Exploring Behaviors of Implicit Relations - AP Calculus AB

  1. Find dydx\frac{dy}{dx} for y=ln⁡(xy)y = \ln(xy) implicitly.
    dydx=1x+y\frac{dy}{dx} = \frac{1}{x + y}. From dydx=1xy(y+xdydx)\frac{dy}{dx} = \frac{1}{xy}(y + x\frac{dy}{dx}), solve for dydx\frac{dy}{dx}.
  2. What does dydx\frac{dy}{dx} represent in implicit differentiation?
    The derivative of yy with respect to xx. The rate of change of yy with respect to xx.
  3. Differentiate y2=x+x2yy^2 = x + x^2y implicitly.
    2ydydx=1+2xy+x2dydx2y \frac{dy}{dx} = 1 + 2xy + x^2 \frac{dy}{dx}. Product rule on right side, power rule on left.
  4. Differentiate x+y=exyx + y = e^{xy} implicitly.
    1+dydx=exy(y+xdydx)1 + \frac{dy}{dx} = e^{xy}(y + x \frac{dy}{dx}). Chain rule on exponential function on right side.
  5. Differentiate exy=x+ye^{xy} = x + y implicitly with respect to xx.
    exy(y+xdydx)=1+dydxe^{xy}(y + x \frac{dy}{dx}) = 1 + \frac{dy}{dx}. Chain rule on left, standard derivatives on right.
  6. Differentiate x3+y3=3xyx^3 + y^3 = 3xy implicitly.
    3x2+3y2dydx=3(y+xdydx)3x^2 + 3y^2 \frac{dy}{dx} = 3(y + x \frac{dy}{dx}). Apply product rule to right side.
  7. Identify the error: ddx(xy)=xdydx+y\frac{d}{dx}(xy) = x \frac{dy}{dx} + y.
    Correct: ddx(xy)=xdydx+ydxdx\frac{d}{dx}(xy) = x \frac{dy}{dx} + y \frac{dx}{dx}. Missing dxdx=1\frac{dx}{dx} = 1 in the product rule.
  8. Differentiate sin⁡(x+y)=y\sin(x + y) = y implicitly.
    cos⁡(x+y)(1+dydx)=dydx\cos(x + y)(1 + \frac{dy}{dx}) = \frac{dy}{dx}. Chain rule on sin⁡(x+y)\sin(x + y) gives cos⁡(x+y)(1+dydx)\cos(x + y)(1 + \frac{dy}{dx}).
  9. Differentiate x4+y4=16x^4 + y^4 = 16 implicitly.
    4x3+4y3dydx=04x^3 + 4y^3 \frac{dy}{dx} = 0. Apply power rule: 4x3+4y3dydx=04x^3 + 4y^3\frac{dy}{dx} = 0.
  10. Differentiate x=tan⁡(xy)x = \tan(xy) implicitly.
    1=sec⁡2(xy)(y+xdydx)1 = \sec^2(xy)(y + x \frac{dy}{dx}). Derivative of tan⁡\tan is sec⁡2\sec^2, apply chain rule.
  11. What is the implicit derivative of x3+y3=6xyx^3 + y^3 = 6xy?
    3x2+3y2dydx=6(y+xdydx)3x^2 + 3y^2 \frac{dy}{dx} = 6(y + x \frac{dy}{dx}). Apply product rule to right side: 6(y+xdydx)6(y + x\frac{dy}{dx}).
  12. What is the implicit derivative of y3+3x2y=12y^3 + 3x^2y = 12?
    3y2dydx+6xy+3x2dydx=03y^2 \frac{dy}{dx} + 6xy + 3x^2 \frac{dy}{dx} = 0. Apply chain rule to y3y^3 and product rule to 3x2y3x^2y.
  13. What is the implicit derivative of y=sin⁡(xy)y = \sin(xy)?
    dydx=cos⁡(xy)(y+xdydx)\frac{dy}{dx} = \cos(xy)(y + x \frac{dy}{dx}). Chain rule on sin⁡(xy)\sin(xy) equals dydx\frac{dy}{dx}.
  14. What is the implicit derivative of y=x+sin⁡(y)y = x + \sin(y)?
    dydx=1+cos⁡(y)dydx\frac{dy}{dx} = 1 + \cos(y) \frac{dy}{dx}. Chain rule on sin⁡(y)\sin(y) gives cos⁡(y)dydx\cos(y)\frac{dy}{dx}.
  15. What is the purpose of implicit differentiation?
    To find derivatives when not in explicit form. Enables differentiation of relations not solved for yy.
  16. What is implicit differentiation?
    Differentiating equations not solved for one variable in terms of others. Used when yy cannot be easily isolated.
