Area Between Curves: Functions of x - AP Calculus AB

  1. Find the intersection points of y=x2y = x^2 and y=4y = 4.
    x=−2,x=2x = -2, x = 2. Solve x2=4x^2 = 4 to get x=±2x = \pm 2.
  2. What is the integral for the area between y=x2y = x^2 and y=−xy = -x from x=0x = 0 to x=1x = 1?
    ∫01[x2−(−x)] dx\int_{0}^{1} [x^2 - (-x)] \, dx. Parabola is above line y=−xy = -x on this interval.
  3. Calculate the area between y=x+1y = x + 1 and y=2xy = 2x from x=0x = 0 to x=1x = 1.
    12\frac{1}{2}. Compute ∫01[(x+1)−2x]dx=∫01(1−x)dx\int_0^1 [(x+1) - 2x]dx = \int_0^1 (1-x)dx.
  4. What is the first step to find the area between two curves f(x)f(x) and g(x)g(x)?
    Identify intersection points of f(x)f(x) and g(x)g(x). Intersection points determine the limits of integration.
  5. Find the intersection points of y=2xy = 2x and y=x2y = x^2.
    x=0,x=2x = 0, x = 2. Solve 2x=x22x = x^2 to find where curves intersect.
  6. Calculate the area between y=4y = 4 and y=x2y = x^2 from x=−2x = -2 to x=2x = 2.
    323\frac{32}{3}. Evaluate ∫−22(4−x2)dx\int_{-2}^2 (4-x^2)dx using symmetry.
  7. Identify the lower function for f(x)=x2+1f(x) = x^2 + 1 and g(x)=x+2g(x) = x + 2 on [0,1][0, 1].
    f(x)=x2+1f(x) = x^2 + 1. Shifted parabola is below line on this interval.
  8. Identify the upper function for f(x)=x3f(x) = x^3 and g(x)=xg(x) = x on [−1,1][-1, 1].
    g(x)=xg(x) = x. Line is above cubic on symmetric interval around origin.
  9. Calculate the area between y=2xy = 2x and y=x2y = x^2 from x=0x = 0 to x=2x = 2.
    83\frac{8}{3}. Line y=2xy=2x is above parabola on [0,2][0,2].
  10. Determine the integral for the area between y=x2y = x^2 and y=4y = 4 from x=−2x = -2 to x=2x = 2.
    ∫−22[4−x2] dx\int_{-2}^{2} [4 - x^2] \, dx. Horizontal line is above parabola from −2-2 to 22.
  11. Which function is lower: y=x3y = x^3 or y=x2y = x^2 on [0,1][0, 1]?
    y=x3y = x^3. Cubic grows slower than quadratic on [0,1][0,1].
  12. Determine the area between y=x3y = x^3 and y=xy = x from x=0x = 0 to x=1x = 1.
    14\frac{1}{4}. Line y=xy=x is above cubic y=x3y=x^3 on [0,1][0,1].
  13. What is the integral to find the area between y=x2y = x^2 and y=4y = 4 from x=0x = 0 to x=2x = 2?
    ∫02[4−x2] dx\int_{0}^{2} [4 - x^2] \, dx. Horizontal line is above parabola on this interval.
  14. Which function is lower: y=x3y = x^3 or y=xy = x on [−1,0][-1, 0]?
    y=x3y = x^3. Cubic function is negative while line is positive on [−1,0][-1,0].
  15. State the condition for f(x)f(x) and g(x)g(x) to find area between curves.
    f(x)≥g(x)f(x) \geq g(x) over interval [a,b][a, b]. Upper function must be greater than or equal to lower function.
  16. How do you express the area between y=3xy = 3x and y=x2y = x^2 on [0,3][0, 3]?
    ∫03[3x−x2] dx\int_{0}^{3} [3x - x^2] \, dx. Line y=3xy=3x is above parabola on [0,3][0,3].
