AP Biology • Cells

Membrane Transport

How cells selectively move molecules across the plasma membrane to maintain homeostasis and drive essential processes.

AP Biology illustration with DNA, a microscope, and a leaf
Inside this lesson 10 sections 5 questions 8 figures

SECTION 1

Historical Context & Motivation

The question of how substances enter and exit living cells has occupied biologists for well over a century. Early microscopists observed that cells could swell and shrink when exposed to different solutions, but the mechanism behind this selective permeability remained elusive. The gradual recognition that cells are bounded by a semipermeable membrane—a structure that permits some molecules to pass while excluding others—launched decades of research that converged on the modern understanding of membrane transport. This history reveals not just how scientific models evolve, but also why membrane transport is so fundamental: without it, cells could not regulate their internal environment, generate energy, or communicate with their surroundings.

1877 • Osmosis Described Quantitatively

Wilhelm Pfeffer constructed a semipermeable membrane from copper ferrocyanide and measured osmotic pressure quantitatively, establishing that water movement across membranes follows predictable physical laws.

1925 • Lipid Bilayer Proposed

Gorter and Grendel extracted lipids from red blood cells and spread them as a monolayer, finding roughly twice the surface area of the cell. They concluded that the cell membrane consists of a lipid bilayer.

1957 • Active Transport Characterized

Jens Christian Skou identified the Na⁺/K⁺-ATPase in crab nerve cells, providing the first molecular evidence for an energy-consuming pump that moves ions against their concentration gradient.

1972 • Fluid Mosaic Model

Singer and Nicolson proposed the fluid mosaic model, depicting the membrane as a dynamic structure with integral and peripheral proteins floating in a fluid phospholipid bilayer.

2003 • Aquaporin Structure Resolved

Peter Agre shared the Nobel Prize in Chemistry for discovering aquaporins, channel proteins that dramatically accelerate water transport across membranes. Their atomic structure revealed how channels achieve specificity.

These milestones converge on a central question that the AP Biology curriculum addresses directly: How do cells exploit the physical chemistry of membranes to control what enters and exits? Understanding the answer requires distinguishing between passive processes—driven by thermodynamic gradients—and active processes that require cellular energy input, a distinction that pervades every level of biological organization from individual enzyme kinetics to organ-level physiology.

SECTION 2

Core Principles of Membrane Transport

Membrane transport can be organized around a small set of foundational principles that distinguish the major categories of molecular movement. Every transport event depends on the physicochemical properties of the solute, the structure of the phospholipid bilayer, and the available energy sources. The plasma membrane's selective permeability arises because its hydrophobic interior excludes charged and large polar molecules, while small nonpolar molecules (O₂, CO₂) and water pass through with relative ease. Transport proteins embedded in the bilayer provide pathways for everything the lipid core rejects.

1

Passive Transport

Movement of molecules down their concentration (or electrochemical) gradient. No metabolic energy is required because the process is thermodynamically favorable (ΔG < 0). Includes simple diffusion, facilitated diffusion, and osmosis.
2

Active Transport

Movement of molecules against their gradient, requiring energy—usually from ATP hydrolysis (primary) or an existing ion gradient (secondary/co-transport). Essential for maintaining steep gradients like the Na⁺/K⁺ balance.
3

Bulk Transport

Large particles and macromolecules that cannot cross through proteins are moved via membrane-enclosed vesicles. Endocytosis brings material in; exocytosis secretes material out. Both require ATP.
4

Electrochemical Gradient

For ions, transport depends on both the concentration gradient and the electrical potential across the membrane. The combined driving force is the electrochemical gradient, which determines net ion movement direction and magnitude.
✦

KEY TAKEAWAY

Think of the cell membrane like a guarded border crossing. Small, familiar travelers (nonpolar molecules) walk through unimpeded—this is simple diffusion. Most travelers, however, need to show credentials and use a specific gate (channel or carrier protein)—facilitated diffusion. Some essential goods must be hauled uphill against economic gravity, requiring energy expenditure—active transport. Finally, oversized cargo arrives in shipping containers that merge with the border wall itself—bulk transport via vesicles.

