Distance Midpoints in the Complex Plane - Algebra 2

  1. Find the midpoint of z1=−3iz_1=-3i and z2=9iz_2=9i.
    3i3i. −3i+9i2=6i2=3i\frac{-3i+9i}{2} = \frac{6i}{2} = 3i.
  2. Find the distance between z1=1+2iz_1=1+2i and z2=4+6iz_2=4+6i.
    55. ∣(1+2i)−(4+6i)∣=∣−3−4i∣=9+16=5|(1+2i)-(4+6i)| = |-3-4i| = \sqrt{9+16} = 5.
  3. Find the midpoint of z1=−2−2iz_1=-2-2i and z2=4+6iz_2=4+6i.
    1+2i1+2i. (−2−2i)+(4+6i)2=2+4i2=1+2i\frac{(-2-2i)+(4+6i)}{2} = \frac{2+4i}{2} = 1+2i.
  4. Find the midpoint of z1=3−5iz_1=3-5i and z2=3+7iz_2=3+7i.
    3+i3+i. (3−5i)+(3+7i)2=6+2i2=3+i\frac{(3-5i)+(3+7i)}{2} = \frac{6+2i}{2} = 3+i.
  5. Find the distance between z1=3+0iz_1=3+0i and z2=0+4iz_2=0+4i.
    55. ∣(3+0i)−(0+4i)∣=∣3−4i∣=9+16=5|(3+0i)-(0+4i)| = |3-4i| = \sqrt{9+16} = 5.
  6. Find ∣z∣|z| for z=5−12iz=5-12i.
    1313. ∣5−12i∣=25+144=169=13|5-12i| = \sqrt{25+144} = \sqrt{169} = 13.
  7. What is the distance between z1=a+biz_1=a+bi and z2=c+diz_2=c+di in coordinates?
    (a−c)2+(b−d)2\sqrt{(a-c)^2+(b-d)^2}. Apply the standard distance formula using coordinates $ (a,b) $ and $ (c,d) $.
  8. Find the distance between z1=−6+8iz_1=-6+8i and z2=0z_2=0.
    1010. Distance from origin: ∣−6+8i∣=36+64=10|-6+8i| = \sqrt{36+64} = 10.
  9. Find and correct the formula error: distance claimed as ∣z1+z2∣|z_1+z_2| for endpoints z1z_1 and z2z_2.
    Correct distance: ∣z1−z2∣|z_1-z_2|. Distance requires subtraction, not addition of the complex numbers.
  10. Find ∣z1−z2∣|z_1-z_2| for z1=7−3iz_1=7-3i and z2=1−3iz_2=1-3i.
    66. ∣(7−3i)−(1−3i)∣=∣6∣=6|(7-3i)-(1-3i)| = |6| = 6.
  11. Find the distance between z1=−3+0iz_1=-3+0i and z2=5+0iz_2=5+0i.
    88. ∣(−3+0i)−(5+0i)∣=∣−8∣=8|(-3+0i)-(5+0i)| = |-8| = 8.
  12. Find the midpoint of z1=2−4iz_1=2-4i and z2=−6+0iz_2=-6+0i.
    −2−2i-2-2i. (2−4i)+(−6+0i)2=−4−4i2=−2−2i\frac{(2-4i)+(-6+0i)}{2} = \frac{-4-4i}{2} = -2-2i.
  13. What is the modulus of z=a+biz=a+bi written in terms of aa and bb?
    ∣z∣=a2+b2|z|=\sqrt{a^2+b^2}. Modulus uses the Pythagorean theorem with real and imaginary parts.
  14. Identify the distance between z1z_1 and z2z_2 if z1−z2=−9+0iz_1-z_2=-9+0i.
    99. ∣−9+0i∣=∣−9∣=9|-9+0i| = |-9| = 9.
  15. What is the midpoint mm if z2=z1+wz_2=z_1+w for a complex step ww?
    m=z1+w2m=z_1+\frac{w}{2}. The midpoint is the starting point plus half the step vector.
  16. Find the midpoint of z1=−4+2iz_1=-4+2i and z2=6+8iz_2=6+8i.
    1+5i1+5i. (−4+2i)+(6+8i)2=2+10i2=1+5i\frac{(-4+2i)+(6+8i)}{2} = \frac{2+10i}{2} = 1+5i.
