Confirming Continuity over an Interval - AP Calculus BC

  1. What is limx→2(x2−4)/(x−2)\text{lim}_{x \to 2} (x^2 - 4)/(x - 2)?
    The limit is 44, indicating a removable discontinuity. Factor (x−2)(x+2)(x-2)(x+2) and cancel to get lim⁡x→2(x+2)=4\lim_{x \to 2} (x+2) = 4.
  2. State the three conditions for continuity at a point.
    f(a)f(a) is defined, limx→af(x)\text{lim}_{x \to a} f(x) exists, limx→af(x)=f(a)\text{lim}_{x \to a} f(x) = f(a). All three must hold for continuity to be confirmed.
  3. What is a removable discontinuity?
    A discontinuity that can be removed by redefining f(a)f(a). The limit exists but doesn't equal the function value.
  4. What must be true for a function's one-sided limits at x=ax = a for continuity?
    The one-sided limits must be equal at x=ax = a. This ensures the limit exists at the point.
  5. Can a polynomial function have discontinuities?
    No, polynomial functions are continuous everywhere. Polynomials have no restrictions on their domain.
  6. What is the Intermediate Value Theorem?
    If f(x)f(x) is continuous on [a,b][a, b], f(c)f(c) takes every value between f(a)f(a) and f(b)f(b). Guarantees existence of intermediate values on continuous functions.
  7. Determine continuity of f(x)=1xf(x) = \frac{1}{x} at x=0x = 0.
    f(x)f(x) is not continuous at x=0x = 0 as it is undefined. Division by zero makes the function undefined at this point.
  8. What is the role of limx→af(x)\text{lim}_{x \to a} f(x) in confirming continuity?
    It must equal f(a)f(a) for continuity at x=ax = a. The limit must equal the function value for continuity.
  9. Can a rational function have discontinuities?
    Yes, at points where the denominator is zero. Discontinuities occur where denominators equal zero.
  10. What is the continuity status of f(x)=1xf(x) = \frac{1}{x} on R\text{R}?
    f(x)f(x) is continuous on R\0\text{R} \backslash \text{0}. Continuous everywhere except where the denominator is zero.
  11. Explain the continuity of f(x)=sin(x)f(x) = \text{sin}(x) on R\text{R}.
    f(x)=sin(x)f(x) = \text{sin}(x) is continuous on all real numbers. Trigonometric sine function has no domain restrictions.
  12. Define continuity for a function on a closed interval [a,b][a, b].
    f(x)f(x) is continuous on [a,b][a, b] if continuous on (a,b)(a, b) and limits match at aa, bb. Requires continuity at interior points and proper one-sided limits.
  13. Is f(x)=∣x∣f(x) = |x| continuous at x=0x = 0?
    Yes, f(x)=∣x∣f(x) = |x| is continuous at x=0x = 0. Both one-sided limits equal 0, matching f(0)=0f(0) = 0.
  14. Identify the type of discontinuity in f(x)=1x2−1f(x) = \frac{1}{x^2 - 1} at x=1x = 1.
    Infinite discontinuity at x=1x = 1. The function approaches infinity as xx approaches 1.
  15. State the limit condition for continuity over an open interval (a,b)(a, b).
    f(x)f(x) is continuous if limx→cf(x)=f(c)\text{lim}_{x \to c} f(x) = f(c) for all c in (a,b)c \text{ in } (a, b). This is the fundamental definition of continuity over intervals.
  16. Determine continuity of f(x)=2x+3f(x) = 2x + 3 on (−infinity,infinity)(-\text{infinity}, \text{infinity}).
    f(x)f(x) is continuous for all real numbers. Linear functions are continuous everywhere.
  17. Determine if f(x)=3x2−2x+1f(x) = 3x^2 - 2x + 1 is continuous at x=2x = 2.
    f(x)f(x) is continuous at x=2x = 2 since it is a polynomial. Polynomials are continuous at every point in their domain.
  18. What does it mean for limx→af(x)\text{lim}_{x \to a} f(x) to exist?
    Both limx→a−f(x)\text{lim}_{x \to a^-} f(x) and limx→a+f(x)\text{lim}_{x \to a^+} f(x) exist and are equal. The left and right limits must converge to the same value.
  19. What is the continuity status of f(x)=ln(x)f(x) = \text{ln}(x) at x=0x = 0?
    f(x)=ln(x)f(x) = \text{ln}(x) is not continuous at x=0x = 0. Natural log is undefined at zero and negative values.
  20. What is the definition of continuity at a point x=ax = a?
    A function f(x)f(x) is continuous at x=ax = a if limx→af(x)=f(a)\text{lim}_{x \to a} f(x) = f(a). This ensures the function value equals its limit at that point.
  21. Identify the type of discontinuity if limx→af(x)\text{lim}_{x \to a} f(x) does not exist.
    There is an infinite or jump discontinuity at x=ax = a. When one-sided limits differ or approach infinity.
  22. Is f(x)=1x−2f(x) = \frac{1}{x-2} continuous at x=2x = 2?
    No, f(x)f(x) is not continuous at x=2x = 2. The denominator equals zero, making the function undefined.
  23. What is the limit condition for f(x)=x2−1x−1f(x) = \frac{x^2 - 1}{x - 1} at x=1x = 1?
    The limit is 22, indicating a removable discontinuity. Factor and cancel: lim⁡x→1(x+1)=2\lim_{x \to 1} (x+1) = 2.
  24. What is the continuity status of f(x)=cos(x)f(x) = \text{cos}(x)?
    f(x)=cos(x)f(x) = \text{cos}(x) is continuous on all real numbers. Trigonometric cosine function has no domain restrictions.
  25. Determine the continuity of f(x)=xx2−1f(x) = \frac{x}{x^2 - 1} at x=1x = 1.
    f(x)f(x) is not continuous at x=1x = 1 due to division by zero. The denominator (x−1)(x+1)(x-1)(x+1) equals zero at x=1x = 1.
  26. For f(x)=x2−1x−1f(x) = \frac{x^2-1}{x-1}, identify the discontinuity at x=1x = 1.
    Removable discontinuity at x=1x = 1. Factor and cancel to find lim⁡x→1(x+1)=2\lim_{x \to 1} (x+1) = 2.
  27. Is f(x)=sin(x)f(x) = \text{sin}(x) continuous at x=pi2x = \frac{\text{pi}}{2}?
    Yes, f(x)=sin(x)f(x) = \text{sin}(x) is continuous at x=pi2x = \frac{\text{pi}}{2}. Sine function is continuous at all points in its domain.
  28. Explain if f(x)=x−2f(x) = x^{-2} is continuous at x=0x = 0.
    f(x)=x−2f(x) = x^{-2} is not continuous at x=0x = 0. The function is undefined due to division by zero.
  29. Is f(x)=x3f(x) = x^3 continuous for all real numbers?
    Yes, f(x)=x3f(x) = x^3 is continuous everywhere. Cubic polynomials have no domain restrictions.
  30. What is necessary for a function to be continuous on a closed interval [a,b][a, b]?
    The function must be continuous on (a,b)(a, b) and limits must match at aa and bb. Combines interior continuity with proper boundary behavior.
  31. Determine the continuity of f(x)=5f(x) = 5 on its domain.
    f(x)=5f(x) = 5 is continuous everywhere. Constant functions are continuous everywhere.
  32. Identify the type of discontinuity for a step function.
    A step function has a jump discontinuity. Function values change abruptly at certain points.

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