Estimating Derivatives of a Function - AP Calculus BC

  1. Estimate f′(3)f'(3) for f(x)=sin⁡xf(x) = \sin x using h=0.01h = 0.01 and the forward difference quotient.
    -0.9895. Forward formula: sin⁡(3.01)−sin⁡(3)0.01≈−0.9895\frac{\sin(3.01) - \sin(3)}{0.01} \approx -0.9895
  2. Identify the error: f′(a)≈f(a+h)+f(a−h)2hf'(a) \approx \frac{f(a+h) + f(a-h)}{2h}
    Correct: f′(a)≈f(a+h)−f(a−h)2hf'(a) \approx \frac{f(a+h) - f(a-h)}{2h}. Should subtract, not add, in the numerator.
  3. Which difference quotient is more accurate: forward or symmetric?
    Symmetric. Averages left and right slopes for better approximation.
  4. For f(x)=x3f(x) = x^3, estimate f′(2)f'(2) using h=0.1h = 0.1 and the symmetric difference quotient.
    12.01. Symmetric formula: (2.1)3−(1.9)30.2=12.01\frac{(2.1)^3 - (1.9)^3}{0.2} = 12.01
  5. Estimate f′(0)f'(0) for f(x)=sin⁡(x2)f(x) = \sin(x^2) using h=0.01h = 0.01 and the backward difference quotient.
    0.0000. Backward formula: derivative is 0 at x=0x=0 for even functions.
  6. Estimate f′(3)f'(3) for f(x)=cos⁡(2x)f(x) = \cos(2x) using h=0.01h = 0.01 and the backward difference quotient.
    -1.9159. Backward formula: cos⁡(6)−cos⁡(5.98)0.01≈−1.9159\frac{\cos(6) - \cos(5.98)}{0.01} \approx -1.9159
  7. Estimate f′(3)f'(3) for f(x)=x2+xf(x) = x^2 + x using h=0.1h = 0.1 and the symmetric difference quotient.
    7.0. Symmetric formula gives exact derivative 2x+1=72x+1=7 at x=3x=3.
  8. Estimate f′(5)f'(5) for f(x)=log⁡xf(x) = \log x using h=0.01h = 0.01 and the backward difference quotient.
    0.1990. Backward formula: log⁡(5)−log⁡(4.99)0.01≈0.1990\frac{\log(5) - \log(4.99)}{0.01} \approx 0.1990
  9. Estimate f′(4)f'(4) for f(x)=1x3f(x) = \frac{1}{x^3} using h=0.1h = 0.1 and the forward difference quotient.
    -0.0351. Forward formula: 1/(4.1)3−1/640.1≈−0.0351\frac{1/(4.1)^3 - 1/64}{0.1} \approx -0.0351
  10. Estimate f′(1)f'(1) for f(x)=sin⁡(2x)f(x) = \sin(2x) using h=0.001h = 0.001 and the symmetric difference quotient.
    1.0806. Symmetric formula: sin⁡(2.002)−sin⁡(1.998)0.002≈1.0806\frac{\sin(2.002) - \sin(1.998)}{0.002} \approx 1.0806
  11. Estimate f′(4)f'(4) for f(x)=1x2f(x) = \frac{1}{x^2} using h=0.1h = 0.1 and the backward difference quotient.
    -0.1251. Backward formula: 1/16−1/15.210.1≈−0.1251\frac{1/16 - 1/15.21}{0.1} \approx -0.1251
  12. Estimate f′(3)f'(3) for f(x)=x2+3xf(x) = x^2 + 3x using h=0.1h = 0.1 and the forward difference quotient.
    9.0. Forward formula gives exact derivative 2x+3=92x+3=9 at x=3x=3.
  13. Estimate f′(0)f'(0) for f(x)=cos⁡xf(x) = \cos x using h=0.01h = 0.01 and the forward difference quotient.
    -0.0005. Forward formula: cos⁡(0.01)−cos⁡(0)0.01≈−0.0005\frac{\cos(0.01) - \cos(0)}{0.01} \approx -0.0005
