The Quotient Rule - AP Calculus AB

  1. In the Quotient Rule, what does uu represent for uv\frac{u}{v}?
    Numerator function. This is the function in the numerator of the fraction uv\frac{u}{v}.
  2. Evaluate the derivative: y=4x3x2−2xy = \frac{4x^3}{x^2 - 2x} using the Quotient Rule.
    (x2−2x)(12x2)−4x3(2x−2)(x2−2x)2\frac{(x^2 - 2x)(12x^2) - 4x^3(2x - 2)}{(x^2 - 2x)^2}. Apply quotient rule with u=4x3u = 4x^3 and v=x2−2xv = x^2 - 2x.
  3. Differentiate f(x)=x2+2x5x+1f(x) = \frac{x^2 + 2x}{5x + 1} using the Quotient Rule.
    (5x+1)(2x+2)−(x2+2x)(5)(5x+1)2\frac{(5x+1)(2x+2) - (x^2+2x)(5)}{(5x+1)^2}. Apply quotient rule with u=x2+2xu = x^2 + 2x and v=5x+1v = 5x + 1.
  4. Use the Quotient Rule to differentiate y=6x3x2+2y = \frac{6x}{3x^2 + 2}.
    (3x2+2)(6)−6x(6x)(3x2+2)2\frac{(3x^2 + 2)(6) - 6x(6x)}{(3x^2 + 2)^2}. Apply quotient rule with u=6xu = 6x and v=3x2+2v = 3x^2 + 2.
  5. In the Quotient Rule, what happens to the denominator after differentiation?
    It is squared. The original denominator vv becomes v2v^2 in the final result.
  6. Use the Quotient Rule to differentiate y=5xx2+1y = \frac{5x}{x^2 + 1}.
    (x2+1)(5)−5x(2x)(x2+1)2\frac{(x^2+1)(5) - 5x(2x)}{(x^2+1)^2}. Apply quotient rule with u=5xu = 5x and v=x2+1v = x^2 + 1.
  7. Differentiate f(x)=2xx2+3f(x) = \frac{2x}{x^2 + 3} using the Quotient Rule.
    (x2+3)(2)−2x(2x)(x2+3)2\frac{(x^2 + 3)(2) - 2x(2x)}{(x^2 + 3)^2}. Apply quotient rule with u=2xu = 2x and v=x2+3v = x^2 + 3.
  8. In the Quotient Rule, what does ddx\frac{d}{dx} denote?
    Derivative with respect to xx. This symbol indicates taking the derivative with respect to variable xx.
  9. What is the derivative of x2x+1\frac{x^2}{x+1} using the Quotient Rule?
    (x+1)(2x)−x2(1)(x+1)2\frac{(x+1)(2x) - x^2(1)}{(x+1)^2}. Apply quotient rule: (x+1)(x+1) times 2x2x minus x2x^2 times 11, over (x+1)2(x+1)^2.
  10. Evaluate the derivative: y=x22x−1y = \frac{x^2}{2x - 1} using the Quotient Rule.
    (2x−1)(2x)−x2(2)(2x−1)2\frac{(2x-1)(2x) - x^2(2)}{(2x-1)^2}. Apply quotient rule with u=x2u = x^2 and v=2x−1v = 2x - 1.
  11. What is the result of differentiating y=1xy = \frac{1}{x} using the Quotient Rule?
    0−1x2\frac{0 - 1}{x^2}. Since dudx=0\frac{du}{dx} = 0 for constant numerator, only the second term remains.
  12. In the Quotient Rule, what is the derivative of the denominator?
    dvdx\frac{dv}{dx}. This represents taking the derivative of the denominator function vv.
  13. Identify the function that is squared in the denominator of the Quotient Rule.
    vv. The denominator function vv appears squared in the final quotient rule result.
  14. Evaluate the derivative: y=2x2x+3y = \frac{2x^2}{x+3} using the Quotient Rule.
    (x+3)(4x)−2x2(1)(x+3)2\frac{(x+3)(4x) - 2x^2(1)}{(x+3)^2}. Apply quotient rule with u=2x2u = 2x^2 and v=x+3v = x + 3.
  15. Differentiate f(x)=x2−1x3f(x) = \frac{x^2 - 1}{x^3} using the Quotient Rule.
    x3(2x)−(x2−1)(3x2)x6\frac{x^3(2x) - (x^2 - 1)(3x^2)}{x^6}. Apply quotient rule with u=x2−1u = x^2 - 1 and v=x3v = x^3.
  16. What is the derivative of xx+2\frac{x}{x+2} using the Quotient Rule?
    (x+2)(1)−x(1)(x+2)2\frac{(x+2)(1) - x(1)}{(x+2)^2}. Apply quotient rule with u=xu = x and v=x+2v = x + 2.
  17. Which operation is used to combine vdudxv\frac{du}{dx} and udvdxu\frac{dv}{dx} in the Quotient Rule?
    Subtraction. The quotient rule formula uses subtraction between these two terms.
  18. In the Quotient Rule, what does vv represent for uv\frac{u}{v}?
    Denominator function. This is the function in the denominator of the fraction uv\frac{u}{v}.
  19. What is the numerator of the Quotient Rule for uv\frac{u}{v}?
    vdudx−udvdxv\frac{du}{dx} - u\frac{dv}{dx}. This is the complete numerator before dividing by v2v^2.
