From the table, as , the values of approach 0. So, as , we have . The limit can be rewritten as . This is a fundamental trigonometric limit which equals 1. Choice A is the limit of the function . Choice C is the value approaches.
- Values of a function are given for selected values of near 2. The table shows that for values of 1.9, 1.99, and 1.999, the corresponding values are 4.71, 4.97, and 4.997. For values of 2.001, 2.01, and 2.1, the corresponding values are 5.003, 5.03, and 5.31. The value of is 7. What is the best estimate for ? Answer: 5 The correct answer is 5. As approaches 2 from the left (), approaches 5. As approaches 2 from the right (), also approaches 5. Since the left-hand and right-hand limits are equal, the limit is 5. The value is irrelevant to the value of the limit. Choice B is the value of the function at , not the limit. Choice C is a single value from the table, not the limit. Choice D is incorrect because the left and right limits both approach 5.
- The functions and are continuous. A table of values near is given. For values of 3.9, 3.99, and 3.999, the values are 6.8, 6.98, and 6.998, and the values are -2.2, -2.02, and -2.002. For values of 4.001, 4.01, and 4.1, the values are 7.002, 7.02, and 7.2, and the values are -1.998, -1.98, and -1.8. What is the best estimate for ? Answer: 5 The correct answer is 5. From the table, as , and . Using the sum property of limits, . Choice B is the difference of the limits. Choice C is the sum of the first values in the table. Choice D is incorrect because both individual limits exist.
- Values of a function are given for selected values of near 3. For values of 2.9, 2.99, and 2.999, the corresponding values are -1.5, -1.95, and -1.995. For values of 3.001, 3.01, and 3.1, the corresponding values are -3.998, -3.98, and -3.8. The function is undefined at . What is the best estimate for ? Answer: -4 The correct answer is -4. The notation indicates the limit as approaches 3 from the right side (values greater than 3). The table shows that for values of 3.001, 3.01, and 3.1, the values of are approaching -4. Choice A is the left-hand limit. Choice C is the value is approaching. Choice D is incorrect because the one-sided limit exists.
- The function has a removable discontinuity at . For values of 0.9, 0.99, and 0.999, the values are -2.19, -2.0199, and -2.001999. For values of 1.001, 1.01, and 1.1, the values are -1.997999, -1.9799, and -1.79. The value of is 5. What is the best estimate for ? Answer: -2 The correct answer is -2. As approaches 1 from the left, the values of approach -2. As approaches 1 from the right, the values of also approach -2. Since both one-sided limits are equal to -2, the limit is -2. The fact that creates a 'hole' in the graph but does not affect the limit value. Choice A is the function value. Choice B is one of the table values.