Using Conjugates with Complex Numbers - Algebra 2

  1. What is 41−3i\frac{4}{1-3i} written as a+bia+bi?
    25+65i\frac{2}{5}+\frac{6}{5}i. Multiply by conjugate 1+3i1+3i: 4(1+3i)(1−3i)(1+3i)=4+12i10\frac{4(1+3i)}{(1-3i)(1+3i)}=\frac{4+12i}{10}
  2. What is ∣3+4i1−2i∣\left|\frac{3+4i}{1-2i}\right|?
    5\sqrt{5}. Use ∣zw∣=∣z∣∣w∣|\frac{z}{w}|=\frac{|z|}{|w|}: ∣3+4i∣∣1−2i∣=55=5\frac{|3+4i|}{|1-2i|}=\frac{5}{\sqrt{5}}=\sqrt{5}
  3. State the formula for the modulus of z=a+biz=a+bi.
    ∣z∣=a2+b2|z|=\sqrt{a^2+b^2}. Distance from origin in the complex plane.
  4. State the quotient formula for a+bic+di\frac{a+bi}{c+di} using a conjugate in the denominator.
    a+bic+di=(a+bi)(c−di)c2+d2\frac{a+bi}{c+di}=\frac{(a+bi)(c-di)}{c^2+d^2}. Multiply numerator and denominator by the conjugate of the denominator.
  5. What is 2−2i2+2i\frac{2-2i}{2+2i} written as a+bia+bi?
    −i-i. Factor and simplify: 2(1−i)2(1+i)=1−i1+i=−i\frac{2(1-i)}{2(1+i)}=\frac{1-i}{1+i}=-i
  6. What is i1+i\frac{i}{1+i} written as a+bia+bi?
    12+12i\frac{1}{2}+\frac{1}{2}i. Multiply by conjugate 1−i1-i: i(1−i)(1+i)(1−i)=i+12\frac{i(1-i)}{(1+i)(1-i)}=\frac{i+1}{2}
  7. What is ∣−9i∣|-9i|?
    99. For pure imaginary numbers, ∣bi∣=∣b∣|bi|=|b|.
  8. What is the complex conjugate of z=7−3iz=7-3i?
    7+3i7+3i. Change the sign of the imaginary part from negative to positive.
  9. What is ∣−8+6i∣|-8+6i|?
    1010. (−8)2+62=100=10\sqrt{(-8)^2+6^2}=\sqrt{100}=10
  10. What is ∣z‾∣|\overline{z}| in terms of ∣z∣|z|?
    ∣z‾∣=∣z∣|\overline{z}|=|z|. Taking the conjugate doesn't change the modulus.
  11. What is (2−5i)(2+5i)(2-5i)(2+5i)?
    2929. (a+bi)(a−bi)=a2−b2i2=a2+b2=4+25=29(a+bi)(a-bi)=a^2-b^2i^2=a^2+b^2=4+25=29
  12. What is 12+i\frac{1}{2+i} written as a+bia+bi?
    25−15i\frac{2}{5}-\frac{1}{5}i. Multiply by conjugate 2−i2-i: 1(2−i)(2+i)(2−i)=2−i5\frac{1(2-i)}{(2+i)(2-i)}=\frac{2-i}{5}
  13. What is 3−4i2+i\frac{3-4i}{2+i} written as a+bia+bi?
    25−115i\frac{2}{5}-\frac{11}{5}i. Multiply by conjugate 2−i2-i: (3−4i)(2−i)(2+i)(2−i)=2−11i5\frac{(3-4i)(2-i)}{(2+i)(2-i)}=\frac{2-11i}{5}
  14. What is ∣3+4i∣|3+4i|?
    55. 32+42=25=5\sqrt{3^2+4^2}=\sqrt{25}=5
  15. What is 13−2i\frac{1}{3-2i} written as a+bia+bi?
    313+213i\frac{3}{13}+\frac{2}{13}i. Multiply by conjugate 3+2i3+2i: 1(3+2i)(3−2i)(3+2i)=3+2i13\frac{1(3+2i)}{(3-2i)(3+2i)}=\frac{3+2i}{13}
  16. State the property of conjugation for products: zw‾=?\overline{zw}=?
    zw‾=z‾ w‾\overline{zw}=\overline{z}\,\overline{w}. The conjugate distributes over multiplication.
  17. State the modulus product rule: ∣zw∣=?|zw|=?
    ∣zw∣=∣z∣∣w∣|zw|=|z||w|. The modulus of a product equals the product of moduli.
  18. What is (a+bi)(a−bi)(a+bi)(a-bi) written in terms of aa and bb?
    a2+b2a^2+b^2. Using the difference of squares pattern with i2=−1i^2=-1.
  19. State the value of zz‾\frac{z}{\overline{z}} for z=2+iz=2+i written as a+bia+bi.
    35+45i\frac{3}{5}+\frac{4}{5}i. zz‾=2+i2−i=3+4i5\frac{z}{\overline{z}}=\frac{2+i}{2-i}=\frac{3+4i}{5} after rationalizing.
  20. Find ∣z∣|z| if zz‾=49z\overline{z}=49 and ∣z∣≥0|z|\ge 0.
    77. Since ∣z∣2=zz‾=49|z|^2=z\overline{z}=49, we have ∣z∣=7|z|=7.
  21. What is the conjugate you multiply by to rationalize 13−2i\frac{1}{3-2i}?
    3+2i3+2i. Multiply by the conjugate to eliminate the imaginary part in the denominator.
