The nth Term Test for Divergence - AP Calculus BC

  1. Evaluate lim⁡n→∞n3n2+1\lim_{{n \to \infty}} \frac{n^3}{n^2 + 1}. Divergent?
    Limit is ∞\infty; series diverges. Degree of numerator exceeds denominator, so limit is infinite.
  2. What does lim⁡n→∞an=0\lim_{{n \to \infty}} a_n = 0 suggest?
    Test is inconclusive. Zero limit means the test provides no information.
  3. Evaluate lim⁡n→∞2n\lim_{{n \to \infty}} \frac{2}{n}. Divergent?
    Limit is 0; test inconclusive. Constant multiple of 1n\frac{1}{n} still gives limit 0.
  4. Identify lim⁡n→∞4n32n3\lim_{{n \to \infty}} \frac{4n^3}{2n^3}. Divergent?
    Limit is 2; series diverges. Coefficients simplify to 42=2≠0\frac{4}{2} = 2 \neq 0.
  5. Determine lim⁡n→∞n+5n\lim_{{n \to \infty}} \frac{n + 5}{n}. Divergent?
    Limit is 1; series diverges. Adding constant to numerator gives limit 1.
  6. Evaluate lim⁡n→∞3nn+3\lim_{{n \to \infty}} \frac{3n}{n+3}. Divergent?
    Limit is 3; series diverges. Leading terms give ratio 31=3≠0\frac{3}{1} = 3 \neq 0.
  7. Determine divergence: lim⁡n→∞nn2\lim_{{n \to \infty}} \frac{n}{n^2}.
    Limit is 0; test inconclusive. Denominator grows faster, giving limit 0.
  8. Determine divergence: lim⁡n→∞n\lim_{{n \to \infty}} \sqrt{n}.
    Limit is ∞\infty; series diverges. Square root grows without bound to infinity.
  9. Identify divergence: lim⁡n→∞ln⁡(n)\lim_{{n \to \infty}} \ln(n).
    Limit is ∞\infty; series diverges. Natural log grows without bound to infinity.
  10. Evaluate lim⁡n→∞1n3\lim_{{n \to \infty}} \frac{1}{n^3}. Divergent?
    Limit is 0; test inconclusive. Higher power in denominator gives limit 0.
  11. Check divergence: lim⁡n→∞e−n\lim_{{n \to \infty}} e^{-n}.
    Limit is 0; test inconclusive. Exponential decay gives limit 0.
  12. Check divergence: lim⁡n→∞e−n\lim_{n \to \infty} e^{-n}.
    Limit is 0; test inconclusive. Exponential decay gives limit 0.
  13. Evaluate divergence: an=sin⁡(n)a_n = \sin(n).
    lim⁡n→∞an\lim_{{n \to \infty}} a_n does not exist; series diverges. Sine function oscillates, so limit doesn't exist.
  14. Determine divergence: lim⁡n→∞(−1)n\lim_{{n \to \infty}} (-1)^n.
    Does not exist; series diverges. Oscillating sequence has no limit, so series diverges.
  15. Identify lim⁡n→∞3n25n2\lim_{{n \to \infty}} \frac{3n^2}{5n^2}. Divergent?
    Limit is 35\frac{3}{5}; series diverges. Equal highest degree terms give ratio 35≠0\frac{3}{5} \neq 0.
  16. What conclusion if lim⁡n→∞an=0\lim_{{n \to \infty}} a_n = 0?
    Test is inconclusive. Zero limit cannot determine convergence or divergence.
  17. What is the nth term test for divergence?
    If lim⁡n→∞an≠0\lim_{n \to \infty} a_n \neq 0, then ∑an\sum a_n diverges. The fundamental condition for proving a series diverges.
  18. Evaluate lim⁡n→∞nn+1\lim_{{n \to \infty}} \frac{n}{n+1} for divergence.
    Limit is 1; series diverges. Since limit equals 1 ≠≠ 0, the test proves divergence.
  19. Determine divergence: lim⁡n→∞n2+2nn\lim_{{n \to \infty}} \frac{n^2 + 2n}{n}.
    Limit is ∞\infty; series diverges. Simplifies to n+2n + 2, which grows to infinity.
  20. Determine divergence: lim⁡n→∞n\lim_{n \to \infty} \sqrt{n}.
    Limit is ∞\infty; series diverges. Square root grows without bound to infinity.
  21. Determine lim⁡n→∞2nn+1\lim_{{n \to \infty}} \frac{2n}{n+1}. Does it diverge?
    Limit is 22; series diverges. Leading coefficients give limit 2≠02 \neq 0, proving divergence.
  22. Evaluate lim⁡n→∞n2+1n2\lim_{{n \to \infty}} \frac{n^2 + 1}{n^2}. Divergent?
    Limit is 1; series diverges. The constant term 1 makes limit equal to 1.