SECTION 3

Visual Overview of Membrane Transport

Overview of Membrane Transport MechanismsEXTRACELLULARINTRACELLULARphospholipid headsO₂ / CO₂SimpleDiffusion(passive)IonsChannelProtein(facilitated)GlucoseCarrierProtein(facilitated)ATP3 Na⁺ out2 K⁺ inNa⁺/K⁺ Pump(primary active)ParticlesEndocytosis(Bulk)(active)NO ENERGY──────────────────────────────▶ATP REQUIRED
This diagram illustrates five major mechanisms of membrane transport arranged from left (passive, no energy) to right (active, ATP-dependent). The violet bands represent the phospholipid bilayer. Small nonpolar molecules pass directly through (simple diffusion), while ions and polar solutes require channel or carrier proteins (facilitated diffusion). The Na⁺/K⁺ pump exemplifies primary active transport, and endocytosis represents bulk transport via vesicle formation.

The diagram above captures the essential logic of membrane transport classification. On the far left, simple diffusion allows small, nonpolar molecules like O₂ and CO₂ to pass directly through the hydrophobic core of the bilayer without any protein assistance. Moving rightward, channel proteins provide hydrophilic tunnels for ions such as Na⁺, K⁺, and Cl⁻, while carrier proteins undergo conformational changes to shuttle larger polar molecules like glucose across the membrane. Both of these facilitated diffusion mechanisms are still passive—they follow the concentration gradient. The Na⁺/K⁺ pump (shown in pink) represents primary active transport, directly hydrolyzing ATP to move 3 Na⁺ out and 2 K⁺ in per cycle, generating an electrochemical gradient. Finally, endocytosis on the far right engulfs extracellular particles in membrane-derived vesicles—a form of bulk transport that also requires energy.

SECTION 4

Quantitative Framework & Mechanisms

While the AP Biology exam does not require complex mathematical derivations of transport equations, a quantitative understanding of the key relationships helps you predict the direction and rate of molecular movement. The fundamental driving force for passive transport is the concentration gradient, formalized in Fick's law of diffusion. For charged species, the Nernst equation and the concept of an electrochemical gradient become essential. Additionally, understanding osmolarity and water potential allows you to predict the direction of water flow in biological and experimental contexts.

FICK'S FIRST LAW (SIMPLIFIED)

J=−P×A×(C2−C1)J = −P × A × (C₂ − C₁)

Where J is the flux (amount per time), P is the permeability coefficient (related to diffusion coefficient and membrane thickness), A is the membrane surface area, and (C₂ − C₁) is the concentration difference across the membrane. The negative sign indicates net movement from high to low concentration.

WATER POTENTIAL

Ψ=Ψs+ΨpΨ = Ψₛ + Ψₚ

Water potential (Ψ) equals the sum of solute potential (Ψₛ) and pressure potential (Ψₚ). Solute potential is calculated as Ψₛ = −iCRT, where i = ionization constant, C = molar concentration, R = pressure constant (0.0831 L·bar/mol·K), and T = temperature in Kelvin. Water moves from high Ψ to low Ψ.

NA⁺/K⁺-ATPase STOICHIOMETRY

ATP+3Na+(in)+2K+(out)→ADP+Pi+3Na+(out)+2K+(in)ATP + 3 Na⁺(in) + 2 K⁺(out) → ADP + Pᵢ + 3 Na⁺(out) + 2 K⁺(in)

Each cycle of the sodium-potassium pump hydrolyzes one ATP to move 3 Na⁺ out and 2 K⁺ in. Because 3 positive charges exit and only 2 return, the pump is electrogenic—it contributes to the negative resting membrane potential.

💡

AP Exam Tip

The water potential equation (Ψ = Ψₛ + Ψₚ) appears frequently on the AP Biology exam, especially in free-response questions involving plant cells or dialysis tubing experiments. Remember: water always moves toward the more negative water potential, and for an open beaker, Ψₚ = 0.

