Selecting Procedures for Calculating Derivatives - AP Calculus AB

  1. For G(x)=exx2+9G(x)=\dfrac{e^{x}}{\sqrt{x^2+9}}, which differentiation rules should be used to compute G′(x)G'(x)?
    Answer: Quotient rule and chain rule This problem requires selecting differentiation procedures for G(x)=exx2+9G(x)=\dfrac{e^{x}}{\sqrt{x^2+9}}. Since this is a quotient, the quotient rule is necessary. Additionally, the denominator x2+9\sqrt{x^2+9} is a composite function where the outer function is the square root and the inner function is x2+9x^2+9, requiring the chain rule when differentiating the denominator. The numerator exe^x differentiates to itself. The product rule alone wouldn't work since this is a quotient structure, and implicit differentiation isn't needed for this explicit function. When you have a quotient where either part contains a composite function, combine the quotient rule with the chain rule.
  2. For k(x)=x2+cos⁡xk(x)=\sqrt{x^2+\cos x}, which differentiation rules are needed to compute k′(x)k'(x)?
    Answer: Chain rule Selecting the appropriate differentiation procedure requires recognizing composite function structures. The function k(x)=x2+cos⁡xk(x)=\sqrt{x^2+\cos x} can be rewritten as (x2+cos⁡x)1/2(x^2+\cos x)^{1/2}, which is clearly a composite function. The chain rule is the necessary and sufficient tool here: we differentiate the outer function (square root or power of 1/2) and multiply by the derivative of the inner function (x2+cos⁡x)(x^2+\cos x). The product rule is not needed because we don't have multiplication of separate functions, and the quotient rule is irrelevant as there's no division. While we use basic differentiation rules for x2x^2 and cos⁡x\cos x within the chain rule application, the chain rule is the primary procedure. The recognition strategy is to identify when one function is "inside" another—square roots, powers, and other function compositions all signal the need for the chain rule.
  3. For u(x)=1−sin⁡xu(x)=\sqrt{1-\sin x}, which differentiation rules are required to find u′(x)u'(x)?
    Answer: Chain rule applied twice This problem requires selecting differentiation procedures for u(x)=1−sin⁡xu(x)=\sqrt{1-\sin x}. This function involves nested composition: the outer function is the square root, and the inner function is 1−sin⁡x1-\sin x. The chain rule must be applied twice - first for the square root, then for the sine function within the expression 1−sin⁡x1-\sin x. Working from outside to inside: the derivative of u\sqrt{u} is 12u\frac{1}{2\sqrt{u}}, and then we need the derivative of 1−sin⁡x1-\sin x, which is −cos⁡x-\cos x. The product rule doesn't apply since this is a single composite function, and implicit differentiation isn't needed. When you encounter functions with multiple layers of composition, apply the chain rule repeatedly, working from the outermost function inward.
  4. Let yy be defined by ey+xy=4e^{y}+xy=4. Which differentiation procedure is needed to find dydx\dfrac{dy}{dx}?
    Answer: Implicit differentiation (including product rule on xyxy) This problem involves selecting the differentiation procedure for finding dydx\dfrac{dy}{dx} when yy is defined implicitly by ey+xy=4e^{y}+xy=4. Since yy cannot be easily isolated as an explicit function of xx, implicit differentiation is required. This involves differentiating both sides with respect to xx, treating yy as a function of xx. The term eye^y requires the chain rule (giving eydydxe^y \frac{dy}{dx}), and the term xyxy requires the product rule (giving y+xdydxy + x\frac{dy}{dx}). Neither quotient rule alone nor explicit function methods apply to this implicit relationship. When you have an equation mixing xx and yy terms where yy cannot be isolated, implicit differentiation with appropriate subsidiary rules is necessary.
  5. For p(x)=x4 ex2p(x)=x^4\,e^{x^2}, which differentiation rule(s) should be used to find p′(x)p'(x)?​
    Answer: Product rule and chain rule Selecting the appropriate differentiation procedure requires recognizing both product and composite structures. The function p(x)=x4ex2p(x)=x^4 e^{x^2} is the product of two functions: x4x^4 and ex2e^{x^2}. The product rule tells us to differentiate as (x4)′⋅ex2+x4⋅(ex2)′(x^4)' \cdot e^{x^2} + x^4 \cdot (e^{x^2})'. The first term gives us 4x3ex24x^3 e^{x^2} using the power rule. For the second term, we need the chain rule to differentiate ex2e^{x^2} because x2x^2 is inside the exponential function, giving us ex2⋅2xe^{x^2} \cdot 2x. Using only the chain rule would miss the product structure, while using only the product rule would incorrectly handle the composite exponential. The recognition strategy is to first identify the main operation (here, multiplication), apply the appropriate rule (product rule), then examine each component for additional complexity (like the composite exponential requiring chain rule).
