Differentiating Inverse Functions - AP Calculus BC

  1. Find (f−1)′(9)(f^{-1})'(9) given f(3)=9f(3)=9 and f′(3)=0f'(3)=0.
    Undefined because f′(3)=0f'(3)=0. Cannot divide by zero when f′(3)=0f'(3)=0.
  2. What is the geometric meaning of inverse derivatives: how do the tangent line slopes compare at inverse points?
    Slopes are reciprocals at (a,b)(a,b) and (b,a)(b,a). Tangent lines at (a,b)(a,b) and (b,a)(b,a) have reciprocal slopes.
  3. Find (f−1)′(4)(f^{-1})'(4) given f(2)=4f(2)=4 and f′(2)=5f'(2)=5.
    (f−1)′(4)=15(f^{-1})'(4)=\frac{1}{5}. Since f(2)=4f(2)=4 and f′(2)=5f'(2)=5, use reciprocal formula.
  4. Find (f−1)′(2)(f^{-1})'(2) if f(x)=x2+1f(x)=x^2+1 with domain [0,∞)[0,\infty).
    (f−1)′(2)=12(f^{-1})'(2)=\frac{1}{2}. Since f′(x)=2xf'(x)=2x and f(1)=2f(1)=2, so f′(1)=2f'(1)=2, reciprocal is 12\frac{1}{2}.
  5. Find (f−1)′(e)(f^{-1})'(e) if f(x)=ln⁡(x)f(x)=\ln(x).
    (f−1)′(e)=e(f^{-1})'(e)=e. Since exe^x and ln⁡(x)\ln(x) are inverses, f′(1)=1ef'(1)=\frac{1}{e} gives reciprocal ee.
  6. Find (f−1)′(π2)(f^{-1})'(\frac{\pi}{2}) if f(x)=sin⁡(x)f(x)=\sin(x) with domain [−π2,π2]\left[-\frac{\pi}{2},\frac{\pi}{2}\right].
    Undefined because cos⁡(π2)=0\cos\left(\frac{\pi}{2}\right)=0. At x=π2x=\frac{\pi}{2}, sin⁡′(x)=cos⁡(x)=0\sin'(x)=\cos(x)=0, so undefined.
  7. Find (f−1)′(1)(f^{-1})'(1) if f(x)=exf(x)=e^x.
    (f−1)′(1)=1(f^{-1})'(1)=1. Since ln⁡′(e)=1e\ln'(e)=\frac{1}{e} and ln⁡(e)=1\ln(e)=1, reciprocal is ee.
  8. Identify the graph transformation for inverses: across which line are y=f(x)y=f(x) and y=f−1(x)y=f^{-1}(x) reflected?
    Reflection across y=xy=x. Inverse functions are mirror images across the diagonal line.
  9. Identify the key condition needed to differentiate an inverse: what must be true about f′(a)f'(a)?
    f′(a)≠0f'(a)\ne 0. Inverse derivative exists only when original derivative is nonzero.
  10. Find (f−1)′(1)(f^{-1})'(1) given f(0)=1f(0)=1 and f′(0)=14f'(0)=\frac{1}{4}.
    (f−1)′(1)=4(f^{-1})'(1)=4. Since f(0)=1f(0)=1 and f′(0)=14f'(0)=\frac{1}{4}, reciprocal is 44.
  11. What is the derivative of y=ln∣x∣y = \text{ln}|x|?
    1x\frac{1}{x} for x≠0x \neq 0. Chain rule applied to absolute value inside logarithm.
  12. State the derivative formula for an inverse function: what is (f−1)′(x)(f^{-1})'(x) in terms of f′f'?
    (f−1)′(x)=1f′(f−1(x))(f^{-1})'(x)=\frac{1}{f'(f^{-1}(x))}. Derivative of inverse is reciprocal of original derivative at corresponding point.
  13. Find (f−1)′(0)(f^{-1})'(0) if f(x)=x+sin⁡(x)f(x)=x+\sin(x) and f(0)=0f(0)=0.
    (f−1)′(0)=12(f^{-1})'(0)=\frac{1}{2}. Since f′(0)=1+cos⁡(0)=2f'(0)=1+\cos(0)=2, reciprocal is 12\frac{1}{2}.
