Counting Methods - ACT Math

  1. How many ways can 5 different keys be arranged on a keyring?
    4. Circular arrangement with identical rotations.
  2. What is the number of distinct permutations of the letters in LEVEL\text{LEVEL}?
    5!2!2!=30\frac{5!}{2!2!} = 30. Two L's and two E's create identical arrangements.
  3. What is the number of ways to choose rr items from nn distinct items when order does not matter?
    nCr^nC_r. Selection without regard to arrangement order.
  4. Identify the number of ways to arrange 4 people in a line.
    24. Calculate 4!=4×3×2×1=244! = 4 \times 3 \times 2 \times 1 = 24 arrangements.
  5. Identify the rule: when choices are mutually exclusive, how do you count total outcomes?
    Add the counts: m+n+⋯m+n+\cdots. Addition principle for disjoint events.
  6. How many ways can 8 people sit in a circle?
    7. Fix one position to eliminate rotational symmetry.
  7. How many ways can you choose 4 items from 10?
    (104)=210\binom{10}{4} = 210. Combination formula with n=10n=10 and r=4r=4.
  8. What is the formula for calculating combinations of nn items taken rr at a time?
    C(n,r)=n!r!(n−r)!C(n, r) = \frac{n!}{r!(n-r)!}. Order doesn't matter, so divide by r!r! arrangements.
  9. How many ways can you select 3 desserts from a menu of 5?
    (53)=10\binom{5}{3} = 10. Order doesn't matter for dessert selection.
  10. What is the number of distinct permutations of nn objects with repeats n1,n2,…,nkn_1,n_2,\dots,n_k?
    n!n1!n2!⋯nk!\frac{n!}{n_1!n_2!\cdots n_k!}. Divide by factorials of identical object counts.
  11. How many ways can you distribute 7 different books to 7 people?
    7. Each book goes to exactly one person.
  12. What is 6C3^6C_3?
    2020. 6!3!3!=72036=20\frac{6!}{3!3!} = \frac{720}{36} = 20
  13. What is the principle of multiplication in counting?
    If one event has mm outcomes and another has nn, total is m×nm \times n. Sequential events multiply their outcome counts.
  14. What is the formula for permutations with repetition?
    nrn^r. Each position can be filled with any of nn items.
  15. What is the number of binary strings of length 55 with exactly 22 ones?
    5C2=10^5C_2 = 10. Choose positions for ones among five spots.
  16. How many different 4-digit numbers can be formed using the digits 1-9?
    9×9×8×7=4,5369 \times 9 \times 8 \times 7 = 4,536. First digit excludes 0, others exclude previous digits.
  17. Identify the number of ways to choose 0 objects from a set of 7.
    1. By definition, C(n,0)=1C(n,0) = 1 for any non-negative integer nn.
  18. What is the number of permutations where 3 items are identical and 2 are distinct?
    5!3!\frac{5!}{3!}. Divides by 3!3! to account for identical items in permutations.
  19. What is the formula for combinations of rr objects from nn objects?
    C(n,r)=n!r!(n−r)!C(n, r) = \frac{n!}{r!(n-r)!}. Divides by r!r! to eliminate order since combinations ignore arrangement.
  20. What is the formula for circular permutations of nn distinct objects?
    (n−1)!(n-1)!. Fix one object to break circular symmetry.
  21. What is the number of 3-letter strings from 2626 letters if repetition is allowed?
    26326^3. Each position chosen independently with replacement.
  22. What is the Fundamental Counting Principle for mm choices followed by nn choices?
    m⋅nm \cdot n total outcomes. Multiply choices at each step for sequential decisions.
  23. What is the number of permutations of nn distinct objects taken all at once?
    n!n!. Each position has decreasing choices available.
  24. What is the value of 1!1!?
    1!=11! = 1. Only one way to arrange a single object.
  25. How many ways can 4 different books be arranged on a shelf if 2 are always together?
    12. Treat the pair as one unit: 3!×2!=123! \times 2! = 12 arrangements.
  26. What is the number of ways to assign president and vice president from 6 people?
    6P2=30^6P_2 = 30. Officer positions require specific ordering.
