Complex Numbers in Rectangular, Polar Form - Algebra 2

  1. Identify the correct principal angle for z=−1+iz=-1+i in polar form.
    3π4\frac{3\pi}{4}. Quadrant II with equal components gives angle 3π4\frac{3\pi}{4}.
  2. What is the polar form of the imaginary number 4i4i using a principal argument?
    4(cos⁡π2+isin⁡π2)4\left(\cos\frac{\pi}{2}+i\sin\frac{\pi}{2}\right). Pure imaginary number 4i4i has angle π2\frac{\pi}{2}.
  3. Find the modulus ∣z∣|z| for z=3+4iz=3+4i.
    55. 32+42=9+16=25=5\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}=5
  4. Which quadrant contains z=a+biz=a+bi if a<0a<0 and b>0b>0?
    Quadrant II\text{II}. Negative real part and positive imaginary part place it in quadrant II.
  5. Convert z=10(cos⁡π6+isin⁡π6)z=10\left(\cos\frac{\pi}{6}+i\sin\frac{\pi}{6}\right) to rectangular form.
    53+5i5\sqrt{3}+5i. cos⁡(π6)=32\cos(\frac{\pi}{6})=\frac{\sqrt{3}}{2} and sin⁡(π6)=12\sin(\frac{\pi}{6})=\frac{1}{2}.
  6. What is Arg⁡(z)\operatorname{Arg}(z) if zz is a positive imaginary number bibi with b>0b>0?
    π2\frac{\pi}{2}. Positive imaginary numbers lie on the positive y-axis.
  7. Convert z=6(cos⁡π4+isin⁡π4)z=6\left(\cos\frac{\pi}{4}+i\sin\frac{\pi}{4}\right) to rectangular form.
    32+32i3\sqrt{2}+3\sqrt{2}i. cos⁡(π4)=22\cos(\frac{\pi}{4})=\frac{\sqrt{2}}{2} and sin⁡(π4)=22\sin(\frac{\pi}{4})=\frac{\sqrt{2}}{2}.
  8. What are cos⁡θ\cos\theta and sin⁡θ\sin\theta in terms of a,b,ra,b,r for z=a+biz=a+bi with r=∣z∣r=|z|?
    cos⁡θ=ar, sin⁡θ=br\cos\theta=\frac{a}{r},\ \sin\theta=\frac{b}{r}. Unit circle relationships connect rectangular and polar coordinates.
  9. Which quadrant contains z=a+biz=a+bi if a<0a<0 and b<0b<0?
    Quadrant III\text{III}. Both real and imaginary parts negative place it in quadrant III.
  10. Find a principal θ\theta for z=3−33iz=3-3\sqrt{3}i (you may leave rr unreported).
    θ=−π3\theta=-\frac{\pi}{3}. Quadrant IV with tan⁡θ=−3\tan\theta=-\sqrt{3} gives principal angle −π3-\frac{\pi}{3}.
  11. Find rr and a principal θ\theta for z=3−iz=\sqrt{3}-i in polar form.
    r=2, θ=−π6r=2,\ \theta=-\frac{\pi}{6}. Quadrant IV with r=2r=2 and reference angle π6\frac{\pi}{6} gives θ=−π6\theta=-\frac{\pi}{6}.
  12. What is the polar form of a complex number zz using modulus rr and angle θ\theta?
    z=r(cos⁡θ+isin⁡θ)z=r(\cos\theta+i\sin\theta). Uses modulus rr and angle θ\theta with trigonometric functions.
  13. What is the polar form of the real number −5-5 using a principal argument?
    5(cos⁡π+isin⁡π)5(\cos\pi+i\sin\pi). Negative real number has angle π\pi and modulus 5.
  14. What is Arg⁡(z)\operatorname{Arg}(z) if zz is a negative imaginary number bibi with b<0b<0?
    −π2-\frac{\pi}{2}. Negative imaginary numbers lie on the negative y-axis.
