Determining Limits Using the Squeeze Theorem - AP Calculus AB

  1. Find lim⁡x→0x2cos⁡(1x)\lim_{x \to 0} x^2 \cos(\frac{1}{x}) using the Squeeze Theorem.
    00. Since −x2≤x2cos⁡(1x)≤x2-x^2 \leq x^2 \cos(\frac{1}{x}) \leq x^2 and both bounds approach 00.
  2. Find lim⁡x→0x2sin⁡(1x)\lim_{x \to 0} x^2 \sin(\frac{1}{x}) using the Squeeze Theorem.
    00. Since −∣x2∣≤x2sin⁡(1x)≤∣x2∣-|x^2| \leq x^2 \sin(\frac{1}{x}) \leq |x^2| and both bounds approach 00.
  3. Determine lim⁡x→0x4sin⁡(1x)\lim_{x \to 0} x^4 \sin(\frac{1}{x}) using the Squeeze Theorem.
    00. Since −x4≤x4sin⁡(1x)≤x4-x^4 \leq x^4 \sin(\frac{1}{x}) \leq x^4 and both bounds approach 00.
  4. What is the limit of xsin⁡(1x)x \sin(\frac{1}{x}) as x→0x \to 0?
    00. Bounded between −∣x∣-|x| and ∣x∣|x|, both approaching 00.
  5. What is lim⁡x→0xsin⁡(2x)\lim_{x \to 0} x \sin(\frac{2}{x})?
    00. Bounded between −∣x∣-|x| and ∣x∣|x|, both approaching 00.
  6. Determine lim⁡x→0x5sin⁡(1x6)\lim_{x \to 0} x^5 \sin(\frac{1}{x^6}) using the Squeeze Theorem.
    00. Since −x5≤x5sin⁡(1x6)≤x5-x^5 \leq x^5 \sin(\frac{1}{x^6}) \leq x^5 and both bounds approach 00.
  7. What is lim⁡x→0xcos⁡(1x3)\lim_{x \to 0} x \cos(\frac{1}{x^3})?
    00. Bounded between $ -|x| $ and $ |x| $, both approaching 00.
  8. What must the limits of g(x)g(x) and h(x)h(x) equal for the Squeeze Theorem to apply?
    Both must equal LL. Required for the theorem to conclude f(x)f(x) has the same limit.
  9. What is lim⁡x→0x3sin⁡(x2)\lim_{x \to 0} x^3 \sin(x^2) using the Squeeze Theorem?
    00. Since ∣x3sin⁡(x2)∣≤x3|x^3 \sin(x^2)| \leq x^3 and x3→0x^3 \to 0.
  10. Find lim⁡x→0x3sin⁡(1x5)\lim_{x \to 0} x^3 \sin(\frac{1}{x^5}) using the Squeeze Theorem.
    00. Since −x3≤x3sin⁡(1x5)≤x3-x^3 \leq x^3 \sin(\frac{1}{x^5}) \leq x^3 and both bounds approach 00.
  11. What inequality must f(x)f(x) satisfy in the Squeeze Theorem?
    g(x)≤f(x)≤h(x)g(x) \leq f(x) \leq h(x). This defines the sandwich relationship between the three functions.
  12. What is the Squeeze Theorem used for in calculus?
    To determine the limit of a function. Forces a function between two bounds that approach the same limit.
  13. What is lim⁡x→0x4cos⁡(1x5)\lim_{x \to 0} x^4 \cos(\frac{1}{x^5})?
    00. Since −x4≤x4cos⁡(1x5)≤x4-x^4 \leq x^4 \cos(\frac{1}{x^5}) \leq x^4 and both bounds approach 00.
  14. Is lim⁡x→0x2sin⁡(1x)\lim_{x \to 0} x^2 \sin(\frac{1}{x}) finite?
    Yes, it is 00. The limit equals 00, which is a finite value.