  6. A function is E(x)=esin⁡(3x)E(x)=e^{\sin(3x)}. Which differentiation rule(s) are required to find E′(x)E'(x)?
    Answer: Chain rule applied multiple times This problem requires selecting differentiation procedures for E(x)=esin⁡(3x)E(x)=e^{\sin(3x)}. This function involves multiple layers of composition: the outer function is the exponential, the middle function is the sine, and the inner function is 3x3x. The chain rule must be applied multiple times to handle this nested structure. Starting from the outside: the derivative of eue^u is eududxe^u \frac{du}{dx}, then we need the derivative of sin⁡(3x)\sin(3x), which requires another application of the chain rule giving cos⁡(3x)⋅3\cos(3x) \cdot 3. Neither product rule, quotient rule, nor implicit differentiation apply since this is a single composite function. When you see exponential functions with composite arguments that are themselves composite, apply the chain rule repeatedly.
  7. For r(x)=tan⁡xx2+3xr(x)=\dfrac{\tan x}{x^2+3x}, which differentiation rules are needed to compute r′(x)r'(x)?
    Answer: Quotient rule Selecting the appropriate differentiation procedure requires careful analysis of the function's structure. The function r(x)=tan⁡xx2+3xr(x)=\frac{\tan x}{x^2+3x} is a quotient with tan⁡x\tan x in the numerator and a polynomial in the denominator. The quotient rule is the primary tool needed here because we have one function divided by another. While differentiating tan⁡x\tan x technically involves knowing that ddx[tan⁡x]=sec⁡2x\frac{d}{dx}[\tan x] = \sec^2 x, this is a standard derivative that doesn't require applying the chain rule in this context. The denominator x2+3xx^2+3x is differentiated using basic power rule. Neither product rule nor chain rule is needed for this particular function. The recognition strategy is straightforward: when you see a fraction bar with functions above and below, the quotient rule is your primary tool.
  8. For R(x)=cos⁡(3x)(x2+1)2R(x)=\dfrac{\cos(3x)}{(x^2+1)^2}, which differentiation rules should be used to find R′(x)R'(x)?
    Answer: Quotient rule and chain rule This problem involves selecting differentiation procedures for R(x)=cos⁡(3x)(x2+1)2R(x)=\dfrac{\cos(3x)}{(x^2+1)^2}. Since this is a quotient, the quotient rule is necessary. Additionally, the numerator cos⁡(3x)\cos(3x) is a composite function requiring the chain rule (outer function is cosine, inner function is 3x3x), and the denominator (x2+1)2(x^2+1)^2 is also composite, requiring the chain rule (outer function is square, inner function is x2+1x^2+1). This demonstrates how the quotient rule often combines with the chain rule when dealing with composite functions in both numerator and denominator. When you have a quotient where both parts contain composite functions, apply the quotient rule with the chain rule for each part.
  9. For d(x)=ln⁡(x)x2+1d(x)=\dfrac{\ln(x)}{x^2+1}, which differentiation rule(s) should be used to compute d′(x)d'(x)?
    Answer: Quotient rule This problem requires selecting the appropriate differentiation procedure for d(x)=ln⁡(x)x2+1d(x)=\dfrac{\ln(x)}{x^2+1}. Since this function is a quotient with both numerator and denominator being functions of xx, the quotient rule is the correct approach. The numerator ln⁡(x)\ln(x) differentiates to 1x\frac{1}{x}, and the denominator x2+1x^2+1 differentiates to 2x2x using basic differentiation rules. The product rule doesn't apply since this is a quotient structure, and chain rule alone isn't sufficient since we need to handle the division properly. When you encounter a fraction where both numerator and denominator are functions of the variable, the quotient rule is the standard method.
  10. For yy defined implicitly by x2y+cos⁡(y)=3x^2y+\cos(y)=3, which differentiation method should be used to find dydx\dfrac{dy}{dx}?
    Answer: Implicit differentiation, using product rule and chain rule This problem involves finding the derivative when yy is defined implicitly by an equation. The equation x2y+cos⁡(y)=3x^2y+\cos(y)=3 cannot be easily solved for yy in terms of xx, making implicit differentiation the appropriate method. When differentiating implicitly, we treat yy as a function of xx and apply the chain rule whenever we differentiate terms containing yy. The term x2yx^2y requires the product rule (since it's a product of x2x^2 and yy), and cos⁡(y)\cos(y) requires the chain rule (since yy is a function of xx). Logarithmic differentiation would be inappropriate here, and trying to use only the product rule would miss the implicit relationship. When variables are mixed in an equation that defines their relationship, implicit differentiation is the key procedure.
