Accuplacer Aaf Quiz
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Let f(x)={2x+1if x<02if 0≤x<2x−1if x≥2f(x) = \begin{cases} 2x+1 & \text{if } x < 0 \\ 2 & \text{if } 0 \le x < 2 \\ x-1 & \text{if } x \ge 2 \end{cases}. How many distinct solutions does the equation f(x)=xf(x) = x have?
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