Integrating Vector-Valued Functions - AP Calculus BC

  1. Evaluate the integral r(t)=(tt2)\textbf{r}(t) = \begin{pmatrix} t \\ t^2 \end{pmatrix} over [1,2][1, 2].
    (3273)\begin{pmatrix} \textstyle\frac{3}{2} \\ \textstyle\frac{7}{3} \end{pmatrix}. Integrate tt to get 32\frac{3}{2} and t2t^2 to get 73\frac{7}{3} over [1,2][1,2].
  2. How do you represent the antiderivative of a vector function r(t)\textbf{r}(t)?
    R(t)=(F(t)G(t)H(t))\textbf{R}(t) = \begin{pmatrix} F(t) \\ G(t) \\ H(t) \end{pmatrix}. Each component is the antiderivative of the corresponding component in r(t)\textbf{r}(t).
  3. Calculate the integral r(t)=(3t4)\textbf{r}(t) = \begin{pmatrix} 3t \\ 4 \end{pmatrix} over [1,3][1, 3].
    (98)\begin{pmatrix} 9 \\ 8 \end{pmatrix}. Integrate 3t3t to get 32(32−12)=9\frac{3}{2}(3^2-1^2)=9 and 44 to get 4(3−1)=84(3-1)=8.
  4. Evaluate the integral of r(t)=(sinh(t)cosh(t))\textbf{r}(t) = \begin{pmatrix} \text{sinh}(t) \\ \text{cosh}(t) \end{pmatrix} over [0,1][0, 1].
    (cosh(1)−1sinh(1))\begin{pmatrix} \text{cosh}(1) - 1 \\ \text{sinh}(1) \end{pmatrix}. Antiderivatives of hyperbolic sine and cosine functions.
  5. State the relationship between definite and indefinite integrals for vector functions.
    Definite Integral=Indefinite Integral evaluated at bounds\text{Definite Integral} = \text{Indefinite Integral evaluated at bounds}. Same principle as scalar functions: evaluate antiderivative at bounds.
  6. State the formula for integrating a vector-valued function with respect to a parameter uu.
    R(u)=(F(u)G(u)H(u))+C\textbf{R}(u) = \begin{pmatrix} F(u) \\ G(u) \\ H(u) \end{pmatrix} + \textbf{C}. General form with parameter uu instead of tt.
  7. In the context of vector-valued functions, what does C\textbf{C} represent?
    Constant vector of integration. Vector analog of the constant of integration in scalar calculus.
  8. State the relationship between integration and differentiation for vector-valued functions.
    They are inverse operations. Differentiation and integration undo each other for vector functions.
  9. What rule applies for integrating vector-valued functions with piecewise components?
    Integrate each piece separately. Apply integration rules to each piece within its domain.
  10. Evaluate the integral r(t)=(tt2)\textbf{r}(t) = \begin{pmatrix} t \\ t^2 \end{pmatrix} over $ [1, 2] $.
    (3273)\begin{pmatrix} \textstyle\frac{3}{2} \\ \textstyle\frac{7}{3} \end{pmatrix}. Integrate tt to get 32\frac{3}{2} and t2t^2 to get 73\frac{7}{3} over $ [1,2] $.
  11. Express the integral r(t)=(t2sin⁡(t))\mathbf{r}(t) = \begin{pmatrix} t^2 \\ \sin(t) \end{pmatrix} over [0,2][0, 2] in component form.
    (831−cos⁡(2))\begin{pmatrix} \frac{8}{3} \\ 1 - \cos(2) \end{pmatrix}. Integrate t2t^2 to get 83\frac{8}{3} and sin⁡(t)\sin(t) to get 1−cos⁡(2)1 - \cos(2).
  12. How does the integral of a vector-valued function change with a change of variable?
    Use substitution method. Apply substitution rule component-wise with appropriate bounds transformation.
  13. What is the derivative of the integral of a vector-valued function r(t)\textbf{r}(t)?
    r(t)\textbf{r}(t). By the Fundamental Theorem of Calculus for vector functions.
  14. Determine the integral of r(t)=(tet)\textbf{r}(t) = \begin{pmatrix} t \\ e^t \end{pmatrix} over [0,1][0, 1].
    (12e−1)\begin{pmatrix} \textstyle\frac{1}{2} \\ e - 1 \end{pmatrix}. Integrate tt to 12\frac{1}{2} and ete^t to e−1e-1 over [0,1][0,1].
  15. What rule applies when integrating vector functions with respect to a parameter?
    Parameter integration rule. Integration is performed component-wise with respect to the parameter.