  11. Given n(x)=sec⁡(x3−2x)n(x)=\sec(x^3-2x), which differentiation rule is needed to find n′(x)n'(x)?
    Answer: Chain rule (with the derivative of sec⁡\sec) This problem involves selecting the appropriate differentiation procedure for n(x)=sec⁡(x3−2x)n(x)=\sec(x^3-2x). This function is a composition where the outer function is the secant function and the inner function is x3−2xx^3-2x. The chain rule is required, using the derivative formula for secant: ddx[sec⁡(u)]=sec⁡(u)tan⁡(u)⋅dudx\frac{d}{dx}[\sec(u)] = \sec(u)\tan(u) \cdot \frac{du}{dx}. The inner function x3−2xx^3-2x differentiates to 3x2−23x^2-2. The product rule and quotient rule don't apply since this is a single composite function, and implicit differentiation isn't needed. When you encounter trigonometric functions with composite arguments, use the chain rule with the appropriate trigonometric derivative formula.
  12. A population is modeled by P(t)=(2t−1)6P(t)=(2t-1)^6. Which differentiation rule is sufficient to find dPdt\dfrac{dP}{dt}?
    Answer: Chain rule Identifying the minimal sufficient differentiation procedure is a key skill in calculus. The population model P(t)=(2t−1)6P(t)=(2t-1)^6 is a composite function where a linear expression (2t−1)(2t-1) is raised to the sixth power. The chain rule alone is sufficient here: we differentiate the outer function (something to the sixth power) and multiply by the derivative of the inner function (2t−1)(2t-1). The product rule is unnecessary because we don't have multiplication of separate functions, and the quotient rule is irrelevant as there's no division. While we do use the power rule as part of applying the chain rule, the chain rule is the primary procedure needed. To recognize such cases, look for a single composite function structure—when one function is "inside" another, the chain rule suffices.
  13. Let D(x)=(2x−5)23D(x)=\sqrt[3]{(2x-5)^2}. Which differentiation rule(s) should be used to find D′(x)D'(x)?
    Answer: Chain rule (rewrite as a rational power) This problem involves selecting the appropriate differentiation procedure for D(x)=(2x−5)23D(x)=\sqrt[3]{(2x-5)^2}. This can be rewritten as D(x)=[(2x−5)2]1/3=(2x−5)2/3D(x)=[(2x-5)^2]^{1/3} = (2x-5)^{2/3}, which is a composition where the outer function is the power 2/32/3 and the inner function is 2x−52x-5. The chain rule is required, treating this as a rational power of a linear function. The quotient rule isn't needed since this can be handled as a single power, and logarithmic differentiation would be unnecessarily complex. When you encounter radical expressions that can be rewritten using rational exponents, the chain rule with power rule is typically the most efficient approach.
  14. A function is W(x)=x2+1+3x2W(x)=\sqrt{x^2+1}+\dfrac{3}{x^2}. Which differentiation rules are needed to compute W′(x)W'(x)?
    Answer: Chain rule and power rule (with sum rule) This problem involves selecting differentiation procedures for W(x)=x2+1+3x2W(x)=\sqrt{x^2+1}+\dfrac{3}{x^2}. This function is a sum of two terms, so the sum rule applies. The first term x2+1\sqrt{x^2+1} requires the chain rule (outer function is square root, inner function is x2+1x^2+1), and the second term 3x2=3x−2\dfrac{3}{x^2} = 3x^{-2} requires the power rule. Neither product rule, quotient rule at the top level, nor implicit differentiation apply since we're dealing with a sum where each term can be differentiated using basic rules. When you encounter sums of functions where individual terms may be composite, apply the sum rule and use appropriate rules for each term.
  15. For h(x)=ln⁡((x2+1)53x−2)h(x)=\ln\left(\dfrac{(x^2+1)^5}{\sqrt{3x-2}}\right), which rules should be used to find h′(x)h'(x)?​
    Answer: Chain rule and properties of logarithms to simplify first Selecting the appropriate differentiation procedure often involves recognizing when simplification can make the process more efficient. The function h(x)=ln⁡((x2+1)53x−2)h(x)=\ln\left(\frac{(x^2+1)^5}{\sqrt{3x-2}}\right) appears complex, but logarithm properties allow us to simplify before differentiating. Using the properties ln⁡(a/b)=ln⁡(a)−ln⁡(b)\ln(a/b) = \ln(a) - \ln(b) and ln⁡(an)=nln⁡(a)\ln(a^n) = n\ln(a), we can rewrite this as h(x)=5ln⁡(x2+1)−12ln⁡(3x−2)h(x) = 5\ln(x^2+1) - \frac{1}{2}\ln(3x-2). Now we can differentiate using the chain rule on each logarithmic term, which is much simpler than applying the quotient rule to the original expression. While the quotient rule could technically work on the argument inside the logarithm, it would create unnecessary complexity. The recognition strategy is to always check if logarithm properties can simplify your expression before differentiating—this often transforms a complex quotient or product into a sum or difference that's easier to handle.
