Equations with Fractions & Decimals - Accuplacer Qas

  1. If mm is a number such that 15m+23m=13\frac{1}{5}m + \frac{2}{3}m = 13, what is the value of mm?
    Answer: 1515 To solve for mm, first combine the terms on the left side. The least common denominator for 5 and 3 is 15. Rewrite the fractions: 315m+1015m=13\frac{3}{15}m + \frac{10}{15}m = 13. Combine them: 1315m=13\frac{13}{15}m = 13. To isolate mm, you can divide both sides by 13, which gives 115m=1\frac{1}{15}m = 1. Then, multiply both sides by 15 to get m=15m = 15.
  2. A student's final grade in a course is calculated as 35\frac{3}{5} of the test average plus 25\frac{2}{5} of the final exam score. A student has a test average of 85. If the student's final grade was 88, what was their final exam score?
    Answer: 92.592.5 Let EE be the final exam score. The formula for the final grade is G=35(TestAverage)+25(E)G = \frac{3}{5}(Test Average) + \frac{2}{5}(E). We are given G=88G = 88 and Test Average = 85. Substitute these values into the equation: 88=35(85)+25E88 = \frac{3}{5}(85) + \frac{2}{5}E. First, calculate 35(85)\frac{3}{5}(85): 3×855=3×17=513 \times \frac{85}{5} = 3 \times 17 = 51. The equation becomes 88=51+25E88 = 51 + \frac{2}{5}E. Subtract 51 from both sides: 37=25E37 = \frac{2}{5}E. To solve for EE, multiply both sides by 52\frac{5}{2}: E=37×52=1852=92.5E = 37 \times \frac{5}{2} = \frac{185}{2} = 92.5.
  3. A solution contains 0.3x+1.7=2.6x−0.80.3x + 1.7 = 2.6x - 0.8. After converting to eliminate decimals by multiplying by 10, what equation must be solved?
    Answer: 3x+17=26x−83x + 17 = 26x - 8 Multiplying the entire equation 0.3x+1.7=2.6x−0.80.3x + 1.7 = 2.6x - 0.8 by 10 gives: 10(0.3x)+10(1.7)=10(2.6x)−10(0.8)10(0.3x) + 10(1.7) = 10(2.6x) - 10(0.8), which becomes 3x+17=26x−83x + 17 = 26x - 8. Choice B incorrectly multiplies 0.3 as 30, Choice C multiplies some terms by 100, Choice D incorrectly makes 2.6x into 260x.
  4. At a certain company, 13\frac{1}{3} of the employees are in sales and 14\frac{1}{4} are in management. The remaining 35 employees are in production. How many employees work at the company in total?
    Answer: 8484 Let T be the total number of employees. The fraction of employees in sales and management combined is 13+14=412+312=712\frac{1}{3} + \frac{1}{4} = \frac{4}{12} + \frac{3}{12} = \frac{7}{12}. The remaining fraction of employees, who are in production, is 1−712=5121 - \frac{7}{12} = \frac{5}{12}. We are given that these remaining employees number 35. So, 512T=35\frac{5}{12}T = 35. To find T, multiply both sides by 125\frac{12}{5}: T=35×125=7×12=84T = 35 \times \frac{12}{5} = 7 \times 12 = 84.
  5. What is the solution to the equation z−26+z4=5\frac{z-2}{6} + \frac{z}{4} = 5?
    Answer: 12.812.8 The least common denominator of 6 and 4 is 12. Multiply every term in the equation by 12 to clear the fractions: 12(z−26)+12(z4)=12(5)12(\frac{z-2}{6}) + 12(\frac{z}{4}) = 12(5). This simplifies to 2(z−2)+3z=602(z-2) + 3z = 60. Distribute the 2: 2z−4+3z=602z - 4 + 3z = 60. Combine the zz terms: 5z−4=605z - 4 = 60. Add 4 to both sides: 5z=645z = 64. Divide by 5: z=645=12.8z = \frac{64}{5} = 12.8.
