Position, Velocity, and Acceleration Using Integrals
AP Calculus BC · Flashcards · Application
AP CALCULUS BC · FLASHCARDS
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QUESTION
If
v
(
t
)
=
5
t
v(t) = 5t
v
(
t
)
=
5
t
, what is the total distance from
t
=
0
t = 0
t
=
0
to
t
=
3
t = 3
t
=
3
?
QUESTION
Determine the acceleration at
t
=
2
t = 2
t
=
2
for
v
(
t
)
=
3
t
2
−
5
t
v(t) = 3t^2 - 5t
v
(
t
)
=
3
t
2
−
5
t
.
QUESTION
Find the acceleration function if
v
(
t
)
=
6
t
2
−
4
t
+
1
v(t) = 6t^2 - 4t + 1
v
(
t
)
=
6
t
2
−
4
t
+
1
.
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ANSWER
a
(
t
)
=
12
t
−
4
a(t) = 12t - 4
a
(
t
)
=
12
t
−
4
. Take the derivative of velocity to get acceleration.
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