Connecting Infinite Limits and Vertical Asymptotes - AP Calculus AB

  1. Find the vertical asymptotes of f(x)=xx2−9f(x) = \frac{x}{x^2 - 9}.
    Vertical asymptotes at x=3x = 3 and x=−3x = -3. Factor denominator: x2−9=(x−3)(x+3)=0x^2 - 9 = (x-3)(x+3) = 0.
  2. What happens if limx→a−f(x)=−infinity\text{lim}_{x \to a^-} f(x) = -\text{infinity}?
    f(x)f(x) has a vertical asymptote at x=ax = a. Left-sided negative limit confirms vertical asymptote.
  3. Identify the vertical asymptote in f(x)=1x−2f(x) = \frac{1}{x-2}.
    Vertical asymptote at x=2x = 2. Denominator equals zero when x−2=0x - 2 = 0.
  4. Identify the asymptote of f(x)=2x+3f(x) = \frac{2}{x+3}.
    Vertical asymptote at x=−3x = -3. Denominator equals zero when x+3=0x + 3 = 0.
  5. What is the condition for a vertical asymptote at x=ax = a in f(x)=p(x)q(x)f(x) = \frac{p(x)}{q(x)}?
    q(a)=0q(a) = 0 and p(a)≠0p(a) \neq 0. Denominator zero with non-zero numerator creates asymptote.
  6. Identify the vertical asymptotes of f(x)=2x2−9x+18f(x) = \frac{2}{x^2 - 9x + 18}.
    Vertical asymptotes at x=3x = 3 and x=6x = 6. Factor x2−9x+18=(x−3)(x−6)=0x^2 - 9x + 18 = (x-3)(x-6) = 0.
  7. Determine the vertical asymptote in g(x)=x3x2−x−6g(x) = \frac{x^3}{x^2 - x - 6}.
    Vertical asymptotes at x=3x = 3 and x=−2x = -2. Factor x2−x−6=(x−3)(x+2)=0x^2 - x - 6 = (x-3)(x+2) = 0.
  8. Find the vertical asymptotes in g(x)=x2x2+4x+4g(x) = \frac{x^2}{x^2 + 4x + 4}.
    Vertical asymptote at x=−2x = -2. Denominator (x+2)2=0(x+2)^2 = 0 only when x=−2x = -2.
  9. What does limx→a+f(x)=infinity\text{lim}_{x \to a^+} f(x) = \text{infinity} tell about f(x)f(x)?
    f(x)f(x) approaches infinity at x=ax = a from the right. Describes function behavior approaching from the right.
  10. Find the vertical asymptote of f(x)=xx2−x−2f(x) = \frac{x}{x^2 - x - 2}.
    Vertical asymptotes at x=2x = 2 and x=−1x = -1. Factor x2−x−2=(x−2)(x+1)=0x^2 - x - 2 = (x-2)(x+1) = 0.
  11. What does limx→af(x)=infinity\text{lim}_{x \to a} f(x) = \text{infinity} imply about f(x)f(x)?
    f(x)f(x) has a vertical asymptote at x=ax = a. An infinite limit indicates unbounded growth near that point.
  12. What does limx→a+f(x)=−infinity\text{lim}_{x \to a^+} f(x) = -\text{infinity} indicate?
    f(x)f(x) has a vertical asymptote at x=ax = a. Right-sided negative infinite limit confirms asymptote.
  13. Find the vertical asymptotes of f(x)=xx2−16f(x) = \frac{x}{x^2 - 16}.
    Vertical asymptotes at x=4x = 4 and x=−4x = -4. Factor denominator: x2−16=(x−4)(x+4)=0x^2 - 16 = (x-4)(x+4) = 0.
  14. Determine the vertical asymptote of f(x)=1(x−1)(x+2)f(x) = \frac{1}{(x-1)(x+2)}.
    Vertical asymptotes at x=1x = 1 and x=−2x = -2. Each factor in denominator creates a separate asymptote.
  15. State the condition for a vertical asymptote in f(x)=p(x)q(x)f(x) = \frac{p(x)}{q(x)}.
    q(x)=0q(x) = 0 at x=ax = a and p(x)≠0p(x) \neq 0. Standard condition for rational function vertical asymptotes.
  16. Find the vertical asymptote of g(x)=1x2−1g(x) = \frac{1}{x^2 - 1}.
    Vertical asymptotes at x=1x = 1 and x=−1x = -1. Factor denominator: x2−1=(x−1)(x+1)=0x^2 - 1 = (x-1)(x+1) = 0.
