AP Calculus AB Quiz
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INTEGRATION AND ACCUMULATION OF CHANGE
Question 1
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Which integral corresponds to
∑
k
=
1
n
(
4
−
k
n
)
3
1
n
\sum_{k=1}^{n}\left(4-\frac{k}{n}\right)^3\frac{1}{n}
∑
k
=
1
n
(
4
−
n
k
)
3
n
1
?
A
∫
0
1
(
4
−
x
)
3
d
x
\displaystyle \int_{0}^{1}(4-x)^3\,dx
∫
0
1
(
4
−
x
)
3
d
x
B
∫
0
4
(
1
−
x
)
3
d
x
\displaystyle \int_{0}^{4}(1-x)^3\,dx
∫
0
4
(
1
−
x
)
3
d
x
C
∫
0
1
(
4
−
4
x
)
3
d
x
\displaystyle \int_{0}^{1}(4-4x)^3\,dx
∫
0
1
(
4
−
4
x
)
3
d
x
D
∫
1
4
x
3
d
x
\displaystyle \int_{1}^{4}x^3\,dx
∫
1
4
x
3
d
x
E
∫
0
1
(
4
+
x
)
3
d
x
\displaystyle \int_{0}^{1}(4+x)^3\,dx
∫
0
1
(
4
+
x
)
3
d
x
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