  16. Calculate the integral r(t)=(3t4)\textbf{r}(t) = \begin{pmatrix} 3t \\ 4 \end{pmatrix} over [1,3][1, 3].
    (98)\begin{pmatrix} 9 \\ 8 \end{pmatrix}. Integrate 3t3t to get 32(32−12)=9\frac{3}{2}(3^2-1^2)=9 and 44 to get 4(3−1)=84(3-1)=8.
  17. What is the integral of the zero vector function 0\textbf{0} over any interval [a,b][a, b]?
    0\textbf{0}. The zero vector integrated over any interval is the zero vector.
  18. Which integral property allows you to integrate each component separately in a vector-valued function?
    Linearity of integration. Integration distributes over vector addition and scalar multiplication.
  19. Evaluate the integral of r(t)=(cosh(t)sinh(t))\textbf{r}(t) = \begin{pmatrix} \text{cosh}(t) \\ \text{sinh}(t) \end{pmatrix} over [0,1][0, 1].
    (sinh(1)cosh(1)−1)\begin{pmatrix} \text{sinh}(1) \\ \text{cosh}(1) - 1 \end{pmatrix}. Integrate hyperbolic functions: cosh⁡(t)→sinh⁡(t)\cosh(t) \to \sinh(t) and sinh⁡(t)→cosh⁡(t)\sinh(t) \to \cosh(t).
  20. What is the integral of constant vector-valued function c\textbf{c} over [a,b][a, b]?
    (b−a)c(b-a)\textbf{c}. A constant vector integrated over an interval equals the vector times the interval length.
  21. How is the integral of a vector-valued function affected by scalar multiplication?
    Scalar multiplies the integral. The scalar factor can be pulled out of the integral.
  22. Which theorem is used to evaluate the integral of a vector-valued function over an interval [a,b][a, b]?
    Fundamental Theorem of Calculus. Applies to vector functions by evaluating at bounds and subtracting.
  23. How do you find the integral of r(t)=(t2t3)\textbf{r}(t) = \begin{pmatrix} t^2 \\ t^3 \end{pmatrix} over [0,1][0, 1]?
    (1314)\begin{pmatrix} \textstyle\frac{1}{3} \\ \textstyle\frac{1}{4} \end{pmatrix}. Apply power rule: ∫tndt=tn+1n+1\int t^n dt = \frac{t^{n+1}}{n+1} to each component.
  24. Find the integral of r(t)=(t3t4)\textbf{r}(t) = \begin{pmatrix} t^3 \\ t^4 \end{pmatrix} over [0,1][0, 1].
    (1415)\begin{pmatrix} \textstyle\frac{1}{4} \\ \textstyle\frac{1}{5} \end{pmatrix}. Use power rule: ∫t3dt=t44\int t^3 dt = \frac{t^4}{4} and ∫t4dt=t55\int t^4 dt = \frac{t^5}{5}.
  25. What is the integral of a linear vector function r(t)=(at+bct+d)\textbf{r}(t) = \begin{pmatrix} at + b \\ ct + d \end{pmatrix}?
    (12at2+bt12ct2+dt)+C\begin{pmatrix} \textstyle\frac{1}{2}at^2 + bt \\ \textstyle\frac{1}{2}ct^2 + dt \end{pmatrix} + \textbf{C}. Apply power rule to each linear component separately.
  26. Find the integral of r(t)=(t3t4)\textbf{r}(t) = \begin{pmatrix} t^3 \\ t^4 \end{pmatrix} over [0,1][0, 1].
    (1415)\begin{pmatrix} \textstyle\frac{1}{4} \\ \textstyle\frac{1}{5} \end{pmatrix}. Use power rule: ∫t3dt=t44\int t^3 dt = \frac{t^4}{4} and ∫t4dt=t55\int t^4 dt = \frac{t^5}{5}.
  27. What is the indefinite integral of r(t)=(1t)\textbf{r}(t) = \begin{pmatrix} 1 \\ t \end{pmatrix}?
    (t12t2)+C\begin{pmatrix} t \\ \textstyle\frac{1}{2}t^2 \end{pmatrix} + \textbf{C}. Antiderivatives of 11 and tt with constant vector added.
  28. Express the integral r(t)=(t2sin⁡(t))\textbf{r}(t) = \begin{pmatrix} t^2 \\ \sin(t) \end{pmatrix} over [0,2][0, 2] in component form.
    (831−cos⁡(2))\begin{pmatrix} \textstyle\frac{8}{3} \\ 1 - \cos(2) \end{pmatrix}. Integrate t2t^2 to get 83\frac{8}{3} and sin⁡(t)\sin(t) to get 1−cos⁡(2)1 - \cos(2).

Study these flashcards