  15. What is the limit of x2sin⁡(1x2)x^2 \sin(\frac{1}{x^2}) as x→0x \to 0?
    00. Bounded between −x2-x^2 and x2x^2, both approaching 00.
  16. What should g(x)g(x) and h(x)h(x) approach for lim⁡x→cf(x)\lim_{x \to c}f(x) to exist?
    The same limit LL. This ensures the squeezed function approaches the unique limit.
  17. Is lim⁡x→0x2sin⁡(x3)\lim_{x \to 0} x^2 \sin(x^3) zero?
    Yes. Since ∣x2sin⁡(x3)∣≤x2|x^2 \sin(x^3)| \leq x^2 and x2→0x^2 \to 0.
  18. Determine lim⁡x→0x4cos⁡(1x)\lim_{x \to 0} x^4 \cos(\frac{1}{x}) using the Squeeze Theorem.
    00. Since −x4≤x4cos⁡(1x)≤x4-x^4 \leq x^4 \cos(\frac{1}{x}) \leq x^4 and both bounds approach 00.
  19. Find lim⁡x→0x2sin⁡(1x3)\lim_{x \to 0} x^2 \sin(\frac{1}{x^3}) using the Squeeze Theorem.
    00. Since −x2≤x2sin⁡(1x3)≤x2-x^2 \leq x^2 \sin(\frac{1}{x^3}) \leq x^2 and both bounds approach 00.
  20. Determine lim⁡x→0x3cos⁡(1x3)\lim_{x \to 0} x^3 \cos(\frac{1}{x^3}) using the Squeeze Theorem.
    00. Since −x3≤x3cos⁡(1x3)≤x3-x^3 \leq x^3 \cos(\frac{1}{x^3}) \leq x^3 and both bounds approach 00.
  21. What is lim⁡x→0x2sin⁡x\lim_{x \to 0} x^2 \sin x?
    00. Since ∣x2sin⁡x∣≤x2|x^2 \sin x| \leq x^2 and x2→0x^2 \to 0.
  22. Determine lim⁡x→0x2cos⁡(x2)\lim_{x \to 0} x^2 \cos(x^2) using the Squeeze Theorem.
    00. Since ∣x2cos⁡(x2)∣≤x2|x^2 \cos(x^2)| \leq x^2 and x2→0x^2 \to 0.
  23. What is the limit lim⁡x→0x2sin⁡(1x4)\lim_{x \to 0} x^2 \sin(\frac{1}{x^4})?
    00. Since −x2≤x2sin⁡(1x4)≤x2-x^2 \leq x^2 \sin(\frac{1}{x^4}) \leq x^2 and both bounds approach 00.
  24. Find lim⁡x→0x3sin⁡(1x)\lim_{x \to 0} x^3 \sin(\frac{1}{x}) using the Squeeze Theorem.
    00. Since −∣x3∣≤x3sin⁡(1x)≤∣x3∣-|x^3| \leq x^3 \sin(\frac{1}{x}) \leq |x^3| and both bounds approach 00.
  25. Determine lim⁡x→0x3cos⁡(1x2)\lim_{x \to 0} x^3 \cos(\frac{1}{x^2}) using the Squeeze Theorem.
    00. Since −x3≤x3cos⁡(1x2)≤x3-x^3 \leq x^3 \cos(\frac{1}{x^2}) \leq x^3 and both bounds approach 00.
  26. Is lim⁡x→0xsin⁡x\lim_{x \to 0} x \sin x equal to zero?
    Yes. Since ∣xsin⁡x∣≤∣x∣|x \sin x| \leq |x| and ∣x∣→0|x| \to 0.