  6. What is the solution to the equation 23(x−6)=12x\frac{2}{3}(x - 6) = \frac{1}{2}x?
    Answer: 2424 To solve the equation 23(x−6)=12x\frac{2}{3}(x - 6) = \frac{1}{2}x, first distribute 23\frac{2}{3} on the left side: 23x−123=12x\frac{2}{3}x - \frac{12}{3} = \frac{1}{2}x, which simplifies to 23x−4=12x\frac{2}{3}x - 4 = \frac{1}{2}x. To eliminate the fractions, multiply all terms by the least common denominator, which is 6. This gives 6(23x)−6(4)=6(12x)6(\frac{2}{3}x) - 6(4) = 6(\frac{1}{2}x), which simplifies to 4x−24=3x4x - 24 = 3x. Subtracting 3x3x from both sides gives x−24=0x - 24 = 0. Adding 24 to both sides gives x=24x = 24.
  7. What is the solution to the equation 34x−0.5=0.25x\frac{3}{4}x - 0.5 = 0.25x?
    Answer: 11 This equation contains both a fraction and decimals. It's often easiest to convert everything to one form. Converting to decimals: 34\frac{3}{4} is 0.75, so the equation becomes 0.75x−0.5=0.25x0.75x - 0.5 = 0.25x. Subtract 0.25x0.25x from both sides: 0.50x−0.5=00.50x - 0.5 = 0. Add 0.5 to both sides: 0.50x=0.50.50x = 0.5. Divide by 0.5: x=1x = 1. Alternatively, converting to fractions: 0.5 is 12\frac{1}{2} and 0.25 is 14\frac{1}{4}. The equation becomes 34x−12=14x\frac{3}{4}x - \frac{1}{2} = \frac{1}{4}x. Multiply all terms by the LCD, 4, to get 3x−2=x3x - 2 = x. Subtract xx from both sides: 2x−2=02x - 2 = 0. Add 2 to both sides: 2x=22x = 2. Divide by 2: x=1x = 1.
  8. The average (arithmetic mean) of three numbers is 15. The first number is 12x\frac{1}{2}x. The second number is 13x\frac{1}{3}x. The third number is 10. What is the value of xx?
    Answer: 4242 The average of three numbers is their sum divided by 3. The equation is 12x+13x+103=15\frac{\frac{1}{2}x + \frac{1}{3}x + 10}{3} = 15. First, multiply both sides by 3 to get the sum: 12x+13x+10=45\frac{1}{2}x + \frac{1}{3}x + 10 = 45. Subtract 10 from both sides: 12x+13x=35\frac{1}{2}x + \frac{1}{3}x = 35. To combine the fractions, find a common denominator (6): 36x+26x=35\frac{3}{6}x + \frac{2}{6}x = 35, which is 56x=35\frac{5}{6}x = 35. To solve for xx, multiply both sides by the reciprocal 65\frac{6}{5}: x=35×65=7×6=42x = 35 \times \frac{6}{5} = 7 \times 6 = 42.
  9. What value of pp satisfies the equation 4p−2p=3\frac{4p - 2}{p} = 3?
    Answer: 22 Assuming p≠0p \neq 0, we can solve this equation by multiplying both sides by pp to clear the denominator. This gives 4p−2=3p4p - 2 = 3p. To isolate the variable pp, subtract 3p3p from both sides: p−2=0p - 2 = 0. Finally, add 2 to both sides to find p=2p = 2.
  10. A customer's monthly phone bill is calculated as a flat fee of $15.00 plus $2.50 per gigabyte of data used. If a customer's bill for one month was $52.50, how many gigabytes of data did they use?
    Answer: 1515 Let gg be the number of gigabytes of data used. The total cost can be represented by the equation 15.00+2.50g=52.5015.00 + 2.50g = 52.50. To find gg, first subtract the flat fee from the total bill: 2.50g=52.50−15.002.50g = 52.50 - 15.00, which simplifies to 2.50g=37.502.50g = 37.50. Then, divide the remaining cost by the price per gigabyte: g=37.502.50=15g = \frac{37.50}{2.50} = 15. The customer used 15 gigabytes of data.
