Extending Polynomial Identities to Complex Numbers - Algebra 2

  1. Rewrite x2+36x^2+36 as a product of two complex conjugate binomials.
    (x+6i)(x−6i)(x+6i)(x-6i). x2+36=x2+(6i)2x^2 + 36 = x^2 + (6i)^2 factors as conjugate pair.
  2. Rewrite x2+5x^2+5 as a product of two complex conjugate binomials.
    (x+i5)(x−i5)(x+i\sqrt{5})(x-i\sqrt{5}). x2+5=x2+(i5)2x^2 + 5 = x^2 + (i\sqrt{5})^2 factors as conjugate pair.
  3. What is i2i^2?
    i2=−1i^2=-1. Definition of the imaginary unit.
  4. What is i27i^{27}?
    i27=−ii^{27}=-i. i27=i24⋅i3=1⋅(−i)=−ii^{27} = i^{24} \cdot i^3 = 1 \cdot (-i) = -i
  5. Rewrite x2+50x^2+50 as a product of two complex conjugate binomials.
    (x+5i2)(x−5i2)(x+5i\sqrt{2})(x-5i\sqrt{2}). 50=25⋅250 = 25 \cdot 2, so 50=52\sqrt{50} = 5\sqrt{2}.
  6. What is i4i^4?
    i4=1i^4=1. i4=(i2)2=(−1)2=1i^4 = (i^2)^2 = (-1)^2 = 1
  7. What are the complex roots of x2−2x+2=0x^2-2x+2=0?
    x=1+i,1−ix=1+i,1-i. Use quadratic formula with discriminant 4−8=−44 - 8 = -4.
  8. Factor x2+2x+5x^2+2x+5 over the complex numbers.
    (x+1+2i)(x+1−2i)(x+1+2i)(x+1-2i). Complete the square: (x+1)2−1+5=(x+1)2+4(x+1)^2 - 1 + 5 = (x+1)^2 + 4.
  9. What are the complex roots of x2+9=0x^2+9=0?
    x=3i,−3ix=3i,-3i. Solve x2=−9x^2 = -9 to get x=±3ix = \pm 3i.
  10. Rewrite x2+2x^2+2 as a product of two complex conjugate binomials.
    (x+i2)(x−i2)(x+i\sqrt{2})(x-i\sqrt{2}). x2+2=x2+(i2)2x^2 + 2 = x^2 + (i\sqrt{2})^2 factors as conjugate pair.
  11. What is i100i^{100}?
    i100=1i^{100}=1. i100=(i4)25=125=1i^{100} = (i^4)^{25} = 1^{25} = 1
  12. Factor x2+4x+8x^2+4x+8 over the complex numbers.
    (x+2+2i)(x+2−2i)(x+2+2i)(x+2-2i). Complete the square: (x+2)2−4+8=(x+2)2+4(x+2)^2 - 4 + 8 = (x+2)^2 + 4.
  13. Factor x2+8x+20x^2+8x+20 over the complex numbers.
    (x+4+2i)(x+4−2i)(x+4+2i)(x+4-2i). Complete the square: (x+4)2−16+20=(x+4)2+4(x+4)^2 - 16 + 20 = (x+4)^2 + 4.
  14. Identify the factorization of x2−2ax+(a2+b2)x^2-2ax+(a^2+b^2) over complex numbers.
    (x−(a+bi))(x−(a−bi))(x-(a+bi))(x-(a-bi)). Standard form with roots a±bia \pm bi.
  15. What is i3i^3?
    i3=−ii^3=-i. i3=i2⋅i=−1⋅i=−ii^3 = i^2 \cdot i = -1 \cdot i = -i
  16. Rewrite x2+27x^2+27 as a product of two complex conjugate binomials.
    (x+3i3)(x−3i3)(x+3i\sqrt{3})(x-3i\sqrt{3}). 27=9⋅327 = 9 \cdot 3, so 27=33\sqrt{27} = 3\sqrt{3}.
  17. Rewrite x2+7x^2+7 as a product of two complex conjugate binomials.
    (x+i7)(x−i7)(x+i\sqrt{7})(x-i\sqrt{7}). x2+7=x2+(i7)2x^2 + 7 = x^2 + (i\sqrt{7})^2 factors as conjugate pair.
