Fundamental Theorem of Calculus: Definite Intervals - AP Calculus AB

  1. Determine ∫141x dx\int_1^4 \frac{1}{x}\,dx.
    ln⁡(4)\ln(4). Antiderivative of 1x\frac{1}{x} is ln⁡(x)\ln(x).
  2. Evaluate ∫04(3x2+2) dx\int_0^4 (3x^2 + 2)\,dx using the Fundamental Theorem.
    68. Use antiderivative x3+2xx^3 + 2x, evaluate at bounds 44 and 00.
  3. For F(x)=∫0x sin⁡(t) dtF(x) = \int_0^x \,\sin(t)\,dt, find F′(x)F'(x).
    sin⁡(x)\sin(x). By Part 2 of FTC, derivative equals the integrand.
  4. What is the result of ∫021 dx\int_0^2 1\,dx?
    2. Integral of constant 11 over interval length 22.
  5. What is a definite integral's geometric interpretation?
    Net area between the curve and the x-axis over [a,b][a, b]. Represents the signed area between curve and x-axis.
  6. For F(x)=∫0xet dtF(x) = \int_0^x e^t\,dt, find F′(x)F'(x).
    exe^x. By Part 2 of FTC, the derivative equals the integrand.
  7. What is the integral of f(x)=1/xf(x) = 1/x over [1,e][1, e]?
    1. Antiderivative of 1x\frac{1}{x} is ln⁡(x)\ln(x); ln⁡(e)−ln⁡(1)=1\ln(e) - \ln(1) = 1.
  8. What condition must a function ff satisfy for the Fundamental Theorem to apply?
    ff must be continuous on [a,b][a, b]. Continuity ensures the antiderivative exists and is differentiable.
  9. Find ∫04(x2−2) dx\int_0^4 (x^2 - 2)\,dx using the Fundamental Theorem.
    323\frac{32}{3}. Use antiderivative x33−2x\frac{x^3}{3} - 2x, evaluate at bounds.
  10. Define a proper antiderivative.
    A function F(x)F(x) whose derivative is f(x)f(x). An antiderivative is any function whose derivative gives f(x)f(x).
  11. Evaluate ∫03(5x−4) dx\int_0^3 (5x - 4)\,dx using the Fundamental Theorem.
    15. Use antiderivative 5x22−4x\frac{5x^2}{2} - 4x, evaluate at bounds.
  12. Determine ∫02x2 dx\int_0^2 x^2\,dx using an antiderivative.
    83\frac{8}{3}. Use antiderivative x33\frac{x^3}{3}, evaluate at bounds.
  13. State the Fundamental Theorem of Calculus, Part 1.
    If FF is an antiderivative of ff on [a,b][a,b], then ∫abf(x) dx=F(b)−F(a)\int_a^b f(x)\,dx = F(b) - F(a). This allows calculation of definite integrals using antiderivatives.
  14. Evaluate ∫−22(x3+2x) dx\int_{-2}^2 (x^3 + 2x)\,dx using symmetry properties.
    00. Both functions are odd, so integral over symmetric interval is zero.
  15. Find the derivative of F(x)=∫2xln⁡(t) dtF(x) = \int_2^x \ln(t)\,dt.
    ln⁡(x)\ln(x). By Part 2 of FTC, the derivative equals the integrand.
  16. Compute ∫−11x3 dx\int_{-1}^1 x^3\,dx using symmetry properties.
    0. Odd function over symmetric interval gives zero area.
  17. What is an antiderivative of f(x)=3x2f(x) = 3x^2?
    F(x)=x3+CF(x) = x^3 + C. Power rule: increase exponent by 1, divide by new exponent.
  18. Find the value of ∫0πcos⁡(x) dx\int_0^\pi \cos(x)\,dx.
    0. Antiderivative is sin⁡(x)\sin(x); sin⁡(π)−sin⁡(0)=0\sin(\pi) - \sin(0) = 0.
  19. Calculate ∫01(x3+1) dx\int_0^1 (x^3 + 1)\,dx using the Fundamental Theorem.
    54\frac{5}{4}. Use antiderivative x44+x\frac{x^4}{4} + x, evaluate at bounds.
  20. What is the definite integral of a constant cc over an interval [a,b][a, b]?
    c(b−a)c(b-a). A constant function integrates to constant times interval length.