  15. Convert z=10(cos⁡5π6+isin⁡5π6)z=10\left(\cos\frac{5\pi}{6}+i\sin\frac{5\pi}{6}\right) to rectangular form.
    −53+5i-5\sqrt{3}+5i. cos⁡(5π6)=−32\cos(\frac{5\pi}{6})=-\frac{\sqrt{3}}{2} and sin⁡(5π6)=12\sin(\frac{5\pi}{6})=\frac{1}{2}.
  16. Find the modulus ∣z∣|z| for z=5−12iz=5-12i.
    1313. 52+(−12)2=25+144=169=13\sqrt{5^2+(-12)^2}=\sqrt{25+144}=\sqrt{169}=13
  17. What is the relationship between all arguments of a nonzero complex number zz and its principal argument Arg⁡(z)\operatorname{Arg}(z)?
    arg⁡(z)=Arg⁡(z)+2πk\arg(z)=\operatorname{Arg}(z)+2\pi k. All arguments differ by multiples of 2π2\pi.
  18. Find rr and a principal θ\theta for z=1+3iz=1+\sqrt{3}i in polar form.
    r=2, θ=π3r=2,\ \theta=\frac{\pi}{3}. r=1+3=2r=\sqrt{1+3}=2 and tan⁡θ=31\tan\theta=\frac{\sqrt{3}}{1} gives θ=π3\theta=\frac{\pi}{3}.
  19. What is the meaning of aa and bb in z=a+biz=a+bi on the complex plane?
    a=ℜ(z), b=ℑ(z)a=\Re(z),\ b=\Im(z). aa is the real part and bb is the imaginary part.
  20. What is the geometric meaning of ∣z∣|z| for z=a+biz=a+bi on the complex plane?
    Distance from (0,0)(0,0) to (a,b)(a,b). Represents the distance from the origin to the point.
  21. Find rr and a principal θ\theta for z=−1+3iz=-1+\sqrt{3}i in polar form.
    r=2, θ=2π3r=2,\ \theta=\frac{2\pi}{3}. Quadrant II with r=2r=2 and reference angle π3\frac{\pi}{3} gives θ=2π3\theta=\frac{2\pi}{3}.
  22. What is the principal argument range commonly used for Arg⁡(z)\operatorname{Arg}(z) in Algebra 22?
    −π<Arg⁡(z)≤π-\pi<\operatorname{Arg}(z)\le\pi. Principal value ranges from −π-\pi to π\pi (excluding −π-\pi).
  23. Which quadrant contains z=a+biz=a+bi if a>0a>0 and b<0b<0?
    Quadrant IV\text{IV}. Positive real part and negative imaginary part place it in quadrant IV.
  24. Find rr and a principal θ\theta for z=−3−iz=-\sqrt{3}-i in polar form.
    r=2, θ=−5π6r=2,\ \theta=-\frac{5\pi}{6}. Quadrant III with r=2r=2 and reference angle π6\frac{\pi}{6} gives θ=−5π6\theta=-\frac{5\pi}{6}.
  25. Find the modulus ∣z∣|z| for z=−8−6iz=-8-6i.
    1010. (−8)2+(−6)2=64+36=100=10\sqrt{(-8)^2+(-6)^2}=\sqrt{64+36}=\sqrt{100}=10
  26. What is the polar form of the imaginary number −4i-4i using a principal argument?
    4(cos⁡(−π2)+isin⁡(−π2))4\left(\cos\left(-\frac{\pi}{2}\right)+i\sin\left(-\frac{\pi}{2}\right)\right). Pure imaginary number −4i-4i has angle −π2-\frac{\pi}{2}.
  27. Convert z=5(cos⁡(−π2)+isin⁡(−π2))z=5\left(\cos\left(-\frac{\pi}{2}\right)+i\sin\left(-\frac{\pi}{2}\right)\right) to rectangular form.
    0−5i0-5i. cos⁡(−π2)=0\cos(-\frac{\pi}{2})=0 and sin⁡(−π2)=−1\sin(-\frac{\pi}{2})=-1, so 5(0−1i)=−5i5(0-1i)=-5i.
  28. What is the formula for the modulus of z=a+biz=a+bi?
    ∣z∣=a2+b2|z|=\sqrt{a^2+b^2}. Distance formula from origin to point (a,b)(a,b).