  17. Calculate the area between y=x2−1y = x^2 - 1 and y=2x−1y = 2x - 1 from x=0x = 0 to x=1x = 1.
    16\frac{1}{6}. Line y=2x−1y=2x-1 is above shifted parabola on [0,1][0,1].
  18. Identify the upper function for f(x)=x2+1f(x) = x^2 + 1 and g(x)=x2g(x) = x^2 on [0,1][0, 1].
    f(x)=x2+1f(x) = x^2 + 1. Shifted parabola is above original parabola.
  19. What is the integral setup for the area between y=3xy = 3x and y=x2y = x^2 from x=0x = 0 to x=3x = 3?
    ∫03[3x−x2] dx\int_{0}^{3} [3x - x^2] \, dx. Same setup as previous identical problem.
  20. Identify the upper function for f(x)=x2f(x) = x^2 and g(x)=x+2g(x) = x + 2 on [0,3][0, 3].
    g(x)=x+2g(x) = x + 2. Linear function is above parabola in this interval.
  21. Find the area between y=x2y = x^2 and y=xy = x from x=0x = 0 to x=1x = 1.
    16\frac{1}{6}. Evaluate ∫01(x−x2)dx\int_0^1 (x-x^2)dx for line above parabola.
  22. What is the integral for the area between y=x2y = x^2 and y=xy = x from x=0x = 0 to x=1x = 1?
    ∫01[x−x2] dx\int_{0}^{1} [x - x^2] \, dx. Line is above parabola on unit interval.
  23. What is the integral to find the area between y=3xy = 3x and y=x2y = x^2 from x=0x = 0 to x=3x = 3?
    ∫03[3x−x2] dx\int_{0}^{3} [3x - x^2] \, dx. Line is above parabola on the given interval.
  24. What is the purpose of finding intersection points of f(x)f(x) and g(x)g(x)?
    To determine limits of integration. Intersection points become the integration bounds.
  25. Find the area between y=2xy = 2x and y=x2y = x^2 from x=0x = 0 to x=2x = 2.
    83\frac{8}{3}. Same calculation as previous identical problem.
  26. What is the area formula for two curves f(x)f(x) and g(x)g(x) over [a,b][a, b]?
    ∫ab∣f(x)−g(x)∣ dx\int_{a}^{b} |f(x) - g(x)| \, dx. Absolute value ensures positive area regardless of function order.
  27. What is the general formula for finding the area between two curves f(x)f(x) and g(x)g(x)?
    ∫ab[f(x)−g(x)] dx\int_{a}^{b} [f(x) - g(x)] \, dx. Integral of upper function minus lower function over the interval.
  28. How do you find the limits of integration for two curves f(x)f(x) and g(x)g(x)?
    Solve f(x)=g(x)f(x) = g(x). Set functions equal and solve for intersection points.
  29. Identify the upper function for f(x)=2xf(x) = 2x and g(x)=x2g(x) = x^2 on [0,2][0, 2].
    f(x)=2xf(x) = 2x. Line has greater slope than parabola on [0,2][0,2].
  30. Calculate the area between y=x2+1y = x^2 + 1 and y=1y = 1 from x=−1x = -1 to x=1x = 1.
    83\frac{8}{3}. Same calculation as before for shifted parabola.
  31. Identify the lower function for f(x)=x2f(x) = x^2 and g(x)=x+2g(x) = x + 2 on [2,3][2, 3].
    f(x)=x2f(x) = x^2. Parabola is below linear function on this interval.
  32. What does ∫ab[f(x)−g(x)] dx\int_{a}^{b} [f(x) - g(x)] \, dx represent geometrically?
    Area between f(x)f(x) and g(x)g(x) on [a,b][a, b]. The definite integral represents signed area between curves.
  33. What is the geometric interpretation of ∫ab[g(x)−f(x)] dx\int_{a}^{b} [g(x) - f(x)] \, dx?
    Area between g(x)g(x) and f(x)f(x) on [a,b][a, b]. When g(x)≥f(x)g(x) \geq f(x), integral gives area between curves.

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