  18. State the identity for factoring a difference of squares over complex numbers.
    a2−b2=(a−b)(a+b)a^2-b^2=(a-b)(a+b). Standard difference of squares identity, valid for complex numbers.
  19. What are the complex roots of x2+1=0x^2+1=0?
    x=i,−ix=i,-i. Solve x2=−1x^2 = -1 to get x=±ix = \pm i.
  20. Factor x2−6x+13x^2-6x+13 over the complex numbers.
    (x−3+2i)(x−3−2i)(x-3+2i)(x-3-2i). Complete the square: (x−3)2−9+13=(x−3)2+4(x-3)^2 - 9 + 13 = (x-3)^2 + 4.
  21. What are the complex roots of x2−6x+13=0x^2-6x+13=0?
    x=3+2i,3−2ix=3+2i,3-2i. Use quadratic formula with discriminant 36−52=−1636 - 52 = -16.
  22. Rewrite x2+64x^2+64 as a product of two complex conjugate binomials.
    (x+8i)(x−8i)(x+8i)(x-8i). x2+64=x2+(8i)2x^2 + 64 = x^2 + (8i)^2 factors as conjugate pair.
  23. Rewrite x2+12x^2+12 as a product of two complex conjugate binomials.
    (x+2i3)(x−2i3)(x+2i\sqrt{3})(x-2i\sqrt{3}). 12=4⋅312 = 4 \cdot 3, so 12=23\sqrt{12} = 2\sqrt{3}.
  24. Rewrite x2+25x^2+25 as a product of two complex conjugate binomials.
    (x+5i)(x−5i)(x+5i)(x-5i). x2+25=x2+(5i)2x^2 + 25 = x^2 + (5i)^2 factors as conjugate pair.
  25. What are the complex roots of x2+4=0x^2+4=0?
    x=2i,−2ix=2i,-2i. Solve x2=−4x^2 = -4 to get x=±2ix = \pm 2i.
  26. Factor x2+10x+29x^2+10x+29 over the complex numbers.
    (x+5+2i)(x+5−2i)(x+5+2i)(x+5-2i). Complete the square: (x+5)2−25+29=(x+5)2+4(x+5)^2 - 25 + 29 = (x+5)^2 + 4.
  27. Factor x2−2x+2x^2-2x+2 over the complex numbers.
    (x−1+i)(x−1−i)(x-1+i)(x-1-i). Complete the square: (x−1)2−1+2=(x−1)2+1(x-1)^2 - 1 + 2 = (x-1)^2 + 1.
  28. Factor x2−10x+29x^2-10x+29 over the complex numbers.
    (x−5+2i)(x−5−2i)(x-5+2i)(x-5-2i). Complete the square: (x−5)2−25+29=(x−5)2+4(x-5)^2 - 25 + 29 = (x-5)^2 + 4.
  29. What are the complex roots of x2+2x+5=0x^2+2x+5=0?
    x=−1+2i,−1−2ix=-1+2i,-1-2i. Use quadratic formula with discriminant 4−20=−164 - 20 = -16.
  30. Rewrite x2+1x^2+1 as a product of two complex conjugate binomials.
    (x+i)(x−i)(x+i)(x-i). x2+1=x2+i2x^2 + 1 = x^2 + i^2 factors as conjugate pair.
  31. What is the factored form of x2+2ax+(a2+b2)x^2+2ax+(a^2+b^2) over complex numbers?
    (x−(−a+bi))(x−(−a−bi))(x-(-a+bi))(x-(-a-bi)). Standard form with roots −a±bi-a \pm bi.
  32. Factor x2+6x+13x^2+6x+13 over the complex numbers.
    (x+3+2i)(x+3−2i)(x+3+2i)(x+3-2i). Complete the square: (x+3)2−9+13=(x+3)2+4(x+3)^2 - 9 + 13 = (x+3)^2 + 4.
  33. Rewrite x2+49x^2+49 as a product of two complex conjugate binomials.
    (x+7i)(x−7i)(x+7i)(x-7i). x2+49=x2+(7i)2x^2 + 49 = x^2 + (7i)^2 factors as conjugate pair.
