Translating to Algebraic Expressions - Accuplacer Qas

  1. A shirt costs cc dollars. The price is first increased by 20%, and then this new price is decreased by 10%. Which expression represents the final price of the shirt?
    Answer: 0.90(c+0.20c)0.90(c + 0.20c) The initial price is cc. An increase of 20% makes the new price c+0.20cc + 0.20c, or 1.20c1.20c. This new price is then decreased by 10%. The discount amount is 10% of the new price, which is 0.10(c+0.20c)0.10(c + 0.20c). The final price is the new price minus the discount: (c+0.20c)−0.10(c+0.20c)(c + 0.20c) - 0.10(c + 0.20c). Factoring out (c+0.20c)(c + 0.20c) gives (1−0.10)(c+0.20c)(1 - 0.10)(c + 0.20c), which is 0.90(c+0.20c)0.90(c + 0.20c). Answer A incorrectly applies the 10% discount to the original price cc. Answers C and D incorrectly treat percentages as flat amounts.
  2. A plumber charges a flat fee of $50 for a house call, plus an hourly rate of rr dollars. For a job that takes hh hours, the plumber gives a 15% discount on the hourly charges only. Which expression represents the total cost?
    Answer: 50+0.85rh50 + 0.85rh The total hourly charge is rhrh. A 15% discount on this amount means the customer pays 85% of it, which is 0.85rh0.85rh. The flat fee of $50 is not discounted. The total cost is the sum of the flat fee and the discounted hourly charges: 50+0.85rh50 + 0.85rh. Answer A incorrectly applies the discount to the flat fee as well. Answer B incorrectly subtracts a flat 15 cents instead of 15 percent. Answer D incorrectly adds 15% instead of subtracting it.
  3. Which expression represents the difference between a number nn cubed and the cube of 5?
    Answer: n3−53n^3 - 5^3 The phrase 'a number nn cubed' is n3n^3. The phrase 'the cube of 5' is 535^3. The 'difference between' these two quantities is n3−53n^3 - 5^3. Answer A fails to cube the 5. Answer B represents 'the cube of the difference between nn and 5'. Answer D reverses the order of subtraction.
  4. A rope is ff feet and 8 inches long. Which expression represents the total length of the rope in inches?
    Answer: 12f+812f + 8 To find the total length in inches, all parts of the measurement must be in inches. There are 12 inches in 1 foot. Therefore, ff feet is equal to 12f12f inches. The additional 8 inches is then added to this amount. The total length in inches is 12f+812f + 8. Answer A incorrectly divides by 12. Answer B represents the total length in feet. Answer D uses an incorrect conversion factor of 3 (for yards to feet).
  5. A parking garage charges a base fee plus an hourly rate. The total cost for parking 3 hours is $12, and for 7 hours is $20. If a customer parks for hh hours and receives a 10% discount when parking exceeds 5 hours, which expression represents their total cost?
    Answer: {6+2hif h≤50.9(6+2h)if h>5\begin{cases} 6 + 2h & \text{if } h \leq 5 \\ 0.9(6 + 2h) & \text{if } h > 5 \end{cases} Let base fee = bb and hourly rate = rr. From given info: b+3r=12b + 3r = 12 and b+7r=20b + 7r = 20. Solving: 4r=84r = 8, so r=2r = 2 and b=6b = 6. Normal cost = 6+2h6 + 2h. For h>5h > 5, 10% discount applies to total cost: 0.9(6+2h)0.9(6 + 2h). Choice B is equivalent but unnecessarily complex. Choice C applies discount only to hourly portion. Choice D applies discount only to hourly rate, not total.
  6. A manufacturer produces widgets where the cost per widget decreases as production volume increases. The cost per widget is $8 for the first 100 widgets, then decreases by $0.02 for each additional group of 50 widgets produced. If xx represents the total number of widgets produced (where x>100x > 100), which expression represents the cost per widget?