  14. Find (f−1)′(8)(f^{-1})'(8) if f(x)=x3f(x)=x^3 and f−1(8)=2f^{-1}(8)=2.
    (f−1)′(8)=112(f^{-1})'(8)=\frac{1}{12}. Since f′(x)=3x2f'(x)=3x^2 and f′(2)=12f'(2)=12, reciprocal is 112\frac{1}{12}.
  15. Identify the derivative of y=arctan(x)y = \text{arctan}(x).
    11+x2\frac{1}{1+x^2}. Standard derivative formula for inverse tangent function.
  16. What is the inverse-derivative relationship between slopes: how are f′(a)f'(a) and (f−1)′(b)(f^{-1})'(b) related when f(a)=bf(a)=b?
    f′(a)⋅(f−1)′(b)=1f'(a)\cdot (f^{-1})'(b)=1. Slopes of inverse functions multiply to 1 at corresponding points.
  17. What is the derivative of y=ln(x)y = \text{ln}(x)?
    1x\frac{1}{x}. Standard derivative of natural logarithm function.
  18. Find (f−1)′(2)(f^{-1})'(2) if f(x)=x3+1f(x)=x^3+1 and f−1(2)=1f^{-1}(2)=1.
    (f−1)′(2)=13(f^{-1})'(2)=\frac{1}{3}. Since f′(x)=3x2f'(x)=3x^2 and f′(1)=3f'(1)=3, reciprocal is 13\frac{1}{3}.
  19. Which theorem relates derivatives of inverses to the original function?
    Inverse Function Theorem. States that (f−1)′(x)=1f′(f−1(x))(f^{-1})'(x) = \frac{1}{f'(f^{-1}(x))} when f′(f−1(x))≠0f'(f^{-1}(x)) \neq 0.
  20. Identify the correct expression: which equals (f−1)′(x)(f^{-1})'(x), 1f′(f−1(x))\frac{1}{f'(f^{-1}(x))} or 1f′(x)\frac{1}{f'(x)}?
    1f′(f−1(x))\frac{1}{f'(f^{-1}(x))}. Must evaluate derivative at f−1(x)f^{-1}(x), not at xx directly.
  21. State the chain-rule identity used for inverse differentiation: what is f(f−1(x))f(f^{-1}(x))?
    f(f−1(x))=xf(f^{-1}(x))=x. Composing a function with its inverse yields the identity function.
  22. State the derivative formula for the inverse function of f(x)f(x).
    1f′(f−1(x))\frac{1}{f'(f^{-1}(x))}. Apply the Inverse Function Theorem: (f−1)′(x)=1f′(f−1(x))(f^{-1})'(x) = \frac{1}{f'(f^{-1}(x))}.
  23. Identify the derivative of y=arccot(x)y = \text{arccot}(x).
    −11+x2-\frac{1}{1+x^2}. Derivative of inverse cotangent, negative of arctan derivative.
  24. What is the equivalent point-slope form for inverses: if f(a)=bf(a)=b, what is (f−1)′(b)(f^{-1})'(b)?
    (f−1)′(b)=1f′(a)(f^{-1})'(b)=\frac{1}{f'(a)}. When f(a)=bf(a)=b, slopes at (a,b)(a,b) and (b,a)(b,a) are reciprocals.
  25. Find (f−1)′(0)(f^{-1})'(0) given f(−3)=0f(-3)=0 and f′(−3)=−2f'(-3)=-2.
    (f−1)′(0)=−12(f^{-1})'(0)=-\frac{1}{2}. Since f(−3)=0f(-3)=0 and f′(−3)=−2f'(-3)=-2, take reciprocal.
  26. State the chain-rule identity used for inverse differentiation: what is f−1(f(x))f^{-1}(f(x)) (on the domain of invertibility)?
    f−1(f(x))=xf^{-1}(f(x))=x. Inverse followed by function returns original input on valid domain.

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