Solving Quadratic Equations with Complex Solutions - Algebra 1
- Simplify in simplest form.
- . .
- Simplify in simplest form.
- . .
- Which condition on guarantees two nonreal complex solutions?
- . Negative discriminant means the square root involves .
- Identify whether has real solutions or complex solutions.
- Real solutions (a repeated real root). , indicating one repeated real root.
- Solve .
- . Take square root: .
- Solve .
- . , so solutions involve .
- Solve .
- . , then divide by .
- Solve .
- . , yielding complex solutions.
- Solve .
- . , so solutions are complex.
- Solve .
- . Rearrange to , then .
- Solve .
- . , so use quadratic formula with .
- Solve .
- . , yielding complex solutions.
- Solve .
- . Take square root of both sides: .
- Identify the sum of roots of in terms of and .
- . Vieta's formula: sum of roots equals .
- Find the discriminant of .
- . .
- Identify the complex conjugate of .
- . Change the sign of the imaginary part.
- Solve .
- . , so solutions are complex.
- State the result of completing the square on .
- . Add and subtract to create a perfect square trinomial.
- What is the sum of the solutions to ?
- . Sum of roots .
- State the vertex -coordinate formula for .
- . Found by setting the derivative equal to zero or completing the square.
- What is written as a complex unit?
- . The imaginary unit, defined as .
- What is the discriminant of ?
- . The expression under the square root in the quadratic formula.
- Solve .
- . , so solutions are complex.
- Identify the real part and imaginary part of the solution .
- Real part , imaginary part . In form, is real part and is imaginary part.
- Find the discriminant of .
- . .
- What are the solutions of ?
- . Rearrange to , then .
- Solve by completing the square.
- . Complete the square: , so .
- Solve .
- . , then divide by .
- Solve .
- . , giving complex solutions.
- What is the product of the solutions to ?
- . Product of roots .
- Solve by completing the square.
- . Complete the square: , so .
- What relationship do nonreal solutions have for a quadratic with real coefficients?
- They occur as conjugate pairs . Complex Conjugate Root Theorem for polynomials with real coefficients.
- Solve .
- . , so solutions involve .
- Solve .
- . , so solutions are complex.
- Solve .
- . , so solutions are nonreal.
- Solve .
- . , so solutions involve .
- Solve .
- . Take square root: .
- Solve .
- . , then divide by .
- Solve .
- . Take square root: .
- What is the standard simplification for when ?
- . Factor out from under the radical: .
- State the quadratic formula for solutions of .
- . Derived by completing the square or using algebraic manipulation.
- Solve .
- . , then divide by .
- Solve .
- . , giving complex solutions.
- Simplify .
- . .
- What are the solutions of ?
- . Rearrange to , then .
- Simplify in simplest form.
- . .
- Identify whether has real solutions or complex solutions.
- Complex solutions (nonreal). , indicating nonreal solutions.
- Identify the product of roots of in terms of and .
- . Vieta's formula: product of roots equals .
- Solve .
- . , giving complex solutions.
- Solve .
- . , then divide by .
- Solve .
- . , yielding complex solutions.