Arithmetic and Geometric Sequences as Functions - Algebra 2

  1. Model: A population starts at 800800 and grows by 6%6\% each year. What is ana_n?
    an=800⋅1.06n−1a_n=800\cdot 1.06^{n-1}. Geometric sequence: each year multiplied by growth factor 1.061.06.
  2. What is the explicit formula for the arithmetic sequence with a1=12a_1=12 and d=−3d=-3?
    an=12+(n−1)(−3)a_n=12+(n-1)(-3). Uses the standard explicit formula with a1=12a_1=12 and d=−3d=-3.
  3. Find the common difference dd if an arithmetic sequence has a3=10a_3=10 and a8=35a_8=35.
    d=5d=5. Using d=am−akm−kd=\frac{a_m-a_k}{m-k}: d=35−108−3=255=5d=\frac{35-10}{8-3}=\frac{25}{5}=5.
  4. What is the explicit formula for the geometric sequence with a1=2a_1=2 and r=14r=\frac{1}{4}?
    an=2(14)n−1a_n=2\left(\frac{1}{4}\right)^{n-1}. Uses the standard explicit formula with a1=2a_1=2 and r=14r=\frac{1}{4}.
  5. Find a7a_7 for the arithmetic sequence an=2+5(n−1)a_n=2+5(n-1).
    a7=32a_7=32. Using an=2+5(n−1)a_n=2+5(n-1): a7=2+5(6)=2+30=32a_7=2+5(6)=2+30=32.
  6. Model: A bouncing ball reaches 120120 cm, then 75%75\% of the previous height each bounce. What is ana_n?
    an=120⋅0.75n−1a_n=120\cdot 0.75^{n-1}. Geometric sequence: each bounce multiplied by factor 0.750.75.
  7. Model: A car value is $18,000\$18{,}000 and depreciates 12%12\% yearly. What is ana_n?
    an=18000⋅0.88n−1a_n=18000\cdot 0.88^{n-1}. Geometric sequence: each year multiplied by decay factor 0.880.88.
  8. Model: A salary starts at $40,000\$40{,}000 and increases by $1,500\$1{,}500 yearly. What is ana_n?
    an=40000+1500(n−1)a_n=40000+1500(n-1). Arithmetic sequence: constant yearly increase of $1,500\$1{,}500.
  9. Translate to explicit form: a1=5a_1=5, an=12an−1a_n=\frac{1}{2}a_{n-1} for n≥2n\ge^2.
    an=5(12)n−1a_n=5\left(\frac{1}{2}\right)^{n-1}. Converting recursive to explicit: r=12r=\frac{1}{2}, so an=5(12)n−1a_n=5\left(\frac{1}{2}\right)^{n-1}.
  10. Use an=ak⋅rn−ka_n=a_k\cdot r^{n-k}: If a3=16a_3=16 and r=12r=\frac{1}{2}, what is a7a_7?
    a7=1a_7=1. Using the general form: a7=16⋅(12)7−3=16⋅116=1a_7=16\cdot\left(\frac{1}{2}\right)^{7-3}=16\cdot\frac{1}{16}=1.
  11. What is the explicit formula for an arithmetic sequence with first term a1a_1 and common difference dd?
    an=a1+(n−1)da_n=a_1+(n-1)d. Standard explicit form adds (n−1)(n-1) copies of dd to the first term.
  12. Find the explicit formula if an arithmetic sequence has a1=−1a_1=-1 and a5=11a_5=11.
    an=−1+3(n−1)a_n=-1+3(n-1). From a1=−1a_1=-1 and a5=11a_5=11: d=11−(−1)5−1=3d=\frac{11-(-1)}{5-1}=3.
  13. Identify the missing term to keep it arithmetic: 2, □, 10, 142,\,\square,\,10,\,14.
    66. Arithmetic mean of 22 and 1010 gives the middle term.
  14. Find a5a_5 for the geometric sequence with a1=3a_1=3 and r=2r=2.
    a5=48a_5=48. Using an=a1⋅rn−1a_n=a_1\cdot r^{n-1}: a5=3⋅25−1=3⋅16=48a_5=3\cdot 2^{5-1}=3\cdot 16=48.
  15. What is the explicit formula for an arithmetic sequence written from term aka_k instead of a1a_1?
    an=ak+(n−k)da_n=a_k+(n-k)d. General explicit form starting from any known term aka_k.
  16. Find rr if a geometric sequence has an=10⋅(32)n−1a_n=10\cdot\left(\frac{3}{2}\right)^{n-1}.
    r=32r=\frac{3}{2}. The base of the exponent gives the common ratio directly.
