Evaluating Improper Integrals - AP Calculus BC
- Determine convergence: .
- Converges. Gaussian integral converges due to exponential decay.
- When does an integral become improper?
- If , , or are infinite or unbounded. Any infinite bound or unbounded integrand makes it improper.
- Evaluate: \textstyle \text{∫}_{0}^{1} \frac{1}{\text{√}x} \text{dx}.
- Converges to . .
- What does it mean if an improper integral converges?
- The limit defining the integral exists and is finite. The limit exists and equals a finite real number.
- Identify convergence: .
- Diverges. Since , the integral diverges.
- Identify the singularity: .
- Unbounded integrand at . Integrand has vertical asymptote at the lower limit.
- Determine behavior: \textstyle \text{∫}_{0}^{1} \frac{1}{\text{√}x} \text{dx}
- Converges. Power ensures convergence at .
- Evaluate: \textstyle \text{∫}_{0}^{\text{∞}} e^{-x} \text{dx}.
- Converges to . .
- Convert to limit form: .
- . Negative infinite lower limit requires limit form.
- Convert to limit: \textstyle \text{∫}_{0}^{1} \frac{1}{x} \text{dx}.
- \textstyle \text{lim}_{a \to 0^+} \text{∫}_{a}^{1} \frac{1}{x} \text{dx}. Integrand is unbounded at lower limit .
- Identify singularity: .
- Unbounded integrand at . Function becomes infinite at the lower limit .
- Evaluate:
- Converges to .
- Evaluate: .
- Converges to . Arcsine function evaluation: .
- State the condition for the convergence of .
- Converges if . For , the singularity at is integrable.
- What is convergence for \textstyle \text{∫}_{1}^{\text{∞}} \frac{1}{x^4} \text{dx}?
- Converges to . .
- What is an improper integral?
- An integral with infinite limits or an unbounded integrand. Defined when limits of integration or integrand are infinite.
- What is convergence for ?
- Converges to . .
- Evaluate limit: .
- Diverges. .
- Determine behavior: for .
- Converges. When , the singularity at is integrable.
- Find the limit: .
- Converges to . .
- Evaluate: .
- Converges to .
- Find the limit:
- Converges to .
- Convert to limit: .
- . Infinite upper limit requires limit evaluation.
- Evaluate:
- Converges to .
- . Infinite upper limit requires limit evaluation.
- Determine convergence:
- Converges. Gaussian integral converges due to exponential decay.
- What is the behavior of \textstyle \text{∫}_{0}^{1} x^{-1/3} \text{dx}?
- Converges. Power ensures convergence.
- Identify the type of improper integral: .
- Unbounded integrand at . becomes infinite as
- State the behavior of .
- Diverges. Same as which diverges.
- Identify singularity: .
- Unbounded integrand at . Function becomes infinite at the lower limit .
- Determine behavior: .
- Converges. Power ensures convergence at .
- Evaluate: .
- Converges. Higher power in denominator ensures convergence.
- What is the behavior of ?
- Converges to . Famous Gaussian integral equals .
- Identify convergence: .
- Diverges. Since , the integral diverges.
- Convert to limit form: .
- . Negative infinite lower limit requires limit form.
- When does an integral become improper?
- If , , or are infinite or unbounded. Any infinite bound or unbounded integrand makes it improper.
- Evaluate limit:
- Diverges.
- Identify the singularity: .
- Unbounded integrand at . Integrand has vertical asymptote at the lower limit.
- What is the behavior of ?
- Converges to . .
- Explain divergence in the context of improper integrals.
- The integral's limit is infinite or does not exist. The limit is infinite or undefined.
- Convert to limit: .
- . Integrand is unbounded at lower limit .
- What is the behavior of \textstyle \text{∫}_{-\text{∞}}^{0} e^x \text{dx}?
- Converges to . .
- State the condition for the convergence of .
- Converges if . For , the singularity at is integrable.
- Determine behavior: for .
- Converges. When , the singularity at is integrable.
- Evaluate: .
- Converges to . Arcsine function evaluation: .
- Evaluate: \textstyle \text{∫}_{1}^{\text{∞}} \frac{1}{x^2} \text{dx}.
- Converges to . .
- State the behavior of
- Diverges. Same as which diverges.
- Determine convergence: .
- Diverges. grows without bound, so the integral diverges.