  29. What are the conversion formulas from polar to rectangular for z=r(cos⁡θ+isin⁡θ)z=r(\cos\theta+i\sin\theta)?
    a=rcos⁡θ, b=rsin⁡θa=r\cos\theta,\ b=r\sin\theta. Trigonometric relationships for converting polar to rectangular.
  30. What is the rectangular form of a complex number zz in terms of aa and bb?
    z=a+biz=a+bi. Standard form with real part aa and imaginary part bb.
  31. Find rr and a principal θ\theta for z=1−3iz=1-\sqrt{3}i in polar form.
    r=2, θ=−π3r=2,\ \theta=-\frac{\pi}{3}. Quadrant IV with r=2r=2 and reference angle π3\frac{\pi}{3} gives θ=−π3\theta=-\frac{\pi}{3}.
  32. What is Arg⁡(z)\operatorname{Arg}(z) if zz is a negative real number?
    π\pi. Negative real numbers lie on the negative x-axis.
  33. Find the modulus ∣z∣|z| for z=−6+8iz=-6+8i.
    1010. (−6)2+82=36+64=100=10\sqrt{(-6)^2+8^2}=\sqrt{36+64}=\sqrt{100}=10
  34. Find rr and a principal θ\theta for z=3+iz=\sqrt{3}+i in polar form.
    r=2, θ=π6r=2,\ \theta=\frac{\pi}{6}. r=3+1=2r=\sqrt{3+1}=2 and tan⁡θ=13\tan\theta=\frac{1}{\sqrt{3}} gives θ=π6\theta=\frac{\pi}{6}.
  35. Find a principal θ\theta for z=−3+33iz=-3+3\sqrt{3}i (you may leave rr unreported).
    θ=2π3\theta=\frac{2\pi}{3}. Quadrant II with tan⁡θ=−3\tan\theta=-\sqrt{3} gives principal angle 2π3\frac{2\pi}{3}.
  36. Find rr and a principal θ\theta for z=−3+iz=-\sqrt{3}+i in polar form.
    r=2, θ=5π6r=2,\ \theta=\frac{5\pi}{6}. Quadrant II with r=2r=2 and reference angle π6\frac{\pi}{6} gives θ=5π6\theta=\frac{5\pi}{6}.
  37. What is the cis notation for the polar form r(cos⁡θ+isin⁡θ)r(\cos\theta+i\sin\theta)?
    z=r cis(θ)z=r\,\text{cis}(\theta). Abbreviated notation where cis stands for cosine plus i sine.
  38. State the identity that explains why r(cos⁡θ+isin⁡θ)r(\cos\theta+i\sin\theta) equals a+bia+bi when a=rcos⁡θa=r\cos\theta and b=rsin⁡θb=r\sin\theta.
    r(cos⁡θ+isin⁡θ)=rcos⁡θ+i(rsin⁡θ)r(\cos\theta+i\sin\theta)=r\cos\theta+i(r\sin\theta). Distributive property shows both forms represent the same complex number.
  39. Identify the correct principal angle for z=−1−iz=-1-i in polar form.
    −3π4-\frac{3\pi}{4}. Quadrant III with equal components gives angle −3π4-\frac{3\pi}{4}.
  40. What is the polar form of the real number 55 using a principal argument?
    5(cos⁡0+isin⁡0)5(\cos^0+i\sin^0). Real number 5 has angle 0 and modulus 5.
  41. Convert z=8(cos⁡7π6+isin⁡7π6)z=8\left(\cos\frac{7\pi}{6}+i\sin\frac{7\pi}{6}\right) to rectangular form.
    −43−4i-4\sqrt{3}-4i. cos⁡(7π6)=−32\cos(\frac{7\pi}{6})=-\frac{\sqrt{3}}{2} and sin⁡(7π6)=−12\sin(\frac{7\pi}{6})=-\frac{1}{2}.
  42. Convert z=3(cos⁡π2+isin⁡π2)z=3\left(\cos\frac{\pi}{2}+i\sin\frac{\pi}{2}\right) to rectangular form.
    0+3i0+3i. cos⁡(π2)=0\cos(\frac{\pi}{2})=0 and sin⁡(π2)=1\sin(\frac{\pi}{2})=1, so 3(0+1i)=3i3(0+1i)=3i.
