Solve Quadratics by Multiple Methods - Algebra 2

  1. Factor and solve x2+7x+12=0x^2+7x+12=0.
    x=−3x=-3 or x=−4x=-4. Factor: (x+3)(x+4)=0(x+3)(x+4)=0, then use zero-product property.
  2. Solve using the quadratic formula: x2+4x+1=0x^2+4x+1=0.
    x=−2±3x=-2\pm\sqrt{3}. Use a=1a=1, b=4b=4, c=1c=1 in the quadratic formula.
  3. Solve using the quadratic formula: x2+2x+5=0x^2+2x+5=0.
    x=−1±2ix=-1\pm 2i. Negative discriminant gives complex solutions: −16=4i\sqrt{-16}=4i.
  4. Solve by taking square roots: (x+2)2=7(x+2)^2=7.
    x=−2±7x=-2\pm\sqrt{7}. Square root both sides: x+2=±7x+2=\pm\sqrt{7}.
  5. What is the zero-product property used after factoring AB=0AB=0?
    AB=0⇒A=0AB=0\Rightarrow A=0 or B=0B=0. If a product equals zero, at least one factor must be zero.
  6. What does Δ<0\Delta<0 guarantee about solutions of ax2+bx+c=0ax^2+bx+c=0?
    Two complex conjugate solutions. Negative discriminant means the parabola doesn't cross the x-axis.
  7. Solve using the quadratic formula: 2x2+4x+5=02x^2+4x+5=0.
    x=−1±62ix=-1\pm\frac{\sqrt{6}}{2}i. Use a=2a=2, b=4b=4, c=5c=5; −24=26i\sqrt{-24}=2\sqrt{6}i.
  8. Solve by factoring: 3x2−12=03x^2-12=0.
    x=±2x=\pm 2. Factor: 3(x2−4)=3(x−2)(x+2)=03(x^2-4)=3(x-2)(x+2)=0.
  9. State the square root property used to solve (x−h)2=k(x-h)^2=k.
    (x−h)2=k⇒x−h=±k(x-h)^2=k\Rightarrow x-h=\pm\sqrt{k}. Take the square root of both sides to isolate x−hx-h.
  10. What is Δ\Delta for x2+2x+5=0x^2+2x+5=0?
    Δ=−16\Delta=-16. Δ=(2)2−4(1)(5)=4−20=−16\Delta=(2)^2-4(1)(5)=4-20=-16.
  11. Solve using the quadratic formula: x2+5x+6=0x^2+5x+6=0.
    x=−2x=-2 or x=−3x=-3. Use a=1a=1, b=5b=5, c=6c=6 in the quadratic formula.
  12. Solve by completing the square: x2−4x−1=0x^2-4x-1=0.
    x=2±5x=2\pm\sqrt{5}. Complete the square: (x−2)2=5(x-2)^2=5, so x−2=±5x-2=\pm\sqrt{5}.
  13. What are the solutions of (x+5)2=9(x+5)^2=9?
    x=−2x=-2 or x=−8x=-8. Square root both sides: x+5=±3x+5=\pm 3, so x=−5±3x=-5\pm 3.
  14. Solve by completing the square: x2+6x+1=0x^2+6x+1=0.
    x=−3±22x=-3\pm 2\sqrt{2}. Complete the square: (x+3)2=8(x+3)^2=8, so x+3=±22x+3=\pm 2\sqrt{2}.
  15. State the quadratic formula for solutions of ax2+bx+c=0ax^2+bx+c=0.
    x=−b±b2−4ac2ax=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Standard form for finding roots of any quadratic equation.
  16. What is the simplified form of −12\sqrt{-12} in terms of ii?
    23i2\sqrt{3}i. Simplify: −12=12i=23i\sqrt{-12}=\sqrt{12}i=2\sqrt{3}i.
  17. Solve by factoring: x2+10x+25=0x^2+10x+25=0.
    x=−5x=-5. Perfect square trinomial: (x+5)2=0(x+5)^2=0, so x=−5x=-5.
  18. Solve using the quadratic formula: 3x2−12x+12=03x^2-12x+12=0.
    x=2x=2. Use a=3a=3, b=−12b=-12, c=12c=12; discriminant equals 0.
  19. Factor and solve x2−5x=0x^2-5x=0.
    x=0x=0 or x=5x=5. Factor out xx: x(x−5)=0x(x-5)=0, then use zero-product property.
  20. What is the simplified form of −1\sqrt{-1}?
    ii. The imaginary unit where i2=−1i^2=-1.
  21. Factor and solve x2−9=0x^2-9=0.
    x=±3x=\pm 3. Difference of squares: (x−3)(x+3)=0(x-3)(x+3)=0.
  22. What are the solutions of x2=49x^2=49?
    x=±7x=\pm 7. Take the square root of both sides: 49=7\sqrt{49}=7.
  23. Solve by taking square roots: (2x−1)2=25(2x-1)^2=25.
    x=3x=3 or x=−2x=-2. Square root both sides: 2x−1=±52x-1=\pm 5, solve for xx.
  24. What does Δ>0\Delta>0 guarantee about solutions of ax2+bx+c=0ax^2+bx+c=0?
    Two distinct real solutions. Positive discriminant means the parabola crosses the x-axis twice.
  25. What is Δ\Delta for 2x2−3x−2=02x^2-3x-2=0?
    Δ=25\Delta=25. Δ=(−3)2−4(2)(−2)=9+16=25\Delta=(-3)^2-4(2)(-2)=9+16=25.
