The nth Term Test for Divergence - AP Calculus BC
- Evaluate . Divergent?
- Limit is ; series diverges. Degree of numerator exceeds denominator, so limit is infinite.
- What does suggest?
- Test is inconclusive. Zero limit means the test provides no information.
- Evaluate . Divergent?
- Limit is 0; test inconclusive. Constant multiple of still gives limit 0.
- Identify . Divergent?
- Limit is 2; series diverges. Coefficients simplify to .
- Determine . Divergent?
- Limit is 1; series diverges. Adding constant to numerator gives limit 1.
- Evaluate . Divergent?
- Limit is 3; series diverges. Leading terms give ratio .
- Determine divergence: .
- Limit is 0; test inconclusive. Denominator grows faster, giving limit 0.
- Determine divergence: .
- Limit is ; series diverges. Square root grows without bound to infinity.
- Identify divergence: .
- Limit is ; series diverges. Natural log grows without bound to infinity.
- Evaluate . Divergent?
- Limit is 0; test inconclusive. Higher power in denominator gives limit 0.
- Check divergence: .
- Limit is 0; test inconclusive. Exponential decay gives limit 0.
- Check divergence: .
- Limit is 0; test inconclusive. Exponential decay gives limit 0.
- Evaluate divergence: .
- does not exist; series diverges. Sine function oscillates, so limit doesn't exist.
- Determine divergence: .
- Does not exist; series diverges. Oscillating sequence has no limit, so series diverges.
- Identify . Divergent?
- Limit is ; series diverges. Equal highest degree terms give ratio .
- What conclusion if ?
- Test is inconclusive. Zero limit cannot determine convergence or divergence.
- What is the nth term test for divergence?
- If , then diverges. The fundamental condition for proving a series diverges.
- Evaluate for divergence.
- Limit is 1; series diverges. Since limit equals 1 0, the test proves divergence.
- Determine divergence: .
- Limit is ; series diverges. Simplifies to , which grows to infinity.
- Determine divergence: .
- Limit is ; series diverges. Square root grows without bound to infinity.
- Determine . Does it diverge?
- Limit is ; series diverges. Leading coefficients give limit , proving divergence.
- Evaluate . Divergent?
- Limit is 1; series diverges. The constant term 1 makes limit equal to 1.
- Evaluate divergence:
- Limit is ; series diverges. Coefficients cancel to give limit
- Find .
- Limit is 0; test inconclusive. Highest degree terms show limit is 0, test inconclusive.
- Evaluate divergence: .
- Limit is ; series diverges. Coefficients cancel to give limit .
- Identify divergence: .
- Limit is ; series diverges. Natural log grows without bound to infinity.
- Evaluate for divergence.
- Limit is ; series diverges. Since limit equals , the test proves divergence.
- What does imply?
- Series diverges. Any non-zero limit guarantees series divergence.
- Assess . Divergent?
- Limit is 2; series diverges. Dividing gives , limit 2.
- Determine divergence: .
- Does not exist; series diverges. Oscillating sequence has no limit, so series diverges.
- Does infer divergence?
- Yes, series diverges. Any non-zero constant limit proves divergence.
- Find for the nth term test.
- Limit is ; test inconclusive. This gives the harmonic series limit of .
- When can the nth term test conclude divergence?
- When . Only when the limit is non-zero can we conclude divergence.
- What must be true for the nth term test to be applicable?
- must be the general term of a series. The test applies only to terms of infinite series.
- Assess divergence: .
- Limit is ; series diverges. Both numerator and denominator approach , limit is .
- Does guarantee convergence?
- No, it does not guarantee convergence. Zero limit is necessary but not sufficient for convergence.
- Evaluate for divergence.
- Limit is 0; test inconclusive. Zero limit means we need other tests to determine behavior.
- Does imply divergence?
- Limit is 1; series diverges. Adding 1 to numerator gives limit 1 ≠ 0.
- What is the outcome if ?
- Series diverges. Any constant proves divergence.
- Identify . Divergence?
- Limit is ; series diverges. Simplifies to , which grows to infinity.
- What role does the nth term test play in series analysis?
- Primarily to identify divergence. It's a quick first test to eliminate divergent series.
- What if ?
- Series diverges. Non-zero limit always implies divergence by the test.
- Assess divergence: .
- Limit is 1; series diverges. Both numerator and denominator approach infinity, limit is 1.
- Find for the nth term test.
- Limit is 0; test inconclusive. This gives the harmonic series limit of 0.
- What does indicate?
- Test is inconclusive. Zero limit cannot prove convergence or divergence alone.
- Assess . Divergent?
- Limit is 2; series diverges. Dividing gives , limit 2.