  34. Rewrite x2+8x^2+8 as a product of two complex conjugate binomials.
    (x+2i2)(x−2i2)(x+2i\sqrt{2})(x-2i\sqrt{2}). 8=4⋅28 = 4 \cdot 2, so 8=22\sqrt{8} = 2\sqrt{2}.
  35. Rewrite x2+4x^2+4 as a product of two complex conjugate binomials.
    (x+2i)(x−2i)(x+2i)(x-2i). x2+4=x2+(2i)2x^2 + 4 = x^2 + (2i)^2 factors as conjugate pair.
  36. State the Complex Conjugate Root Theorem for polynomials with real coefficients.
    If a+bia+bi is a root, then a−bia-bi is a root. Complex roots of real polynomials come in conjugate pairs.
  37. Factor x2+4x+5x^2+4x+5 over the complex numbers.
    (x+2+i)(x+2−i)(x+2+i)(x+2-i). Complete the square: (x+2)2−4+5=(x+2)2+1(x+2)^2 - 4 + 5 = (x+2)^2 + 1.
  38. What are the complex roots of x2+16=0x^2+16=0?
    x=4i,−4ix=4i,-4i. Solve x2=−16x^2 = -16 to get x=±4ix = \pm 4i.
  39. Rewrite x2+3x^2+3 as a product of two complex conjugate binomials.
    (x+i3)(x−i3)(x+i\sqrt{3})(x-i\sqrt{3}). x2+3=x2+(i3)2x^2 + 3 = x^2 + (i\sqrt{3})^2 factors as conjugate pair.
  40. Factor x2−4x+8x^2-4x+8 over the complex numbers.
    (x−2+2i)(x−2−2i)(x-2+2i)(x-2-2i). Complete the square: (x−2)2−4+8=(x−2)2+4(x-2)^2 - 4 + 8 = (x-2)^2 + 4.
  41. What are the complex roots of x2+2=0x^2+2=0?
    x=i2,−i2x=i\sqrt{2},-i\sqrt{2}. Solve x2=−2x^2 = -2 to get x=±i2x = \pm i\sqrt{2}.
  42. State the identity for factoring a sum of squares using ii.
    a2+b2=(a+bi)(a−bi)a^2+b^2=(a+bi)(a-bi). Uses complex conjugates to factor sum of squares.
  43. Factor x2−4x+5x^2-4x+5 over the complex numbers.
    (x−2+i)(x−2−i)(x-2+i)(x-2-i). Complete the square: (x−2)2−4+5=(x−2)2+1(x-2)^2 - 4 + 5 = (x-2)^2 + 1.
  44. What is i10i^{10}?
    i10=−1i^{10}=-1. i10=i8⋅i2=1⋅(−1)=−1i^{10} = i^{8} \cdot i^2 = 1 \cdot (-1) = -1
  45. What is the product (a+bi)(a−bi)(a+bi)(a-bi) equal to, simplified?
    a2+b2a^2+b^2. Multiplying complex conjugates eliminates the imaginary terms.
  46. Rewrite x2+18x^2+18 as a product of two complex conjugate binomials.
    (x+3i2)(x−3i2)(x+3i\sqrt{2})(x-3i\sqrt{2}). 18=9⋅218 = 9 \cdot 2, so 18=32\sqrt{18} = 3\sqrt{2}.
  47. Rewrite x2+9x^2+9 as a product of two complex conjugate binomials.
    (x+3i)(x−3i)(x+3i)(x-3i). x2+9=x2+(3i)2x^2 + 9 = x^2 + (3i)^2 factors as conjugate pair.
  48. Rewrite x2+16x^2+16 as a product of two complex conjugate binomials.
    (x+4i)(x−4i)(x+4i)(x-4i). x2+16=x2+(4i)2x^2 + 16 = x^2 + (4i)^2 factors as conjugate pair.
  49. Rewrite x2+100x^2+100 as a product of two complex conjugate binomials.
    (x+10i)(x−10i)(x+10i)(x-10i). x2+100=x2+(10i)2x^2 + 100 = x^2 + (10i)^2 factors as conjugate pair.
  50. Factor x2−8x+20x^2-8x+20 over the complex numbers.
    (x−4+2i)(x−4−2i)(x-4+2i)(x-4-2i). Complete the square: (x−4)2−16+20=(x−4)2+4(x-4)^2 - 16 + 20 = (x-4)^2 + 4.

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