  22. What is 1+i1−i\frac{1+i}{1-i} written as a+bia+bi?
    ii. Multiply by conjugate 1+i1+i: (1+i)(1+i)(1−i)(1+i)=2i2\frac{(1+i)(1+i)}{(1-i)(1+i)}=\frac{2i}{2}
  23. What is (2+i)(3−4i)‾\overline{(2+i)(3-4i)}?
    2+5i2+5i. (2+i)(3−4i)=2−5i(2+i)(3-4i)=2-5i, so 2−5i‾=2+5i\overline{2-5i}=2+5i
  24. What is z‾‾\overline{\overline{z}} in terms of zz?
    z‾‾=z\overline{\overline{z}}=z. Taking the conjugate twice returns the original number.
  25. State the identity relating zz‾z\overline{z} and the modulus ∣z∣|z|.
    zz‾=∣z∣2z\overline{z}=|z|^2. Multiplying a complex number by its conjugate gives the square of its modulus.
  26. What is the complex conjugate of z=a−biz=a-bi?
    z‾=a+bi\overline{z}=a+bi. Change the sign of the imaginary part.
  27. Identify the value of z+z‾z+\overline{z} for z=a+biz=a+bi.
    2a2a. Adding a complex number to its conjugate gives twice the real part.
  28. State the property of conjugation for sums: z+w‾=?\overline{z+w}=?
    z+w‾=z‾+w‾\overline{z+w}=\overline{z}+\overline{w}. The conjugate distributes over addition.
  29. State the formula for the complex conjugate of z=a+biz=a+bi.
    z‾=a−bi\overline{z}=a-bi. Change the sign of the imaginary part.
  30. Identify 1a+bi\frac{1}{a+bi} written using a conjugate, assuming aa and bb are real and not both 00.
    1a+bi=a−bia2+b2\frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}. Multiply numerator and denominator by the conjugate a−bia-bi.
  31. What is 1+2i3−i‾\overline{\frac{1+2i}{3-i}} written as a+bia+bi?
    12−12i\frac{1}{2}-\frac{1}{2}i. 1+2i3−i=12+12i\frac{1+2i}{3-i}=\frac{1}{2}+\frac{1}{2}i, so its conjugate is 12−12i\frac{1}{2}-\frac{1}{2}i
  32. Identify the value of z−z‾z-\overline{z} for z=a+biz=a+bi.
    2bi2bi. Subtracting the conjugate gives twice the imaginary part.
  33. What is ∣7∣|7| when z=7z=7 is viewed as a complex number?
    77. For real numbers, the modulus equals the absolute value.
  34. What is ∣5−12i∣|5-12i|?
    1313. 52+(−12)2=169=13\sqrt{5^2+(-12)^2}=\sqrt{169}=13
  35. What is the complex conjugate of the real number z=11z=11?
    1111. Real numbers are their own conjugates.
  36. What is the complex conjugate of z=−4+9iz=-4+9i?
    −4−9i-4-9i. Change the sign of the imaginary part from positive to negative.
  37. What is the complex conjugate of the pure imaginary number z=−6iz=-6i?
    6i6i. For pure imaginary numbers, change the sign of the imaginary part.
  38. State the property of conjugation for quotients: zw‾=?\overline{\frac{z}{w}}=? for w≠0w\neq 0.
    zw‾=z‾w‾\overline{\frac{z}{w}}=\frac{\overline{z}}{\overline{w}}. The conjugate distributes over division.
  39. What is 6−πi‾\overline{6-\pi i}?
    6+πi6+\pi i. Change the sign of the imaginary part from −πi-\pi i to +πi+\pi i.
  40. What is 1i\frac{1}{i} written as a real number?
    −i-i. Multiply by −i-i: 1i⋅−i−i=−i−i2=−i1=−i\frac{1}{i}\cdot\frac{-i}{-i}=\frac{-i}{-i^2}=\frac{-i}{1}=-i
  41. What is the complex conjugate of z=12−53iz=\frac{1}{2}-\frac{5}{3}i?
    12+53i\frac{1}{2}+\frac{5}{3}i. Change the sign of the imaginary part from negative to positive.
  42. What is ∣1+i∣2|1+i|^2?
    22. ∣1+i∣2=12+12=2|1+i|^2=1^2+1^2=2
  43. State the modulus quotient rule for nonzero ww: ∣zw∣=?\left|\frac{z}{w}\right|=?
    ∣zw∣=∣z∣∣w∣\left|\frac{z}{w}\right|=\frac{|z|}{|w|}. The modulus of a quotient equals the quotient of moduli.
  44. What is z‾ z\overline{z}\,z if z=4−3iz=4-3i?
    2525. zz‾=∣z∣2=42+(−3)2=25z\overline{z}=|z|^2=4^2+(-3)^2=25
  45. What is z−z‾z-\overline{z} if z=−3+7iz=-3+7i?
    14i14i. z−z‾=(−3+7i)−(−3−7i)=14iz-\overline{z}=(-3+7i)-(-3-7i)=14i
  46. What is z+z‾z+\overline{z} if z=−3+7iz=-3+7i?
    −6-6. z+z‾=(−3+7i)+(−3−7i)=−6z+\overline{z}=(-3+7i)+(-3-7i)=-6
  47. What is ∣2−5i∣2|2-5i|^2?
    2929. ∣z∣2=zz‾=(2−5i)(2+5i)=29|z|^2=z\overline{z}=(2-5i)(2+5i)=29

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