Graph Proportional Relationships - 8th Grade Math

  1. Identify the constant of proportionality for the table rule y=5xy = 5x.
    k=5k = 5. The coefficient of xx in y=5xy = 5x is the constant.
  2. What point must be on the graph of any proportional relationship y=kxy = kx?
    (0,0)(0,0). All proportional relationships pass through the origin.
  3. What is the slope of the line representing y=kxy = kx on a coordinate plane?
    kk. In y=kxy = kx, the coefficient kk is the slope.
  4. Identify the unit rate (slope) for the proportional relationship y=6xy = 6x.
    66. The coefficient of xx is the unit rate.
  5. Identify the slope for the proportional graph that passes through (0,0)(0,0) and (2,−6)(2,-6).
    −62=−3\frac{-6}{2} = -3. Calculate slope using two points: −6−02−0\frac{-6-0}{2-0}.
  6. What is the equation of a proportional relationship with unit rate k=9k=9?
    y=9xy = 9x. Substitute kk into the form y=kxy = kx.
  7. What is the slope of the line y=−12xy = -\frac{1}{2}x and what does its sign indicate?
    −12-\frac{1}{2}; yy decreases as xx increases. Negative slope means inverse relationship.
  8. Find the unit rate from the table: (t,d)=(1,7),(2,14),(3,21)(t,d)=(1,7),(2,14),(3,21).
    77. Distance increases by 77 for each unit of time.
  9. A proportional graph includes (1,7)(1,7). What is the equation in the form y=kxy = kx?
    y=7xy = 7x. Since (1,7)(1,7) is on the line, k=71=7k = \frac{7}{1} = 7.
  10. What is the slope of a proportional relationship if yy increases by 99 when xx increases by 33?
    93=3\frac{9}{3} = 3. Slope equals change in yy over change in xx.
  11. What is the yy-intercept of any proportional relationship graphed as a line on a coordinate plane?
    00. All proportional relationships pass through (0,0)(0,0).
  12. What is the slope (unit rate) of a proportional relationship written as y=kxy = kx?
    kk. In y=kxy = kx, the coefficient kk represents the slope.
  13. Find kk for a proportional relationship where y=18y = 18 when x=9x = 9.
    k=2k = 2. Solve k=yx=189=2k = \frac{y}{x} = \frac{18}{9} = 2.
  14. Choose the greater unit rate: y=2.5xy = 2.5x or y=114xy = \frac{11}{4}x.
    y=114xy = \frac{11}{4}x. 114=2.75>2.5\frac{11}{4} = 2.75 > 2.5, so greater unit rate.
  15. What is the definition of a proportional relationship in terms of yy and xx?
    y=kxy = kx for a constant kk. Direct variation where yy is always kk times xx.
  16. Which equation represents a proportional relationship: y=3x+2y = 3x + 2 or y=3xy = 3x?
    y=3xy = 3x. Only y=3xy = 3x passes through (0,0)(0,0).
  17. What is the slope of the line y=−32xy = -\frac{3}{2}x?
    −32-\frac{3}{2}. The coefficient of xx is the slope.
  18. Identify the slope of the line through (0,0)(0,0) and (4,−10)(4,-10).
    −52-\frac{5}{2}. Use m=−10−04−0=−104=−52m = \frac{-10-0}{4-0} = \frac{-10}{4} = -\frac{5}{2}
  19. Which equation represents a proportional relationship: y=3xy = 3x or y=3x+2y = 3x + 2?
    y=3xy = 3x. Only y=3xy = 3x passes through (0,0)(0,0).
  20. Which representation has the greater unit rate: y=2.8xy=2.8x or a graph with slope 3.13.1?
    The graph with slope 3.13.1. Compare unit rates: 3.1>2.83.1 > 2.8.
  21. What is the unit rate (slope) for the table pair x=4x=4, y=14y=14 in a proportional relationship?
    k=144=3.5k = \frac{14}{4} = 3.5. Divide yy by xx to find the constant of proportionality.