  27. What is 5P5^5P_5?
    120120. All arrangements of 55 distinct objects: 5!=1205! = 120
  28. What is the number of ways to arrange 8 objects in a circle?
    5040. Circular arrangements use (n−1)!=7!=5040(n-1)! = 7! = 5040 for 8 objects.
  29. How many ways can 2 identical balls be placed in 3 different boxes?
    6. Stars and bars: C(2+3−1,3−1)=C(4,2)=6C(2+3-1,3-1) = C(4,2) = 6 placements.
  30. What is the number of 3-letter strings from 2626 letters if repetition is not allowed?
    26P3^ {26}P_3. Permutation formula for distinct selections.
  31. What is the two-set inclusion–exclusion formula for ∣A∪B∣|A \cup B|?
    ∣A∪B∣=∣A∣+∣B∣−∣A∩B∣|A \cup B| = |A| + |B| - |A \cap B|. Add sets, subtract overlap to avoid double-counting.
  32. What does n!n! represent in counting methods?
    The product of all positive integers up to nn. Calculated as n×(n−1)×...×2×1n \times (n-1) \times ... \times 2 \times 1.
  33. How many ways can a president and vice president be selected from 5 candidates?
    20. Order matters for president and vice president roles.
  34. What is a combination?
    A selection of items without regard to order. Order is not important in selections.
  35. How many ways can you arrange the letters in the word 'BOOK'?
    4!2!=12\frac{4!}{2!} = 12. Two O's are identical, so divide by 2!2!.
  36. How many distinct permutations can be made from the letters in 'LEVEL'?
    30. Calculate 5!2!2!=1204=30\frac{5!}{2!2!} = \frac{120}{4} = 30 with repeated letters.
  37. In a group of 10 people, how many ways can you choose a committee of 3?
    (103)=120\binom{10}{3} = 120. Order doesn't matter when selecting committee members.
  38. State the number of ways to arrange 3 books on a shelf.
    6. Three distinct books can be arranged in 3!=63! = 6 ways.
  39. How many ways can 3 objects be selected from 5 distinct objects?
    10. Using C(5,3)=5!3!2!=1206⋅2=10C(5,3) = \frac{5!}{3!2!} = \frac{120}{6 \cdot 2} = 10.
  40. What is the formula for calculating permutations of nn items taken rr at a time?
    P(n,r)=n!(n−r)!P(n, r) = \frac{n!}{(n-r)!}. Order matters, so divide by unused positions (n−r)!(n-r)!.
  41. What is the factorial definition of n!n! for a positive integer nn?
    n!=n(n−1)(n−2)⋯2⋅1n! = n(n-1)(n-2)\cdots 2\cdot 1. Product of all positive integers from nn down to 11.
  42. What is the formula for the number of subsets of a set with nn elements?
    2n2^n. Each element can either be included or excluded.
  43. What is the complement rule for counting: how do you count outcomes in set AA using AcA^c?
    ∣A∣=∣U∣−∣Ac∣|A| = |U| - |A^c|. Count complement, subtract from universal set.
  44. How many ways can you form a group of 4 from 10 people?
    (104)=210\binom{10}{4} = 210. Same as choosing 4 from 10 people.
  45. What is 5C5^5C_5?
    11. One way to choose everything from any set.
  46. If a lock has 3 dials with 10 digits each, how many combinations are possible?
    103=1,00010^3 = 1,000. Each dial has 10 choices, multiply together.
  47. What is $ ^8C_2 $?
    2828. 8!2!6!=8⋅72=28\frac{8!}{2!6!} = \frac{8 \cdot 7}{2} = 28
  48. What is the value of 5!5!?
    120. Compute 5!=5×4×3×2×1=1205! = 5 \times 4 \times 3 \times 2 \times 1 = 120.
  49. What is $ ^7P_3 $?
    210210. 7!4!=504024=210\frac{7!}{4!} = \frac{5040}{24} = 210
  50. How many different outcomes are possible when tossing 3 coins?
    23=82^3 = 8. Each coin has 2 outcomes, multiply together.
