Integrating, Long Division, Completing the Square - AP Calculus AB

  1. What is the completed square form of x2+2x+3x^2 + 2x + 3?
    (x+1)2+2(x+1)^2 + 2. Complete the square: (x+1)2+2(x+1)^2 + 2 where 2=3−12 = 3 - 1.
  2. Express x2+4x+13x^2 + 4x + 13 in completed square form.
    (x+2)2+9(x+2)^2 + 9. Complete the square by adding and subtracting (42)2=4(\frac{4}{2})^2 = 4.
  3. State the integral of 1x2+2x+3\frac{1}{x^2 + 2x + 3} after completing the square.
    Use 1(x+1)2+2\frac{1}{(x+1)^2 + 2} form. After completing the square: x2+2x+3=(x+1)2+2x^2 + 2x + 3 = (x+1)^2 + 2.
  4. Express x2+14x+49x^2 + 14x + 49 in completed square form.
    (x+7)2(x+7)^2. This is a perfect square trinomial: (x+7)2(x+7)^2.
  5. What is the integral of 1(x+3)2+1\frac{1}{(x+3)^2 + 1}?
    tan⁡−1(x+3)+C\tan^{-1}(x+3) + C. Standard arctangent integral form.
  6. Convert x2+12x+36x^2 + 12x + 36 into a completed square.
    (x+6)2(x+6)^2. Perfect square trinomial with a=6a = 6.
  7. What is the integral of 1(x+1)2+4\frac{1}{(x+1)^2 + 4}?
    12tan⁡−1x+12+C\frac{1}{2} \tan^{-1}\frac{x+1}{2} + C. Arctangent formula with a=2a = 2.
  8. What is the integral of 1(x+6)2\frac{1}{(x+6)^2}?
    −1x+6+C-\frac{1}{x+6} + C. Power rule: ∫(x+6)−2dx=−(x+6)−1+C\int (x+6)^{-2} dx = -(x+6)^{-1} + C.
  9. What is the integral of 1(x+2)2+1\frac{1}{(x+2)^2+1}?
    tan⁡−1(x+2)+C\tan^{-1}(x+2) + C. Standard arctangent integral with a=1a = 1.
  10. What is the antiderivative of 1(x+1)2\frac{1}{(x+1)^2}?
    −1x+1+C-\frac{1}{x+1} + C. Standard integral of u−2u^{-2} form.
  11. Convert x2+4x+6x^2 + 4x + 6 into completed square form.
    (x+2)2+2(x+2)^2 + 2. Complete the square: (x+2)2+2(x+2)^2 + 2 where 2=6−42 = 6 - 4.
  12. Convert x2+4x+5x^2 + 4x + 5 into completed square form.
    (x+2)2+1(x+2)^2 + 1. Complete the square: x2+4x+4+1=(x+2)2+1x^2 + 4x + 4 + 1 = (x+2)^2 + 1.
  13. What is the integral of 1(x+1)2+2\frac{1}{(x+1)^2 + 2}?
    12tan⁡−1x+12+C\frac{1}{\sqrt{2}} \tan^{-1}\frac{x+1}{\sqrt{2}} + C. Use arctangent formula with a=2a = \sqrt{2}.
  14. Find the completed square form of x2+10x+25x^2 + 10x + 25.
    (x+5)2(x+5)^2. This is already a perfect square trinomial.
  15. What is the integral of 1(x+7)2\frac{1}{(x+7)^2}?
    −1x+7+C-\frac{1}{x+7} + C. Standard power rule for u−2u^{-2}
  16. Express x2+2x+2x^2 + 2x + 2 in completed square form.
    (x+1)2+1(x+1)^2 + 1. Add and subtract (22)2=1(\frac{2}{2})^2 = 1 to complete the square.
  17. What is the integral of 1(x+2)2+2\frac{1}{(x+2)^2 + 2}?
    12tan⁡−1x+22+C\frac{1}{\sqrt{2}} \tan^{-1}\frac{x+2}{\sqrt{2}} + C. Arctangent formula with a=2a = \sqrt{2}.
  18. What is the integral of 1(x+3)2+2\frac{1}{(x+3)^2 + 2}?
    12tan⁡−1x+32+C\frac{1}{\sqrt{2}} \tan^{-1}\frac{x+3}{\sqrt{2}} + C. Use the formula ∫1x2+a2dx=1atan⁡−1(xa)+C\int \frac{1}{x^2 + a^2} dx = \frac{1}{a} \tan^{-1}(\frac{x}{a}) + C.
  19. What is the integral of 1(x+2)2+4\frac{1}{(x+2)^2 + 4}?
    12tan⁡−1x+22+C\frac{1}{2} \tan^{-1}\frac{x+2}{2} + C. Use ∫1x2+a2dx\int \frac{1}{x^2 + a^2} dx formula with a=2a = 2.
