Volumes with Cross Sections: Triangles/Semicircles - AP Calculus BC

  1. Find the volume of a solid with triangular cross sections, base = 4, height = 5, length = 6.
    Volume = 60. Apply volume formula: 12×4×5×6\frac{1}{2} \times 4 \times 5 \times 6.
  2. What is the diameter for semicircular cross sections if base function f(x)=x+2f(x) = x + 2 and g(x)=xg(x) = x?
    Diameter = 2. Distance between functions (x+2)−x=2(x+2)-x=2.
  3. Given f(x)=exf(x) = e^x and g(x)=0g(x) = 0, find the height of the triangular cross section at x=0x=0.
    Height = 1. At x=0x=0: e0−0=1e^0-0=1, giving height 1.
  4. Compute the volume of a solid with triangular cross sections, base =6= 6, height =4= 4, length =8= 8.
    Volume = 96. Apply formula: 12×6×4×8\frac{1}{2} \times 6 \times 4 \times 8.
  5. Identify the base for triangular cross sections in the plane x=ax = a.
    Base = f(a)−g(a)f(a) - g(a). Distance between upper and lower boundary functions.
  6. If f(x)=x3f(x) = x^3 and g(x)=0g(x) = 0, what is the radius of the semicircular cross section at x=1x=1?
    Radius = 0.5. At x=1x=1: 13−02=12=0.5\frac{1^3-0}{2}=\frac{1}{2}=0.5.
  7. Calculate the volume of a solid with semicircular cross sections, radius =3= 3, and length =7= 7.
    Volume = 31.5π31.5\text{π}. Semicircle area 9π2\frac{9\pi}{2} times length 7.
  8. Find the volume of a solid with semicircular cross sections, diameter =8= 8 and length =2= 2.
    Volume = 16π16\text{π}. Radius 4, area 8π8\pi, times length 2.
  9. What is the formula for the radius of a semicircle given diameter dd?
    Radius = d2\frac{d}{2}. Basic relationship between radius and diameter.
  10. What is the area of a triangle with base bb and height hh?
    Area = 12×b×h\frac{1}{2} \times b \times h. Standard triangle area formula.
  11. Find the volume of a solid with triangular cross sections, base =9= 9, height =12= 12, length =10= 10.
    Volume = 540. Apply formula: 12×9×12×10\frac{1}{2} \times 9 \times 12 \times 10.
  12. What is the formula for the area of a semicircle with diameter dd?
    Area = π×(d/2)22\frac{\text{π} \times (d/2)^2}{2}. Semicircle area using diameter instead of radius.
  13. What is the volume of a solid with triangular cross sections where base and height are both constant at 5?
    Volume = 12.5×Length12.5 \times \text{Length}. Triangle area 12×5×5=12.5\frac{1}{2} \times 5 \times 5 = 12.5 times length.
  14. If f(x)=x2f(x) = x^2 and g(x)=0g(x) = 0, what is the radius of the semicircular cross section at x=3x=3?
    Radius = 4.5. Half the distance from 32=93^2=9 to 0 gives 9/2=4.59/2=4.5.
  15. Given f(x)=x2+1f(x) = x^2 + 1 and g(x)=xg(x) = x, find the diameter of the semicircular cross section at x=2x=2.
    Diameter = 3. Distance between (22+1)=5(2^2+1)=5 and 22 gives diameter 3.
  16. Given the function y=sin(x)y = \text{sin}(x), find the base of triangle cross section at x=π2x=\frac{\text{π}}{2}.
    Base = 1. At x=π2x=\frac{\pi}{2}, sin⁡(π2)=1\sin(\frac{\pi}{2})=1 gives base of 1.
  17. If f(x)=x3f(x) = x^3 and g(x)=xg(x) = x, find the base of the triangular cross section at x=1x=1.
    Base = 0. At x=1x=1: 13−1=01^3-1=0, so base is 0.
  18. Find the volume of a solid with semicircular cross sections, radius =4= 4, and length =5= 5.
    Volume = 40π40\text{π}. Semicircle area π×422=8π\frac{\pi \times 4^2}{2}=8\pi times length 5.
  19. What is the volume of a solid with semicircular cross sections where the radius is constant at 3?
    Volume = 9π×Length9\text{π} \times \text{Length}. Semicircle area πr22\frac{\pi r^2}{2} with r=3r=3 times length.
  20. What is the role of the base function g(x)g(x) in determining cross sections?
    g(x)g(x) provides the lower boundary. Defines the bottom edge of each cross-section.
  21. Identify the radius for semicircular cross sections in the plane x=ax = a.
    Radius = f(a)−g(a)2\frac{f(a) - g(a)}{2}. Half the distance between boundary functions.
  22. Compute the volume for a solid with semicircular cross sections with radius r=2r = 2 and length l=6l = 6.
    Volume = 12π12\text{π}. Semicircle area π×222=2π\frac{\pi \times 2^2}{2}=2\pi times length 6.
  23. What is the volume of a solid with semicircular cross sections where the diameter is 10 and length is 3?
    Volume = 37.5π37.5\text{π}. Radius 5, area 25π2\frac{25\pi}{2}, times length 3.
  24. If f(x)=x2f(x) = x^2 and g(x)=0g(x) = 0, what is the base of the triangular cross section at x=2x=2?
    Base = 4. Distance from x2x^2 to 0 at x=2x=2 gives 4−0=44-0=4.
  25. What is the volume of a solid with triangular cross sections, base =7= 7 and height =8= 8?
    Volume = 28×Length28 \times \text{Length}. Triangle area 12×7×8=28\frac{1}{2} \times 7 \times 8 = 28 times length.
  26. Given f(x)=x+1f(x) = x+1 and g(x)=xg(x) = x, find the height of the triangular cross section at x=1x=1.
    Height = 1. Distance between functions: (1+1)−(1)=1(1+1)-(1)=1.
  27. Find the volume of a solid with triangular cross sections, base =4= 4, height =5= 5, length =6= 6.
    Volume = 60. Apply volume formula: 12×4×5×6\frac{1}{2} \times 4 \times 5 \times 6.
  28. What is the role of the base function f(x)f(x) in determining cross sections?
    f(x)f(x) provides the upper boundary. Defines the top edge of each cross-section.
  29. What is the volume formula for a solid with equilateral triangular cross sections?
    Volume = √34×side2×Length\frac{\text{√3}}{4} \times \text{side}^2 \times \text{Length}. Uses equilateral triangle area formula with side length.
  30. Calculate the volume of a solid with semicircular cross sections, diameter =6= 6, length =4= 4.
    Volume = 18π18\text{π}. Using semicircle formula with radius 3 and length 4.

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