  17. What is the explicit formula for a geometric sequence written from term aka_k instead of a1a_1?
    an=ak⋅rn−ka_n=a_k\cdot r^{n-k}. General explicit form starting from any known term aka_k.
  18. Find the geometric mean between 44 and 3636 (assume positive).
    1212. Using ab\sqrt{ab}: 4⋅36=144=12\sqrt{4\cdot 36}=\sqrt{144}=12.
  19. What is the formula for the common ratio rr using two terms aka_k and ama_m of a geometric sequence?
    r=(amak)1m−kr=\left(\frac{a_m}{a_k}\right)^{\frac{1}{m-k}}. Ratio formula using the (m−k)(m-k)th root of the term quotient.
  20. Identify whether an=2n+1a_n=2n+1 defines an arithmetic or geometric sequence.
    Arithmetic. Linear form an=2n+1a_n=2n+1 has constant differences between consecutive terms.
  21. Find and correct the error: Arithmetic explicit written as an=a1+nda_n=a_1+nd.
    Correct: an=a1+(n−1)da_n=a_1+(n-1)d. The exponent should be (n−1)(n-1), not nn, for standard form.
  22. Find the recursive form if a geometric sequence has a1=10a_1=10 and a2=−5a_2=-5.
    a1=10a_1=10; an=−12an−1a_n=-\frac{1}{2}a_{n-1}. From consecutive terms: r=a2a1=−510=−12r=\frac{a_2}{a_1}=\frac{-5}{10}=-\frac{1}{2}.
  23. Identify the arithmetic sequence: 3,7,11,15,…3,7,11,15,\dots; what is the common difference dd?
    d=4d=4. Each term increases by 44: 7−3=47-3=4, 11−7=411-7=4, etc.
  24. What is the recursive definition for the geometric sequence with a1=9a_1=9 and r=−2r=-2?
    a1=9a_1=9; an=−2 an−1a_n=-2\,a_{n-1}. Standard recursive form with given first term and ratio.
  25. Translate to recursive form: an=8⋅(−3)n−1a_n=8\cdot(-3)^{n-1} with n≥1n\ge^1.
    a1=8a_1=8; an=−3 an−1a_n=-3\,a_{n-1}. Converting explicit to recursive: a1=8a_1=8 and r=−3r=-3.
  26. Find a1a_1 for a geometric sequence with a3=36a_3=36 and r=3r=3.
    a1=4a_1=4. Working backwards: a1=a3r2=3632=369=4a_1=\frac{a_3}{r^2}=\frac{36}{3^2}=\frac{36}{9}=4.
  27. Translate to explicit form: a1=7a_1=7, an=an−1−2a_n=a_{n-1}-2 for n≥2n\ge^2.
    an=7+(n−1)(−2)a_n=7+(n-1)(-2). Converting recursive to explicit: d=−2d=-2, so an=7+(n−1)(−2)a_n=7+(n-1)(-2).
  28. Identify which is geometric: an=12−3na_n=12-3n or an=12(−3)n−1a_n=12\left(-3\right)^{n-1}?
    an=12(−3)n−1a_n=12\left(-3\right)^{n-1}. Exponential function has constant ratios; linear has constant differences.
  29. Find a6a_6 for the arithmetic sequence with a1=4a_1=4 and d=7d=7.
    a6=39a_6=39. Using an=a1+(n−1)da_n=a_1+(n-1)d: a6=4+(6−1)(7)=4+35=39a_6=4+(6-1)(7)=4+35=39.
  30. Identify which is arithmetic: an=5n−2a_n=5n-2 or an=5⋅2n−1a_n=5\cdot 2^{n-1}?
    an=5n−2a_n=5n-2. Linear function has constant differences; exponential has constant ratios.
  31. Identify the geometric sequence: 5,15,45,135,…5,15,45,135,\dots; what is the common ratio rr?
    r=3r=3. Each term is multiplied by 33: 15÷5=315÷5=3, 45÷15=345÷15=3, etc.
  32. Find the arithmetic mean between 88 and 2020.
    1414. Using a+b2\frac{a+b}{2}: 8+202=282=14\frac{8+20}{2}=\frac{28}{2}=14.
  33. What is the explicit formula for a geometric sequence with first term a1a_1 and common ratio rr?
    an=a1⋅rn−1a_n=a_1\cdot r^{n-1}. Standard explicit form multiplies a1a_1 by rr raised to power (n−1)(n-1).
  34. What is the arithmetic mean formula that gives the middle term between aa and bb in an arithmetic sequence?
    a+b2\frac{a+b}{2}. Average of two consecutive terms in an arithmetic sequence.
  35. Model: You save $50 the first week and increase by $10 weekly. What is ana_n?
    an=50+10(n−1)a_n=50+10(n-1). Arithmetic sequence: constant weekly increase of $10.
