Integrating Using Substitution - AP Calculus AB

  1. Determine dudu if u=ln xu = \text{ln } x in substitution.
    du=1x dxdu = \frac{1}{x} \, dx. The derivative of u=ln⁡xu = \ln x is 1x\frac{1}{x}, so du=1xdxdu = \frac{1}{x} dx.
  2. Determine dudu if u=ln(4x)u = \text{ln}(4x) in substitution.
    du=1x dxdu = \frac{1}{x} \, dx. The derivative of u=ln⁡(4x)u = \ln(4x) is 1x\frac{1}{x}, so du=1xdxdu = \frac{1}{x} dx.
  3. Identify uu for substitution if du=sec2x dxdu = \text{sec}^2 x \, dx.
    u=tan xu = \text{tan } x. Since ddx(tan⁡x)=sec⁡2x\frac{d}{dx}(\tan x) = \sec^2 x, if du=sec⁡2xdxdu = \sec^2 x dx, then u=tan⁡xu = \tan x.
  4. What substitution simplifies the integral of (2x+1)5(2x + 1)^5?
    u=2x+1u = 2x + 1. Let u=2x+1u = 2x + 1 to transform (2x+1)5(2x + 1)^5 into u5u^5 for easier integration.
  5. What is the integral of eu due^u \, du?
    eu+Ce^u + C. The antiderivative of eue^u is eue^u plus the constant of integration.
  6. Determine dudu if u=2x3+1u = 2x^3 + 1 in substitution.
    du=6x2 dxdu = 6x^2 \, dx. The derivative of u=2x3+1u = 2x^3 + 1 is 6x26x^2, so du=6x2dxdu = 6x^2 dx.
  7. Identify dudu if u=x3u = x^3 in substitution.
    du=3x2 dxdu = 3x^2 \, dx. The derivative of u=x3u = x^3 is dudx=3x2\frac{du}{dx} = 3x^2, so du=3x2dxdu = 3x^2 dx.
  8. What is the integral of 1u du\frac{1}{u} \, du?
    ln ∣u∣+C\text{ln } |u| + C. The antiderivative of 1u\frac{1}{u} is ln⁡∣u∣\ln|u| plus the constant of integration.
  9. Determine dudu for u=sin xu = \text{sin } x in substitution.
    du=cos x dxdu = \text{cos } x \, dx. The derivative of u=sin⁡xu = \sin x is cos⁡x\cos x, so du=cos⁡xdxdu = \cos x dx.
  10. Find uu for substitution if du=7x6 dxdu = 7x^6 \, dx.
    u=x7u = x^7. Since ddx(x7)=7x6\frac{d}{dx}(x^7) = 7x^6, if du=7x6dxdu = 7x^6 dx, then u=x7u = x^7.
  11. Find the integral of sec2u du\text{sec}^2 u \, du.
    tan u+C\text{tan } u + C. The antiderivative of sec⁡2u\sec^2 u is tan⁡u\tan u plus the constant of integration.
  12. Find uu for substitution if du=3x2dxdu = 3x^2 dx in 1(x3+1)2\frac{1}{(x^3+1)^2}.
    u=x3+1u = x^3 + 1. If du=3x2dxdu = 3x^2 dx, then u=x3+1u = x^3 + 1 since ddx(x3+1)=3x2\frac{d}{dx}(x^3 + 1) = 3x^2.
  13. What substitution simplifies the integral of xex2x e^{x^2}?
    u=x2u = x^2. Let u=x2u = x^2 so that du=2xdxdu = 2x dx matches the xx factor in xex2xe^{x^2}.
  14. Identify uu for substitution if du=5x4 dxdu = 5x^4 \, dx.
    u=x5u = x^5. Since ddx(x5)=5x4\frac{d}{dx}(x^5) = 5x^4, if du=5x4dxdu = 5x^4 dx, then u=x5u = x^5.
  15. What is the integral of sin u du\text{sin } u \, du?
    −cos u+C-\text{cos } u + C. The antiderivative of sin⁡u\sin u is −cos⁡u-\cos u plus the constant of integration.