SECTION 5

Detailed Classification of Transport Types

A detailed breakdown of transport types is essential for the AP exam, which frequently tests whether students can identify specific mechanisms and predict outcomes under different conditions. The classification below distinguishes mechanisms by their energy requirements, the molecular players involved, and the biological contexts where each is most relevant.

Classification of Membrane TransportMembrane TransportPassive (No ATP)Active (ATP Required)Simple DiffusionOsmosisFacilitated Diff.Primary ActiveBulk TransportChannel ProteinsCarrier ProteinsEndocytosisExocytosisSimple Diffusion• O₂, CO₂, N₂, steroid hormones• No protein needed• Rate ∝ concentration gradient• No saturation kineticsNonpolar, small molecules onlyFacilitated Diffusion• Glucose, amino acids, ions• Requires channel or carrier• Exhibits saturation (Vmax)• Specific to molecule shapeStill passive — follows gradientActive Transport• Na⁺/K⁺-ATPase, H⁺ pump, Ca²⁺ pump• Moves against gradient• Primary: directly uses ATP• Secondary: uses ion gradient (symport / antiport)Electrogenic pumps → membranepotential (≈ −70 mV in neurons)
A hierarchical flowchart showing the classification of membrane transport into passive and active categories, with further subdivision into specific mechanisms. The detail boxes at the bottom summarize key features of simple diffusion, facilitated diffusion, and active transport.
FeatureSimple DiffusionFacilitated DiffusionActive Transport
Energy sourceNone (ΔG < 0)None (ΔG < 0)ATP or ion gradient
Protein required?NoYes (channel or carrier)Yes (pump)
DirectionDown gradientDown gradientAgainst gradient
SaturabilityNo (linear increase)Yes (Vmax reached)Yes (Vmax reached)
SpecificityLow (size & polarity)High (substrate-specific)High (substrate-specific)
ExamplesO₂, CO₂, ethanolGlucose (GLUT1), K⁺ leak channelsNa⁺/K⁺-ATPase, H⁺/sucrose symport

Comparison of the three major categories of solute transport across biological membranes

A conceptual membrane has higher sodium outside and lower sodium in the cytosol. A violet pump moves three sodium out and two potassium in per ATP. A separate gold symporter brings one sodium and one glucose inward, using the gradient. Protein forms and their juxtaposition are schematic.In this conceptual membrane, the Na+/K+ ATPase uses one ATP to move three Na+ out and two K+ in, maintaining a sodium electrochemical gradient. A separate symporter uses that gradient to bring Na+ and glucose inward; the 1:1 ratio is a selected teaching model and varies among transporters. The cutaways do not represent constitutively open pores: both transport cycles and the protein shapes are schematic. The juxtaposition does not assert a shared membrane face in a particular tissue.

SECTION 6

Worked Example: Water Potential Calculation

Water potential problems appear frequently on the AP Biology exam, particularly in free-response questions involving plant cells or dialysis tubing experiments. The following example walks through a complete calculation, demonstrating how to determine the direction of water movement between two compartments.

Predicting Direction of Osmosis in a Plant Cell

  1. 1

    Step 1 — Identify Given Values

    A plant cell with a solute concentration of 0.3 M sucrose (a nonionizing solute, so i = 1) is placed in a beaker of 0.1 M sucrose solution at 22 °C (295 K). The cell has a turgor pressure (Ψₚ) of 0.5 bar. The beaker is open, so its Ψₚ = 0. We need to determine the direction of net water movement.
    Ccell = 0.3 M, Cbeaker = 0.1 M, T = 295 K, Ψₚ(cell) = 0.5 bar, Ψₚ(beaker) = 0
  2. 2