  14. Estimate f′(1)f'(1) for f(x)=xf(x) = \sqrt{x} using h=0.001h = 0.001 and the backward difference quotient.
    0.4995. Backward formula: 1−0.9990.001≈0.4995\frac{\sqrt{1} - \sqrt{0.999}}{0.001} \approx 0.4995
  15. Estimate f′(2)f'(2) for f(x)=ln⁡(1+x2)f(x) = \ln(1+x^2) using h=0.1h = 0.1 and the symmetric difference quotient.
    0.8000. Symmetric formula: ln⁡(5.41)−ln⁡(4.01)0.2≈0.8000\frac{\ln(5.41) - \ln(4.01)}{0.2} \approx 0.8000
  16. For f(x)=x4f(x) = x^4, estimate f′(1)f'(1) using h=0.1h = 0.1 and the forward difference quotient.
    4.0301. Forward formula: (1.1)4−10.1≈4.0301\frac{(1.1)^4 - 1}{0.1} \approx 4.0301
  17. What is the impact of a smaller hh on the accuracy of a derivative estimate?
    Increases accuracy. Smaller step sizes give more precise estimates.
  18. Estimate f′(0)f'(0) for f(x)=e2xf(x) = e^{2x} using h=0.01h = 0.01 and the symmetric difference quotient.
    2.0000. Symmetric formula: e0.02−e−0.020.02≈2.0000\frac{e^{0.02} - e^{-0.02}}{0.02} \approx 2.0000
  19. Identify the error: f′(a)≈f(a+h)+f(a−h)2hf'(a) \approx \frac{f(a+h) + f(a-h)}{2h}
    Correct: f′(a)≈f(a+h)−f(a−h)2hf'(a) \approx \frac{f(a+h) - f(a-h)}{2h}. Should subtract, not add, in the numerator.
  20. Estimate f′(0)f'(0) for f(x)=cos⁡xf(x) = \cos x using h=0.01h = 0.01 and the forward difference quotient.
    -0.0005. Forward formula: cos⁡(0.01)−cos⁡(0)0.01≈−0.0005\frac{\cos(0.01) - \cos(0)}{0.01} \approx -0.0005
  21. Estimate f′(2)f'(2) for f(x)=x3−3x2+2xf(x) = x^3 - 3x^2 + 2x using h=0.1h = 0.1 and the forward difference quotient.
    -2.999. Forward formula for f′(x)=3x2−6x+2f'(x) = 3x^2 - 6x + 2 at x=2x=2.
  22. Estimate f′(3)f'(3) for f(x)=tan⁡−1(x)f(x) = \tan^{-1}(x) using h=0.01h = 0.01 and the backward difference quotient.
    0.0995. Backward formula: tan⁡−1(3)−tan⁡−1(2.99)0.01≈0.0995\frac{\tan^{-1}(3) - \tan^{-1}(2.99)}{0.01} \approx 0.0995
  23. Estimate f′(2)f'(2) for f(x)=1+xf(x) = \sqrt{1+x} using h=0.1h = 0.1 and the symmetric difference quotient.
    0.3536. Symmetric formula: 3.1−2.90.2≈0.3536\frac{\sqrt{3.1} - \sqrt{2.9}}{0.2} \approx 0.3536
  24. Estimate f′(2)f'(2) for f(x)=ln⁡xf(x) = \ln x using h=0.01h = 0.01 and the backward difference quotient.
    0.5001. Backward formula: ln⁡(2)−ln⁡(1.99)0.01≈0.5001\frac{\ln(2) - \ln(1.99)}{0.01} \approx 0.5001
  25. Which value of hh gives a more accurate estimate: h=0.1h=0.1 or h=0.01h=0.01?
    h=0.01h=0.01. Smaller hh values reduce approximation error.