  51. What is $ {}^7 P3P_3 $?
    210210. 7!4!=504024=210\frac{7!}{4!} = \frac{5040}{24} = 210
  52. If a password consists of 4 digits, how many possible passwords are there?
    104=10,00010^4 = 10,000. Each digit has 10 choices, multiply for all positions.
  53. How many ways can 4 identical items be distributed into 3 different boxes?
    15. Stars and bars: C(4+3−1,3−1)=C(6,2)=15C(4+3-1,3-1) = C(6,2) = 15 distributions.
  54. What is a permutation?
    An arrangement of items in a specific order. Order is important in arrangements.
  55. What is the number of ways to arrange nn distinct objects in a circle (rotations considered identical)?
    (n−1)!(n-1)!. Fix one position to eliminate rotational symmetry.
  56. How many different 3-person committees can be formed from 7 people?
    35. Calculate C(7,3)=7!3!4!=2106=35C(7,3) = \frac{7!}{3!4!} = \frac{210}{6} = 35 committees.
  57. What is the number of ways to choose a 2-person committee from 6 people?
    $ {}^6C_2 = 15 $. Committee selection ignores member ordering.
  58. What is the number of outcomes when rolling a die and flipping a coin once?
    6⋅2=126\cdot 2 = 12. Independent events multiply their outcome counts.
  59. If there are 3 routes from A to B and 2 from B to C, how many routes from A to C?
    6. Multiply choices for each segment of the journey.
  60. What is $ ^6C_3 $?
    2020. 6!3!3!=72036=20\frac{6!}{3!3!} = \frac{720}{36} = 20
  61. How many ways can 3 identical balls be placed in 4 different boxes?
    20. Stars and bars: C(3+4−1,4−1)=C(6,3)=20C(3+4-1,4-1) = C(6,3) = 20 placements.
  62. How many permutations are possible for arranging nn distinct objects?
    n!n!. Each position has decreasing choices, resulting in n!n! total arrangements.
  63. What is the number of ways to distribute 5 identical apples to 3 children?
    21. Stars and bars: C(5+3−1,3−1)=C(7,2)=21C(5+3-1,3-1) = C(7,2) = 21 ways.
  64. What is the number of subsets of a set with nn elements?
    2n2^n. Each element can be included or excluded.
  65. If you have 4 shirts and 3 pants, how many outfits can you create?
    12. Multiply clothing options using multiplication principle.
  66. What is ∣A∪B∣|A \cup B| if ∣A∣=12|A|=12, ∣B∣=9|B|=9, and ∣A∩B∣=5|A\cap B|=5?
    1616. Using inclusion-exclusion: 12+9−5=1612 + 9 - 5 = 16
  67. How many ways can the letters in 'ACT' be arranged?
    6. Three distinct letters give 3!=63! = 6 different arrangements.
  68. What is the formula for the number of ways to arrange nn objects where some are alike?
    n!p1!p2!...pk!\frac{n!}{p_1!p_2!...p_k!}. Divide by factorials of repeated object counts.
  69. What is the formula for combinations of nn distinct objects chosen rr at a time?
    nCr=n!r!(n−r)!^{n}C_r = \frac{n!}{r!(n-r)!}. Divides out arrangements within selected group.
  70. What is 5C0^5C_0?
    11. One way to choose nothing from any set.
  71. What is the factorial of 5?
    120. 5!=5×4×3×2×15! = 5 \times 4 \times 3 \times 2 \times 1.
  72. How many ways can a committee of 2 be formed from 5 people?
    (52)=10\binom{5}{2} = 10. Order doesn't matter for committee selection.
  73. What is the number of binary strings of length nn (each position 00 or 11)?
    2n2^n. Each position has 22 independent choices.
  74. What is the binomial coefficient notation for combinations?
    (nr)\binom{n}{r}. 'n choose r' notation for combination calculations.
  75. What is the number of circular arrangements of 77 distinct people around a round table?
    (7−1)!=720(7-1)! = 720. Fix one person's position to eliminate rotations.
  76. What is the value of 0!0!?
    1. By definition, factorial of zero equals one.
  77. What is the formula to calculate the number of subsets of a set?
    2n2^n. Each element can be included or excluded from any subset.
  78. What is the factorial of a non-negative integer nn represented by?
    n!n!. The symbol for the product of all positive integers from 1 to nn.