  16. For z(x)=xln⁡xz(x)=\dfrac{\sqrt{x}}{\ln x}, which differentiation rule(s) should be used to compute z′(x)z'(x)?
    Answer: Quotient rule This problem involves selecting the appropriate differentiation procedure for z(x)=xln⁡xz(x)=\dfrac{\sqrt{x}}{\ln x}. Since this function is a quotient with both numerator and denominator being functions of xx, the quotient rule is the correct approach. The numerator x=x1/2\sqrt{x} = x^{1/2} differentiates using the power rule to give 12x−1/2\frac{1}{2}x^{-1/2}, and the denominator ln⁡x\ln x differentiates to 1x\frac{1}{x}. Neither product rule, chain rule alone, nor implicit differentiation apply to this quotient structure. When you encounter a fraction where both numerator and denominator are functions of the variable (even if they're basic functions), the quotient rule is the standard method.
  17. Let yy be defined by ln⁡(y)=x2−3x\ln(y)=x^2-3x. Which differentiation procedure is required to find dydx\dfrac{dy}{dx}?
    Answer: Implicit differentiation This problem requires selecting the differentiation procedure for finding dydx\dfrac{dy}{dx} when yy is defined implicitly by ln⁡(y)=x2−3x\ln(y)=x^2-3x. Since yy appears inside a logarithm and cannot be easily isolated as an explicit function of xx, implicit differentiation is required. Differentiating both sides with respect to xx: the left side gives 1ydydx\frac{1}{y} \frac{dy}{dx} using the chain rule, and the right side gives 2x−32x-3. The equation can then be solved for dydx\frac{dy}{dx}. Neither explicit function rules nor other standard rules apply directly to this implicit relationship. When you have an equation where the dependent variable appears inside functions and cannot be isolated, implicit differentiation is the necessary approach.
  18. A population is modeled by P(t)=t2+3tln⁡(t+1)P(t)=\dfrac{t^2+3t}{\ln(t+1)}. Which differentiation rule(s) should be used to compute P′(t)P'(t)?
    Answer: Quotient rule and chain rule This problem requires selecting appropriate differentiation procedures for P(t)=t2+3tln⁡(t+1)P(t)=\dfrac{t^2+3t}{\ln(t+1)}. Since this is a fraction with both numerator and denominator being functions of tt, the quotient rule is necessary. Additionally, the denominator ln⁡(t+1)\ln(t+1) is a composite function requiring the chain rule to differentiate properly. The product rule alone wouldn't work since this is a quotient, and the power rule is insufficient for handling the logarithmic denominator. Logarithmic differentiation is not required here as we can directly apply the quotient rule. When you see a fraction where the denominator contains a composite function, expect to use both quotient rule and chain rule.
  19. Given U(x)=x2 exU(x)=x^2\,e^{\sqrt{x}}, which differentiation rules are needed to compute U′(x)U'(x)?
    Answer: Product rule and chain rule This problem involves selecting differentiation procedures for U(x)=x2 exU(x)=x^2\,e^{\sqrt{x}}. This function is a product of two functions: x2x^2 and exe^{\sqrt{x}}, so the product rule is necessary. Additionally, the second factor exe^{\sqrt{x}} is a composite function where the outer function is the exponential and the inner function is x\sqrt{x}, requiring the chain rule. The first factor x2x^2 differentiates to 2x2x using the power rule. This demonstrates how the product rule combines with the chain rule when one factor involves nested composition. When you encounter a product where one factor is a composite exponential function, expect to use both product rule and chain rule.
  20. For q(x)=(x2−1x2+1)6q(x)=\left(\dfrac{x^2-1}{x^2+1}\right)^6, which differentiation rule(s) should be used to find q′(x)q'(x)?​​
    Answer: Chain rule and quotient rule Identifying the correct differentiation procedure requires recognizing a power of a quotient, which creates a composite function. The function q(x)=(x2−1x2+1)6q(x)=\left(\frac{x^2-1}{x^2+1}\right)^6 has the structure of an inner function (the quotient x2−1x2+1\frac{x^2-1}{x^2+1}) raised to the 6th power, requiring the chain rule. We first apply the power rule to get 6(x2−1x2+1)56\left(\frac{x^2-1}{x^2+1}\right)^5, then multiply by the derivative of the inner quotient. To find the derivative of x2−1x2+1\frac{x^2-1}{x^2+1}, we need the quotient rule. Using only the quotient rule would ignore the outer power structure, while using only the power rule would incorrectly treat the quotient. The key insight is recognizing nested operations: when you see an entire expression (especially a fraction) raised to a power, you'll need the chain rule for the power and additional rules for whatever's inside the parentheses.

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