  21. Find ∫0πsin⁡(x) dx\int_0^\pi \sin(x)\,dx using the Fundamental Theorem.
    2. Antiderivative is −cos⁡(x)-\cos(x); −cos⁡(π)−(−cos⁡(0))=2-\cos(\pi) - (-\cos(0)) = 2.
  22. Evaluate ∫03(x2+x+1) dx\int_0^3 (x^2 + x + 1)\,dx using the Fundamental Theorem.
    18. Use antiderivative x33+x22+x\frac{x^3}{3} + \frac{x^2}{2} + x, evaluate at bounds.
  23. Evaluate ∫01(4x3−x) dx\int_0^1 (4x^3 - x)\,dx using the Fundamental Theorem.
    34\frac{3}{4}. Use antiderivative x4−x22x^4 - \frac{x^2}{2}, evaluate at bounds.
  24. Evaluate ∫02(3x2−2x) dx\int_0^2 (3x^2 - 2x)\,dx using the Fundamental Theorem.
    4. Use antiderivative x3−x2x^3 - x^2, evaluate at bounds.
  25. What is the purpose of the definite integral?
    To find the net area under a curve. It represents the signed area between curve and x-axis.
  26. What is the result of a definite integral when the upper and lower limits are equal?
    0. When limits are equal, the interval has zero length.
  27. State the Fundamental Theorem of Calculus, Part 2.
    If ff is continuous on [a,b][a,b], then F(x)=∫axf(t) dtF(x) = \int_a^x f(t)\,dt is differentiable and F′(x)=f(x)F'(x) = f(x). Shows that differentiation and integration are inverse operations.
  28. Calculate ∫13(2x2−x) dx\int_1^3 (2x^2 - x)\,dx using the Fundamental Theorem.
    263\frac{26}{3}. Use antiderivative 2x33−x22\frac{2x^3}{3} - \frac{x^2}{2}, evaluate at bounds.
  29. What is the integral of f(x)=exf(x) = e^x over [0,1][0, 1]?
    e−1e - 1. Antiderivative of exe^x is exe^x; evaluate at bounds.
  30. What does the second part of the Fundamental Theorem allow us to compute?
    The derivative of an integral function. It gives the rate of change of the area function.
  31. What is the integral of f(x)=sin⁡(x)f(x) = \sin(x) over [0,π][0, \pi]?
    2. Antiderivative is −cos⁡(x)-\cos(x); −cos⁡(π)−(−cos⁡(0))=2-\cos(\pi) - (-\cos(0)) = 2.
  32. What does the Fundamental Theorem of Calculus connect?
    It connects differentiation and integration. They are inverse operations of each other.
  33. What is the integral of f(x)=cos⁡(x)f(x) = \cos(x) over [0,π][0, \pi]?
    0. Antiderivative is sin⁡(x)\sin(x); sin⁡(π)−sin⁡(0)=0\sin(\pi) - \sin(0) = 0.
  34. Find ∫01(x2+2x) dx\int_0^1 (x^2 + 2x)\,dx using an antiderivative.
    73\frac{7}{3}. Use antiderivative x33+x2\frac{x^3}{3} + x^2, evaluate at bounds.
  35. Find ∫02(4x3+x) dx\int_0^2 (4x^3 + x)\,dx using an antiderivative.
    18. Use antiderivative x4+x22x^4 + \frac{x^2}{2}, evaluate at bounds.
  36. Determine ∫13x2 dx\int_1^3 x^2\,dx using an antiderivative.
    26/326/3. Use antiderivative x33\frac{x^3}{3}, then evaluate at bounds.
  37. Determine ∫01(5x2−3x) dx\int_0^1 (5x^2 - 3x)\,dx using an antiderivative.
    13\frac{1}{3}. Use antiderivative 5x33−3x22\frac{5x^3}{3} - \frac{3x^2}{2}, evaluate at bounds.
  38. Evaluate ∫012x dx\int_0^1 2x\,dx using the Fundamental Theorem of Calculus.
    1. Find antiderivative x2x^2, then evaluate 12−02=11^2 - 0^2 = 1.
  39. What does it mean for a function F(x)F(x) to be differentiable?
    F(x)F(x) has a derivative at every point in its domain. The function has a well-defined derivative at each point.

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