AP Calculus AB Quiz
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APPLICATIONS OF INTEGRATION
Question 1
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For
y
=
x
2
y=x^2
y
=
x
2
and
y
=
2
−
x
2
y=2-x^2
y
=
2
−
x
2
on
[
−
2
,
2
]
[-2,2]
[
−
2
,
2
]
, which setup gives the total area between curves?
A
∫
−
2
2
[
x
2
−
(
2
−
x
2
)
]
d
x
\displaystyle \int_{-2}^{2}\left[x^2-(2-x^2)\right]dx
∫
−
2
2
[
x
2
−
(
2
−
x
2
)
]
d
x
B
∫
−
2
2
[
(
2
−
x
2
)
−
x
2
]
d
x
\displaystyle \int_{-2}^{2}\left[(2-x^2)-x^2\right]dx
∫
−
2
2
[
(
2
−
x
2
)
−
x
2
]
d
x
C
∫
−
2
2
[
x
2
+
(
2
−
x
2
)
]
d
x
\displaystyle \int_{-2}^{2}\left[x^2+(2-x^2)\right]dx
∫
−
2
2
[
x
2
+
(
2
−
x
2
)
]
d
x
D
∫
−
2
−
1
[
x
2
−
(
2
−
x
2
)
]
d
x
+
∫
−
1
1
[
(
2
−
x
2
)
−
x
2
]
d
x
+
∫
1
2
[
x
2
−
(
2
−
x
2
)
]
d
x
\displaystyle \int_{-2}^{-1}\left[x^2-(2-x^2)\right]dx+\int_{-1}^{1}\left[(2-x^2)-x^2\right]dx+\int_{1}^{2}\left[x^2-(2-x^2)\right]dx
∫
−
2
−
1
[
x
2
−
(
2
−
x
2
)
]
d
x
+
∫
−
1
1
[
(
2
−
x
2
)
−
x
2
]
d
x
+
∫
1
2
[
x
2
−
(
2
−
x
2
)
]
d
x
E
∫
−
2
2
[
x
2
(
2
−
x
2
)
]
d
x
\displaystyle \int_{-2}^{2}\left[x^2(2-x^2)\right]dx
∫
−
2
2
[
x
2
(
2
−
x
2
)
]
d
x
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