Motion Problems, Parametric, Vector-Valued Functions - AP Calculus BC

  1. State the formula for the tangent vector of a parametric curve at t=t0t = t_0.
    T(t0)=v(t0)∥v(t0)∥\mathbf{T}(t_0) = \frac{\mathbf{v}(t_0)}{\|\mathbf{v}(t_0)\|}. Unit vector formula using velocity magnitude.
  2. What is the parametric equation for x(t)x(t) of a projectile launched at angle θ\theta?
    x(t)=v0cos⁡(θ)tx(t) = v_0 \cos(\theta) t. Horizontal motion with constant velocity component.
  3. What is the horizontal component of the velocity vector for x(t)=5tx(t)=5t?
    vx(t)=5v_x(t) = 5. Derivative of 5t5t is constant 55.
  4. Find the unit tangent vector at t=1t=1 for r(t)=⟨t2,t3⟩\mathbf{r}(t) = \langle t^2, t^3 \rangle.
    ⟨213,313⟩\langle \frac{2}{\sqrt{13}}, \frac{3}{\sqrt{13}} \rangle. Normalize ⟨2,3⟩\langle 2, 3 \rangle with magnitude 13\sqrt{13}.
  5. What is the formula for total distance traveled in vector form?
    ∫ab∥v(t)∥ dt\int_a^b \| \mathbf{v}(t) \| \, dt. Integral of speed over time interval.
  6. What is the formula for the torsion τ(t)\tau(t) of a space curve?
    τ(t)=−(B′⋅N)∥v∥\tau(t) = -\frac{(\mathbf{B}' \cdot \mathbf{N})}{\|\mathbf{v}\|}. Standard torsion formula for space curves.
  7. What is the parametric equation for y(t)y(t) of a projectile launched at angle θ\theta?
    y(t)=v0sin⁡(θ)t−12gt2y(t) = v_0 \sin(\theta) t - \frac{1}{2}gt^2. Vertical motion with gravity acceleration −g-g.
  8. Identify the position vector r(t)\mathbf{r}(t) for x(t)=2tx(t) = 2t and y(t)=3t2y(t) = 3t^2.
    r(t)=⟨2t,3t2⟩\mathbf{r}(t) = \langle 2t, 3t^2 \rangle. Combine components into vector form.
  9. What is the vertical component of the velocity vector for y(t)=6t2y(t)=6t^2?
    vy(t)=12tv_y(t) = 12t. Derivative of 6t26t^2 is 12t12t.
  10. Find the derivative of x(t)=6t3x(t) = 6t^3 with respect to tt.
    18t218t^2. Power rule: derivative of 6t36t^3 is 18t218t^2.
  11. State the formula for speed of a particle given vx(t)v_x(t) and vy(t)v_y(t).
    Speed = vx(t)2+vy(t)2\sqrt{v_x(t)^2 + v_y(t)^2}. Pythagorean theorem for vector magnitude.
  12. What is the velocity vector v(t)\mathbf{v}(t) for x(t)=t2x(t) = t^2, y(t)=t3y(t) = t^3?
    ⟨2t,3t2⟩\langle 2t, 3t^2 \rangle. Derivatives: vx=2tv_x = 2t, vy=3t2v_y = 3t^2.
  13. What is the horizontal distance traveled by a projectile at t=5t=5 for x(t)=10tx(t)=10t?
    5050. Substitute t=5t=5 into horizontal position.
  14. Find dydx\frac{dy}{dx} for y(t)=t3y(t)=t^3, x(t)=t2x(t)=t^2 at t=1t=1.
    32\frac{3}{2}. Chain rule: dydtdxdt=3t22t=32\frac{ \frac{dy}{dt} }{ \frac{dx}{dt} } = \frac{3t^2}{2t} = \frac{3}{2}
  15. Find the value of dydx\frac{dy}{dx} for y(t)=t2y(t)=t^2, x(t)=t+1x(t)=t+1 at t=1t=1.
    22. At t=1t=1: 2t1=2\frac{2t}{1} = 2.
  16. Identify the velocity vector v(t)\mathbf{v}(t) given x(t)=3tx(t) = 3t and y(t)=4t2y(t) = 4t^2.
    v(t)=⟨3,8t⟩\mathbf{v}(t) = \langle 3, 8t \rangle. Take derivatives: vx=3v_x = 3, vy=8tv_y = 8t.
  17. Find the derivative of y(t)=5t2y(t) = 5t^2 with respect to tt.
    10t10t. Power rule: derivative of 5t25t^2 is 10t10t.
  18. State the formula for the position vector r(t)\mathbf{r}(t) given x(t)x(t) and y(t)y(t).
    r(t)=⟨x(t),y(t)⟩\mathbf{r}(t) = \langle x(t), y(t) \rangle. Standard vector notation for position.
  19. What is the formula for the normal vector N(t)\mathbf{N}(t) of a curve?
    N(t)=dTdt∥dTdt∥\mathbf{N}(t) = \frac{ \frac{d \mathbf{T}}{dt} }{ \| \frac{d \mathbf{T}}{dt} \| }. Normalize derivative of unit tangent vector.
  20. What is the formula for the binormal vector B(t)\mathbf{B}(t) of a curve?
    B(t)=T(t)×N(t)\mathbf{B}(t) = \mathbf{T}(t) \times \mathbf{N}(t). Cross product of tangent and normal vectors.
  21. Find the magnitude of the velocity vector ⟨7,24⟩\langle 7, 24 \rangle.
    2525. Magnitude formula: 72+242=625=25\sqrt{7^2 + 24^2} = \sqrt{625} = 25.
  22. Find the position vector at t=3t=3 for r(t)=⟨t2,t3⟩\mathbf{r}(t) = \langle t^2, t^3 \rangle.
    ⟨9,27⟩\langle 9, 27 \rangle. Substitute t=3t=3: ⟨9,27⟩\langle 9, 27 \rangle.
  23. State the formula for arc length of a parametric curve from t=at=a to t=bt=b.
    ∫ab(x′(t))2+(y′(t))2 dt\int_a^b \sqrt{(x'(t))^2 + (y'(t))^2} \, dt. Integral of speed over time interval.
  24. What is the magnitude of the acceleration vector a(t)=⟨3,4⟩\mathbf{a}(t) = \langle 3, 4 \rangle?
    55. Magnitude formula: 32+42=25=5\sqrt{3^2 + 4^2} = \sqrt{25} = 5.
  25. What is the formula for the curvature κ(t)\kappa(t) of a parametric curve?
    κ(t)=∣x′y′′−y′x′′∣(x′2+y′2)3/2\kappa(t) = \frac{|x'y'' - y'x''|}{(x'^2 + y'^2)^{3/2}}. Standard curvature formula for parametric curves.
  26. What is the acceleration vector a(t)\mathbf{a}(t) for x(t)=4t2x(t) = 4t^2 and y(t)=2t3y(t) = 2t^3?
    a(t)=⟨8,12t⟩\mathbf{a}(t) = \langle 8, 12t \rangle. Second derivatives: ax=8a_x = 8, ay=12ta_y = 12t.

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