    Answer: 8−0.02×⌊x−10050⌋8 - 0.02 \times \lfloor\frac{x-100}{50}\rfloor When you encounter piecewise pricing problems like this, you need to carefully track how the price changes occur and what triggers each change. Let's break down what happens: The first 100 widgets cost $8 each. After that, the cost decreases by $0.02 for each additional group of 50 widgets. The key insight is that the price reduction happens in discrete steps - only when you complete another full group of 50 widgets beyond the initial 100. For the correct answer D, 8−0.02×⌊x−10050⌋8 - 0.02 \times \lfloor\frac{x-100}{50}\rfloor, let's trace through the logic. If you produce 175 widgets, you've made 75 widgets beyond the first 100. Dividing 75 by 50 gives 1.5, but the floor function ⌊1.5⌋=1\lfloor 1.5 \rfloor = 1 means you've completed exactly 1 full group of 50. So the cost per widget is 8−0.02(1)=7.988 - 0.02(1) = 7.98. Answer A treats every single widget beyond 100 as triggering a $0.02 reduction, which contradicts the "group of 50" requirement. Answer B uses the exact division without the floor function, so it would give partial reductions (like $0.03 for 75 widgets) rather than step-wise changes. Answer C incorrectly includes the first 100 widgets in the division, which would apply discounts to the base production volume. Remember: When you see "group of" or "every X units" in pricing problems, look for the floor function ⌊⌋\lfloor \rfloor to handle the step-wise changes correctly.
  7. Let kk be the smallest of three consecutive odd integers. Which expression represents the sum of these three integers?
    Answer: 3k+63k + 6 Consecutive odd integers differ by 2. If the smallest is kk, the next odd integer is k+2k + 2, and the one after that is k+4k + 4. The sum is k+(k+2)+(k+4)k + (k + 2) + (k + 4). Combining like terms gives 3k+63k + 6. Answer B, 3k+33k + 3, represents the sum of three consecutive integers (e.g., k,k+1,k+2k, k+1, k+2). Answer A, (3k), would be the sum if the integers were k−2,k,k+2k-2, k, k+2, but the stem specifies that kk is the smallest. Answer D, 3k−63k - 6, would be the sum if kk were the largest integer (k−4,k−2,kk-4, k-2, k).
  8. A student's scores on four quizzes are 88, 92, 85, and xx. Which expression represents the average (arithmetic mean) of the student's quiz scores?
    Answer: 265+x4\frac{265 + x}{4} The average is the sum of the values divided by the number of values. There are 4 quiz scores. The sum is 88+92+85+x=265+x88 + 92 + 85 + x = 265 + x. To find the average, this sum must be divided by 4, giving 265+x4\frac{265 + x}{4}. Answer B represents the sum, not the average. Answer C incorrectly divides by 3, the number of known scores, instead of the total number of scores. Answer D is an order-of-operations error, dividing only xx by 4.
  9. A person buys xx apples at $0.75 each and yy oranges at $0.90 each. Which expression represents the total change received from a $20 bill?
    Answer: 20−(0.75x+0.90y)20 - (0.75x + 0.90y) First, calculate the total cost. The cost of apples is 0.75x0.75x and the cost of oranges is 0.90y0.90y. The total cost is their sum, 0.75x+0.90y0.75x + 0.90y. The change from a $20 bill is the initial amount minus the total cost. This requires subtracting the entire cost expression, so parentheses are necessary: 20−(0.75x+0.90y)20 - (0.75x + 0.90y). Answer A represents only the total cost. Answer B reverses the subtraction. Answer C is a common error where the subtraction is not distributed to the second term.