  17. Find and correct the formula error: midpoint claimed as z1−z22\frac{z_1-z_2}{2} for endpoints z1z_1 and z2z_2.
    Correct midpoint: z1+z22\frac{z_1+z_2}{2}. Midpoint requires addition, not subtraction of the complex numbers.
  18. Find ∣z1−z2∣|z_1-z_2| for z1=4+iz_1=4+i and z2=1+5iz_2=1+5i.
    55. ∣(4+i)−(1+5i)∣=∣3−4i∣=9+16=5|(4+i)-(1+5i)| = |3-4i| = \sqrt{9+16} = 5.
  19. Find the distance between z1=0+2iz_1=0+2i and z2=0−4iz_2=0-4i.
    66. ∣(0+2i)−(0−4i)∣=∣6i∣=6|(0+2i)-(0-4i)| = |6i| = 6.
  20. Find the midpoint of z1=−7+3iz_1=-7+3i and z2=1−5iz_2=1-5i.
    −3−i-3-i. (−7+3i)+(1−5i)2=−6−2i2=−3−i\frac{(-7+3i)+(1-5i)}{2} = \frac{-6-2i}{2} = -3-i.
  21. Find the midpoint of z1=−8z_1=-8 and z2=2z_2=2.
    −3-3. −8+22=−62=−3\frac{-8+2}{2} = \frac{-6}{2} = -3.
  22. Find the distance between z1=2−4iz_1=2-4i and z2=−6+0iz_2=-6+0i.
    80\sqrt{80}. ∣(2−4i)−(−6+0i)∣=∣8−4i∣=64+16=80|(2-4i)-(-6+0i)| = |8-4i| = \sqrt{64+16} = \sqrt{80}.
  23. What is ∣z1−z2∣|z_1-z_2| interpreted as geometrically in the complex plane?
    The distance between z1z_1 and z2z_2. The modulus of a difference represents geometric distance.
  24. State the formula for the distance between complex numbers z1z_1 and z2z_2 in the complex plane.
    d=∣z1−z2∣d=|z_1-z_2|. Distance is the modulus of the difference between two complex numbers.
  25. What is the midpoint of z1=az_1=a and z2=bz_2=b when both endpoints are real numbers?
    a+b2\frac{a+b}{2}. For real numbers, the midpoint formula reduces to the average.
  26. Find the midpoint of z1=2+6iz_1=2+6i and z2=8+0iz_2=8+0i.
    5+3i5+3i. (2+6i)+(8+0i)2=10+6i2=5+3i\frac{(2+6i)+(8+0i)}{2} = \frac{10+6i}{2} = 5+3i.
  27. Find the midpoint of z1=1+2iz_1=1+2i and z2=9+10iz_2=9+10i.
    5+6i5+6i. (1+2i)+(9+10i)2=10+12i2=5+6i\frac{(1+2i)+(9+10i)}{2} = \frac{10+12i}{2} = 5+6i.
  28. Find the distance between z1=5z_1=5 and z2=−1+4iz_2=-1+4i.
    52\sqrt{52}. ∣5−(−1+4i)∣=∣6−4i∣=36+16=52|5-(-1+4i)| = |6-4i| = \sqrt{36+16} = \sqrt{52}.
  29. Identify the real part of the midpoint m=z1+z22m=\frac{z_1+z_2}{2} for z1=a+biz_1=a+bi and z2=c+diz_2=c+di.
    a+c2\frac{a+c}{2}. Average the real parts: a+c2\frac{a+c}{2}.
  30. Find ∣z∣|z| for z=9+12iz=9+12i.
    1515. ∣9+12i∣=81+144=225=15|9+12i| = \sqrt{81+144} = \sqrt{225} = 15.
  31. Find the distance between z1=−1+2iz_1=-1+2i and z2=2−2iz_2=2-2i.
    55. ∣(−1+2i)−(2−2i)∣=∣−3+4i∣=9+16=5|(-1+2i)-(2-2i)| = |-3+4i| = \sqrt{9+16} = 5.
  32. Identify the complex number that represents the midpoint of points (a,b)(a,b) and (c,d)(c,d).
    a+c2+b+d2i\frac{a+c}{2}+\frac{b+d}{2}i. Average the real parts and imaginary parts separately.
  33. Find the distance between z1=3+4iz_1=3+4i and z2=0z_2=0.
    55. Distance from origin: ∣3+4i∣=32+42=5|3+4i| = \sqrt{3^2+4^2} = 5.
  34. Find the distance between z1=−8z_1=-8 and z2=2z_2=2.
    1010. ∣(−8)−(2)∣=∣−10∣=10|(-8)-(2)| = |-10| = 10
  35. Find the distance between z1=1+iz_1=1+i and z2=1−iz_2=1-i.
    22. ∣(1+i)−(1−i)∣=∣2i∣=2|(1+i)-(1-i)| = |2i| = 2.
