Solving Systems Using Matrix Inverses - Algebra 2

  1. What is the identity matrix I3I_3?
    I3=(100010001)I_3=\begin{pmatrix}1&0&0\\0&1&0\\0&0&1\end{pmatrix}. The 3x3 identity matrix has 1s on the main diagonal and 0s elsewhere, acting as the multiplicative identity.
  2. What is A−1A^{-1} for A=(2005)A=\begin{pmatrix}2&0\\0&5\end{pmatrix}?
    A−1=(120015)A^{-1}=\begin{pmatrix}\frac{1}{2}&0\\0&\frac{1}{5}\end{pmatrix}. The inverse of a diagonal matrix reciprocates each diagonal entry.
  3. What is the relationship between det⁡(A)\det(A) and the number of solutions to Ax⃗=b⃗A\vec{x}=\vec{b}?
    det⁡(A)≠0\det(A)\neq 0 implies a unique solution for every b⃗\vec{b}. A non-zero determinant confirms invertibility, guaranteeing a unique solution for every b⃗\vec{b}.
  4. Identify whether A=(1224)A=\begin{pmatrix}1&2\\2&4\end{pmatrix} is invertible.
    Not invertible because det⁡(A)=0\det(A)=0. A zero determinant confirms the matrix is singular.
  5. What does it mean for the columns of AA if AA is invertible?
    The columns are linearly independent. Invertibility requires the columns to form a linearly independent set.
  6. What does it indicate if row reduction of [A∣I][A\mid I] cannot make the left side II?
    AA is not invertible, so A−1A^{-1} does not exist. Inability to reach the identity on the left indicates the matrix is singular.
  7. What is the augmented matrix form of the system Ax⃗=b⃗A\vec{x}=\vec{b}?
    [A∣b⃗][A\mid \vec{b}]. The augmented matrix combines coefficients and constants for row reduction.
  8. What is the identity matrix I2I_2?
    I2=(1001)I_2=\begin{pmatrix}1&0\\0&1\end{pmatrix}. The 2x2 identity matrix has 1s on the main diagonal and 0s elsewhere, serving as the multiplicative identity.
  9. What matrix equation represents a linear system in matrix form?
    Ax⃗=b⃗A\vec{x}=\vec{b}. This form represents the linear system as a matrix-vector product equaling the constant vector.
  10. What is the inverse-matrix solution to Ax⃗=b⃗A\vec{x}=\vec{b} when AA is invertible?
    x⃗=A−1b⃗\vec{x}=A^{-1}\vec{b}. Multiplying both sides on the left by A−1A^{-1} isolates x⃗\vec{x} as the unique solution.
  11. Identify the correct criterion: AA is invertible iff det⁡(A)=0\det(A)=0 or det⁡(A)≠0\det(A)\neq 0?
    AA is invertible iff det⁡(A)≠0\det(A)\neq 0. Invertibility requires a non-zero determinant.
  12. What is the inverse of a diagonal matrix D=diag(d1,…,dn)D=\mathrm{diag}(d_1,\dots,d_n) when all di≠0d_i\neq 0?
    D−1=diag(1d1,…,1dn)D^{-1}=\mathrm{diag}(\frac{1}{d_1},\dots,\frac{1}{d_n}). Each diagonal entry is reciprocated to ensure the product is the identity matrix.
  13. Find det⁡ ⁣((100230456))\det\!\left(\begin{pmatrix}1&0&0\\2&3&0\\4&5&6\end{pmatrix}\right).
    1818. For upper triangular matrices, the determinant is the product of diagonal entries.
  14. Identify whether A=(4−26−3)A=\begin{pmatrix}4&-2\\6&-3\end{pmatrix} is invertible.
    Not invertible because det⁡(A)=0\det(A)=0. A zero determinant indicates linear dependence and non-invertibility.
  15. What does it mean if Ax⃗=b⃗A\vec{x}=\vec{b} has a unique solution for every b⃗\vec{b}?
    AA is invertible. Invertibility ensures the system has a unique solution for any right-hand side vector.
  16. What is the inverse of a scalar multiple kAkA when k≠0k\neq 0 and AA is invertible?
    (kA)−1=1kA−1(kA)^{-1}=\frac{1}{k}A^{-1}. The inverse scales by the reciprocal of kk to counteract the scalar multiple.
  17. What is the determinant of A=(a00d)A=\begin{pmatrix}a&0\\0&d\end{pmatrix}?
    det⁡(A)=ad\det(A)=ad. For diagonal matrices, the determinant is the product of diagonal entries.
  18. Identify the correct solution form for Ax⃗=b⃗A\vec{x}=\vec{b} when AA is invertible: x⃗=Ab⃗\vec{x}=A\vec{b} or x⃗=A−1b⃗\vec{x}=A^{-1}\vec{b}?
    x⃗=A−1b⃗\vec{x}=A^{-1}\vec{b}. The correct form uses the inverse matrix multiplied on the left by b⃗\vec{b}.
  19. Compute (3A)−1(3A)^{-1} if A−1=MA^{-1}=M and 3≠03\neq 0.
    (3A)−1=13M(3A)^{-1}=\frac{1}{3}M. The scalar 3 requires dividing the inverse by 3.
