Arc Length of Smooth, Planar Curve - AP Calculus BC

  1. What is the relationship between curvature and radius of curvature?
    R=1κR = \frac{1}{\kappa}. Curvature and radius of curvature are reciprocals of each other.
  2. What is the curvature of the parametric curve x(t)=t,y(t)=t2x(t) = t, y(t) = t^2?
    κ=2(1+4t2)3/2\kappa = \frac{2}{(1 + 4t^2)^{3/2}}. Applies the parametric curvature formula with x′(t)=1,y′(t)=2t,y′′(t)=2x'(t) = 1, y'(t) = 2t, y''(t) = 2.
  3. Find the total distance traveled by a particle with velocity v(t)=3tv(t) = 3t from t=0t = 0 to t=2t = 2.
    D=6D = 6. Distance equals ∫023t dt=3t22∣02=6\int_0^2 3t \, dt = \frac{3t^2}{2}|_0^2 = 6.
  4. Identify the expression for the arc length of a curve x=g(y)x = g(y) from y=cy = c to y=dy = d.
    L=∫cd1+(g′(y))2 dyL = \int_{c}^{d} \sqrt{1 + (g'(y))^2} \, dy. Similar to y=f(x)y = f(x) formula but with xx as a function of yy.
  5. Determine the arc length of r=1+sin⁡(θ)r = 1 + \sin(\theta) from θ=0\theta = 0 to θ=π\theta = \pi.
    L=5.333L = 5.333 (approximately). The cardioid r=1+sin⁡(θ)r = 1 + \sin(\theta) has a complex arc length integral.
  6. Find the radius of curvature of y=sin⁡(x)y = \sin(x) at x=0x = 0.
    R=1R = 1. At x=0x = 0: f′(0)=1,f′′(0)=−1f'(0) = 1, f''(0) = -1, giving κ=1\kappa = 1.
  7. How do you express arc length in polar coordinates from θ=a\theta = a to θ=b\theta = b?
    L=∫ab(drdθ)2+r2 dθL = \int_{a}^{b} \sqrt{(\frac{dr}{d\theta})^2 + r^2} \, d\theta. Combines radial and tangential components: drdθ\frac{dr}{d\theta} and rr respectively.
  8. What is the differential arc length dsds in polar coordinates (r,θ)(r, \theta)?
    ds=(dr)2+(r dθ)2ds = \sqrt{(dr)^2 + (r \, d\theta)^2}. In polar coordinates, r dθr \, d\theta represents the tangential component of arc length.
  9. Determine the arc length of x(t)=t2,y(t)=t3x(t) = t^2, y(t) = t^3 from t=0t = 0 to t=2t = 2.
    L=13(1717−1)L = \frac{1}{3} (17\sqrt{17} - 1). Uses parametric formula with x′(t)=2t,y′(t)=3t2x'(t) = 2t, y'(t) = 3t^2, then integrates.
  10. Find the arc length for r=2cos⁡(θ)r = 2\cos(\theta) from θ=0\theta = 0 to θ=π2\theta = \frac{\pi}{2}.
    L=2L = 2. For r=2cos⁡(θ)r = 2\cos(\theta), this represents a semicircle with diameter 2.
  11. What is the formula for the speed of a particle in terms of its parametric derivatives?
    v=(dxdt)2+(dydt)2v = \sqrt{(\frac{dx}{dt})^2 + (\frac{dy}{dt})^2}. Speed is the magnitude of the velocity vector in parametric form.
  12. Find the arc length of y=3xy = 3x from x=0x = 0 to x=4x = 4.
    L=410L = 4 \sqrt{10}. For y=3xy = 3x, f′(x)=3f'(x) = 3, so 1+9=10\sqrt{1 + 9} = \sqrt{10} over length 4.
  13. What is the formula for the total distance traveled by a particle with position s(t)s(t)?
    D=∫ab∣v(t)∣ dtD = \int_{a}^{b} |v(t)| \, dt. Integrates the absolute value of velocity to account for direction changes.
  14. Compute the radius of curvature for y=x3y = x^3 at x=0x = 0.
    R=∞R = \infty. At x=0x = 0: f′′(0)=0f''(0) = 0, so curvature is 0 and radius is infinite.
