Rewrite Exponential Expressions Using Exponents - Algebra 1

  1. Rewrite 8t38^{\frac{t}{3}} as a power with exponent tt.
    8t3=2t8^{\frac{t}{3}} = 2^t. Since 8=238 = 2^3, we get (23)t/3=2t(2^3)^{t/3} = 2^t.
  2. State the exponent rule that rewrites (am)n(a^m)^n as a single power.
    (am)n=amn(a^m)^n = a^{mn}. Power of a power rule: multiply the exponents.
  3. Rewrite 1.21t1.21^t to show a quarterly factor raised to 4t4t.
    1.21t=(1.2114)4t1.21^t = \left(1.21^{\frac{1}{4}}\right)^{4t}. Rewrites annual factor as quarterly factor raised to 4 times the power.
  4. Rewrite 26t2^{6t} as a base raised to tt.
    26t=64t2^{6t} = 64^t. Since 26=642^6 = 64, using power of a power rule gives 64t64^t.
  5. State the exponent rule that rewrites aman\frac{a^m}{a^n} as a single power (for a≠0a \neq 0).
    aman=am−n\frac{a^m}{a^n} = a^{m-n}. Quotient of powers rule: subtract the exponents when bases are equal.
  6. Identify the annual factor aa if the annual interest rate is RR (as a decimal).
    a=1+Ra = 1 + R. Growth factor is 1 plus the interest rate.
  7. Identify the equivalent weekly factor if the annual factor is 0.800.80.
    0.801520.80^{\frac{1}{52}}. Weekly factor is the 52nd root of the annual factor.
  8. Rewrite 103t10t\frac{10^{3t}}{10^{t}} as a base raised to tt.
    103t10t=102t=100t\frac{10^{3t}}{10^{t}} = 10^{2t} = 100^t. Quotient rule gives 102t10^{2t}, then (102)t=100t(10^2)^t = 100^t.
  9. Rewrite (1.52)t\left(1.5^2\right)^t as a single exponential expression with base 1.51.5.
    (1.52)t=1.52t\left(1.5^2\right)^t = 1.5^{2t}. Power of a power rule: (1.52)t=1.52t(1.5^2)^t = 1.5^{2t}.
  10. Find and correct the error: 52t5t=52t\frac{5^{2t}}{5^t} = 5^{2t}.
    Correct: 52t5t=5t\frac{5^{2t}}{5^t} = 5^t. Quotient rule subtracts exponents: 2t−t=t2t - t = t, not 2t2t.
  11. Rewrite 2t+12t−2\frac{2^{t+1}}{2^{t-2}} as a constant (no variable exponent).
    2t+12t−2=23=8\frac{2^{t+1}}{2^{t-2}} = 2^3 = 8. Quotient rule: 2t+12t−2=2(t+1)−(t−2)=23=8\frac{2^{t+1}}{2^{t-2}} = 2^{(t+1)-(t-2)} = 2^3 = 8.
  12. State the exponent rule for rewriting (ab)n\left(\frac{a}{b}\right)^n for b≠0b \neq 0.
    (ab)n=anbn\left(\frac{a}{b}\right)^n = \frac{a^n}{b^n}. Quotient to power rule: distribute the exponent to numerator and denominator.
  13. What transformation rewrites btb^t as an equivalent expression with exponent ktkt?
    bt=(b1k)ktb^t = \left(b^{\frac{1}{k}}\right)^{kt}. Uses power of a power rule: (b1/k)kt=b(1/k)⋅kt=bt(b^{1/k})^{kt} = b^{(1/k) \cdot kt} = b^t.
  14. Find and correct the error: (1.10t)12=1.10t+12\left(1.10^t\right)^{12} = 1.10^{t+12}.
    Correct: (1.10t)12=1.1012t\left(1.10^t\right)^{12} = 1.10^{12t}. Power of a power rule multiplies exponents, not adds them.
  15. Rewrite 27t327^{\frac{t}{3}} as a base raised to tt.
    27t3=3t27^{\frac{t}{3}} = 3^t. Since 27=3327 = 3^3, we get (33)t/3=3t(3^3)^{t/3} = 3^t.
  16. What is the monthly factor mm for a 15%15\% annual rate, written exactly using exponents?
    m=1.15112m = 1.15^{\frac{1}{12}}. 15% annually means factor 1.15, so monthly is 1.151/121.15^{1/12}.
  17. Identify the monthly interest rate rr if the monthly factor is mm.
    r=m−1r = m - 1. Interest rate is the growth factor minus 1.
  18. Identify the daily growth factor dd if the annual factor is aa and there are 365365 days.
    d=a1365d = a^{\frac{1}{365}}. Daily factor is the 365th root of the annual factor.
  19. Rewrite (7t)(7−t)\left(7^t\right)\left(7^{-t}\right) as a constant.
    (7t)(7−t)=70=1\left(7^t\right)\left(7^{-t}\right) = 7^0 = 1. Product rule: 7t⋅7−t=7t+(−t)=70=17^t \cdot 7^{-t} = 7^{t+(-t)} = 7^0 = 1.
