Average Value of Functions on Intervals
AP Calculus BC · Flashcards · Application
AP CALCULUS BC · FLASHCARDS
Card 1
of 42
0 got it
0 to review
Current
Got it
Still learning
Not seen
QUESTION
What is the average value of
f
(
x
)
=
x
2
−
x
f(x) = x^2 - x
f
(
x
)
=
x
2
−
x
on
[
0
,
3
]
[0, 3]
[
0
,
3
]
?
QUESTION
Determine the average value of
f
(
x
)
=
x
2
+
1
f(x) = x^2 + 1
f
(
x
)
=
x
2
+
1
on
[
0
,
3
]
[0, 3]
[
0
,
3
]
.
QUESTION
Identify the average value of
f
(
x
)
=
cos
2
(
x
)
f(x) = \cos^2(x)
f
(
x
)
=
cos
2
(
x
)
on
[
0
,
π
]
[0, \pi]
[
0
,
π
]
.
Tap to flip before you grade
ANSWER
1
2
\frac{1}{2}
2
1
. Squared cosine uses identity
cos
2
x
=
1
+
cos
(
2
x
)
2
\cos^2 x = \frac{1 + \cos(2x)}{2}
cos
2
x
=
2
1
+
c
o
s
(
2
x
)
.
Swipe → got it · swipe ← still learning
Got it
Still learning
Flip Card
Previous card
Next card