    Step 2 — Calculate Solute Potential (Ψₛ) for Each Compartment

    Using the formula Ψₛ = −iCRT, where i = 1 (sucrose does not ionize), R = 0.0831 L·bar/(mol·K), and T = 295 K. For the cell: Ψₛ = −(1)(0.3)(0.0831)(295) = −7.35 bar. For the beaker: Ψₛ = −(1)(0.1)(0.0831)(295) = −2.45 bar.
    Ψₛ(cell) = −7.35 bar; Ψₛ(beaker) = −2.45 bar
  3. 3

    Step 3 — Calculate Total Water Potential (Ψ)

    For the cell: Ψ = Ψₛ + Ψₚ = −7.35 + 0.5 = −6.85 bar. For the beaker: Ψ = Ψₛ + Ψₚ = −2.45 + 0 = −2.45 bar.
    Ψ(cell) = −6.85 bar; Ψ(beaker) = −2.45 bar
  4. 4

    Step 4 — Determine Direction of Water Movement

    Water moves from regions of higher (less negative) water potential to regions of lower (more negative) water potential. The beaker has Ψ = −2.45 bar, which is higher than the cell's Ψ = −6.85 bar. Therefore, water will flow from the beaker into the cell. This makes biological sense: the cell has more solute (is hypertonic relative to the beaker), so water enters by osmosis. As water enters, turgor pressure increases until Ψ(cell) = Ψ(beaker), at which point equilibrium is reached and net water movement stops.
    Net water movement: beaker → cell (into the cell)

A plant-cell schematic at 295K has total water potential minus 6.854 bar, below the bath at minus 2.451 bar. The arrow points into the cell despite its positive 0.5 bar pressure.Turgor raises water potential and can oppose solute effects; these stated initial conditions still favor water entry. Values are an explicitly stated teaching model.

SECTION 7

Tonicity, Cell Responses & Common Confusions

One of the most testable areas on the AP exam involves predicting cellular responses in different osmotic environments. The concept of tonicity—the ability of an extracellular solution to cause water to move into or out of a cell—depends on the relative concentrations of nonpenetrating solutes on each side of the membrane. Critically, tonicity is distinct from osmolarity, because solutes that freely cross the membrane (like urea) contribute to osmolarity but not to tonicity, since they equilibrate and cannot sustain an osmotic gradient.

EnvironmentAnimal Cell ResponsePlant Cell Response
Hypotonic (less solute outside)Water enters → cell swells → may lyse (cytolysis)Water enters → turgor pressure increases → cell becomes turgid (ideal state)
Isotonic (equal solute)No net water movement → cell maintains normal shapeNo net water movement → cell is flaccid (limp)
Hypertonic (more solute outside)Water exits → cell shrinks (crenation)Water exits → plasma membrane pulls from cell wall (plasmolysis)

Cellular responses to different osmotic environments

⚠

COMMON EXAM PITFALL

Students often confuse the direction of solute movement with the direction of water movement. Remember: water follows its own gradient—it moves toward the region with lower (more negative) water potential, which is the region with more solute. An analogy from engineering: imagine two reservoirs connected by a pipe. Water flows downhill—from higher water potential to lower water potential—regardless of what is dissolved in it. The solute itself doesn't 'pull' water; rather, solutes lower the free energy of water on their side, creating the gradient.

Another frequently tested distinction involves primary versus secondary active transport. Primary active transport directly couples ATP hydrolysis to solute movement (e.g., the Na⁺/K⁺-ATPase). Secondary active transport (co-transport) uses the electrochemical gradient established by a primary pump to drive another solute against its gradient. For example, the Na⁺/glucose symporter in intestinal epithelial cells exploits the Na⁺ gradient created by the Na⁺/K⁺-ATPase to import glucose—a classic example of energy coupling across two transport events.

Plant wall is thick and distinct from inner membrane; large central vacuole and peripheral cytoplasm visible. Animal cell has flexible boundary and no wall. Separate exact panel: Paired plant states retain the same wall while the inner membrane is pressed outward or retracted; animal membrane has no surrounding wall.For nonpenetrating solutes, a plant wall limits expansion as water enters. Water loss retracts the protoplast from the wall during plasmolysis; animal cells lack this rigid wall.