  20. Rewrite atna^{\frac{t}{n}} as a power with exponent tt.
    atn=(a1n)ta^{\frac{t}{n}} = \left(a^{\frac{1}{n}}\right)^t. Uses power of a power rule to rewrite with exponent tt.
  21. Rewrite 1.15t1.15^t in the form (1.15112)12t\left(1.15^{\frac{1}{12}}\right)^{12t}.
    1.15t=(1.15112)12t1.15^t = \left(1.15^{\frac{1}{12}}\right)^{12t}. Applies the power of a power rule: (a1/n)nt=at(a^{1/n})^{nt} = a^t.
  22. What is the general formula for the periodic factor if aa is the factor per 1 time unit and there are nn periods?
    period factor=a1n\text{period factor} = a^{\frac{1}{n}}. Periodic factor is the nth root of the factor per unit time.
  23. Rewrite (0.99)365t\left(0.99\right)^{365t} as an equivalent annual factor raised to tt.
    (0.99)365t=(0.99365)t\left(0.99\right)^{365t} = \left(0.99^{365}\right)^t. Power of a power rule: (0.99365)t=0.99365t(0.99^{365})^t = 0.99^{365t}.
  24. Rewrite 43t4^{3t} as a power with exponent tt.
    43t=64t4^{3t} = 64^t. Since 43=644^3 = 64, using power of a power rule gives (43)t=64t(4^3)^t = 64^t.
  25. State the exponent rule for rewriting (ab)n(ab)^n.
    (ab)n=anbn(ab)^n = a^n b^n. Product to power rule: distribute the exponent to each factor.
  26. Rewrite (94)t2\left(\frac{9}{4}\right)^{\frac{t}{2}} as a base raised to tt.
    (94)t2=(32)t\left(\frac{9}{4}\right)^{\frac{t}{2}} = \left(\frac{3}{2}\right)^t. Since 9/4=(3/2)29/4 = (3/2)^2, we get ((3/2)2)t/2=(3/2)t((3/2)^2)^{t/2} = (3/2)^t.
  27. Rewrite 9t29^{\frac{t}{2}} as a base raised to tt.
    9t2=3t9^{\frac{t}{2}} = 3^t. Since 9=329 = 3^2, we get (32)t/2=3t(3^2)^{t/2} = 3^t.
  28. What is the definition of a zero exponent for a≠0a \neq 0?
    a0=1a^0 = 1. Any nonzero base raised to the zero power equals 1.
  29. Rewrite 16t416^{\frac{t}{4}} as a base raised to tt.
    16t4=2t16^{\frac{t}{4}} = 2^t. Since 16=2416 = 2^4, we get (24)t/4=2t(2^4)^{t/4} = 2^t.
  30. Rewrite ((3t)2)4\left(\left(3^t\right)^2\right)^4 as a single exponential expression.
    ((3t)2)4=38t\left(\left(3^t\right)^2\right)^4 = 3^{8t}. Applying power rules repeatedly: ((3t)2)4=(32t)4=38t((3^t)^2)^4 = (3^{2t})^4 = 3^{8t}.
  31. Identify the monthly growth factor mm if the annual factor is aa and there are 1212 months.
    m=a112m = a^{\frac{1}{12}}. Monthly factor is the 12th root of the annual factor.
  32. Rewrite (1625)t2\left(\frac{16}{25}\right)^{\frac{t}{2}} as a base raised to tt.
    (1625)t2=(45)t\left(\frac{16}{25}\right)^{\frac{t}{2}} = \left(\frac{4}{5}\right)^t. Since 16/25=(4/5)216/25 = (4/5)^2, we get ((4/5)2)t/2=(4/5)t((4/5)^2)^{t/2} = (4/5)^t.
  33. Rewrite (14)t2\left(\frac{1}{4}\right)^{\frac{t}{2}} as a base raised to tt.
    (14)t2=(12)t\left(\frac{1}{4}\right)^{\frac{t}{2}} = \left(\frac{1}{2}\right)^t. Since 1/4=(1/2)21/4 = (1/2)^2, we get ((1/2)2)t/2=(1/2)t((1/2)^2)^{t/2} = (1/2)^t.
  34. Rewrite (1.02)12t\left(1.02\right)^{12t} as an equivalent annual factor raised to tt.
    (1.02)12t=(1.0212)t\left(1.02\right)^{12t} = \left(1.02^{12}\right)^t. Power of a power rule: (1.0212)t=1.0212t(1.02^{12})^t = 1.02^{12t}.
  35. Rewrite (13)2t\left(\frac{1}{3}\right)^{2t} as a base raised to tt.
    (13)2t=(19)t\left(\frac{1}{3}\right)^{2t} = \left(\frac{1}{9}\right)^t. Since (1/3)2=1/9(1/3)^2 = 1/9, using power rule gives (1/9)t(1/9)^t.