  15. Calculate the arc length of y=x2y = x^2 from x=0x = 0 to x=1x = 1.
    L=5+ln⁡(1+5)2L = \frac{\sqrt{5} + \ln(1 + \sqrt{5})}{2}. Uses f′(x)=2xf'(x) = 2x in the arc length formula and evaluates the resulting integral.
  16. Find the total distance traveled by x(t)=2t,y(t)=3tx(t) = 2t, y(t) = 3t from t=0t = 0 to t=2t = 2.
    D=413D = 4\sqrt{13}. Linear motion with constant speed 4+9=13\sqrt{4 + 9} = \sqrt{13} over time interval 2.
  17. What is the expression for the curvature κ\kappa of a curve y=f(x)y = f(x)?
    κ=∣f′′(x)∣(1+(f′(x))2)3/2\kappa = \frac{|f''(x)|}{(1 + (f'(x))^2)^{3/2}}. Measures how quickly the curve deviates from its tangent line.
  18. Calculate the total distance traveled by x(t)=t,y(t)=t2x(t) = t, y(t) = t^2 from t=0t = 0 to t=3t = 3.
    D=5.196D = 5.196 (approximately). Integrates 1+4t2\sqrt{1 + 4t^2} from 0 to 3 to get the total path length.
  19. Calculate the curvature of r(θ)=1+cos⁡(θ)r(\theta) = 1 + \cos(\theta) at θ=0\theta = 0.
    κ=34\kappa = \frac{3}{4}. For cardioid at θ=0\theta = 0: r=2,r′=0,r′′=−1r = 2, r' = 0, r'' = -1.
  20. What is the arc length for y=sin⁡(x)y = \sin(x) from x=0x = 0 to x=π2x = \frac{\pi}{2}?
    L=1.910L = 1.910 (approximately). The arc length integral for sin⁡(x)\sin(x) cannot be expressed in elementary functions.
  21. What is the formula for the radius of curvature RR of a curve y=f(x)y = f(x)?
    R=1κ=(1+(f′(x))2)3/2∣f′′(x)∣R = \frac{1}{\kappa} = \frac{(1 + (f'(x))^2)^{3/2}}{|f''(x)|}. Radius of curvature is the reciprocal of curvature.
  22. What is the curvature of a circle with radius rr?
    κ=1r\kappa = \frac{1}{r}. For a circle, curvature is the reciprocal of the radius.
  23. What is the formula for the arc length of a parametric curve x(t),y(t)x(t), y(t) from t=at = a to t=bt = b?
    L=∫ab(dxdt)2+(dydt)2 dtL = \int_{a}^{b} \sqrt{(\frac{dx}{dt})^2 + (\frac{dy}{dt})^2} \, dt. Combines xx and yy velocity components using the distance formula in parametric form.
  24. Determine the curvature of y=x2y = x^2 at x=1x = 1.
    κ=2(1+4)3/2\kappa = \frac{2}{(1 + 4)^{3/2}}. At x=1x = 1: f′(1)=2,f′′(1)=2f'(1) = 2, f''(1) = 2, so κ=253/2\kappa = \frac{2}{5^{3/2}}.
  25. State the formula for the arc length of a curve y=f(x)y = f(x) from x=ax = a to x=bx = b.
    L=∫ab1+(f′(x))2 dxL = \int_{a}^{b} \sqrt{1 + (f'(x))^2} \, dx. Uses Pythagorean theorem on small segments with 1+(f′(x))21 + (f'(x))^2 under the square root.
  26. State the formula for curvature κ\kappa in parametric form.
    κ=∣x′(t)y′′(t)−y′(t)x′′(t)∣((x′(t))2+(y′(t))2)3/2\kappa = \frac{|x'(t)y''(t) - y'(t)x''(t)|}{((x'(t))^2 + (y'(t))^2)^{3/2}}. Uses the cross product of velocity and acceleration vectors in the numerator.
  27. What is the arc length differential dsds in terms of dxdx and dydy?
    ds=(dx)2+(dy)2ds = \sqrt{(dx)^2 + (dy)^2}. Represents the infinitesimal arc length element using the Pythagorean theorem.

Study these flashcards