  17. Differentiate x2+y2=1x^2 + y^2 = 1 implicitly with respect to xx.
    2x+2ydydx=02x + 2y \frac{dy}{dx} = 0. Apply power rule to both terms, treat yy as function of xx.
  18. Differentiate x2−y2=1x^2 - y^2 = 1 implicitly.
    2x−2ydydx=02x - 2y \frac{dy}{dx} = 0. Difference of squares: coefficients have opposite signs.
  19. State the Chain Rule for implicit differentiation.
    Differentiate outer, multiply by derivative of inner. Essential for composite functions involving yy.
  20. Differentiate tan⁡(xy)=x\tan(xy) = x implicitly.
    sec⁡2(xy)(y+xdydx)=1\sec^2(xy)(y + x \frac{dy}{dx}) = 1. Chain rule: derivative of tan⁡\tan is sec⁡2\sec^2.
  21. Find dydx\frac{dy}{dx} for xy+y=3xxy + y = 3x.
    dydx=3−yx+1\frac{dy}{dx} = \frac{3 - y}{x + 1}. Factor out terms with yy: y(x+1)=3xy(x + 1) = 3x.
  22. Find dydx\frac{dy}{dx} for cos⁡(xy)=x\cos(xy) = x.
    dydx=ysin⁡(xy)−1xsin⁡(xy)\frac{dy}{dx} = \frac{y\sin(xy) - 1}{x\sin(xy)}. Chain rule gives −sin⁡(xy)(y+xdydx)=1-\sin(xy)(y + x\frac{dy}{dx}) = 1, solve.
  23. Differentiate x2+y2=25x^2 + y^2 = 25 implicitly.
    2x+2ydydx=02x + 2y \frac{dy}{dx} = 0. Same as x2+y2=1x^2 + y^2 = 1 with different radius.
  24. Differentiate y=x2+tan⁡(y)y = x^2 + \tan(y) implicitly.
    dydx=2x+sec⁡2(y)dydx\frac{dy}{dx} = 2x + \sec^2(y) \frac{dy}{dx}. Chain rule on tan⁡(y)\tan(y) gives sec⁡2(y)dydx\sec^2(y)\frac{dy}{dx}.
  25. Find dydx\frac{dy}{dx} for xy=ln⁡(x)xy = \ln(x).
    dydx=1−yx\frac{dy}{dx} = \frac{1 - y}{x}. From product rule: y+xdydx=1xy + x\frac{dy}{dx} = \frac{1}{x}.
  26. Find dydx\frac{dy}{dx} for xy=4xy = 4 using implicit differentiation.
    dydx=−yx\frac{dy}{dx} = -\frac{y}{x}. Use product rule: y+xdydx=0y + x\frac{dy}{dx} = 0, solve for dydx\frac{dy}{dx}.
  27. What is the implicit differential of x2+xy=10x^2 + xy = 10?
    2x+y+xdydx=02x + y + x \frac{dy}{dx} = 0. Product rule on xyxy term.
  28. Find dydx\frac{dy}{dx} for x2−xy+y2=7x^2 - xy + y^2 = 7.
    dydx=y−2x2y−x\frac{dy}{dx} = \frac{y - 2x}{2y - x}. Differentiate each term, collect dydx\frac{dy}{dx} terms, solve.
  29. Find dydx\frac{dy}{dx} for y=cos⁡(xy)y = \cos(xy) implicitly.
    dydx=−sin⁡(xy)(y+xdydx)\frac{dy}{dx} = -\sin(xy)(y + x \frac{dy}{dx}). Chain rule: dydx=−sin⁡(xy)(y+xdydx)\frac{dy}{dx} = -\sin(xy)(y + x\frac{dy}{dx}).
  30. Differentiate x=cos⁡(xy)x = \cos(xy) implicitly.
    1=−sin⁡(xy)(y+xdydx)1 = -\sin(xy)(y + x \frac{dy}{dx}). Derivative of cos⁡\cos is −sin⁡-\sin, apply chain rule.
  31. Differentiate x2y2=1x^2y^2 = 1 implicitly.
    2xy2+2x2ydydx=02xy^2 + 2x^2y \frac{dy}{dx} = 0. Product rule: 2xy2+2x2ydydx=02xy^2 + 2x^2y\frac{dy}{dx} = 0.
  32. Find dydx\frac{dy}{dx} for x2+y2=4x^2 + y^2 = 4.
    dydx=−xy\frac{dy}{dx} = -\frac{x}{y}. Circle equation: slope is negative reciprocal of radius slope.
  33. What is the implicit differentiation of x2y+y2=1x^2y + y^2 = 1?
    2xy+x2dydx+2ydydx=02xy + x^2 \frac{dy}{dx} + 2y \frac{dy}{dx} = 0. Product rule on x2yx^2y, power rule on y2y^2.

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