Connecting Position, Velocity, and Acceleration
AP Calculus BC · Flashcards · Application
AP CALCULUS BC · FLASHCARDS
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QUESTION
Find
a
(
3
)
a(3)
a
(
3
)
if
v
(
t
)
=
t
2
−
2
t
+
1
v(t) = t^2 - 2t + 1
v
(
t
)
=
t
2
−
2
t
+
1
.
QUESTION
Find
v
(
2
)
v(2)
v
(
2
)
if
s
(
t
)
=
5
t
2
−
t
s(t) = 5t^2 - t
s
(
t
)
=
5
t
2
−
t
.
QUESTION
What is the velocity function
v
(
t
)
v(t)
v
(
t
)
if
a
(
t
)
=
6
t
a(t) = 6t
a
(
t
)
=
6
t
?
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ANSWER
v
(
t
)
=
3
t
2
+
C
v(t) = 3t^2 + C
v
(
t
)
=
3
t
2
+
C
. Integrate acceleration to get velocity, adding constant of integration.
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