  10. A number, yy, is 8 less than the product of 3 and another number, xx. Which expression represents the value of yy?
    Answer: 3x−83x - 8 The phrase 'the product of 3 and another number, xx' translates to 3x3x. The phrase '8 less than' indicates that 8 should be subtracted from this product. Therefore, the correct expression is 3x−83x - 8. Answer A, 8−3x8 - 3x, is a common reversal error for 'less than'. Answer B, 3(x−8)3(x - 8), incorrectly subtracts 8 from xx before multiplying by 3. Answer D, 3x+83x + 8, incorrectly uses addition instead of subtraction.
  11. Three consecutive odd integers have the property that when the largest is divided by the smallest, the quotient is 13\frac{1}{3} more than when the middle integer is divided by the smallest. If nn represents the smallest odd integer, which equation correctly models this relationship?
    Answer: n+4n−n+2n=13\frac{n+4}{n} - \frac{n+2}{n} = \frac{1}{3} Three consecutive odd integers: nn, n+2n+2, n+4n+4. The condition states: largestsmallest=middlesmallest+13\frac{\text{largest}}{\text{smallest}} = \frac{\text{middle}}{\text{smallest}} + \frac{1}{3}. This gives n+4n=n+2n+13\frac{n+4}{n} = \frac{n+2}{n} + \frac{1}{3}. Rearranging: n+4n−n+2n=13\frac{n+4}{n} - \frac{n+2}{n} = \frac{1}{3}. Choice A is the unrearranged form. Choice C uses wrong denominator for largest/middle. Choice D interprets 'more than' as multiplication.
  12. Maria is mm years old. Her brother, David, is 3 years older than her. Which expression represents the sum of their ages 5 years from now?
    Answer: 2m+132m + 13 Currently, Maria's age is mm and David's age is m+3m + 3. In 5 years, Maria's age will be m+5m + 5 and David's age will be (m+3)+5(m + 3) + 5, which is m+8m + 8. The sum of their ages in 5 years will be (m+5)+(m+8)(m + 5) + (m + 8). Combining like terms gives 2m+132m + 13. Answer A is the sum of their current ages. Answer C represents adding 5 years only once to their combined current age (2m+3+52m+3+5). Answer B would be correct if David were 3 years younger than Maria.
  13. The length of a rectangular garden is 5 feet less than twice its width. If the width is represented by ww, which expression represents the perimeter of the garden?
    Answer: 2w+2(2w−5)2w + 2(2w - 5) First, translate the length. 'Twice its width' is 2w2w. '5 feet less than' that is 2w−52w - 5. The perimeter of a rectangle is 2L+2W2L + 2W, where LL is length and WW is width. Substituting the expressions gives 2(2w−5)+2w2(2w - 5) + 2w. Answer A represents the area, not the perimeter. Answer B represents the sum of one width and one length (half the perimeter). Answer C makes a reversal error for 'less than', writing the length as 5−2w5 - 2w.
  14. A person has qq quarters, dd dimes, and nn nickels. The number of dimes is twice the number of quarters. Which expression represents the total value of the coins in cents, in terms of qq and nn?
    Answer: 45q+5n45q + 5n The value of the coins in cents is 25q+10d+5n25q + 10d + 5n. The problem states that the number of dimes is twice the number of quarters, so d=2qd = 2q. We substitute 2q2q for dd in the value expression: 25q+10(2q)+5n25q + 10(2q) + 5n. This simplifies to 25q+20q+5n25q + 20q + 5n, which equals 45q+5n45q + 5n. Answer A represents the number of coins, not their value. Answer B represents the value in dollars, not cents. Answer C results from incorrectly setting up the relationship as q=2dq = 2d.
  15. Which expression represents one-half of the number that is 10 more than the square of xx?
    Answer: x2+102\frac{x^2 + 10}{2} Working from the inside out, 'the square of xx' is x2x^2. '10 more than' that is x2+10x^2 + 10. 'One-half of' this entire quantity means dividing the whole expression by 2, which gives x2+102\frac{x^2 + 10}{2}. Answer A, x22+10\frac{x^2}{2} + 10, represents '10 more than one-half of the square of xx', an order-of-operations error. Answer C represents 'one-half of the square of the sum of xx and 10'. Answer D incorrectly uses subtraction for 'more than'.