  20. Use long division for x2+3x+2x+1\frac{x^2 + 3x + 2}{x + 1}. What is the quotient?
    x+2x + 2. Long division gives quotient and remainder.
  21. Perform long division on x2+5x+6x+1\frac{x^2 + 5x + 6}{x + 1}. What is the quotient?
    x+4x + 4. Polynomial long division of quadratic by linear.
  22. How do you handle x2+3x+5x+2\frac{x^2 + 3x + 5}{x + 2} using long division?
    Divide x2+3x+5x^2 + 3x + 5 by x+2x + 2. Degree of numerator > degree of denominator requires polynomial division first.
  23. Use long division for x3+6x2+11x+6x+3\frac{x^3 + 6x^2 + 11x + 6}{x + 3}. What is the quotient?
    x2+3x+2x^2 + 3x + 2. Divide cubic by linear using polynomial long division.
  24. What is the integral of 1(x+5)2\frac{1}{(x+5)^2}?
    −1x+5+C-\frac{1}{x+5} + C. Integral of u−2u^{-2} is −u−1+C-u^{-1} + C.
  25. What is the first step in completing the square for x2+10x+29x^2 + 10x + 29?
    Write as (x+5)2+4(x+5)^2 + 4. Take half the coefficient of xx: (102)2=25(\frac{10}{2})^2 = 25, then adjust.
  26. What is the first step when integrating x3+2x2+x+1x2+1\frac{x^3 + 2x^2 + x + 1}{x^2 + 1} using long division?
    Divide x3+2x2+x+1x^3 + 2x^2 + x + 1 by x2+1x^2 + 1. Use polynomial long division when the degree of numerator ≥ degree of denominator.
  27. What is the purpose of completing the square in integration?
    To simplify the integrand into a recognizable form. Transforms expressions into standard forms that match integration formulas.
  28. Find the completed square form of x2+2x+1x^2 + 2x + 1.
    (x+1)2(x+1)^2. Perfect square trinomial: (x+1)2(x+1)^2.
  29. Convert x2+8x+16x^2 + 8x + 16 into a completed square.
    (x+4)2(x+4)^2. This is already a perfect square trinomial.
  30. Convert x2+2x+5x^2 + 2x + 5 into completed square form.
    (x+1)2+4(x+1)^2 + 4. Complete the square: add/subtract (22)2=1(\frac{2}{2})^2 = 1.
  31. Identify the integral of 1x2+4x+13\frac{1}{x^2 + 4x + 13} after completing the square.
    Use 1(x+2)2+9\frac{1}{(x+2)^2 + 9} form. Complete the square: x2+4x+13=(x+2)2+9x^2 + 4x + 13 = (x+2)^2 + 9.
  32. What is the antiderivative of 1(x+2)2+9\frac{1}{(x+2)^2 + 9}?
    13tan⁡−1(x+23)+C\frac{1}{3} \tan^{-1} \left( \frac{x+2}{3} \right) + C. Use arctangent formula with a=3a = 3: 1atan⁡−1(xa)+C\frac{1}{a} \tan^{-1}(\frac{x}{a}) + C.
  33. What is the integral of 1(x+1)2+1\frac{1}{(x+1)^2 + 1}?
    tan⁡−1(x+1)+C\tan^{-1}(x+1) + C. Arctangent integral with a=1a = 1.
  34. Identify the completed square form of x2+6x+11x^2 + 6x + 11.
    (x+3)2+2(x + 3)^2 + 2. Take half the coefficient of xx, square it: (62)2=9(\frac{6}{2})^2 = 9, so add/subtract 9.
  35. Express x2+6x+10x^2 + 6x + 10 in completed square form.
    $ (x+3)2(x+3)^2 + 1 $. Complete the square: $ (x+3)2(x+3)^2 + 1 $ where 1=10−91 = 10 - 9.
  36. What is the completed square form of x2+4x+8x^2 + 4x + 8?
    (x+2)2+4(x+2)^2 + 4. Complete the square: (x+2)2+4(x+2)^2 + 4 where 4=8−44 = 8 - 4.
  37. Perform long division on x2+x+1x+1\frac{x^2 + x + 1}{x + 1}. What is the quotient?
    xx. Polynomial division of x2+x+1x^2 + x + 1 by x+1x + 1.
  38. What is the integral of 1(x+4)2\frac{1}{(x+4)^2}?
    −1x+4+C-\frac{1}{x+4} + C. Use the power rule: ∫u−2du=−u−1+C\int u^{-2} du = -u^{-1} + C.

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