  17. Find the vertical asymptotes of f(x)=3xx2+2x−3f(x) = \frac{3x}{x^2 + 2x - 3}.
    Vertical asymptotes at x=1x = 1 and x=−3x = -3. Factor x2+2x−3=(x−1)(x+3)=0x^2 + 2x - 3 = (x-1)(x+3) = 0.
  18. What is the behavior of f(x)f(x) if limx→a−f(x)=infinity\text{lim}_{x \to a^-} f(x) = \text{infinity}?
    f(x)f(x) approaches infinity at x=ax = a from the left. Left-sided limit describes approach from negative direction.
  19. Identify the vertical asymptotes of f(x)=2xx2−4f(x) = \frac{2x}{x^2 - 4}.
    Vertical asymptotes at x=2x = 2 and x=−2x = -2. Factor denominator: x2−4=(x−2)(x+2)=0x^2 - 4 = (x-2)(x+2) = 0.
  20. Determine the asymptote of f(x)=3xx2−2xf(x) = \frac{3x}{x^2 - 2x}.
    Vertical asymptote at x=0x = 0 and x=2x = 2. Factor out xx: denominator x(x−2)=0x(x-2) = 0.
  21. What does it mean if limx→a−f(x)=infinity\text{lim}_{x \to a^-} f(x) = \text{infinity}?
    f(x)f(x) has a vertical asymptote at x=ax = a. Left-sided infinite limit confirms vertical asymptote exists.
  22. What does limx→af(x)=−infinity\text{lim}_{x \to a} f(x) = -\text{infinity} imply about f(x)f(x)?
    f(x)f(x) has a vertical asymptote at x=ax = a. Negative infinite limit still indicates vertical asymptote.
  23. Calculate the vertical asymptotes of f(x)=x2+1x−5f(x) = \frac{x^2 + 1}{x - 5}.
    Vertical asymptote at x=5x = 5. Denominator equals zero only when x−5=0x - 5 = 0.
  24. What is the behavior of f(x)f(x) near a vertical asymptote at x=ax = a?
    f(x)f(x) approaches infinity or negative infinity. Function values become unbounded near asymptotes.
  25. Identify the vertical asymptotes of f(x)=x2x2−4f(x) = \frac{x^2}{x^2 - 4}.
    Vertical asymptotes at x=2x = 2 and x=−2x = -2. Factor denominator: (x−2)(x+2)=0(x-2)(x+2) = 0 gives both roots.
  26. What does limx→a+f(x)=−infinity\text{lim}_{x \to a^+} f(x) = -\text{infinity} tell us?
    f(x)f(x) has a vertical asymptote at x=ax = a. Right-sided negative limit confirms vertical asymptote.
  27. What does limx→a−f(x)=−infinity\text{lim}_{x \to a^-} f(x) = -\text{infinity} indicate?
    f(x)f(x) has a vertical asymptote at x=ax = a. Left-sided infinite limit confirms vertical asymptote exists.
  28. Determine the vertical asymptotes of f(x)=x2+2x2−4x+4f(x) = \frac{x^2 + 2}{x^2 - 4x + 4}.
    Vertical asymptote at x=2x = 2. Denominator (x−2)2=0(x-2)^2 = 0 only when x=2x = 2.
  29. What is the behavior of f(x)f(x) near a vertical asymptote?
    f(x)f(x) approaches infinity or negative infinity. Function values grow without bound near the asymptote.
  30. Identify the asymptotes of f(x)=2xx2−4x+4f(x) = \frac{2x}{x^2 - 4x + 4}.
    Vertical asymptote at x=2x = 2. Denominator x2−4x+4=(x−2)2=0x^2 - 4x + 4 = (x-2)^2 = 0 at x=2x = 2.
  31. What does limx→af(x)=infinity\text{lim}_{x \to a} f(x) = \text{infinity} imply for f(x)f(x)?
    f(x)f(x) has a vertical asymptote at x=ax = a. Two-sided infinite limit confirms vertical asymptote.
  32. What does it mean if limx→a+f(x)=infinity\text{lim}_{x \to a^+} f(x) = \text{infinity}?
    f(x)f(x) has a vertical asymptote at x=ax = a. Right-sided infinite limit confirms vertical asymptote exists.
  33. Identify the asymptotes of f(x)=1x2−4x+3f(x) = \frac{1}{x^2 - 4x + 3}.
    Vertical asymptotes at x=1x = 1 and x=3x = 3. Factor x2−4x+3=(x−1)(x−3)=0x^2 - 4x + 3 = (x-1)(x-3) = 0.

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