  16. Find uu for substitution if du=1x dxdu = \frac{1}{x} \, dx.
    u=ln xu = \text{ln } x. Since ddx(ln⁡x)=1x\frac{d}{dx}(\ln x) = \frac{1}{x}, if du=1xdxdu = \frac{1}{x} dx, then u=ln⁡xu = \ln x.
  17. Find uu for substitution if du=1x2 dxdu = \frac{1}{x^2} \, dx.
    u=−1xu = -\frac{1}{x}. Since ddx(−1x)=1x2\frac{d}{dx}(-\frac{1}{x}) = \frac{1}{x^2}, if du=1x2dxdu = \frac{1}{x^2} dx, then u=−1xu = -\frac{1}{x}.
  18. What substitution simplifies the integral of cos(x2)\text{cos}(x^2)?
    u=x2u = x^2. Let u=x2u = x^2 to simplify the argument of the cosine function.
  19. Determine dudu if u=3x4+2xu = 3x^4 + 2x in substitution.
    du=(12x3+2) dxdu = (12x^3 + 2) \, dx. The derivative of u=3x4+2xu = 3x^4 + 2x is 12x3+212x^3 + 2, so du=(12x3+2)dxdu = (12x^3 + 2) dx.
  20. What is the integral of un duu^n \, du?
    un+1n+1+C\frac{u^{n+1}}{n+1} + C, n≠−1n \neq -1. Use the power rule for integration: increase exponent by 1 and divide.
  21. What is the integral of cos u du\text{cos } u \, du?
    sin u+C\text{sin } u + C. The antiderivative of cos⁡u\cos u is sin⁡u\sin u plus the constant of integration.
  22. Determine dudu if u=x2−1u = x^2 - 1 in substitution.
    du=2x dxdu = 2x \, dx. The derivative of u=x2−1u = x^2 - 1 is 2x2x, so du=2xdxdu = 2x dx.
  23. Identify uu for substitution if du=4x3 dxdu = 4x^3 \, dx.
    u=x4u = x^4. Since ddx(x4)=4x3\frac{d}{dx}(x^4) = 4x^3, if du=4x3dxdu = 4x^3 dx, then u=x4u = x^4.
  24. Determine dudu if u=5x+3u = 5x + 3 in substitution.
    du=5 dxdu = 5 \, dx. The derivative of u=5x+3u = 5x + 3 is 55, so du=5dxdu = 5 dx.
  25. What substitution simplifies the integral of xcos(x2)x \text{cos}(x^2)?
    u=x2u = x^2. Let u=x2u = x^2 so that du=2xdxdu = 2x dx matches the xx factor in xcos⁡(x2)x\cos(x^2).
  26. Identify uu for substitution if du=ex dxdu = e^x \, dx.
    u=exu = e^x. Since ddx(ex)=ex\frac{d}{dx}(e^x) = e^x, if du=exdxdu = e^x dx, then u=exu = e^x.
  27. What is the substitution for uu if du=−sin x dxdu = -\text{sin } x \, dx?
    u=cos xu = \text{cos } x. Since ddx(cos⁡x)=−sin⁡x\frac{d}{dx}(\cos x) = -\sin x, if du=−sin⁡xdxdu = -\sin x dx, then u=cos⁡xu = \cos x.
  28. What substitution simplifies the integral of cos⁡(x2)\cos(x^2)?
    u=x2u = x^2. Let u=x2u = x^2 to simplify the argument of the cosine function.
  29. Identify uu for substitution if du=2x dxdu = 2x \, dx.
    u=x2u = x^2. Since ddx(x2)=2x\frac{d}{dx}(x^2) = 2x, if du=2xdxdu = 2x dx, then u=x2u = x^2.
  30. Find uu for substitution if du=cos x dxdu = \text{cos } x \, dx.
    u=sin xu = \text{sin } x. Since ddx(sin⁡x)=cos⁡x\frac{d}{dx}(\sin x) = \cos x, if du=cos⁡xdxdu = \cos x dx, then u=sin⁡xu = \sin x.
  31. Determine dudu if u=tan xu = \text{tan } x in substitution.
    du=sec2x dxdu = \text{sec}^2 x \, dx. The derivative of u=tan⁡xu = \tan x is sec⁡2x\sec^2 x, so du=sec⁡2xdxdu = \sec^2 x dx.

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