  16. A container holds GG gallons of water. A portion of the water, pp percent, is poured out. Then, 5 gallons are added. Which expression represents the final amount of water in the container, in gallons?
    Answer: G(1−p100)+5G(1 - \frac{p}{100}) + 5 The initial amount is GG. The amount poured out is pp percent of GG, which is (p100)G(\frac{p}{100})G. The amount remaining is G−(p100)GG - (\frac{p}{100})G, which can be factored as G(1−p100)G(1 - \frac{p}{100}). Finally, 5 gallons are added, so the final amount is G(1−p100)+5G(1 - \frac{p}{100}) + 5. Answer A treats the percentage pp as a flat amount. Answer B incorrectly applies the percentage decrease after the 5 gallons are added. Answer D incorrectly subtracts 5 instead of adding it.
  17. The value of a car, initially VV dollars, decreases by a total of DD dollars over a period of YY years at a constant rate. Which expression represents the value of the car after tt years, where t<Yt < Y?
    Answer: V−t(DY)V - t(\frac{D}{Y}) First, find the rate of decrease per year. If the value decreases by DD dollars in YY years, the constant rate is DY\frac{D}{Y} dollars per year. The total decrease after tt years is the rate multiplied by the time, which is t(DY)t(\frac{D}{Y}). The value after tt years is the initial value VV minus this total decrease: V−t(DY)V - t(\frac{D}{Y}). Answer A forgets to divide by YY to find the yearly rate. Answer B incorrectly adds the decrease, representing appreciation. Answer D omits the total decrease amount DD.
  18. Which expression represents the result when the sum of a number xx and 6 is subtracted from triple the number?
    Answer: 3x−(x+6)3x - (x + 6) The phrase 'subtracted from' means the first quantity is taken away from the second. 'The sum of a number xx and 6' is (x+6)(x + 6). 'Triple the number' is 3x3x. Subtracting the sum from triple the number means starting with 3x3x and subtracting the entire quantity (x+6)(x+6), which yields 3x−(x+6)3x - (x + 6). Answer A is a common reversal error for 'subtracted from'. Answer B makes a common error by failing to distribute the negative sign to both terms in the sum. Answer C misinterprets 'triple the number' as 'triple the sum'.
  19. Which expression represents the quotient of 10 and the quantity 3 less than a number xx?
    Answer: 10x−3\frac{10}{x-3} The phrase 'the quotient of A and B' translates to AB\frac{A}{B}. Here, A is 10 and B is 'the quantity 3 less than a number xx'. The quantity '3 less than xx' is x−3x - 3. Therefore, the full expression is 10x−3\frac{10}{x-3}. Answer A reverses the numerator and denominator. Answer B makes the common reversal error for 'less than'. Answer C is an order-of-operations error, representing 'the quotient of 10 and xx, minus 3'.
  20. A rectangular swimming pool is surrounded by a walkway of uniform width. The pool dimensions are 20 feet by 30 feet. If the walkway width is ww feet and the total area of the pool plus walkway exceeds the pool area by more than 440 square feet, which inequality represents this constraint?
    Answer: 4w2+100w>4404w^2 + 100w > 440 Pool area = 20×30=60020 \times 30 = 600 sq ft. Total area including walkway = (20+2w)(30+2w)=600+40w+60w+4w2=600+100w+4w2(20 + 2w)(30 + 2w) = 600 + 40w + 60w + 4w^2 = 600 + 100w + 4w^2. Difference = 600+100w+4w2−600=4w2+100w600 + 100w + 4w^2 - 600 = 4w^2 + 100w. Given this exceeds 440: 4w2+100w>4404w^2 + 100w > 440. Choice B is unreduced form. Choice C uses wrong threshold. Choice D assumes walkway only on two sides.

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