Wall support changes the response. For nonpenetrating solutes, a plant wall limits expansion as water enters. Water loss retracts the protoplast from the wall during plasmolysis; animal cells lack this rigid wall.For nonpenetrating solutes, a plant wall limits expansion as water enters. Water loss retracts the protoplast from the wall during plasmolysis; animal cells lack this rigid wall.

SECTION 8

Connections to Signaling, Energetics & Disease

Membrane transport does not exist in isolation—it intersects with virtually every major topic in AP Biology. The proton motive force generated by the electron transport chain in mitochondria is itself an electrochemical gradient: protons (H⁺) are pumped across the inner mitochondrial membrane by complexes I, III, and IV, and their flow back through ATP synthase drives oxidative phosphorylation. Similarly, in chloroplasts, the thylakoid membrane maintains a steep H⁺ gradient that powers photosynthetic ATP synthesis. Understanding membrane transport therefore provides the mechanistic foundation for cellular energetics.

AP Biology TopicConnection to Membrane Transport
Cell SignalingLigand-gated ion channels open in response to neurotransmitter binding, enabling rapid signal transduction in neurons. The resting potential maintained by the Na⁺/K⁺-ATPase is prerequisite for action potentials.
Cellular RespirationChemiosmosis in the mitochondrial inner membrane: H⁺ ions pumped by ETC complexes flow down their gradient through ATP synthase, coupling transport to phosphorylation.
PhotosynthesisThe thylakoid lumen accumulates H⁺ as water is split and electrons move through photosystems. This gradient drives ATP synthase in the chloroplast.
Immune SystemPhagocytosis (a form of endocytosis) allows macrophages to engulf pathogens. Receptor-mediated endocytosis enables cells to internalize specific molecules like LDL cholesterol.
Cystic FibrosisMutations in the CFTR gene disrupt a Cl⁻ channel protein, leading to thick mucus accumulation. This is a direct example of how a single transport protein defect causes systemic disease.

How membrane transport connects to other AP Biology topics

Looking forward, upper-division courses in cell biology and biophysics treat membrane transport with mathematical rigor through the Goldman equation (which extends the Nernst equation to multiple ions), patch-clamp electrophysiology (which measures current through individual ion channels), and structural biology approaches that reveal the three-dimensional conformational changes of transporters at atomic resolution. The foundational principles covered here—gradient-driven movement, protein specificity, energy coupling, and electrochemical gradients—remain the conceptual backbone of all those advanced treatments.

SECTION 9

Practice Problems

Question 1: CONCEPTUAL

A researcher adds a metabolic poison that blocks all ATP production in a cell. Which of the following transport processes would continue to function normally?
  • A. Na⁺/K⁺-ATPase pumping sodium out of the cell
  • B. Facilitated diffusion of glucose through GLUT1 transporters
  • C. Exocytosis of neurotransmitter vesicles
  • D. Phagocytosis of a bacterial cell
Show answer (B)
B is correct. Facilitated diffusion through GLUT1 is a passive process that relies on the concentration gradient, not ATP. As long as a glucose gradient exists across the membrane, transport will continue. A is incorrect because the Na⁺/K⁺-ATPase is a primary active transporter that directly hydrolyzes ATP. C is incorrect because exocytosis requires ATP-dependent vesicle fusion with the plasma membrane. D is incorrect because phagocytosis is a form of bulk endocytosis that requires ATP for cytoskeletal rearrangement and membrane remodeling.

Question 2: BASIC CALCULATION

A cell with a solute potential (Ψₛ) of −4.0 bar and a pressure potential (Ψₚ) of 2.0 bar is placed in pure water at 25 °C. What is the water potential of the cell?
  • A. −6.0 bar
  • B. −4.0 bar
  • C. −2.0 bar
  • D. 0.0 bar
Show answer (C)
C is correct. Water potential Ψ = Ψₛ + Ψₚ = (−4.0) + (2.0) = −2.0 bar. A is incorrect because −6.0 bar would result from subtracting (rather than adding) Ψₚ from Ψₛ. B is incorrect because it ignores the positive pressure potential entirely. D is incorrect because 0.0 bar is the water potential of pure water (the surrounding environment), not the cell. Since the cell's Ψ (−2.0 bar) is lower than the surrounding pure water's Ψ (0.0 bar), water will move into the cell.

