Applying the Binomial Theorem - Algebra 2

  1. What is the coefficient of x6y4x^6y^4 in (x+y)10(x+y)^{10}?
    (104)=210\binom{10}{4}=210. The coefficient of x6y4x^6y^4 is (104)=210\binom{10}{4}=210.
  2. What is the coefficient of x5yx^5y in (x−y)6(x-y)^6?
    −(61)=−6-\binom{6}{1}=-6. The coefficient is (61)=6\binom{6}{1}=6 with negative sign from (−y)1(-y)^1.
  3. What is the coefficient of x3x^3 in (x+2)5(x+2)^5?
    (52)22=40\binom{5}{2}2^2=40. From term (52)x3(2)2=10⋅4x3=40x3\binom{5}{2}x^3(2)^2=10 \cdot 4x^3=40x^3.
  4. Find the two middle terms of (x+y)7(x+y)^7.
    35x4y335x^4y^3 and 35x3y435x^3y^4. For odd n=7n=7, terms 4 and 5 are both middle terms.
  5. Find the value of (82)\binom{8}{2}.
    2828. Using (82)=8!2!6!=8⋅72=28\binom{8}{2}=\frac{8!}{2!6!}=\frac{8 \cdot 7}{2}=28.
  6. State the Binomial Theorem formula for expanding (x+y)n(x+y)^n using binomial coefficients.
    (x+y)n=∑k=0n(nk)xn−kyk(x+y)^n=\sum_{k=0}^{n}\binom{n}{k}x^{n-k}y^k. The general formula for binomial expansion with coefficients and powers.
  7. What are the values of (n0)\binom{n}{0} and (nn)\binom{n}{n} for any positive integer nn?
    (n0)=1\binom{n}{0}=1 and (nn)=1\binom{n}{n}=1. Only one way to choose all or none of the elements.
  8. Identify the term containing x3x^3 in the expansion of (x+y)5(x+y)^5.
    (52)x3y2=10x3y2\binom{5}{2}x^3y^2=10x^3y^2. The term with y2y^2 gives (52)x3y2=10x3y2\binom{5}{2}x^3y^2=10x^3y^2.
  9. What is the coefficient of x7y2x^7y^2 in (x+y)9(x+y)^9?
    (92)=36\binom{9}{2}=36. The coefficient of x7y2x^7y^2 is (92)=36\binom{9}{2}=36.
  10. Expand (x−y)3(x-y)^3.
    x3−3x2y+3xy2−y3x^3-3x^2y+3xy^2-y^3. Alternating signs from (−y)k(-y)^k with coefficients 1,3,3,11,3,3,1.
  11. In (x+y)n(x+y)^n, what is the exponent of xx in the term containing yky^k?
    n−kn-k. Exponents of xx and yy must sum to nn.
  12. What is the factorial definition of the binomial coefficient (nk)\binom{n}{k}?
    (nk)=n!k!(n−k)!\binom{n}{k}=\frac{n!}{k!(n-k)!}. Uses factorial formula to calculate combinations.
  13. Find the value of (94)\binom{9}{4}.
    126126. Using (94)=9!4!5!=126\binom{9}{4}=\frac{9!}{4!5!}=126.
  14. Expand (x+y)3(x+y)^3.
    x3+3x2y+3xy2+y3x^3+3x^2y+3xy^2+y^3. Using coefficients 1,3,3,11,3,3,1 from Pascal's triangle.
  15. Find the value of (103)\binom{10}{3}.
    120120. Using (103)=10⋅9⋅86=120\binom{10}{3}=\frac{10 \cdot 9 \cdot 8}{6}=120.
  16. Expand (x+y)4(x+y)^4.
    x4+4x3y+6x2y2+4xy3+y4x^4+4x^3y+6x^2y^2+4xy^3+y^4. Using coefficients 1,4,6,4,11,4,6,4,1 from Pascal's triangle.
  17. What is the coefficient of x2x^2 in (3x−2)5(3x-2)^5?
    (52)32(−2)3=−720\binom{5}{2}3^2(-2)^3=-720. From term (52)(3x)2(−2)3=10⋅9⋅(−8)x2=−720x2\binom{5}{2}(3x)^2(-2)^3=10 \cdot 9 \cdot (-8)x^2=-720x^2.