  79. State the number of ways to assign 3 tasks to 3 workers, one task per worker.
    6. One-to-one assignment gives 3!=63! = 6 possible arrangements.
  80. What is the number of combinations of 10 objects taken 4 at a time?
    210. Using C(10,4)=10!4!6!=504024=210C(10,4) = \frac{10!}{4!6!} = \frac{5040}{24} = 210 combinations.
  81. How many ways can you choose 2 cards from a deck of 52?
    (522)=1,326\binom{52}{2} = 1,326. Order doesn't matter when choosing cards.
  82. How many distinct permutations are there of the letters in 'MISSISSIPPI'?
    11!4!4!2!=34,650\frac{11!}{4!4!2!} = 34,650. Divide by repeated letters: 4 I's, 4 S's, 2 P's.
  83. What is the number of distinct permutations of the letters in MISS\text{MISS}?
    4!2!=12\frac{4!}{2!} = 12. Two S's create identical arrangements.
  84. How many ways can you arrange 3 red balls and 2 blue balls in a row?
    5!3!2!=10\frac{5!}{3!2!} = 10. Divide by repetitions of identical colored balls.
  85. What is the formula for permutations of nn distinct objects taken rr at a time?
    nPr=n!(n−r)!^nP_r = \frac{n!}{(n-r)!}. Accounts for unused objects in denominator.
  86. State the number of ways to choose 2 items from a set of 6.
    15. Using C(6,2)=6!2!4!=302=15C(6,2) = \frac{6!}{2!4!} = \frac{30}{2} = 15 ways.
  87. What is the number of subsets of a set with 66 elements?
    26=642^6 = 64. Each element independently included or excluded.
  88. What is the number of ways to choose rr items from nn distinct items when order matters?
    nPr^nP_r. Selection where arrangement order matters.
  89. What is the number of outcomes for kk independent steps with n1,n2,…,nkn_1,n_2,\dots,n_k choices each?
    n1n2⋯nkn_1 n_2 \cdots n_k. Multiply choices at each independent step.
  90. What is 9P2^9P_2?
    7272. 9!7!=9⋅8=72\frac{9!}{7!} = 9 \cdot 8 = 72
  91. How many ways to arrange 6 people in a line if 2 must stand together?
    5! ×2\times 2. Treat the pair as one unit, then arrange.
  92. How many ways can a president and a vice-president be selected from 5 people?
    20. Use permutations: P(5,2)=5!3!=20P(5,2) = \frac{5!}{3!} = 20 ordered selections.
  93. Which formula calculates permutations of rr objects from nn objects?
    P(n,r)=n!(n−r)!P(n, r) = \frac{n!}{(n-r)!}. Removes (n−r)!(n-r)! to account for unfilled positions in permutations.
  94. How many different 3-letter codes can be formed using the letters A, B, C, D?
    43=644^3 = 64. Each position has 4 letter choices with repetition.
  95. Identify the number of ways to arrange 6 people if 2 must sit together.
    240. Treat the pair as one unit: 5!×2!=2405! \times 2! = 240 arrangements.
  96. How many ways to arrange 3 red, 2 blue, and 1 green ball in a row?
    6!3!2!1!=60\frac{6!}{3!2!1!} = 60. Divide by repetitions of each color group.
  97. How many ways can 4 books be arranged on a shelf?
    24. Number of ways to arrange 4 distinct objects.
  98. What is the number of permutations of 5 objects taken 2 at a time?
    20. Apply P(5,2)=5!3!=1206=20P(5,2) = \frac{5!}{3!} = \frac{120}{6} = 20 permutations.
  99. What is the relationship between permutations and combinations: $ ^nP_r $ in terms of $ ^nC_r $?
    nPr=nCr⋅r!^nP_r = ^nC_r \cdot r!. Permutations equal combinations times internal arrangements.
  100. How many subsets can be formed from a set with 4 elements?
    16. Each element can be in or out, giving 24=162^4 = 16 subsets.
  101. What is 8C2^8C_2?
    2828. 8!2!6!=8⋅72=28\frac{8!}{2!6!} = \frac{8 \cdot 7}{2} = 28

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