Question 3: INTERMEDIATE

A scientist observes that the rate of glucose uptake into erythrocytes increases as extracellular glucose concentration rises, but eventually plateaus at high concentrations. When a structurally similar sugar, galactose, is added to the medium, glucose uptake decreases. Which combination of transport characteristics is best supported by these observations?
  • A. Simple diffusion with competitive inhibition
  • B. Facilitated diffusion through a carrier protein that exhibits saturation and competitive inhibition
  • C. Primary active transport that is inhibited by galactose binding to the pump
  • D. Channel-mediated diffusion with allosteric regulation by galactose
Show answer (B)
B is correct. The saturation kinetics (rate plateaus at high concentration) indicate a protein-mediated process with a finite number of binding sites. The fact that galactose—a structurally similar molecule—reduces glucose uptake indicates competitive inhibition at the same binding site. Together, these are hallmarks of facilitated diffusion via a carrier protein (GLUT1 in erythrocytes). A is incorrect because simple diffusion does not saturate and does not involve a specific binding site that could be subject to competitive inhibition. Simple diffusion depends solely on the concentration gradient and membrane permeability. C is incorrect because glucose uptake into erythrocytes follows the concentration gradient and does not require ATP. Primary active transport uses ATP hydrolysis to move solutes against their concentration gradient, which is not indicated by the data described. D is incorrect because channel proteins form aqueous pores and do not typically exhibit the saturation kinetics or competitive substrate interactions characteristic of carrier-mediated transport. Channels allow rapid passive flow and lack the conformational binding site needed for competitive inhibition by a structurally similar molecule.

Question 4: APPLIED

4 pts
A student hypothesizes that increasing temperature will increase the rate of osmosis across a semipermeable dialysis membrane. Design an experiment to test this hypothesis. In your response: (a) Identify the independent variable, dependent variable, and at least two controlled variables. (b) Describe the experimental setup, including a control group. (c) Predict the expected results and provide a biological explanation for why temperature would affect osmosis rate. (d) Describe one potential source of error and how it could be minimized.
Show answer
Rubric (4 points): Point 1 — Variables correctly identified (1 pt): Independent variable: temperature of the water bath (e.g., 10 °C, 20 °C, 30 °C, 40 °C). Dependent variable: rate of osmosis, measured as change in mass (or volume) of the dialysis bag per unit time. Controlled variables: concentration of sucrose solution inside the bag, volume of solution in the bag, type and size of dialysis tubing, external solution concentration, duration of each trial. Point 2 — Experimental setup with control (1 pt): Fill identical dialysis bags with the same volume and concentration of sucrose solution. Seal each bag, record initial mass, and place each bag into a beaker of distilled water maintained at a different temperature (water baths). Include a room-temperature group (e.g., 20 °C) as a baseline control. After a set time interval (e.g., 30 minutes), remove bags, blot dry, and reweigh. Multiple replicates (≥3 per temperature) should be performed. Point 3 — Prediction with biological justification (1 pt): As temperature increases, the rate of osmosis should increase, as reflected by a greater mass gain per unit time. Higher temperature increases the kinetic energy of water molecules, increasing their rate of movement through the membrane pores. This relationship is consistent with Fick's law, where the diffusion coefficient (and thus permeability, P) increases with temperature. Point 4 — Error identification and mitigation (1 pt): A potential source of error is inconsistent blotting of dialysis bags before weighing, which could lead to variable amounts of surface water being included in the mass measurement. This can be minimized by using a standardized blotting protocol (e.g., rolling each bag on filter paper three times with consistent pressure) and by having the same person blot all bags.

