AP Calculus AB Quiz
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LIMITS AND CONTINUITY
Question 1
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For
r
(
x
)
=
{
x
2
−
36
x
−
6
,
x
≠
6
11
,
x
=
6
r(x)=\begin{cases}\dfrac{x^2-36}{x-6},&x\ne6\\11,&x=6\end{cases}
r
(
x
)
=
⎩
⎨
⎧
x
−
6
x
2
−
36
,
11
,
x
=
6
x
=
6
, what value should replace
11
11
11
to make
r
r
r
continuous at
x
=
6
x=6
x
=
6
?
A
6
6
6
B
12
12
12
C
11
11
11
D
36
36
36
E
−
12
-12
−
12
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