  20. What is the determinant test for invertibility of a square matrix AA?
    AA is invertible iff det⁡(A)≠0\det(A)\neq 0. A non-zero determinant indicates the matrix has full rank and is thus invertible.
  21. What is A−1A^{-1} for A=(1000−20004)A=\begin{pmatrix}1&0&0\\0&-2&0\\0&0&4\end{pmatrix}?
    A−1=(1000−1200014)A^{-1}=\begin{pmatrix}1&0&0\\0&-\frac{1}{2}&0\\0&0&\frac{1}{4}\end{pmatrix}. Reciprocate each diagonal entry to form the inverse.
  22. Compute det⁡ ⁣((50001000−2))\det\!\left(\begin{pmatrix}5&0&0\\0&1&0\\0&0&-2\end{pmatrix}\right).
    −10-10. The determinant of a diagonal matrix is the product of its diagonal entries.
  23. Solve Ax⃗=b⃗A\vec{x}=\vec{b} if A−1=(10−21)A^{-1}=\begin{pmatrix}1&0\\-2&1\end{pmatrix} and b⃗=(35)\vec{b}=\begin{pmatrix}3\\5\end{pmatrix}.
    x⃗=(3−1)\vec{x}=\begin{pmatrix}3\\-1\end{pmatrix}. Matrix multiplication of A−1A^{-1} by b⃗\vec{b} gives the solution vector.
  24. What is det⁡ ⁣((3124))\det\!\left(\begin{pmatrix}3&1\\2&4\end{pmatrix}\right)?
    1010. Computed using the 2x2 determinant formula ad−bcad-bc.
  25. What is the inverse of the inverse of an invertible matrix AA?
    (A−1)−1=A(A^{-1})^{-1}=A. Inverting the inverse restores the original matrix, as they are multiplicative inverses.
  26. What does it mean for the system Ax⃗=b⃗A\vec{x}=\vec{b} if AA is not invertible?
    The system has either no solution or infinitely many solutions. Non-invertible matrices lead to systems that are either inconsistent or have infinite solutions.
  27. Solve using an inverse: (1002)x⃗=(56)\begin{pmatrix}1&0\\0&2\end{pmatrix}\vec{x}=\begin{pmatrix}5\\6\end{pmatrix}.
    x⃗=(53)\vec{x}=\begin{pmatrix}5\\3\end{pmatrix}. Multiplying the inverse matrix by the vector yields the solution.
  28. Identify the correct statement: A−1b⃗A^{-1}\vec{b} or b⃗A−1\vec{b}A^{-1} solves Ax⃗=b⃗A\vec{x}=\vec{b}?
    x⃗=A−1b⃗\vec{x}=A^{-1}\vec{b}. A−1b⃗A^{-1}\vec{b} is the correct order for matrix-vector multiplication to solve the system.
  29. What is the inverse of the product ABAB when AA and BB are invertible?
    (AB)−1=B−1A−1(AB)^{-1}=B^{-1}A^{-1}. The inverse of a product requires reversing the order of the individual inverses.
  30. What is the determinant of a triangular matrix in terms of its diagonal entries?
    det⁡(A)\det(A) equals the product of the diagonal entries. For triangular matrices, the determinant is the product of the diagonal elements.
  31. What is the determinant of A=(ab0d)A=\begin{pmatrix}a&b\\0&d\end{pmatrix}?
    det⁡(A)=ad\det(A)=ad. For upper triangular matrices, the determinant equals the product of diagonals.
  32. Which matrix must have the same size as AA to form [A∣I][A\mid I] for an n×nn\times n matrix?
    The identity matrix InI_n. InI_n is square n×nn\times n to match AA's dimensions for augmentation.
  33. What is det⁡(A−1)\det(A^{-1}) in terms of det⁡(A)\det(A) for invertible AA?
    det⁡(A−1)=1det⁡(A)\det(A^{-1})=\frac{1}{\det(A)}. This follows from the multiplicative property of determinants and det⁡(I)=1\det(I)=1.
  34. What is the determinant of the identity matrix InI_n?
    det⁡(In)=1\det(I_n)=1. It is the product of the diagonal entries, all of which are 1.
  35. Identify whether A=(100002030)A=\begin{pmatrix}1&0&0\\0&0&2\\0&3&0\end{pmatrix} is invertible using det⁡(A)\det(A).
    Invertible because det⁡(A)=−6≠0\det(A)=-6\neq 0. The non-zero determinant confirms the matrix is invertible.
  36. Compute (AB)−1(AB)^{-1} if A−1=PA^{-1}=P and B−1=QB^{-1}=Q for invertible A,BA,B.
    (AB)−1=QP(AB)^{-1}=QP. Given A−1=PA^{-1}=P and B−1=QB^{-1}=Q, the product inverse is B−1A−1B^{-1}A^{-1}.
  37. What is det⁡(AB)\det(AB) in terms of det⁡(A)\det(A) and det⁡(B)\det(B) for square matrices?
    det⁡(AB)=det⁡(A)det⁡(B)\det(AB)=\det(A)\det(B). The determinant function is multiplicative for square matrices.
