Candidates Test - AP Calculus AB
- Find at for .
- . Substitution shows is a root of the function.
- What is the Candidates Test used for in calculus?
- Determining the absolute extrema on a closed interval. Finds global max/min on closed intervals by testing all candidate points.
- What are the critical points of ?
- Critical points: . Set and solve for .
- Identify the type of interval required for the Candidates Test.
- A closed interval . Ensures function is continuous and extrema exist by EVT.
- Find at for .
- . Direct substitution of into the function.
- If changes sign at , what is ?
- A critical point. Sign changes in derivative indicate critical points.
- State the first step in the Candidates Test.
- Find the derivative of the function. Need derivative to locate critical points where extrema may occur.
- Which function value determines the absolute maximum?
- The largest value among evaluated points. Highest function output among all tested candidates.
- Find for .
- . This is a perfect square: at .
- Find the derivative of .
- . Apply power rule: , etc.
- What is a critical point?
- Where or is undefined. Points where derivative equals zero or doesn't exist.
- Evaluate for critical points.
- Critical point: . Set and solve for .
- Determine the endpoints for the interval .
- Endpoints are and . These are the boundary values of the given interval.
- Evaluate at endpoints for on .
- , . Substitute boundary values into the function.
- What is the final step in the Candidates Test?
- Compare function values at critical points and endpoints. Determines which candidate gives the absolute maximum/minimum.
- State the condition for a point to be a candidate for extrema.
- Point must be a critical point or endpoint. Only these points can produce absolute extrema on closed intervals.
- Find at for .
- . Substitute into the function.
- Evaluate for critical points.
- Critical points: . Solve to get .
- Identify the formula for finding critical points.
- Set and solve for . Standard method to find where slope equals zero.
- Evaluate for critical points.
- Critical point: . Set and solve for .
- Which values are evaluated in the Candidates Test?
- Endpoints and critical points of the interval. All possible locations where absolute extrema can occur.
- Find at for .
- . Direct substitution shows this is a perfect square.
- Determine at for .
- . Direct substitution of into the cubic function.
- Evaluate at endpoints for on .
- , . Substitute endpoint values into .
- What is the derivative of ?
- . Apply power rule to each term.
- What is at for on ?
- Not applicable; is not in . Point outside domain cannot be evaluated.
- What must be determined after finding the derivative in the Candidates Test?
- Critical points where the derivative is zero or undefined. These are locations where extrema can occur on the interval.
- Which function value determines the absolute minimum?
- The smallest value among evaluated points. Lowest function output among all tested candidates.
- What are endpoints in the context of the Candidates Test?
- The boundary values of the closed interval. The left and right limits of the domain interval.