  20. Identify the error in: ddx(xx2+1)=(x2+1)(1)−x(2x)x2+1\frac{d}{dx}\left(\frac{x}{x^2+1}\right) = \frac{(x^2+1)(1) - x(2x)}{x^2+1}
    Denominator should be (x2+1)2(x^2+1)^2. The denominator must be squared when using the quotient rule.
  21. Differentiate f(x)=x3x2+1f(x) = \frac{x}{3x^2 + 1} using the Quotient Rule.
    (3x2+1)(1)−x(6x)(3x2+1)2\frac{(3x^2+1)(1) - x(6x)}{(3x^2+1)^2}. Apply quotient rule with u=xu = x and v=3x2+1v = 3x^2 + 1.
  22. Find the derivative using the Quotient Rule: y=x2+3x2xy = \frac{x^2 + 3x}{2x}.
    2x(2x+3)−(x2+3x)(2)4x2\frac{2x(2x+3) - (x^2+3x)(2)}{4x^2}. Apply quotient rule with u=x2+3xu = x^2 + 3x and v=2xv = 2x.
  23. Find the derivative using the Quotient Rule: y=3x4x2+7y = \frac{3x}{4x^2 + 7}.
    (4x2+7)(3)−3x(8x)(4x2+7)2\frac{(4x^2 + 7)(3) - 3x(8x)}{(4x^2 + 7)^2}. Apply quotient rule with u=3xu = 3x and v=4x2+7v = 4x^2 + 7.
  24. In the Quotient Rule, what is the role of dudx\frac{du}{dx}?
    Derivative of the numerator function. This term represents how the numerator changes with respect to xx.
  25. What is the derivative of 2x+3x\frac{2x + 3}{x} using the Quotient Rule?
    x(2)−(2x+3)(1)x2\frac{x(2) - (2x+3)(1)}{x^2}. Apply quotient rule with u=2x+3u = 2x + 3 and v=xv = x.
  26. State the formula for the Quotient Rule in calculus.
    ddx(uv)=vdudx−udvdxv2\frac{d}{dx}\left(\frac{u}{v}\right) = \frac{v\frac{du}{dx} - u\frac{dv}{dx}}{v^2}. This is the standard form: low dd high minus high dd low, all over low squared.
  27. In the Quotient Rule, what is the derivative of the numerator?
    dudx\frac{du}{dx}. This represents taking the derivative of the numerator function uu.
  28. Differentiate f(x)=3x2+2x+4f(x) = \frac{3x^2 + 2}{x+4} using the Quotient Rule.
    (x+4)(6x)−(3x2+2)(1)(x+4)2\frac{(x+4)(6x) - (3x^2+2)(1)}{(x+4)^2}. Apply quotient rule with u=3x2+2u = 3x^2 + 2 and v=x+4v = x + 4.
  29. Evaluate the derivative: y=5x32x+1y = \frac{5x^3}{2x + 1} using the Quotient Rule.
    (2x+1)(15x2)−5x3(2)(2x+1)2\frac{(2x+1)(15x^2) - 5x^3(2)}{(2x+1)^2}. Apply quotient rule with u=5x3u = 5x^3 and v=2x+1v = 2x + 1.
  30. What operation is performed between vdudxv\frac{du}{dx} and udvdxu\frac{dv}{dx} in the Quotient Rule?
    Subtraction. The quotient rule requires subtracting udvdxu\frac{dv}{dx} from vdudxv\frac{du}{dx}.
  31. Which term is subtracted in the Quotient Rule formula?
    udvdxu\frac{dv}{dx}. In the quotient rule formula, this term is subtracted from vdudxv\frac{du}{dx}.
  32. Use the Quotient Rule to differentiate y=1x2+4xy = \frac{1}{x^2 + 4x}.
    (x2+4x)(0)−1(2x+4)(x2+4x)2\frac{(x^2 + 4x)(0) - 1(2x + 4)}{(x^2 + 4x)^2}. Since u=1u = 1, its derivative is 00, simplifying the numerator.
  33. Differentiate f(x)=x3+xx2f(x) = \frac{x^3 + x}{x^2} using the Quotient Rule.
    x2(3x2+1)−(x3+x)(2x)x4\frac{x^2(3x^2 + 1) - (x^3 + x)(2x)}{x^4}. Apply quotient rule with u=x3+xu = x^3 + x and v=x2v = x^2.
  34. What is the denominator in the Quotient Rule for uv\frac{u}{v}?
    v2v^2. The denominator function is always squared in the quotient rule.
  35. Evaluate the derivative: y=7x3+2xy = \frac{7}{x^3 + 2x} using the Quotient Rule.
    0(x3+2x)−7(3x2+2)(x3+2x)2\frac{0(x^3 + 2x) - 7(3x^2 + 2)}{(x^3 + 2x)^2}. Since u=7u = 7 is constant, dudx=0\frac{du}{dx} = 0 simplifies the expression.
  36. What is the Quotient Rule derivative for 1x2\frac{1}{x^2}?
    0−2xx4\frac{0 - 2x}{x^4}. Since u=1u = 1 has derivative 00, only the subtraction term remains.
  37. When using the Quotient Rule, what must be done to the denominator function vv?
    Square it. The denominator vv must be squared to complete the quotient rule formula.
  38. Differentiate f(x)=x2+1xf(x) = \frac{x^2 + 1}{x} using the Quotient Rule.
    x(2x)−(x2+1)(1)x2\frac{x(2x) - (x^2 + 1)(1)}{x^2}. Apply quotient rule with u=x2+1u = x^2 + 1 and v=xv = x.

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