  18. What is the constant term of (x−2)7(x-2)^7?
    (−2)7=−128(-2)^7=-128. The last term with x0x^0 gives (−2)7=−128(-2)^7=-128.
  19. What is the coefficient pattern (Pascal row) for expanding (x+y)6(x+y)^6?
    1,6,15,20,15,6,11,6,15,20,15,6,1. Row 6 of Pascal's triangle.
  20. Expand (x+y)2(x+y)^2.
    x2+2xy+y2x^2+2xy+y^2. Using coefficients 1,2,11,2,1 from Pascal's triangle.
  21. What is the coefficient of x4x^4 in (1−2x)6(1-2x)^6?
    (64)(−2)4=240\binom{6}{4}(-2)^4=240. From term (64)(1)2(−2x)4=15⋅16x4=240x4\binom{6}{4}(1)^2(-2x)^4=15 \cdot 16x^4=240x^4.
  22. In (x+y)n(x+y)^n, what is the general term (the kkth term) written in powers of xx and yy?
    (nk)xn−kyk\binom{n}{k}x^{n-k}y^k. The (k+1)(k+1)th term in the binomial expansion.
  23. What is the coefficient of x4y4x^4y^4 in (x−y)8(x-y)^8?
    (84)=70\binom{8}{4}=70. Coefficient is (84)=70\binom{8}{4}=70 with positive sign from (−y)4(-y)^4.
  24. How many terms are in the expanded form of (x+y)n(x+y)^n when like terms are combined?
    n+1n+1. Terms range from k=0k=0 to k=nk=n.
  25. What is the coefficient of x5x^5 in (2x+1)7(2x+1)^7?
    (75)25=672\binom{7}{5}2^5=672. From term (75)(2x)5(1)2=21⋅32x5=672x5\binom{7}{5}(2x)^5(1)^2=21 \cdot 32x^5=672x^5.
  26. Find the value of (101)\binom{10}{1}.
    1010. Using (101)=10\binom{10}{1}=10.
  27. What is the constant term of (2x−5)6(2x-5)^6?
    (−5)6=15625(-5)^6=15625. The last term with (2x)0(2x)^0 gives (−5)6=15625(-5)^6=15625.
  28. Identify the term containing y4y^4 in the expansion of (x+y)7(x+y)^7.
    (74)x3y4=35x3y4\binom{7}{4}x^3y^4=35x^3y^4. The term with x3x^3 gives (74)x3y4=35x3y4\binom{7}{4}x^3y^4=35x^3y^4.
  29. Identify the coefficient of the x2y3x^2y^3 term in (x+y)5(x+y)^5.
    (53)=10\binom{5}{3}=10. The coefficient of x2y3x^2y^3 is (53)=10\binom{5}{3}=10.
  30. Find the middle term of (x+y)8(x+y)^8.
    (84)x4y4=70x4y4\binom{8}{4}x^4y^4=70x^4y^4. For even n=8n=8, the middle term is (84)x4y4=70x4y4\binom{8}{4}x^4y^4=70x^4y^4.
  31. What is the coefficient of x4x^4 in (x+2)6(x+2)^6?
    (62)22=60\binom{6}{2}2^2=60. From term (62)x4(2)2=15⋅4x4=60x4\binom{6}{2}x^4(2)^2=15 \cdot 4x^4=60x^4.
  32. What is the coefficient of x2x^2 in (x−3)4(x-3)^4?
    (42)(−3)2=54\binom{4}{2}(-3)^2=54. From term (42)x2(−3)2=6⋅9x2=54x2\binom{4}{2}x^2(-3)^2=6 \cdot 9x^2=54x^2.
  33. Find the two middle terms of (x+y)7(x + y)^7.
    35x4y335x^4y^3 and 35x3y435x^3y^4. For odd $ n=7 $, terms 4 and 5 are both middle terms.