  11. What value of yy satisfies the equation 35y−2=13y+6\frac{3}{5}y - 2 = \frac{1}{3}y + 6?
    Answer: 3030 To solve the equation, first eliminate the fractions by multiplying every term by the least common denominator of 5 and 3, which is 15. The equation becomes 15(35y)−15(2)=15(13y)+15(6)15(\frac{3}{5}y) - 15(2) = 15(\frac{1}{3}y) + 15(6), which simplifies to 9y−30=5y+909y - 30 = 5y + 90. Next, gather the variable terms on one side by subtracting 5y5y from both sides: 4y−30=904y - 30 = 90. Add 30 to both sides: 4y=1204y = 120. Finally, divide by 4: y=30y = 30.
  12. A rectangle has a length of 12x+3\frac{1}{2}x + 3 units and a width of 13x−1\frac{1}{3}x - 1 units. If the perimeter of the rectangle is 34 units, what is the value of xx?
    Answer: 1818 The formula for the perimeter of a rectangle is P=2(L+W)P = 2(L+W). Substitute the given expressions: 34=2((12x+3)+(13x−1))34 = 2((\frac{1}{2}x + 3) + (\frac{1}{3}x - 1)). First, simplify the expression inside the parentheses by combining like terms: 12x+13x=36x+26x=56x\frac{1}{2}x + \frac{1}{3}x = \frac{3}{6}x + \frac{2}{6}x = \frac{5}{6}x, and 3−1=23 - 1 = 2. The equation becomes 34=2(56x+2)34 = 2(\frac{5}{6}x + 2). Distribute the 2: 34=106x+434 = \frac{10}{6}x + 4, which simplifies to 34=53x+434 = \frac{5}{3}x + 4. Subtract 4 from both sides: 30=53x30 = \frac{5}{3}x. To solve for xx, multiply both sides by 35\frac{3}{5}: x=30×35=18x = 30 \times \frac{3}{5} = 18.
  13. The equation 0.2(y−5)+0.3=1.70.2(y - 5) + 0.3 = 1.7 is given. What is the value of yy?
    Answer: 1212 First, isolate the term containing the parentheses by subtracting 0.3 from both sides: 0.2(y−5)=1.7−0.30.2(y - 5) = 1.7 - 0.3, which simplifies to 0.2(y−5)=1.40.2(y - 5) = 1.4. Next, divide both sides by 0.2: y−5=1.40.2=7y - 5 = \frac{1.4}{0.2} = 7. Finally, add 5 to both sides to solve for yy: y=7+5=12y = 7 + 5 = 12.
  14. Solve for zz: z+53=z−12\frac{z + 5}{3} = \frac{z - 1}{2}
    Answer: 1313 To solve this proportion, you can cross-multiply. This gives 2(z+5)=3(z−1)2(z + 5) = 3(z - 1). Distribute the numbers on both sides: 2z+10=3z−32z + 10 = 3z - 3. To solve for zz, gather the zz terms on one side and the constants on the other. Subtract 2z2z from both sides: 10=z−310 = z - 3. Add 3 to both sides: 13=z13 = z.
  15. A chemist mixes a quantity of a 20% acid solution with a 60% acid solution to produce 50 liters of a 30% acid solution. How many liters of the 20% acid solution were used?
    Answer: 37.537.5 Let xx be the number of liters of the 20% solution. Then 50−x50 - x is the number of liters of the 60% solution. The total amount of acid in the final mixture is the sum of the amounts of acid from each solution. This can be written as the equation: 0.20x+0.60(50−x)=0.30(50)0.20x + 0.60(50 - x) = 0.30(50). Distribute on the left side: 0.20x+30−0.60x=150.20x + 30 - 0.60x = 15. Combine the xx terms: −0.40x+30=15-0.40x + 30 = 15. Subtract 30 from both sides: −0.40x=−15-0.40x = -15. Divide by -0.40: x=−15−0.40=37.5x = \frac{-15}{-0.40} = 37.5. So, 37.5 liters of the 20% solution were used.