  23. Evaluate divergence: lim⁡n→∞5n3n\lim_{n \to \infty} \frac{5n}{3n}
    Limit is 53\frac{5}{3}; series diverges. Coefficients cancel to give limit 53≠0\frac{5}{3} \neq 0
  24. Find lim⁡n→∞n2n3+1\lim_{{n \to \infty}} \frac{n^2}{n^3 + 1}.
    Limit is 0; test inconclusive. Highest degree terms show limit is 0, test inconclusive.
  25. Evaluate divergence: lim⁡n→∞5n3n\lim_{n \to \infty} \frac{5n}{3n}.
    Limit is 53\frac{5}{3}; series diverges. Coefficients cancel to give limit 53≠0\frac{5}{3} \neq 0.
  26. Identify divergence: lim⁡n→∞ln⁡(n)\lim_{n \to \infty} \ln(n).
    Limit is ∞\infty; series diverges. Natural log grows without bound to infinity.
  27. Evaluate lim⁡n→∞nn+1\lim_{n \to \infty} \frac{n}{n+1} for divergence.
    Limit is 11; series diverges. Since limit equals 1≠01 \neq 0, the test proves divergence.
  28. What does lim⁡n→∞an=L≠0\lim_{{n \to \infty}} a_n = L \neq 0 imply?
    Series ∑an\sum a_n diverges. Any non-zero limit guarantees series divergence.
  29. Assess lim⁡n→∞2n+1n\lim_{{n \to \infty}} \frac{2n+1}{n}. Divergent?
    Limit is 2; series diverges. Dividing gives 2+1n2 + \frac{1}{n}, limit 2.
  30. Determine divergence: lim⁡n→∞(−1)n\lim_{n \to \infty} (-1)^n.
    Does not exist; series diverges. Oscillating sequence has no limit, so series diverges.
  31. Does lim⁡n→∞an=d≠0\lim_{{n \to \infty}} a_n = d \neq 0 infer divergence?
    Yes, series ∑an\sum a_n diverges. Any non-zero constant limit proves divergence.
  32. Find lim⁡n→∞1n\lim_{n \to \infty} \frac{1}{n} for the nth term test.
    Limit is 00; test inconclusive. This gives the harmonic series limit of 00.
  33. When can the nth term test conclude divergence?
    When lim⁡n→∞an≠0\lim_{{n \to \infty}} a_n \neq 0. Only when the limit is non-zero can we conclude divergence.
  34. What must be true for the nth term test to be applicable?
    ana_n must be the general term of a series. The test applies only to terms of infinite series.
  35. Assess divergence: lim⁡n→∞n+1n+2\lim_{n \to \infty} \frac{n+1}{n+2}.
    Limit is 11; series diverges. Both numerator and denominator approach ∞\infty, limit is 11.
  36. Does lim⁡n→∞an=0\lim_{{n \to \infty}} a_n = 0 guarantee convergence?
    No, it does not guarantee convergence. Zero limit is necessary but not sufficient for convergence.
  37. Evaluate lim⁡n→∞1n2\lim_{{n \to \infty}} \frac{1}{n^2} for divergence.
    Limit is 0; test inconclusive. Zero limit means we need other tests to determine behavior.
  38. Does lim⁡n→∞n+1n\lim_{{n \to \infty}} \frac{n+1}{n} imply divergence?
    Limit is 1; series diverges. Adding 1 to numerator gives limit 1 ≠ 0.
  39. What is the outcome if lim⁡n→∞an=c≠0\lim_{{n \to \infty}} a_n = c \neq 0?
    Series ∑an\sum a_n diverges. Any constant c≠0c \neq 0 proves divergence.
  40. Identify lim⁡n→∞n4n3\lim_{{n \to \infty}} \frac{n^4}{n^3}. Divergence?
    Limit is ∞\infty; series diverges. Simplifies to nn, which grows to infinity.
  41. What role does the nth term test play in series analysis?
    Primarily to identify divergence. It's a quick first test to eliminate divergent series.
  42. What if lim⁡n→∞an≠0\lim_{{n \to \infty}} a_n \neq 0?
    Series ∑an\sum a_n diverges. Non-zero limit always implies divergence by the test.
  43. Assess divergence: lim⁡n→∞n+1n+2\lim_{{n \to \infty}} \frac{n+1}{n+2}.
    Limit is 1; series diverges. Both numerator and denominator approach infinity, limit is 1.
  44. Find lim⁡n→∞1n\lim_{{n \to \infty}} \frac{1}{n} for the nth term test.
    Limit is 0; test inconclusive. This gives the harmonic series limit of 0.
  45. What does lim⁡n→∞an=0\lim_{{n \to \infty}} a_n = 0 indicate?
    Test is inconclusive. Zero limit cannot prove convergence or divergence alone.
  46. Assess lim⁡n→∞2n+1n\lim_{n \to \infty} \frac{2n+1}{n}. Divergent?
    Limit is 2; series diverges. Dividing gives 2+1n2 + \frac{1}{n}, limit 2.

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