  34. Expand (x−y)4(x-y)^4.
    x4−4x3y+6x2y2−4xy3+y4x^4-4x^3y+6x^2y^2-4xy^3+y^4. Alternating signs from (−y)k(-y)^k with coefficients 1,4,6,4,11,4,6,4,1.
  35. Identify the sign pattern of terms in (x−y)n(x-y)^n as kk increases in (nk)xn−k(−y)k\binom{n}{k}x^{n-k}(-y)^k.
    Signs alternate by (−1)k(-1)^k. The factor (−1)k(-1)^k creates alternating positive and negative terms.
  36. What is the symmetry identity for binomial coefficients relating (nk)\binom{n}{k} and (nn−k)\binom{n}{n-k}?
    (nk)=(nn−k)\binom{n}{k}=\binom{n}{n-k}. Choosing kk from nn equals choosing n−kn-k from nn.
  37. What is the coefficient of x2y4x^2y^4 in (x−y)6(x-y)^6?
    (64)=15\binom{6}{4}=15. The coefficient is (64)=15\binom{6}{4}=15 with positive sign from (−y)4(-y)^4.
  38. What is the coefficient of a2b4a^2b^4 in (a+b)6(a+b)^6?
    (64)=15\binom{6}{4}=15. The coefficient of a2b4a^2b^4 is (64)=15\binom{6}{4}=15.
  39. What is the coefficient sum of (x−y)n(x-y)^n (equivalently, evaluate at x=1,y=1x=1,y=1)?
    00 if nn is odd; 2n2^n if nn is even. Substitute x=1x=1 and y=−1y=-1 into (x−y)n(x-y)^n.
  40. Find the value of (86)\binom{8}{6}.
    2828. Using symmetry: (86)=(82)=28\binom{8}{6}=\binom{8}{2}=28.
  41. What is the coefficient pattern (Pascal row) for expanding (x+y)3(x+y)^3?
    1,3,3,11,3,3,1. Row 3 of Pascal's triangle.
  42. What is the coefficient of a4b2a^4b^2 in (a+b)6(a+b)^6?
    (62)=15\binom{6}{2}=15. The coefficient of a4b2a^4b^2 is (62)=15\binom{6}{2}=15.
  43. What is the coefficient pattern (Pascal row) for expanding (x+y)5(x+y)^5?
    1,5,10,10,5,11,5,10,10,5,1. Row 5 of Pascal's triangle.
  44. In (x+y)n(x+y)^n, what is the exponent of yy in the term containing xn−kx^{n-k}?
    kk. Exponents of xx and yy must sum to nn.
  45. What is the coefficient of x3y5x^3y^5 in (x+y)8(x+y)^8?
    (85)=56\binom{8}{5}=56. The coefficient of x3y5x^3y^5 is (85)=56\binom{8}{5}=56.
  46. Find the value of (102)\binom{10}{2}.
    4545. Using (102)=10⋅92=45\binom{10}{2}=\frac{10 \cdot 9}{2}=45.
  47. What is the coefficient of x5y3x^5y^3 in (x−y)8(x-y)^8?
    −(83)=−56-\binom{8}{3}=-56. Coefficient is (83)=56\binom{8}{3}=56 with negative sign from (−y)3(-y)^3.
  48. What is the sum of the coefficients of (x+y)n(x+y)^n (equivalently, evaluate at x=1,y=1x=1,y=1)?
    2n2^n. Substitute x=1x=1 and y=1y=1 into (x+y)n(x+y)^n.
  49. What is the coefficient of x3y3x^3y^3 in (x+y)6(x+y)^6?
    (63)=20\binom{6}{3}=20. The coefficient of x3y3x^3y^3 is (63)=20\binom{6}{3}=20.
  50. What is the coefficient pattern (Pascal row) for expanding (x+y)4(x+y)^4?
    1,4,6,4,11,4,6,4,1. Row 4 of Pascal's triangle.
  51. What is Pascal's identity for binomial coefficients?
    (nk)=(n−1k)+(n−1k−1)\binom{n}{k}=\binom{n-1}{k}+\binom{n-1}{k-1}. Each coefficient equals the sum of two above it in Pascal's triangle.

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