  16. If 4.5+0.2(x−1)=64.5 + 0.2(x-1) = 6, what is the value of xx?
    Answer: 8.58.5 To solve for xx, first isolate the term containing the variable. Subtract 4.5 from both sides of the equation: 0.2(x−1)=6−4.50.2(x-1) = 6 - 4.5, which simplifies to 0.2(x−1)=1.50.2(x-1) = 1.5. Next, divide both sides by 0.2: x−1=1.50.2=7.5x-1 = \frac{1.5}{0.2} = 7.5. Finally, add 1 to both sides: x=7.5+1=8.5x = 7.5 + 1 = 8.5.
  17. If 23k−4=2\frac{2}{3}k - 4 = 2, what is the value of the expression k−3k - 3?
    Answer: 66 First, solve the given equation for kk. Add 4 to both sides of 23k−4=2\frac{2}{3}k - 4 = 2 to get 23k=6\frac{2}{3}k = 6. To isolate kk, multiply both sides by the reciprocal of 23\frac{2}{3}, which is 32\frac{3}{2}. This gives k=6×32=9k = 6 \times \frac{3}{2} = 9. The question asks for the value of k−3k - 3. Substitute the value of kk: 9−3=69 - 3 = 6.
  18. If 23x+58=34x−16\frac{2}{3}x + \frac{5}{8} = \frac{3}{4}x - \frac{1}{6}, what is the value of xx?
    Answer: x=192x = \frac{19}{2} Rearrange to get all xx terms on one side: 23x−34x=−16−58\frac{2}{3}x - \frac{3}{4}x = -\frac{1}{6} - \frac{5}{8}. Find common denominators: 812x−912x=−424−1524\frac{8}{12}x - \frac{9}{12}x = -\frac{4}{24} - \frac{15}{24}. This simplifies to −112x=−1924-\frac{1}{12}x = -\frac{19}{24}. Multiply both sides by −12-12: x=19×1224=192x = \frac{19 \times 12}{24} = \frac{19}{2}. Choice B incorrectly uses 5 in denominator, Choice C uses wrong arithmetic, Choice D makes fraction errors.
  19. If 0.4(x+10)−0.1x=10.4(x + 10) - 0.1x = 1, what is the value of xx?
    Answer: −10-10 To solve for xx, first distribute the 0.4: 0.4x+4−0.1x=10.4x + 4 - 0.1x = 1. Combine the terms with xx: 0.3x+4=10.3x + 4 = 1. Subtract 4 from both sides: 0.3x=−30.3x = -3. Finally, divide by 0.3: x=−30.3=−10x = \frac{-3}{0.3} = -10. Alternatively, multiply the entire equation by 10 to clear the decimals: 4(x+10)−1x=104(x + 10) - 1x = 10, which becomes 4x+40−x=104x + 40 - x = 10, then 3x+40=103x + 40 = 10, so 3x=−303x = -30, and x=−10x = -10.
  20. The equation 1.2x−0.4(x+3)=0.6x+1.81.2x - 0.4(x + 3) = 0.6x + 1.8 has what solution?
    Answer: x=15x = 15 Expand: 1.2x−0.4x−1.2=0.6x+1.81.2x - 0.4x - 1.2 = 0.6x + 1.8. Combine like terms: 0.8x−1.2=0.6x+1.80.8x - 1.2 = 0.6x + 1.8. Subtract 0.6x0.6x and add 1.21.2: 0.2x=30.2x = 3. Therefore x=15x = 15. Choice A results from decimal calculation errors, Choice C from incorrectly combining terms, Choice D incorrectly assumes the equation has no solution when coefficients appear similar.

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