Derivatives of Reciprocal Trig Functions - AP Calculus BC

  1. Identify the derivative: ddxsec⁡(x)\frac{d}{dx} \sec(x)
    sec⁡(x)tan⁡(x)\sec(x)\tan(x). Standard derivative of secant.
  2. Differentiate: cot⁡(x)\cot(x)
    −csc⁡2(x)-\csc^2(x). Use derivative formula for cot⁡(x)\cot(x).
  3. Evaluate ddxtan⁡(x)\frac{d}{dx} \tan(x) at x=0x = 0.
    11. sec⁡2(0)=12=1\sec^2(0) = 1^2 = 1.
  4. Find the derivative of y=cot⁡(x)y = \cot(x).
    dydx=−csc⁡2(x)\frac{dy}{dx} = -\csc^2(x). Apply cotangent derivative rule.
  5. Find the derivative of y=tan⁡(x)y = \tan(x).
    dydx=sec⁡2(x)\frac{dy}{dx} = \sec^2(x). Apply tangent derivative rule.
  6. State the formula for the derivative of tangent.
    sec⁡2(x)\sec^2(x). Memorized derivative formula.
  7. State the formula for the derivative of secant.
    sec⁡(x)tan⁡(x)\sec(x)\tan(x). Memorized derivative formula.
  8. What is the derivative of csc⁡(x)\csc(x)?
    −csc⁡(x)cot⁡(x)-\csc(x)\cot(x). Derivative formula for cosecant function.
  9. What is the slope of the tangent line to y=tan⁡(x)y = \tan(x) at x=π4x = \frac{\pi}{4}?
    22. Derivative equals slope at given point.
  10. Determine the derivative of f(x)=cot⁡2(x)f(x) = \cot^2(x).
    −2cot⁡(x)csc⁡2(x)-2\cot(x)\csc^2(x). Use chain rule: 2cot⁡(x)⋅(−csc⁡2(x))2\cot(x) \cdot (-\csc^2(x)).
  11. Evaluate ddxcot⁡(x)\frac{d}{dx} \cot(x) at x=π4x = \frac{\pi}{4}.
    −2-2. −csc⁡2(π4)=−(2)2=−2-\csc^2(\frac{\pi}{4}) = -(\sqrt{2})^2 = -2.
  12. What is the slope of the tangent line to y=cot⁡(x)y = \cot(x) at x=π2x = \frac{\pi}{2}?
    −1-1. Derivative equals slope at given point.
  13. Identify the derivative: ddxcsc⁡(x)\frac{d}{dx} \csc(x)
    −csc⁡(x)cot⁡(x)-\csc(x)\cot(x). Standard derivative of cosecant.
  14. Find the derivative of y=csc⁡(x)y = \csc(x).
    dydx=−csc⁡(x)cot⁡(x)\frac{dy}{dx} = -\csc(x)\cot(x). Apply cosecant derivative rule.
  15. State the formula for the derivative of cosecant.
    −csc⁡(x)cot⁡(x)-\csc(x)\cot(x). Memorized derivative formula.
  16. What is the derivative of tan⁡(x)\tan(x)?
    sec⁡2(x)\sec^2(x). Derivative formula for tangent function.
  17. Compute the derivative of f(x)=sec⁡(x)f(x) = \sec(x) at x=π3x = \frac{\pi}{3}.
    232\sqrt{3}. sec⁡(π3)tan⁡(π3)=2⋅3=23\sec(\frac{\pi}{3})\tan(\frac{\pi}{3}) = 2 \cdot \sqrt{3} = 2\sqrt{3}.
  18. Identify the derivative: ddxtan⁡(x)\frac{d}{dx} \tan(x)
    sec⁡2(x)\sec^2(x). Standard derivative of tangent.
  19. Evaluate ddxsec⁡(x)\frac{d}{dx} \sec(x) at x=0x = 0.
    00. sec⁡(0)tan⁡(0)=1⋅0=0\sec(0)\tan(0) = 1 \cdot 0 = 0.
  20. Differentiate: tan⁡(x)\tan(x)
    sec⁡2(x)\sec^2(x). Use derivative formula for tan⁡(x)\tan(x).
  21. Evaluate ddxcsc⁡(x)\frac{d}{dx} \csc(x) at x=π2x = \frac{\pi}{2}.
    00. −csc⁡(π2)cot⁡(π2)=−1⋅0=0-\csc(\frac{\pi}{2})\cot(\frac{\pi}{2}) = -1 \cdot 0 = 0.
  22. Identify the derivative: ddxcot⁡(x)\frac{d}{dx} \cot(x)
    −csc⁡2(x)-\csc^2(x). Standard derivative of cotangent.
  23. Compute the derivative of f(x)=tan⁡(x)f(x) = \tan(x) at x=π4x = \frac{\pi}{4}.
    22. sec⁡2(π4)=(2)2=2\sec^2(\frac{\pi}{4}) = (\sqrt{2})^2 = 2.
  24. What is the derivative of sec⁡(x)\sec(x)?
    sec⁡(x)tan⁡(x)\sec(x)\tan(x). Derivative formula for secant function.
  25. Determine the derivative of f(x)=tan⁡2(x)f(x) = \tan^2(x).
    2tan⁡(x)sec⁡2(x)2\tan(x)\sec^2(x). Use chain rule: 2tan⁡(x)⋅sec⁡2(x)2\tan(x) \cdot \sec^2(x).
  26. What is the derivative of cot⁡(x)\cot(x)?
    −csc⁡2(x)-\csc^2(x). Derivative formula for cotangent function.
  27. Differentiate: csc⁡(x)\csc(x)
    −csc⁡(x)cot⁡(x)-\csc(x)\cot(x). Use derivative formula for csc⁡(x)\csc(x).
  28. State the formula for the derivative of cotangent.
    −csc⁡2(x)-\csc^2(x). Memorized derivative formula.
  29. Differentiate: sec⁡(x)\sec(x)
    sec⁡(x)tan⁡(x)\sec(x)\tan(x). Use derivative formula for sec⁡(x)\sec(x).
  30. Find the derivative of y=sec⁡(x)y = \sec(x).
    dydx=sec⁡(x)tan⁡(x)\frac{dy}{dx} = \sec(x)\tan(x). Apply secant derivative rule.

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