Question 5: CRITICAL THINKING

4 pts
The table below shows the percent change in mass of potato cores placed in sucrose solutions of varying concentrations for 24 hours at 22 °C. Sucrose (M): 0.0, 0.2, 0.4, 0.6, 0.8, 1.0 % Mass Change: +18.0, +8.5, +1.2, −5.8, −12.3, −17.6 (a) At what approximate molar concentration of sucrose is the potato tissue isotonic to the surrounding solution? Explain your reasoning. (b) Calculate the solute potential (Ψₛ) of the potato cells at the isotonic point. Assume i = 1 for sucrose, R = 0.0831 L·bar/(mol·K), and T = 295 K. (c) If these potato cores were from a freshwater plant instead, explain how the results at 0.0 M sucrose might differ and why. (d) A student claims that the negative percent mass change at 0.8 M is caused by active transport of water out of the cells. Evaluate this claim.
Show answer
Rubric (4 points): Point 1 — Isotonic concentration identified (1 pt): The isotonic concentration is approximately 0.4 M sucrose. At this concentration, the percent mass change is closest to zero (+1.2%), indicating that the water potential of the potato cells is approximately equal to the water potential of the 0.4 M sucrose solution, so there is no net water movement. Interpolating between 0.4 M (+1.2%) and 0.6 M (−5.8%), the precise isotonic point is approximately 0.42–0.43 M. Point 2 — Solute potential calculation (1 pt): Using Ψₛ = −iCRT = −(1)(0.4)(0.0831)(295) = −9.81 bar (approximately −9.8 bar). At the isotonic point in an open system, the potato cells have Ψₚ ≈ 0 (cells are flaccid, no turgor), so Ψ = Ψₛ + 0 = −9.8 bar. The external solution also has Ψ ≈ −9.8 bar (Ψₚ = 0 in open beaker), confirming equilibrium. Point 3 — Plant cell comparison at 0.0 M (1 pt): A freshwater aquatic plant cell placed in pure water (0.0 M) would show less mass gain than the potato core. Plant cells possess a rigid cell wall, so as water enters by osmosis, turgor pressure (Ψₚ) builds rapidly, increasing the cell's total water potential until it equals that of the surroundings (Ψ = 0 bar). This limits further water entry. Potato tissue, while having cell walls, is cut into cores that may have damaged cells at the surface, allowing more water uptake. A fully intact freshwater plant cell would reach equilibrium faster due to high turgor resistance. Point 4 — Evaluating the student's claim (1 pt): The claim is incorrect. Water does not undergo active transport in cells. The mass loss at 0.8 M is fully explained by osmosis—a passive process. The 0.8 M sucrose solution has a much more negative water potential than the cell interior, so water moves out of the cells along its water potential gradient (from high Ψ inside the cell to low Ψ in the hypertonic solution). No energy expenditure is required for this movement.

SUMMARY

Membrane Transport — Key Concepts Review

Summary

Membrane transport encompasses all mechanisms by which molecules cross the phospholipid bilayer. Passive transport (simple diffusion, facilitated diffusion, and osmosis) moves substances down their concentration or electrochemical gradient without energy input. Facilitated diffusion requires channel or carrier proteins and exhibits saturation kinetics and substrate specificity, distinguishing it from simple diffusion. Water potential (Ψ = Ψₛ + Ψₚ) predicts the direction of osmosis: water moves from higher to lower Ψ. Tonicity describes a solution's effect on cell volume and determines whether cells undergo lysis, crenation, turgidity, or plasmolysis.

Active transport moves substances against their gradient and requires energy. Primary active transport (e.g., Na⁺/K⁺-ATPase) directly hydrolyzes ATP, while secondary active transport (co-transport) harnesses an existing ion gradient. Bulk transport via endocytosis and exocytosis moves large particles in membrane-bound vesicles. These mechanisms connect to chemiosmosis in cellular respiration and photosynthesis, cell signaling via ion channels, and disease states such as cystic fibrosis caused by defective transport proteins.

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