  38. Find ((02−31))−1\left(\begin{pmatrix}0&2\\-3&1\end{pmatrix}\right)^{-1}.
    (16−13frac120)\begin{pmatrix}\frac{1}{6}&-\frac{1}{3}\\frac{1}{2}&0\end{pmatrix}. The inverse is scaled by 1/det⁡(A)1/\det(A) using the adjugate matrix.
  39. What is the solution of Ax⃗=0⃗A\vec{x}=\vec{0} when AA is invertible?
    x⃗=0⃗\vec{x}=\vec{0}. Invertible AA implies only the trivial solution for the homogeneous system.
  40. What is A−1A^{-1} if AA is the identity matrix InI_n?
    In−1=InI_n^{-1}=I_n. The identity matrix multiplied by itself yields itself, satisfying the inverse definition.
  41. What technology-based method is commonly used to find A−1A^{-1} for 3×33\times 3 or larger matrices?
    Use a calculator or software to compute A−1A^{-1} or solve Ax⃗=b⃗A\vec{x}=\vec{b}. Technology is recommended for efficient computation of inverses or solutions for larger matrices.
  42. Solve using an inverse: (200−4)x⃗=(812)\begin{pmatrix}2&0\\0&-4\end{pmatrix}\vec{x}=\begin{pmatrix}8\\12\end{pmatrix}.
    x⃗=(4−3)\vec{x}=\begin{pmatrix}4\\-3\end{pmatrix}. The inverse scales each equation to solve for the variables.
  43. What does it mean if a row of zeros appears on the left side when row-reducing [A∣I][A\mid I]?
    AA is singular, so A−1A^{-1} does not exist. A zero row indicates linear dependence, meaning the matrix is singular.
  44. What does Ax⃗=b⃗A\vec{x}=\vec{b} represent when AA is 3×33\times 3?
    A system of 33 linear equations in 33 unknowns. The dimensions of AA determine the number of equations and unknowns.
  45. What does it mean for a square matrix AA to be invertible?
    A−1A^{-1} exists such that AA−1=IAA^{-1}=I and A−1A=IA^{-1}A=I. A square matrix is invertible if there exists a unique matrix that, when multiplied on either side, yields the identity matrix.
  46. What condition on a,b,c,da,b,c,d makes (abcd)\begin{pmatrix}a&b\\c&d\end{pmatrix} non-invertible?
    ad−bc=0ad-bc=0. This condition makes the determinant zero, rendering the matrix singular and non-invertible.
  47. What is the determinant of a diagonal matrix D=diag(d1,…,dn)D=\mathrm{diag}(d_1,\dots,d_n)?
    det⁡(D)=d1d2⋯dn\det(D)=d_1d_2\cdots d_n. The determinant is the product of its diagonal entries.
  48. What matrix is used to compute A−1A^{-1} by row reduction for an n×nn\times n matrix AA?
    Augment [A∣In][A\mid I_n] and row-reduce to [In∣A−1][I_n\mid A^{-1}]. Row operations transform AA to InI_n, applying the same to InI_n to obtain A−1A^{-1}.
  49. Identify the matrix equation you should solve to find A−1A^{-1} using row reduction.
    Row-reduce [A∣In][A\mid I_n] to [In∣A−1][I_n\mid A^{-1}]. Row reduction of the augmented matrix yields the inverse on the right.
  50. What is the inverse of a 2×22\times 2 matrix A=(abcd)A=\begin{pmatrix}a&b\\c&d\end{pmatrix} when it exists?
    A−1=1ad−bc(d−b−ca)A^{-1}=\frac{1}{ad-bc}\begin{pmatrix}d&-b\\-c&a\end{pmatrix}. The formula scales the adjugate matrix by the reciprocal of the determinant to satisfy AA−1=IAA^{-1}=I.
  51. What is the transpose-inverse rule for an invertible matrix AA?
    (AT)−1=(A−1)T(A^T)^{-1}=(A^{-1})^T. The transpose of the inverse equals the inverse of the transpose for invertible matrices.
  52. What equation defines the inverse matrix A−1A^{-1} of a square matrix AA?
    AA−1=IAA^{-1}=I (equivalently A−1A=IA^{-1}A=I). The inverse satisfies the multiplicative identity property when multiplied on the left or right by the original matrix.
  53. Compute det⁡ ⁣((02−31))\det\!\left(\begin{pmatrix}0&2\\-3&1\end{pmatrix}\right).
    66. Apply the 2x2 determinant formula ad−bcad-bc.
  54. Find ((1234))−1\left(\begin{pmatrix}1&2\\3&4\end{pmatrix}\right)^{-1}.
    (−21frac32−12)\begin{pmatrix}-2&1\\frac{3}{2}&-\frac{1}{2}\end{pmatrix}. The 2x2 inverse formula scales the adjugate by 1/det⁡(A)1/\det(A).
  55. What is the matrix size of AA in Ax⃗=b⃗A\vec{x}=\vec{b} for a system of nn equations in nn unknowns?
    AA is n×nn\times n. A square n×nn\times n matrix corresponds to nn equations in nn variables.

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