  26. Estimate f′(5)f'(5) for f(x)=x2f(x) = x^2 using h=0.01h = 0.01 and the forward difference quotient.
    10.01. Forward formula: (5.01)2−250.01=10.01\frac{(5.01)^2 - 25}{0.01} = 10.01
  27. Estimate f′(0)f'(0) for f(x)=log⁡(1+x)f(x) = \log(1+x) using h=0.01h = 0.01 and the symmetric difference quotient.
    0.9950. Symmetric formula: log⁡(1.01)−log⁡(0.99)0.02≈0.9950\frac{\log(1.01) - \log(0.99)}{0.02} \approx 0.9950
  28. Estimate f′(1)f'(1) for f(x)=e−xf(x) = e^{-x} using h=0.001h = 0.001 and the backward difference quotient.
    -0.368. Backward formula: e−1−e−1.0010.001≈−0.368\frac{e^{-1} - e^{-1.001}}{0.001} \approx -0.368
  29. Estimate f′(0)f'(0) for f(x)=ln⁡(1+x)f(x) = \ln(1+x) using h=0.1h = 0.1 and the symmetric difference quotient.
    0.9950. Symmetric formula: ln⁡(1.1)−ln⁡(0.9)0.2≈0.9950\frac{\ln(1.1) - \ln(0.9)}{0.2} \approx 0.9950
  30. What is the formula for the backward difference quotient to estimate the derivative at a point?
    f′(a)≈f(a)−f(a−h)hf'(a) \approx \frac{f(a) - f(a-h)}{h}. Uses the point before aa to estimate the slope.
  31. Estimate f′(0)f'(0) for f(x)=11+xf(x) = \frac{1}{1+x} using h=0.1h = 0.1 and the symmetric difference quotient.
    -0.9990. Symmetric formula: 1/1.1−1/0.90.2≈−0.9990\frac{1/1.1 - 1/0.9}{0.2} \approx -0.9990
  32. Estimate f′(2)f'(2) for f(x)=tan⁡xf(x) = \tan x using h=0.01h = 0.01 and the forward difference quotient.
    2.0199. Forward formula: tan⁡(2.01)−tan⁡(2)0.01≈2.0199\frac{\tan(2.01) - \tan(2)}{0.01} \approx 2.0199
  33. Estimate f′(1)f'(1) for f(x)=2xf(x) = 2^x using h=0.001h = 0.001 and the symmetric difference quotient.
    1.3863. Symmetric formula: 21.001−20.9990.002≈1.3863\frac{2^{1.001} - 2^{0.999}}{0.002} \approx 1.3863
  34. Which method reduces error due to truncation: forward or symmetric difference quotient?
    Symmetric. Balances left and right approximation errors.
  35. What is the formula for the forward difference quotient to estimate the derivative at a point?
    $f'(a) \approx \frac{f(a+h) - f(a)}{h}. Uses the point after aa to estimate the slope.
  36. Estimate f′(1)f'(1) for f(x)=x⋅exf(x) = x \cdot e^x using h=0.001h = 0.001 and the forward difference quotient.
    5.4379. Forward formula: 1.001⋅e1.001−e0.001≈5.4379\frac{1.001 \cdot e^{1.001} - e}{0.001} \approx 5.4379
  37. Estimate f′(2)f'(2) for f(x)=x2f(x) = x^2 using h=0.01h = 0.01 and the symmetric difference quotient.
    4.0001. Symmetric formula: (2.01)2−(1.99)20.02=4.0001\frac{(2.01)^2 - (1.99)^2}{0.02} = 4.0001
  38. Estimate f′(4)f'(4) for f(x)=1xf(x) = \frac{1}{x} using h=0.1h = 0.1 and the forward difference quotient.
    -0.0625. Forward formula: 1/4.1−1/40.1≈−0.0625\frac{1/4.1 - 1/4}{0.1} \approx -0.0625
  39. Estimate f′(1)f'(1) for f(x)=exf(x) = e^x using h=0.001h = 0.001 and the backward difference quotient.
    2.718. Backward formula: e1−e0.9990.001≈2.718\frac{e^1 - e^{0.999}}{0.001} \approx 2.718
  40. What is the formula to estimate the derivative of a function at a point using the symmetric difference quotient?
    f′(a)≈f(a+h)−f(a−h)2hf'(a) \approx \frac{f(a+h) - f(a-h)}{2h}. Uses points on both sides of aa for better accuracy.

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