  43. Convert z=8(cos⁡π3+isin⁡π3)z=8\left(\cos\frac{\pi}{3}+i\sin\frac{\pi}{3}\right) to rectangular form.
    4+43i4+4\sqrt{3}i. cos⁡(π3)=12\cos(\frac{\pi}{3})=\frac{1}{2} and sin⁡(π3)=32\sin(\frac{\pi}{3})=\frac{\sqrt{3}}{2}.
  44. What point represents z=a+biz=a+bi on the complex plane (as an ordered pair)?
    (a,b)(a,b). Real part gives x-coordinate, imaginary part gives y-coordinate.
  45. What is Arg⁡(z)\operatorname{Arg}(z) if zz is a positive real number (and z≠0z\ne^0)?
    00. Positive real numbers lie on the positive x-axis.
  46. What are the conversion formulas from rectangular to polar for z=a+biz=a+bi (in terms of r,θr,\theta)?
    r=a2+b2, tan⁡θ=bar=\sqrt{a^2+b^2},\ \tan\theta=\frac{b}{a}. Use distance formula for rr and inverse tangent for θ\theta.
  47. Find rr and a principal θ\theta for z=−1−3iz=-1-\sqrt{3}i in polar form.
    r=2, θ=−2π3r=2,\ \theta=-\frac{2\pi}{3}. Quadrant III with r=2r=2 and reference angle π3\frac{\pi}{3} gives θ=−2π3\theta=-\frac{2\pi}{3}.
  48. Identify the ordered pair on the complex plane corresponding to z=9−3iz=9-3i.
    (9,−3)(9,-3). Complex number maps to point with x-coordinate 99, y-coordinate −3-3.
  49. Convert z=12(cos⁡2π3+isin⁡2π3)z=12\left(\cos\frac{2\pi}{3}+i\sin\frac{2\pi}{3}\right) to rectangular form.
    −6+63i-6+6\sqrt{3}i. cos⁡(2π3)=−12\cos(\frac{2\pi}{3})=-\frac{1}{2} and sin⁡(2π3)=32\sin(\frac{2\pi}{3})=\frac{\sqrt{3}}{2}.
  50. Convert z=12(cos⁡(−π3)+isin⁡(−π3))z=12\left(\cos\left(-\frac{\pi}{3}\right)+i\sin\left(-\frac{\pi}{3}\right)\right) to rectangular form.
    6−63i6-6\sqrt{3}i. cos⁡(−π3)=12\cos(-\frac{\pi}{3})=\frac{1}{2} and sin⁡(−π3)=−32\sin(-\frac{\pi}{3})=-\frac{\sqrt{3}}{2}.
  51. Convert z=6(cos⁡5π4+isin⁡5π4)z=6\left(\cos\frac{5\pi}{4}+i\sin\frac{5\pi}{4}\right) to rectangular form.
    −32−32i-3\sqrt{2}-3\sqrt{2}i. cos⁡(5π4)=−22\cos(\frac{5\pi}{4})=-\frac{\sqrt{2}}{2} and sin⁡(5π4)=−22\sin(\frac{5\pi}{4})=-\frac{\sqrt{2}}{2}.
  52. Identify the ordered pair on the complex plane corresponding to z=−2+7iz=-2+7i.
    (−2,7)(-2,7). Complex number maps to point with x-coordinate −2-2, y-coordinate 77.
  53. Convert z=2(cos⁡0+isin⁡0)z=2(\cos^0+i\sin^0) to rectangular form.
    2+0i2+0i. cos⁡(0)=1\cos(0)=1 and sin⁡(0)=0\sin(0)=0, so 2(1+0i)=22(1+0i)=2.
  54. Convert z=7(cos⁡π+isin⁡π)z=7(\cos\pi+i\sin\pi) to rectangular form.
    −7+0i-7+0i. cos⁡(π)=−1\cos(\pi)=-1 and sin⁡(π)=0\sin(\pi)=0, so 7(−1+0i)=−77(-1+0i)=-7.

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