  27. Find lim⁡x→0x5sin⁡(1x4)\lim_{x \to 0} x^5 \sin(\frac{1}{x^4}) using the Squeeze Theorem.
    00. Since −x5≤x5sin⁡(1x4)≤x5-x^5 \leq x^5 \sin(\frac{1}{x^4}) \leq x^5 and both bounds approach 00.
  28. Find lim⁡x→0x2cos⁡x\lim_{x \to 0} x^2 \cos x using the Squeeze Theorem.
    00. Since ∣x2cos⁡x∣≤x2|x^2 \cos x| \leq x^2 and x2→0x^2 \to 0.
  29. Find lim⁡x→0xsin⁡(1x2)\lim_{x \to 0} x \sin(\frac{1}{x^2}) using the Squeeze Theorem.
    00. Since −∣x∣≤xsin⁡(1x2)≤∣x∣-|x| \leq x \sin(\frac{1}{x^2}) \leq |x| and both bounds approach 00.
  30. Find lim⁡x→0x3sin⁡(2x)\lim_{x \to 0} x^3 \sin(\frac{2}{x}) using the Squeeze Theorem.
    00. Since −x3≤x3sin⁡(2x)≤x3-x^3 \leq x^3 \sin(\frac{2}{x}) \leq x^3 and both bounds approach 00.
  31. Find lim⁡x→∞sin⁡xx\lim_{x \to \infty} \frac{\sin x}{x} using the Squeeze Theorem.
    00. Since −1x≤sin⁡xx≤1x-\frac{1}{x} \leq \frac{\sin x}{x} \leq \frac{1}{x} and both bounds approach 00.
  32. Determine lim⁡x→0x3cos⁡(x4)\lim_{x \to 0} x^3 \cos(x^4) using the Squeeze Theorem.
    00. Since ∣x3cos⁡(x4)∣≤x3|x^3 \cos(x^4)| \leq x^3 and x3→0x^3 \to 0.
  33. What is the result of lim⁡x→0xcos⁡(1x)\lim_{x \to 0} x \cos(\frac{1}{x})?
    00. Bounded between −∣x∣-|x| and ∣x∣|x|, both approaching 00.
  34. What is the limit lim⁡x→0x2sin⁡(x2)\lim_{x \to 0} x^2 \sin(x^2)?
    00. Since ∣x2sin⁡(x2)∣≤x2|x^2 \sin(x^2)| \leq x^2 and x2→0x^2 \to 0.
  35. State the Squeeze Theorem in terms of f(x)f(x), g(x)g(x), h(x)h(x).
    If g(x)≤f(x)≤h(x)g(x) \leq f(x) \leq h(x) and lim⁡x→cg(x)=lim⁡x→ch(x)=L\lim_{x \to c}g(x) = \lim_{x \to c}h(x) = L, then lim⁡x→cf(x)=L\lim_{x \to c}f(x) = L. The fundamental statement of the Squeeze Theorem with three functions.
  36. Find lim⁡x→0x2cos⁡(2x)\lim_{x \to 0} x^2 \cos(\frac{2}{x}) using the Squeeze Theorem.
    00. Since −x2≤x2cos⁡(2x)≤x2-x^2 \leq x^2 \cos(\frac{2}{x}) \leq x^2 and both bounds approach 00.
  37. What is lim⁡x→0x4sin⁡(1x3)\lim_{x \to 0} x^4 \sin(\frac{1}{x^3})?
    00. Since −x4≤x4sin⁡(1x3)≤x4-x^4 \leq x^4 \sin(\frac{1}{x^3}) \leq x^4 and both bounds approach 00.
  38. Can the Squeeze Theorem be used if lim⁡x→cg(x)≠lim⁡x→ch(x)\lim_{x \to c}g(x) \neq \lim_{x \to c}h(x)?
    No. The bounding functions must approach the same value for the theorem to work.
  39. Identify the conditions necessary for the Squeeze Theorem to apply.
    Functions g(x)g(x), f(x)f(x), h(x)h(x) must satisfy g(x)≤f(x)≤h(x)g(x) \leq f(x) \leq h(x) near cc. The inequality must hold in a neighborhood around cc.

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