  36. Identify whether an=7⋅5na_n=7\cdot 5^{n} defines an arithmetic or geometric sequence.
    Geometric. Exponential form an=7⋅5na_n=7\cdot 5^n has constant ratios between consecutive terms.
  37. Find a6a_6 for the geometric sequence an=(−2)⋅3n−1a_n=\left(-2\right)\cdot 3^{n-1}.
    a6=−486a_6=-486. Using an=(−2)⋅3n−1a_n=(-2)\cdot 3^{n-1}: a6=(−2)⋅35=(−2)⋅243=−486a_6=(-2)\cdot 3^5=(-2)\cdot 243=-486.
  38. What is the recursive definition for the arithmetic sequence with a1=−5a_1=-5 and d=6d=6?
    a1=−5a_1=-5; an=an−1+6a_n=a_{n-1}+6. Standard recursive form with given first term and difference.
  39. What is the recursive definition for an arithmetic sequence with first term a1a_1 and difference dd?
    a1a_1 given; an=an−1+da_n=a_{n-1}+d for n≥2n\ge^2. Each term equals the previous term plus the common difference.
  40. What is the formula for the common difference dd using two terms aka_k and ama_m of an arithmetic sequence?
    d=am−akm−kd=\frac{a_m-a_k}{m-k}. Difference formula: change in terms divided by change in positions.
  41. Which option is the common ratio for the geometric sequence −4,12,−36,108,…-4,12,-36,108,\dots?
    r=−3r=-3. Each term is multiplied by −3-3: 12÷(−4)=−312÷(-4)=-3.
  42. Find and correct the error: Geometric explicit written as an=a1⋅rna_n=a_1\cdot r^{n}.
    Correct: an=a1⋅rn−1a_n=a_1\cdot r^{n-1}. The exponent should be (n−1)(n-1), not nn, for standard form.
  43. Translate to recursive form: an=3+4(n−1)a_n=3+4(n-1) with n≥1n\ge^1.
    a1=3a_1=3; an=an−1+4a_n=a_{n-1}+4. Converting explicit to recursive: a1=3a_1=3 and d=4d=4.
  44. Find the common ratio rr if a geometric sequence has a2=6a_2=6 and a5=48a_5=48.
    r=2r=2. Using r=(amak)1m−kr=\left(\frac{a_m}{a_k}\right)^{\frac{1}{m-k}}: r=(486)13=813=2r=\left(\frac{48}{6}\right)^{\frac{1}{3}}=8^{\frac{1}{3}}=2.
  45. Identify the missing term to keep it geometric: 3, □, 12, 243,\,\square,\,12,\,24.
    66. Geometric mean of 33 and 1212 gives the middle term.
  46. Which option is the common difference for the arithmetic sequence −2,1,4,7,…-2,1,4,7,\dots?
    d=3d=3. Each term increases by the same amount: 1−(−2)=31-(-2)=3.
  47. Find the recursive form if an arithmetic sequence has a1=9a_1=9 and a2=4a_2=4.
    a1=9a_1=9; an=an−1−5a_n=a_{n-1}-5. From consecutive terms: d=a2−a1=4−9=−5d=a_2-a_1=4-9=-5.
  48. What is the geometric mean formula that gives the middle positive term between aa and bb in a geometric sequence?
    ab\sqrt{ab}. Square root of the product of two consecutive positive terms.
  49. Find dd if an arithmetic sequence has an=18−6(n−1)a_n=18-6(n-1).
    d=−6d=-6. The coefficient of (n−1)(n-1) gives the common difference directly.
  50. Use an=ak+(n−k)da_n=a_k+(n-k)d: If a4=9a_4=9 and d=2d=2, what is a10a_{10}?
    a10=21a_{10}=21. Using the general form: a10=9+(10−4)(2)=9+12=21a_{10}=9+(10-4)(2)=9+12=21.
  51. Find the explicit formula if a geometric sequence has a1=6a_1=6 and a4=48a_4=48.
    an=6⋅2n−1a_n=6\cdot 2^{n-1}. From a1=6a_1=6 and a4=48a_4=48: r=(486)13=2r=\left(\frac{48}{6}\right)^{\frac{1}{3}}=2.
  52. Find a1a_1 for an arithmetic sequence with a4=20a_4=20 and d=3d=3.
    a1=11a_1=11. Working backwards: a1=a4−3d=20−3(3)=20−9=11a_1=a_4-3d=20-3(3)=20-9=11.
  53. What is the recursive definition for a geometric sequence with first term a1a_1 and ratio rr?
    a1a_1 given; an=r⋅an−1a_n=r\cdot a_{n-1} for n≥2n\ge^2. Each term equals the previous term multiplied by the common ratio.

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