  26. What does Δ=0\Delta=0 guarantee about solutions of ax2+bx+c=0ax^2+bx+c=0?
    One real double solution. Zero discriminant means the parabola touches the x-axis at one point.
  27. Solve by completing the square: x2+2x−8=0x^2+2x-8=0.
    x=2x=2 or x=−4x=-4. Complete the square: (x+1)2=9(x+1)^2=9, so x+1=±3x+1=\pm 3.
  28. Factor and solve x2−6x+8=0x^2-6x+8=0.
    x=2x=2 or x=4x=4. Factor: (x−2)(x−4)=0(x-2)(x-4)=0, then use zero-product property.
  29. Identify the best method for x2−16=0x^2-16=0 from factoring or quadratic formula.
    Factoring. Difference of squares factors easily as (x−4)(x+4)=0(x-4)(x+4)=0.
  30. What is the simplified form of −49\sqrt{-49} in terms of ii?
    7i7i. Use −49=49⋅−1=7i\sqrt{-49}=\sqrt{49}\cdot\sqrt{-1}=7i.
  31. Identify aa, bb, and cc for −3x2+2x−7=0-3x^2+2x-7=0.
    a=−3a=-3, b=2b=2, c=−7c=-7. Coefficients from standard form ax2+bx+c=0ax^2+bx+c=0.
  32. Solve by factoring: x2−2x−15=0x^2-2x-15=0.
    x=5x=5 or x=−3x=-3. Factor: (x−5)(x+3)=0(x-5)(x+3)=0, then use zero-product property.
  33. What are the solutions of (x−4)2=0(x-4)^2=0?
    x=4x=4. Only one solution since the square root of 0 is 0.
  34. What is the discriminant for ax2+bx+c=0ax^2+bx+c=0?
    Δ=b2−4ac\Delta=b^2-4ac. The discriminant determines the nature of quadratic solutions.
  35. What is Δ\Delta for x2−6x+9=0x^2-6x+9=0?
    Δ=0\Delta=0. Δ=(−6)2−4(1)(9)=36−36=0\Delta=(-6)^2-4(1)(9)=36-36=0.
  36. Solve by inspection: x2=14x^2=\frac{1}{4}.
    x=±12x=\pm\frac{1}{2}. Take the square root: 14=12\sqrt{\frac{1}{4}}=\frac{1}{2}.
  37. Rewrite x2−12x+36x^2-12x+36 as a perfect square trinomial.
    (x−6)2(x-6)^2. Perfect square trinomial with a=xa=x and b=−6b=-6.
  38. How do you write solutions when the quadratic formula yields −k\sqrt{-k} for k>0k>0?
    Use −k=ik\sqrt{-k}=i\sqrt{k} to write a±bia\pm bi. Convert negative square roots to imaginary form using ii.
  39. What number completes the square for x2−6x+□x^2-6x+\square?
    99. Half of -6 is -3, and (−3)2=9(-3)^2=9.
  40. Identify the best method for (x−9)2=12(x-9)^2=12 from square roots or quadratic formula.
    Taking square roots. Already in perfect square form, ready for square root method.
  41. What are the solutions of (x−3)2=16(x-3)^2=16?
    x=7x=7 or x=−1x=-1. Square root both sides: x−3=±4x-3=\pm 4, so x=3±4x=3\pm 4.
  42. Solve by factoring: x2−4x+3=0x^2-4x+3=0.
    x=1x=1 or x=3x=3. Factor: (x−1)(x−3)=0(x-1)(x-3)=0, then use zero-product property.
  43. Rewrite x2+8x+16x^2+8x+16 as a perfect square trinomial.
    (x+4)2(x+4)^2. Perfect square trinomial with a=xa=x and b=4b=4.
  44. Factor and solve x2+x−6=0x^2+x-6=0.
    x=2x=2 or x=−3x=-3. Factor: (x+3)(x−2)=0(x+3)(x-2)=0, then use zero-product property.
  45. Solve using the quadratic formula: 2x2+3x−2=02x^2+3x-2=0.
    x=12x=\frac{1}{2} or x=−2x=-2. Use a=2a=2, b=3b=3, c=−2c=-2 in the quadratic formula.
  46. What are the solutions of x2+8x+16=0x^2+8x+16=0?
    x=−4x=-4. Perfect square trinomial: (x+4)2=0(x+4)^2=0, so x=−4x=-4.
  47. Solve using the quadratic formula: x2−2x+5=0x^2-2x+5=0.
    x=1±2ix=1\pm 2i. Negative discriminant gives complex solutions: −16=4i\sqrt{-16}=4i.
  48. Solve by factoring: 2x2−8x=02x^2-8x=0.
    x=0x=0 or x=4x=4. Factor out 2x2x: 2x(x−4)=02x(x-4)=0, then use zero-product property.
  49. What is the simplified form of −18\sqrt{-18} in terms of ii?
    32i3\sqrt{2}i. Simplify: −18=18i=32i\sqrt{-18}=\sqrt{18}i=3\sqrt{2}i.
  50. What number completes the square for x2+10x+□x^2+10x+\square?
    2525. Half of 10 is 5, and 52=255^2=25.
  51. What are the solutions of 2(x−1)2=182(x-1)^2=18?
    x=4x=4 or x=−2x=-2. Divide by 2 first: (x−1)2=9(x-1)^2=9, then x−1=±3x-1=\pm 3.
  52. State the first step to complete the square for x2+bxx^2+bx.
    Add (b2)2\left(\frac{b}{2}\right)^2. Take half the coefficient of xx, then square it.

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