  36. What is the distance between z1=az_1=a and z2=bz_2=b when both endpoints are real numbers?
    ∣a−b∣|a-b|. For real numbers, distance is the absolute value of the difference.
  37. Identify the imaginary part of the midpoint m=z1+z22m=\frac{z_1+z_2}{2} for z1=a+biz_1=a+bi and z2=c+diz_2=c+di.
    b+d2\frac{b+d}{2}. Average the imaginary parts: b+d2\frac{b+d}{2}.
  38. Find the distance between z1=−3iz_1=-3i and z2=9iz_2=9i.
    1212. ∣(−3i)−(9i)∣=∣−12i∣=12|(-3i)-(9i)| = |-12i| = 12.
  39. What is the distance between z1z_1 and z2z_2 if z1−z2=3−4iz_1-z_2=3-4i?
    55. ∣3−4i∣=9+16=5|3-4i| = \sqrt{9+16} = 5.
  40. Find the distance between z1=−2+1iz_1=-2+1i and z2=4−7iz_2=4-7i.
    1010. ∣(−2+1i)−(4−7i)∣=∣−6+8i∣=36+64=10|(-2+1i)-(4-7i)| = |-6+8i| = \sqrt{36+64} = 10.
  41. Identify the distance between z1z_1 and z2z_2 if z1−z2=0+7iz_1-z_2=0+7i.
    77. ∣0+7i∣=∣7i∣=7|0+7i| = |7i| = 7.
  42. What is the distance from the origin to zz in the complex plane, written using modulus?
    ∣z∣|z|. The modulus gives the distance from any point to the origin.
  43. Find the midpoint of z1=3+0iz_1=3+0i and z2=0+4iz_2=0+4i.
    32+2i\frac{3}{2}+2i. (3+0i)+(0+4i)2=3+4i2=32+2i\frac{(3+0i)+(0+4i)}{2} = \frac{3+4i}{2} = \frac{3}{2}+2i.
  44. Find the midpoint of z1=0z_1=0 and z2=6+8iz_2=6+8i.
    3+4i3+4i. 0+(6+8i)2=6+8i2=3+4i\frac{0+(6+8i)}{2} = \frac{6+8i}{2} = 3+4i.
  45. Find the distance between z1=2+3iz_1=2+3i and z2=5+3iz_2=5+3i.
    33. ∣(2+3i)−(5+3i)∣=∣−3∣=3|(2+3i)-(5+3i)| = |-3| = 3.
  46. Find the midpoint of z1=5z_1=5 and z2=−1+4iz_2=-1+4i.
    2+2i2+2i. 5+(−1+4i)2=4+4i2=2+2i\frac{5+(-1+4i)}{2} = \frac{4+4i}{2} = 2+2i.
  47. Identify the complex number that represents the midpoint of points $ (a,b) $ and $ (c,d) $.
    a+c2+b+d2i\frac{a+c}{2}+\frac{b+d}{2}i. Average the real parts and imaginary parts separately.
  48. What is the distance between z1z_1 and z2z_2 if z2=z1+(6+8i)z_2=z_1+(6+8i)?
    1010. ∣6+8i∣=36+64=10|6+8i| = \sqrt{36+64} = 10.
  49. State the formula for the midpoint of endpoints z1z_1 and z2z_2 in the complex plane.
    m=z1+z22m=\frac{z_1+z_2}{2}. Average the two endpoints by adding and dividing by 2.
  50. What is the distance between z1z_1 and z2z_2 if z1−z2=−8+6iz_1-z_2=-8+6i?
    1010. ∣−8+6i∣=64+36=10|-8+6i| = \sqrt{64+36} = 10.
  51. What is the midpoint between z1z_1 and z2z_2 interpreted as geometrically in the complex plane?
    The point halfway along the segment from z1z_1 to z2z_2. The midpoint is equidistant from both endpoints on the line segment.
  52. Find the distance between z1=−2+5iz_1=-2+5i and z2=−2−1iz_2=-2-1i.
    6. ∣(−2+5i)−(−2−1i)∣=∣6i∣=6|(-2+5i)-(-2-1i)| = |6i| = 6

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