  22. Which object is faster: A has d=5td=5t, B has d=4td=4t (same units)?
    A. Compare coefficients: 5>45 > 4.
  23. Find and correct the error: "For y=34xy=\frac{3}{4}x, the slope is 43\frac{4}{3}." What is the correct slope?
    Correct slope: 34\frac{3}{4}. The coefficient 34\frac{3}{4} is the slope, not its reciprocal.
  24. Identify whether the relationship is proportional if the graph line crosses the yy-axis at 22.
    Not proportional. Must pass through (0,0)(0,0) to be proportional.
  25. Find the constant of proportionality kk if yy is proportional to xx and (x,y)=(8,−20)(x,y)=(8,-20).
    k=−208=−52k = \frac{-20}{8} = -\frac{5}{2}. Use k=yxk = \frac{y}{x} with the given point.
  26. What is the speed (unit rate) for the distance-time equation d=12td = 12t?
    1212 (distance units per time unit). Coefficient of tt gives speed in distance per time.
  27. Which object has greater speed: A passes through (2,14)(2,14) on a dd vs. tt graph, B has d=6td = 6t?
    Object A. A has slope 142=7>6\frac{14}{2} = 7 > 6, so A is faster.
  28. What is the unit rate for the ratio 246\frac{24}{6} (as yy per xx)?
    44. Divide yy by xx: 246=4\frac{24}{6} = 4.
  29. What is the constant of proportionality for a proportional relationship shown by the ratio yx\frac{y}{x}?
    k=yxk = \frac{y}{x}. The constant ratio of yy to xx equals kk.
  30. What is the slope formula between two points $ (x1x_1,y1y_1) $ and $ (x2x_2,y2y_2) $?
    m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}. Rise over run gives the rate of change between points.
  31. Which object is faster: A has slope 33, B has slope 72\frac{7}{2} (same units)?
    B. Compare slopes: 72=3.5>3\frac{7}{2} = 3.5 > 3.
  32. Find the slope of the proportional relationship through (0,0)(0,0) and (3,12)(3,12).
    m=4m = 4. Use m=12−03−0=123=4m = \frac{12-0}{3-0} = \frac{12}{3} = 4.
  33. A car travels 180180 miles in 33 hours. What is the speed (unit rate) in mileshour\frac{\text{miles}}{\text{hour}}?
    6060. Speed = distancetime=1803\frac{\text{distance}}{\text{time}} = \frac{180}{3}.
  34. What is the unit rate in the equation y=kxy = kx?
    kk (the value of yy when x=1x = 1). The constant kk represents the rate of change per unit of xx.
  35. Compare: A has slope 33 on a dd vs. tt graph; B has equation d=2.8td = 2.8t. Which is faster?
    Object A. Slope 3>2.83 > 2.8, so A is faster.
  36. Compare speeds: Object A d=45td = 45t and Object B d=40td = 40t. Which is faster?
    Object A. Compare coefficients: 45>4045 > 40.
  37. What point must the graph of any proportional relationship include on the coordinate plane?
    (0,0)(0,0). Proportional relationships always pass through the origin.
  38. Choose the correct slope for a distance-time graph that goes through (0,0)(0,0) and (4,30)(4,30).
    304=7.5\frac{30}{4} = 7.5. Use slope formula: 30−04−0\frac{30-0}{4-0}.
  39. Find the slope of the line through (0,0)(0,0) and (5,20)(5,20), and interpret it as a unit rate.
    205=4\frac{20}{5} = 4. Slope = rise over run = 20−05−0\frac{20-0}{5-0}.
  40. What is the slope of a distance-time graph if distance increases 150150 meters in 55 seconds?
    3030. Slope = DeltadDeltat=1505\frac{Delta d}{Delta t} = \frac{150}{5}.

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