Implicit Differentiation - AP Calculus AB

  1. Differentiate xy=1\frac{x}{y} = 1 with respect to xx.
    y−xdydxy2=0\frac{y - x\frac{dy}{dx}}{y^2} = 0. Apply quotient rule: ddx[xy]=y−xdydxy2\frac{d}{dx}[\frac{x}{y}] = \frac{y - x\frac{dy}{dx}}{y^2}.
  2. What does dydx\frac{dy}{dx} represent in implicit differentiation?
    The derivative of yy with respect to xx. It's the rate of change of yy with respect to xx.
  3. Differentiate x2−y2=4x^2 - y^2 = 4 using implicit differentiation.
    2x−2ydydx=02x - 2y\frac{dy}{dx} = 0. Apply power rule to both x2x^2 and y2y^2 terms.
  4. What is the first step in implicit differentiation?
    Differentiate both sides with respect to xx. This sets up the differentiation process.
  5. Find the derivative of xy=x+yxy = x + y using implicit differentiation.
    y+xdydx=1+dydxy + x\frac{dy}{dx} = 1 + \frac{dy}{dx}. Apply product rule to left side.
  6. Differentiate 3x2+4y2=123x^2 + 4y^2 = 12 with respect to xx.
    6x+8ydydx=06x + 8y\frac{dy}{dx} = 0. Apply power rule to each term.
  7. Differentiate x2y+y3=0x^2y + y^3 = 0 using implicit differentiation.
    2xy+x2dydx+3y2dydx=02xy + x^2\frac{dy}{dx} + 3y^2\frac{dy}{dx} = 0. Apply product rule to x2yx^2y and chain rule to y3y^3.
  8. Differentiate: x2+y2=1x^2 + y^2 = 1 with respect to xx.
    2x+2ydydx=02x + 2y\frac{dy}{dx} = 0. Apply power rule to each term, using chain rule for y2y^2.
  9. Find dydx\frac{dy}{dx} for y=x2y+xy = x^2y + x.
    dydx=2xy+x2dydx+1\frac{dy}{dx} = 2xy + x^2\frac{dy}{dx} + 1. Use product rule for x2yx^2y term.
  10. Differentiate: dydx\frac{dy}{dx} if x2+y2=r2x^2 + y^2 = r^2.
    2x+2ydydx=02x + 2y \frac{dy}{dx} = 0. Same as differentiating x2+y2=1x^2 + y^2 = 1 but with constant r2r^2.
  11. Differentiate x3+3xy+y3=0x^3 + 3xy + y^3 = 0 using implicit differentiation.
    3x2+3y+3xdydx+3y2dydx=03x^2 + 3y + 3x\frac{dy}{dx} + 3y^2\frac{dy}{dx} = 0. Apply chain rule to x3x^3 and y3y^3, product rule to 3xy3xy.
  12. Differentiate 2x2y=32x^2y = 3 using implicit differentiation.
    4xy+2x2dydx=04xy + 2x^2\frac{dy}{dx} = 0. Use product rule on 2x2y2x^2y.
  13. Differentiate x2+y2=9x^2 + y^2 = 9 using implicit differentiation.
    2x+2ydydx=02x + 2y\frac{dy}{dx} = 0. Same form as circle equation with radius 3.
  14. Differentiate x2+2xy+y2=16x^2 + 2xy + y^2 = 16 with respect to xx.
    2x+2y+2xdydx+2ydydx=02x + 2y + 2x\frac{dy}{dx} + 2y\frac{dy}{dx} = 0. This is (x+y)2=16(x+y)^2 = 16; use chain rule.
  15. What is the result of differentiating x+y=1x + y = 1 implicitly?
    1+dydx=01 + \frac{dy}{dx} = 0. Each term differentiates to its coefficient.
  16. Find dydx\frac{dy}{dx} for y3+xy=1y^3 + xy = 1.
    3y2dydx+y+xdydx=03y^2\frac{dy}{dx} + y + x\frac{dy}{dx} = 0. Apply chain rule to y3y^3 and product rule to xyxy.
  17. Differentiate xy2=4xy^2 = 4 with respect to xx.
    y2+2xydydx=0y^2 + 2xy\frac{dy}{dx} = 0. Apply product rule to xy2xy^2.
  18. Find the derivative of yy in 3x2+2xy−y3=03x^2 + 2xy - y^3 = 0.
    6x+2y+2xdydx−3y2dydx=06x + 2y + 2x\frac{dy}{dx} - 3y^2\frac{dy}{dx} = 0. Use product rule for 2xy2xy and chain rule for y3y^3.
  19. Which rule is applied when differentiating y2y^2 with respect to xx?
    The Chain Rule. Since yy depends on xx, we need dydx\frac{dy}{dx} when differentiating y2y^2.
  20. Differentiate x3+y3=6xyx^3 + y^3 = 6xy using implicit differentiation.
    3x2+3y2dydx=6y+6xdydx3x^2 + 3y^2\frac{dy}{dx} = 6y + 6x\frac{dy}{dx}. Use chain rule for y3y^3 and product rule for 6xy6xy.
  21. What is implicit differentiation?
    A technique to find derivatives of equations not solved for yy. Used when yy is not isolated on one side of the equation.
  22. Differentiate x3y=1\frac{x^3}{y} = 1 with respect to xx.
    3x2−x3dydxy2=03x^2 - \frac{x^3\frac{dy}{dx}}{y^2} = 0. Apply quotient rule to x3y\frac{x^3}{y}.
  23. What is the derivative of xy=1xy = 1 using implicit differentiation?
    xdydx+y=0x\frac{dy}{dx} + y = 0. Use product rule on xyxy.
  24. Find the derivative of x2+xy+y2=7x^2 + xy + y^2 = 7.
    2x+y+xdydx+2ydydx=02x + y + x\frac{dy}{dx} + 2y\frac{dy}{dx} = 0. Apply product rule to xyxy and power rule to other terms.
  25. Differentiate x2y2=4x^2y^2 = 4 with respect to xx.
    2xy2+2x2ydydx=02xy^2 + 2x^2y\frac{dy}{dx} = 0. Use product rule: ddx[x2y2]=2x(y2)+x2(2ydydx)\frac{d}{dx}[x^2y^2] = 2x(y^2) + x^2(2y\frac{dy}{dx}).
  26. Find dydx\frac{dy}{dx} for y2=x2+2y^2 = x^2 + 2.
    2ydydx=2x2y\frac{dy}{dx} = 2x. Apply power rule to y2y^2 using chain rule.
  27. Find the derivative of x2y+y2=10x^2y + y^2 = 10 using implicit differentiation.
    2xy+x2dydx+2ydydx=02xy + x^2\frac{dy}{dx} + 2y\frac{dy}{dx} = 0. Use product rule for x2yx^2y and power rule for y2y^2.
  28. Differentiate x+y=xyx + y = xy with respect to xx.
    1+dydx=y+xdydx1 + \frac{dy}{dx} = y + x\frac{dy}{dx}. Use product rule on right side xyxy.

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