  36. Identify the equivalent monthly factor if the annual factor is 1.061.06.
    1.061121.06^{\frac{1}{12}}. Monthly factor is the 12th root of the annual factor.
  37. What is the definition of a negative exponent for a≠0a \neq 0?
    a−n=1ana^{-n} = \frac{1}{a^n}. A negative exponent means reciprocal of the positive power.
  38. Rewrite 81t481^{\frac{t}{4}} as a base raised to tt.
    81t4=3t81^{\frac{t}{4}} = 3^t. Since 81=3481 = 3^4, we get (34)t/4=3t(3^4)^{t/4} = 3^t.
  39. Rewrite (1.01)30t\left(1.01\right)^{30t} as an equivalent factor raised to tt.
    (1.01)30t=(1.0130)t\left(1.01\right)^{30t} = \left(1.01^{30}\right)^t. Power of a power rule: (1.0130)t=1.0130t(1.01^{30})^t = 1.01^{30t}.
  40. Rewrite (2t)(23t)\left(2^t\right)\left(2^{3t}\right) as a single exponential expression.
    (2t)(23t)=24t\left(2^t\right)\left(2^{3t}\right) = 2^{4t}. Product rule: 2t⋅23t=2t+3t=24t2^t \cdot 2^{3t} = 2^{t+3t} = 2^{4t}.
  41. Identify the weekly growth factor ww if the annual factor is aa and there are 5252 weeks.
    w=a152w = a^{\frac{1}{52}}. Weekly factor is the 52nd root of the annual factor.
  42. Rewrite 5t+35^{t+3} as a product involving 5t5^t.
    5t+3=125⋅5t5^{t+3} = 125\cdot 5^t. Using am+n=am⋅ana^{m+n} = a^m \cdot a^n, so 5t+3=53⋅5t=125⋅5t5^{t+3} = 5^3 \cdot 5^t = 125 \cdot 5^t.
  43. What transformation rewrites bktb^{kt} as an equivalent expression with exponent tt?
    bkt=(bk)tb^{kt} = \left(b^k\right)^t. Uses power of a power rule: (bk)t=bkt(b^k)^t = b^{kt}.
  44. Identify the equivalent quarterly factor if the annual factor is 1.121.12.
    1.12141.12^{\frac{1}{4}}. Quarterly factor is the 4th root of the annual factor.
  45. Rewrite 1.08t1.08^t to show a monthly factor raised to 12t12t.
    1.08t=(1.08112)12t1.08^t = \left(1.08^{\frac{1}{12}}\right)^{12t}. Rewrites annual factor as monthly factor raised to 12 times the power.
  46. Rewrite 1.44t1.44^t to show a monthly factor raised to 12t12t.
    1.44t=(1.44112)12t1.44^t = \left(1.44^{\frac{1}{12}}\right)^{12t}. Rewrites annual factor as monthly factor raised to 12 times the power.
  47. Rewrite 10t−210^{t-2} as a product involving 10t10^t.
    10t−2=1100⋅10t10^{t-2} = \frac{1}{100}\cdot 10^t. Using am−n=amana^{m-n} = \frac{a^m}{a^n}, so 10t−2=10t102=1100⋅10t10^{t-2} = \frac{10^t}{10^2} = \frac{1}{100} \cdot 10^t.
  48. Rewrite (bt)3\left(b^t\right)^3 as a single exponential expression in bb and tt.
    (bt)3=b3t\left(b^t\right)^3 = b^{3t}. Power of a power rule: (am)n=amn(a^m)^n = a^{mn}.
  49. Rewrite 32t532^{\frac{t}{5}} as a power with exponent tt.
    32t5=2t32^{\frac{t}{5}} = 2^t. Since 32=2532 = 2^5, we get (25)t/5=2t(2^5)^{t/5} = 2^t.
  50. Rewrite 32t3^{2t} as a power with exponent tt.
    32t=9t3^{2t} = 9^t. Since 32=93^2 = 9, using power of a power rule gives (32)t=9t(3^2)^t = 9^t.
  51. Rewrite (2t)5\left(2^t\right)^5 as a single exponential expression.
    (2t)5=25t\left(2^t\right)^5 = 2^{5t}. Power of a power rule: (2t)5=25t(2^t)^5 = 2^{5t}.
  52. State the exponent rule that rewrites amana^m a^n as a single power.
    aman=am+na^m a^n = a^{m+n}. Product of powers rule: add the exponents when bases are equal.
  53. Find and correct the error: (34)t=34+t\left(3^4\right)^t = 3^{4+t}.
    Correct: (34)t=34t\left(3^4\right)^t = 3^{4t}. Power of a power rule multiplies exponents, not adds them.
  54. Rewrite 52t5t\frac{5^{2t}}{5^t} as a single exponential expression.
    52t5t=5t\frac{5^{2t}}{5^t} = 5^t. Quotient rule: 52t5t=52t−t=5t\frac{5^{2t}}{5^t} = 5^{2t-t} = 5^t.

Study these flashcards